Answer:
-3/5 or a
Step-by-step explanation:
5 - 2 = 3
0-5 = -5
3/-5 = -3/5
as part of video game, the point (5,2) is rotated counterclockwise about the origin through an angle of 5 degrees. find the new coordinates of this point
The new coordinates of the point (5, 2) after rotating counterclockwise about the origin through an angle of 5 degrees are approximately (4.993, 2.048).
To find the new coordinates of the point (5, 2) after rotating counterclockwise about the origin through an angle of 5 degrees, we can use the rotation formula:
x' = x * cos(theta) - y * sin(theta)
y' = x * sin(theta) + y * cos(theta)
Where (x, y) are the original coordinates, (x', y') are the new coordinates after rotation, and theta is the angle of rotation in radians.
Converting the angle of rotation from degrees to radians:
theta = 5 degrees * (pi/180) ≈ 0.08727 radians
Plugging in the values into the rotation formula:
x' = 5 * cos(0.08727) - 2 * sin(0.08727)
y' = 5 * sin(0.08727) + 2 * cos(0.08727)
Evaluating the trigonometric functions and simplifying:
x' ≈ 4.993
y' ≈ 2.048
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Please help‼️ domain and range‼️
The domain and the range of the function are (-∝, ∝) and (0, ∝), respectively
Calculating the domain and range of the graph?From the question, we have the following parameters that can be used in our computation:
The graph
The above graph is an exponential function
The rule of an function is that
The domain is the set of all real values
In this case, the domain is (-∝, ∝)
For the range, we have
Range = (0, ∝)
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mrs.torres's class has 28 students the class includes 12 boys what is the ratio of girls and boys
Answer:
4:3.
Step-by-step explanation:
Number of boys = 12 and number girls = 16.
Ratio girls to boys = 16:12
= 4:3.
What’s the answer to this question
The recursive formula of the arithmetic sequence is:
xₙ = n*4 + 13
With that we can see that x₁₁ = 57
How to write the arithmetic sequence?Here we know that the first elements of the sequence are:
17, 21, 25, 29, ...
To find the common difference, d, we take the difference between any two consecutive elements, so we have:
c = 21 - 17 = 4
Then the recursive formula for the n-th term is:
xₙ = n*4 + d
The first element x₁ is 17, so we will have:
17 = 1*4 + d
17 - 4 = d = 13
The recursive formula is:
xₙ = n*4 + 13
b) the eleventh term of the sequence is given by replacing n in the above formula by 11.
x₁₁ = 4*11 + 13 = 44 + 13 = 57
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In a class of students, the following data table summarizes how many students passed
a test and complete the homework due the day of the test. What is the probability that
a student chosen randomly from the class passed the test?
Completed the homework
Did not complete the homework
Passed the test Failed the test
12
2
4
3
Answer:
20/27
Step-by-step explanation:
Chastity ran a hypothesis test with an alpha level of .01 and her test statistic fell outside of the critical region. what should she do?
The critical region is determined based on the alpha level, which is the probability of making a Type I error (rejecting the null hypothesis when it is true). An alpha level of .01 means that there is a 1% chance of making a Type I error.
If Chastity ran a hypothesis test with an alpha level of .01 and her test statistic fell outside of the critical region, it means that the test statistic does not provide enough evidence to reject the null hypothesis.
In this case, Chastity should fail to reject the null hypothesis and accept it as the plausible explanation. This implies that there is not enough evidence to support the alternative hypothesis.
When a test statistic falls outside of the critical region, it indicates that the observed data is not extreme enough to reject the null hypothesis. The critical region is determined based on the alpha level, which is the probability of making a Type I error (rejecting the null hypothesis when it is true). An alpha level of .01 means that there is a 1% chance of making a Type I error.
In summary, when Chastity's test statistic falls outside of the critical region, she should fail to reject the null hypothesis and accept it as the plausible explanation. This means that there is not enough evidence to support the alternative hypothesis at the given alpha level of .01.
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. h e l p
...... ....... ......... ........
no u ,...................................................................................................................................
you want to know the percentage of utility companies that earned revenue between 41 million and 99 million dollars. if the mean revenue was 70 million dollars and the data has a standard deviation of 18 million, find the percentage. assume that the distribution is normal. round your answer to the nearest hundredth.
Approximately 89.26% of utility companies have revenue between 41 million and 99 million dollars. We need to use the normal distribution formula and find the z-scores for the given values.
First, we need to find the z-score for the lower limit of the range (41 million dollars): z = (41 - 70) / 18 = -1.61
Next, we need to find the z-score for the upper limit of the range (99 million dollars): z = (99 - 70) / 18 = 1.61
We can now use a standard normal distribution table or a calculator to find the area under the curve between these two z-scores. The area between -1.61 and 1.61 is approximately 0.9044. This means that approximately 90.44% of utility companies earned revenue between 41 million and 99 million dollars.
To find the percentage of utility companies with revenue between 41 million and 99 million dollars, we can use the z-score formula and the standard normal distribution table. The z-score formula is: (X - mean) / standard deviation. First, we'll calculate the z-scores for both 41 million and 99 million dollars: Z1 = (41 million - 70 million) / 18 million = -29 / 18 ≈ -1.61
Z2 = (99 million - 70 million) / 18 million = 29 / 18 ≈ 1.61
Now, we'll look up the z-scores in the standard normal distribution table to find the corresponding percentage values.
For Z1 = -1.61, the table value is approximately 0.0537, or 5.37%.
For Z2 = 1.61, the table value is approximately 0.9463, or 94.63%.
Percentage = 94.63% - 5.37% = 89.26%
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camilla leans a 18foot ladder against a wall so that it forms an angle of 71 with the ground. how high up the wall does the ladder reach? Round your answer to the nearest tenth of a foot if necessary
The wall is 17.0 ft from the point ladder touches the wall
Explanation:The length of the ladder = 18 ft
The angle the ladder makes with the wall = 71°
We need to find the distance betwen the base of the wall and the point the ladder touches the wall.
To solve this, we will do an illustration of the scenario:
Let x = distance between the base of the wall and the point the ladder touches the wall
To get x, we will apply sine ratio (SOH):
\(\begin{gathered} si\text{ n }71\degree\text{ = }\frac{opposite}{hypotenuse} \\ \text{opposite = x, hypotenuse = }18 \\ \\ \sin \text{ }71\degree=\text{ }\frac{x}{18} \end{gathered}\)\(\begin{gathered} x\text{ = 18(}\sin 71\degree) \\ x\text{ = 18(}0.9455) \\ x\text{ = 17.019} \\ To\text{ the nearest tenth, x = 17.0} \end{gathered}\)The wall is 17.0 ft from the point ladder touches the wall
answer choices:
6cm by 1.5cm
10cm by 2cm
13cm by 4cm
18cm by 4.5cm
80cm by 20cm
worth 23 points! and i will give brainly , pls hellpppp
Answer:
6cm by 1.5cm
18cm by 4.5cm
80cm by 20cm
Step-by-step explanation:
The length of a rectangle is 7 centimeters less than its width. What are the dimensions of the rectangle if its area is 60 square centimeters?
The dimensions of the rectangle has a width = 12cm and length = 5cm.
Area of rectangleIn calculating the area of a rectangle, we multiply its length and width.
Let us use the letter x to represent the width, so that the length = x - 7
hence we calculate for the unknown x as follows;
x(x - 7) = 60
expand and equate to zero to derive a quadratic equation
x² + 7x - 60 = 0
by factorisation;
x² - 12x + 5x - 60 = 0
x(x - 12) +5(x -12) = 0
(x + 5)(x - 12) = 0
thus for x + 5 = 0
x = -5
and for x - 12 = 0
x = 12
Therefore, x = 12 is true for the quadratic equation and also for the width = 12 and length = 5cm for the rectangle.
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Directions: Draw a histogram to represent the set of data.
number of points scored in each
basketball game: 28, 16, 38, 44, 21, 38,
35, 48, 33, 29, 37, 39, 18, 38, 42, 37, 32
Using the frequency distribution, boundary points and central value of the data, the histogram of the given data is attached below.
What is the histogram of the dataTo draw the histogram of the given data, we need to find the class, class boundaries, tally marks and the frequency of the data.
Class Class Boundaries Tally marks Frequency
11 - 20 10.5 - 20.5 || 2
21 - 30 20.5 - 30.5 ||| 3
31 - 40 30.5 - 40.5 ||||| |||| 9
41 - 50 40.5 - 50.5 ||| 3
Total 17
To draw histogram, we first prepare the frequency distribution with boundary points, with central value of each class
Class Lower Upper Frequency(f)
11 - 20 10.5 20.5 2
21 - 30 20.5 30.5 3
31 - 40 30.5 40.5 9
41 - 50 40.5 50.5 3
The histogram of the data is plotted below
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Answer the following question
14 is 35% of what?
Answer:
40
Step-by-step explanation:
14 / 0.35 = 40
I hope this helps!!!
PLEASE HELP ASAP, will give Brainlyst to the best answer:
Solve for X:
4x - 12 = 8x + 24
O A. x=-9
O
B. X=-3
O C. x=1
О O
D. x= 3
Answer:
-9
Step-by-step explanation:
4x-12=8x+24
we change the signs when we bring 8x on the left hand side so positive 8x becomes -8x.
4x-8x-12=24
we change sign when we bring -12 on the right hand side it becomes +12
4x-8x=24+12
-4x=36
x=36/-4
x=-4
let β = {x1, . . . , xk} be an orthonormal basis for the subspace W of R^n. use the matrix x ∈ Mn×k(R) with columns x1, . . . , xk, to construct p ∈ Mn×n(R) such that Lp is the orthogonal projection on W. Justify your answer rigorously, i.e., show that Lp is indeed an orthogonal projection with R(Lp) = W.
To construct the matrix P that represents the orthogonal projection onto the subspace W spanned by the orthonormal basis β = {x1, ..., xk} in R^n, we can use the formula:
P = X (X^T X)^(-1) X^T
Here, X is the matrix with columns x1, ..., xk. The matrix P will have dimensions n x n.
To justify that Lp is the orthogonal projection with R(Lp) = W, we need to show two properties:
Lp is an orthogonal projection:
Lp is idempotent: (Lp)^2 = Lp
Lp is self-adjoint: (Lp)^T = Lp
R(Lp) = W:
Every vector in the range of Lp is in W
Every vector in W is in the range of Lp
Let's break down the steps to construct P and verify these properties:
Step 1: Compute the matrix X^T X
X^T is the transpose of X
Multiply X^T with X to obtain X^T X
Step 2: Invert the matrix (X^T X)^(-1)
If X^T X is invertible, calculate its inverse (if it is not invertible, the orthogonal projection does not exist)
Step 3: Compute the matrix P = X (X^T X)^(-1) X^T
Multiply X by (X^T X)^(-1)
Multiply the result by X^T
Step 4: Verify the properties of Lp
Check if (Lp)^2 = Lp
Check if (Lp)^T = Lp
Step 5: Verify R(Lp) = W
Check if every vector in W is in the range of Lp
Check if every vector in the range of Lp is in W
By following these steps and verifying the properties, we can rigorously show that Lp is indeed an orthogonal projection with R(Lp) = W.
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The drama club is selling gift baskets to raise money for new costumes. During the fall play, they sold a combined 15 regular gift baskets and 17 deluxe gift baskets, earning a total of $978. During the spring musical, they sold 27 regular gift baskets and 17 deluxe gift baskets, earning a total of $1,230. How much are they charging for the different-sized gift baskets?
The drama club is charging $__ for a regular gift basket and $__ for a deluxe gift basket.
Using the system of equations, we get that the drama club is charging $21 for a regular gift basket and $39 or a deluxe gift basket.
Given that,
The drama club is selling gift baskets to raise money for new costumes.
Let x be cost of the regular gift baskets and y be the cost of the deluxe gift baskets.
During the fall play, they sold a combined 15 regular gift baskets and 17 deluxe gift baskets, earning a total of $978.
15x + 17y = 978
During the spring musical, they sold 27 regular gift baskets and 17 deluxe gift baskets, earning a total of $1,230.
27x + 17y = 1230
From both equations,
978 - 15x = 1230 - 27x
12x = 252
x = 21
Cost of regular gift basket = $21
Cost of deluxe gift basket = y = (978 - 15 (21)) / 17 = $39
Hence the cost two kinds of baskets are $21 and $39.
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The probability of one of the two events listed in part (a) can be calculated even though the distribution of the population is strongly skewed right. For which event can the probability be calculated
The event for which the probability can be calculated from the two events given is event B.
Given that:
Mean = 2.5 children per family
Standard deviation = 1.3 children per family
Here, for event B, the sample size is going to take 40.
So, the distribution can be formulated to be approximately normal distribution since the sample size is 40 which is greater than 30.
So, the mean is the same which is 2.5.
The standard deviation can be calculated as 1.3/√40.
So, event B can be calculated for the probability.
Hence the event is event B.
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The complete question is given below:
The distribution of the number of children per family in the United States is strongly skewed right with a mean of 2.5 children per family and a standard deviation of 1.3 children per family.
Event A: Randomly selecting a family from the United States that has 3 or more children.
Event B: Randomly selecting 40 families from the United States and finding an average of 3 or more children.
The probability of one of the two events can be calculated even though the distribution of the population is strongly skewed right. For which event can the probability be calculated?
Here's a graph of a linear function.
Write the
equation that describes that function.
Express it in slope-intercept form.
Answer:
y = 1/2x + 3Step-by-step explanation:
As per graph, using the points (-6, 0) and (0, 3) we determine that:
the y-intercept is 3 and the slope is m = (3-0)/(0 - (-6)) = /3/6 = 1/2So the equation is:
y = mx + by = 1/2x + 3given that 2x + 3y divideby 3x+4y ,find the ratio y : x
Although part of your question is missing, you might be referring to the question :
Given that 2x+3y / 3x+4y = 5, find the ratio of y:x
Given : 2x+3y / 3x+4y =5
To find : y : x
Solution :
(2x+3y) / (3x+4y) = 5, or
2x + 3y = 15x + 20y, or
-15x + 2x = 20y - 3y, or
-13x = 17y
Therefore, x/y = -17/13
Hence, y/x = -13/17
y : x = -13 : 17.
The answer is -13 : 17.
In ADEF, the measure of ZF=90°, EF = 2.3 feet, and FD = 2.9 feet. Find the measure
of ZD to the nearest tenth of a degree.
Answer:38.4
Step-by-step explanation:
1. In a single-loop, two-pole de machine shown right, the coil side ab is lo- cated at A - B (B > 0) from the coil ) side cd. (ab and cd may not be on the diameter of the rotor circle.) The radius (r), the length (l), the nota- 1 tions (a to d) of the loop, and the air- gap flux densities are defined in the same way as in the machine shown in Sec. 7.1. Assume there are no fring- ing fields at the edges of pole faces. N Vcd V Bl vabh S eind 와 ab В. B 1117 θ =π - α θ =π+α (a) (15 pts) When a = B = = 5°, express the induced voltage (lind) for 0
In a single-loop, two-pole de machine shown right, the coil side ab is located at A - B (B > 0) from the coil side cd.
The radius (r), the length (l), the notations (a to d) of the loop, and the air-gap flux densities are defined in the same way as in the machine shown in Sec. 7.1. Assume there are no fringing fields at the edges of pole faces.The induced voltage is expressed as lind = Blvabsinα, whereα is the angle between the flux density vector and the normal vector to the armature plane.
Here,α= π −a.
The expression for lindis given below;lin d = Blvabsin(π − a)Let us plug in the values to the above equation;
lind = 1.0 T × 10 m/s × 0.1 m × 0.05 m × sin(π − 5)lind
= 0.157 V
Hence, the induced voltage is 0.157 V when a = B = 5°.
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A standard normal distribution is a normal distribution with : a . a mean of zero and a standard deviation of one b . a mean of one and a standard deviation of zero c . a mean zero and a standard deviation of zero d . a mean of one and a standard deviation of one e . none of these
A standard normal distribution is a normal distribution with a mean of zero and a standard deviation of one. Option A is the correct answer.
The standard normal distribution, often known as the z-distribution, is a special sort of ordinary distribution with a mean of zero and a standard deviation of one. Option A is the correct answer.
Any normal distribution can be standardized through transforming its values into z scores. The Z scores indicate how many standard deviations a certain result is from the mean. All normal distributions are unimodal, symmetrically distributed, and have a bell-shaped curve. One such distribution is the common normal distribution. On the other hand, a normal distribution's mean and standard deviation can be any value. In the typical normal distribution, the mean and standard deviation remain constant.
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A standard normal distribution is a normal distribution with a mean of zero and a standard deviation of one.
A standard normal distribution, also known as the Z-distribution, is a specific type of normal distribution. It has a mean of zero and a standard deviation of one. The Z-distribution is often used in statistics to standardize data and calculate probabilities.
The standard normal distribution is represented by a bell-shaped curve that is symmetric around the mean of zero. The area under the curve represents the probability of a random variable falling within a certain range.
The Z-score, which measures the number of standard deviations a data point is from the mean, is commonly used in hypothesis testing and confidence interval calculations.
The standard normal distribution is widely used in various fields, including finance, psychology, and quality control.
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Triangles abd and ace are similar right triangles.which ratio best explain why the slope of ab is the same as the slope ac
The ratio that best explains why the slope of AB is the same as the slope of AC in similar right triangles ABD and ACE is the ratio of the corresponding side lengths. In similar triangles, corresponding sides are proportional to each other.
This ratio indicates that the slopes of AB and AC are equal because the corresponding side lengths of the similar triangles are proportional.
Let's consider the sides of the triangles that are parallel to the x-axis. In triangle ABD, side AB corresponds to side AC in triangle ACE. Since the triangles are similar, the ratio of the lengths of these sides will be the same as the ratio of their slopes.
Therefore, the ratio of the slopes can be expressed as:
Slope of AB / Slope of AC = Length of AB / Length of AC
This ratio indicates that the slopes of AB and AC are equal because the corresponding side lengths of the similar triangles are proportional.
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i need help solving this math problem from my practice work
Sanford's gym coach made him run 20 laps on a 400 m track. How many kilometers did he run? How many miles?
Answer:
8km 5mi
Step-by-step explanation:
20x400=8000meters a km = to 1000meters
8000/1000=8km
A mile is a kilometer/ 1.6 8/1.6=5 miles
Sanford ran approximately 8 kilometers and about 4.97 miles.
Given that a coach made someone run 20 laps on a 400 m track.
We need to find the number of mile he ran as well as number of kilometers he ran.
To find out how many kilometers Sanford ran, we can use the fact that 1 kilometer is equal to 1000 meters.
Similarly, to find out how many miles he ran, we'll use the conversion factor of 1 mile being equal to approximately 1609.34 meters.
Let's calculate it:
1 lap = 400 meters
20 laps = 20 x 400 = 8000 meters
Kilometers:
8000 meters ÷ 1000 meters/kilometer = 8 kilometers
Miles:
8000 meters ÷ 1609.34 meters/mile ≈ 4.97 miles
So, Sanford ran approximately 8 kilometers and about 4.97 miles.
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From the diagram below, if the tree is 61 ft tall, and the angle of elevation from point B to the top of the tree is
29, find the distance that the tree is from point B. (Round to the nearest whole foot.)
Select one
O a.55 ft.
O b.82 ft.
O c. 123ft
d. 110 ft.
The distance that the tree is from point B is 110 ft option (d) 110 ft is correct.
What is trigonometry?Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have:
From the diagram below, if the tree is 61 ft tall, and the angle of elevation from point B to the top of the tree is 29.
Angle B = 29 degrees
Height of the tree h = 61 ft
As we know, the trigonometric ratio is defined as the ratio of the pair of a right-angled triangle.
Applying tan ratio:
tan29 = 61/x
x is the distance that the tree is from point B:
x = 61/tan29
x = 110.04 ≈ 110 ft
Thus, the distance that the tree is from point B is 110 ft option (d) 110 ft is correct.
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7. If A (6,8) and B (7, 4J are two points,
find the distance between a andB.
any
- Solo,
Answer:
√17 units
Step-by-step explanation:
(6, 8) & (7, 4)
To find the distance between two points, we use the distance formula:
\(d = \sqrt{(x_{2}-x_1)^2 + (y_2-y_1)^2 }\)
Plug in the values you know.
\(d = \sqrt{(7 -6)^2 + (4 -8)^2 }\)
Evaluate the parentheses.
\(d = \sqrt{(1)^2 + (-4)^2 }\)
Evaluate the exponents.
\(d = \sqrt{(1) + (16) }\)
Add.
\(d = \sqrt{(17)\)
Evaluate the square root.
\(d=\sqrt{17}\)
This square root is already fully simplified.
Your answer is √17 units.
Hope this helps!
Problem 7.1 (35 points): Solve the following system of DEs using three methods substitution method, (2) operator method and (3) eigen-analysis method: ( x' =x - 3y y'=3x +7y
The integral value is x = -3c1*(e^(3t/2)/2)(cos((sqrt(89)/2)t) + (sqrt(89)/2)sin((sqrt(89)/2)t)) - 3c2(e^(3t/2)/2)(sin((sqrt(89)/2)t) - (sqrt(89)/2)*cos((sqrt(89)/2)t)) + C
We have the following system of differential equations:
x' = x - 3y
y' = 3x + 7y
Substitution Method:
From the first equation, we have x' + 3y = x, which we can substitute into the second equation for x:
y' = 3(x' + 3y) + 7y
Simplifying, we get:
y' = 3x' + 16y
Now we have two first-order differential equations:
x' = x - 3y
y' = 3x' + 16y
We can solve for x in the first equation and substitute into the second equation:
x = x' + 3y
y' = 3(x' + 3y) + 16y
y' = 3x' + 25y
Now we have a single second-order differential equation for y:
y'' - 3y' - 25y = 0
The characteristic equation is:
r^2 - 3r - 25 = 0
Solving for r, we get:
r = (3 ± sqrt(89)i) / 2
The general solution for y is:
y = c1*e^(3t/2)cos((sqrt(89)/2)t) + c2e^(3t/2)*sin((sqrt(89)/2)t)
To find x, we can substitute this solution for y into the first equation and solve for x:
x' = x - 3(c1*e^(3t/2)cos((sqrt(89)/2)t) + c2e^(3t/2)*sin((sqrt(89)/2)t))
x' - x = -3c1*e^(3t/2)cos((sqrt(89)/2)t) - 3c2e^(3t/2)*sin((sqrt(89)/2)t)
This is a first-order linear differential equation that can be solved using an integrating factor:
IF = e^(-t)
Multiplying both sides by IF, we get:
(e^(-t)x)' = -3c1e^tcos((sqrt(89)/2)t) - 3c2e^t*sin((sqrt(89)/2)t)
Integrating both sides with respect to t, we get:
e^(-t)x = -3c1int(e^tcos((sqrt(89)/2)t) dt) - 3c2int(e^t*sin((sqrt(89)/2)t) dt) + C
Using integration by parts, we can solve the integrals on the right-hand side:
int(e^tcos((sqrt(89)/2)t) dt) = (e^t/2)(cos((sqrt(89)/2)t) + (sqrt(89)/2)*sin((sqrt(89)/2)t)) + C1
int(e^tsin((sqrt(89)/2)t) dt) = (e^t/2)(sin((sqrt(89)/2)t) - (sqrt(89)/2)*cos((sqrt(89)/2)t)) + C2
Substituting these integrals back into the equation for x, we get:
x = -3c1*(e^(3t/2)/2)(cos((sqrt(89)/2)t) + (sqrt(89)/2)sin((sqrt(89)/2)t)) - 3c2(e^(3t/2)/2)(sin((sqrt(89)/2)t) - (sqrt(89)/2)*cos((sqrt(89)/2)t)) + C
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Let's solve the system of differential equations using three different methods: substitution method, operator method, and eigen-analysis method.
Substitution Method:
We have the following system of differential equations:
x' = x - 3y ...(1)
y' = 3x + 7y ...(2)
To solve this system using the substitution method, we can solve one equation for one variable and substitute it into the other equation.
From equation (1), we can rearrange it to solve for x:
x = x' + 3y ...(3)
Substituting equation (3) into equation (2), we get:
y' = 3(x' + 3y) + 7y
y' = 3x' + 16y ...(4)
Now, we have a new system of differential equations:
x' = x - 3y ...(3)
y' = 3x' + 16y ...(4)
We can now solve equations (3) and (4) simultaneously using standard techniques, such as separation of variables or integrating factors, to find the solutions for x and y.
Operator Method:
The operator method involves representing the system of differential equations using matrix notation and finding the eigenvalues and eigenvectors of the coefficient matrix.
Let's represent the system as a matrix equation:
X' = AX
where X = [x, y]^T is the vector of variables, and A is the coefficient matrix given by:
A = [[1, -3], [3, 7]]
To find the eigenvalues and eigenvectors of A, we solve the characteristic equation:
det(A - λI) = 0
where I is the identity matrix and λ is the eigenvalue. By solving the characteristic equation, we can obtain the eigenvalues and corresponding eigenvectors.
Eigen-analysis Method:
The eigen-analysis method involves diagonalizing the coefficient matrix A by finding a diagonal matrix D and a matrix P such that:
A = PDP^(-1)
where D contains the eigenvalues of A on the diagonal, and P contains the corresponding eigenvectors as columns.
By diagonalizing A, we can rewrite the system of differential equations in a new coordinate system, making it easier to solve.
To solve the system using the eigen-analysis method, we need to find the eigenvalues and eigenvectors of A, and then perform the necessary matrix operations to obtain the solutions.
Please note that the above methods outline the general approach to solving the system of differential equations. The specific calculations and solutions may vary depending on the values of the coefficients and initial conditions provided.
Know more about differential equations here:
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Evaluate x - 3y when x = -2 and y= -4
A. -10
B. -4
C. 4
D. 14
Answer: 10
Step-by-step explanation:
When given the x and y values, you plug them in and solve.
-2-3(-4) [multiply]
-2+12 [add]
10
Now, we know that the answer is 10. 10 is not provided as an answer choice, but it is the correct the answer.
Answer: I got 10 (not negative 10) but I don’t see it up there unless you put -10 as a choice on accident.
In a survey of 164 pet owners, 61 said they own a dog, and 66 said they own a cat. 11 said they own both a dog and a cat. How many owned neither a cat nor a dog?
The given information is:
- They surveied 164 pet owners
- 61 own a dog
- 66 own a cat
- 11 own both a dog and a cat
We have to find how many owned neither a cat nor a dog.
We can represent this survey in the following diagram:
To find the solution we need to subtract the number of people who said they own a dog, own a cat, and own both, from the total number of people in the survey, so:
\(\begin{gathered} People\text{ who own neither a dog nor a cat}=164-61-66-11 \\ P=26 \end{gathered}\)The people who own neither a dog nor a cat are 26.