Objective: Go through a few problems involving Newton's Laws and friction! Tasks (10 points) 1. Find the mass of a 745 N person and find the weight of an 8.20 kg mass. Use metric units! What is known? What is unknown? What is the basic equation? What is the working equation? Plug in your values. 2. A 2000 kg car is slowed down uniformly from 20.0 m/s to 5.00 m/s in 4.00 seconds. a. What average force acted on the car during that time? What is known? What is unknown? What is the basic equation? What is the working equation? Plug in your values. What is the answer? b. How far did the car travel during that time? What is known? What is unknown? What is the basic equation? What is the working equation? Plug in your values. What is the answer? 3. A 38.4-pound block sits on a level surface, and a horizontal 21.3-pound force is applied to the block. If the coefficient of static friction between the block and the surface is 0.75, does the block start to move? Hint: it may help to draw a force diagram to visualize where everything is happening. What is known? What is unknown? What is the basic equation? What is the working equation? Plug in your values. What is the answer?

Based on scientific facts the layer of the atmosphere where short-wave radio signals be reflected is the Thermosphere.

The thermosphere is the layer of the Earth's atmosphere that lies just above the mesosphere and under the exosphere. Within this layer of the atmosphere, UV light induces photoionization/photodissociation of molecules, resulting in the formation of ions; the thermosphere consequently makes up the majority of the ionosphere.

The thermosphere is essential for all life on Earth because it shields it from some of the sun's most destructive energy, including x-rays and ultraviolet rays (its shortest wavelengths).

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The truck's displacement is 4.4 km west.

Distance is the total length traveled by the truck, while displacement is the change in position from the starting point to the ending point.
The truck travels 1.6 km due east, then turns around and goes 9.5 km due west, and finally turns around again and travels 3.5 km due east.
Total distance = 1.6 km + 9.5 km + 3.5 km
Total distance = 14.6 km

tan(theta) = opposite/adjacent
tan(theta) = 3.5 km/9.5 km
theta = tan^-1(3.5/9.5)
theta = 20.1 degrees
(a) the total distance traveled by the truck, simply add all the distances covered in each segment of the trip: 1.6 km (east) + 9.5 km (west) + 3.5 km (east).
Total distance = 1.6 km + 9.5 km + 3.5 km = 14.6 km
(b)the magnitude and direction of the truck's displacement, subtract the distance covered in the opposite direction:
Net displacement (east) = 1.6 km + 3.5 km = 5.1 km
Net displacement (west) = 9.5 km
Magnitude of displacement = Net displacement (west) - Net displacement (east) = 9.5 km - 5.1 km = 4.4 km
The direction of the truck's displacement is west, as it has a net displacement in the westward direct.

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Answer:

μ=1/5=0.2

Explanation:

using the formula

Fs=Fn*μ

Where

Fs is the static force

Fn = Normal force

μ= coefficient

so if Fn=25n

and it requires 5 n to start moving, means the max Fs is 5n

5=25μ

μ=5/25

μ=1/5=0.2

Answer:

Explanation:

Velocity is at its greatest when kinetic energy is at its max which is when all the ball's energy has been transformed from potential energy to kinetic energy which is at the lowest point in its travels (assuming the ball is rolling down a ramp). You have no picture here so this answer is a general one, not a specific one.

To determine which subatomic particle has a longer lifespan, we compare the average lifetimes of the tau lepton and the neutral pion. The average lifetime of the tau lepton is 2.906 x 10^-12 seconds, and the average lifetime of the neutral pion is 8.4 x 10^-17 seconds.

Comparing these values, we can see that the average lifetime of the tau lepton (2.906 x 10^-12 seconds) is significantly longer than the average lifetime of the neutral pion (8.4 x 10^-17 seconds).

To calculate how many times longer the lifespan of the tau lepton is compared to the neutral pion, we divide the average lifetime of the tau lepton by the average lifetime of the neutral pion:

(2.906 x 10^-12 seconds) / (8.4 x 10^-17 seconds) = 3.453 x 10^4

Therefore, the tau lepton has a lifespan that is approximately 3.453 x 10^4 (34,530) times longer than the neutral pion.

We can use the formula:v = u + atwhere:v = final velocity of the sprinter, which is 2.0 m/su = initial velocity of the sprinte, , the magnitude of the friction force is 300 N.

To determine the magnitude of the friction force, use the formula for force, F=ma, where m is the mass of the sprinter and a is the acceleration of the sprinter. The friction force is equal in magnitude and opposite in direction to the force of the sprinter's foot pushing backward against the ground.

Mass of the sprinter,

m = 60 kgTime the sprinter's foot is on the ground,

t = 0.40 sInitial velocity of the sprinter, u = 0 m/sFinal velocity of the sprinter,

v = 2.0 m/sWe need to calculate the friction force acting on the sprinter.To do this, we first need to calculate the acceleration of the sprinter. We can use the formula:v = u + where:

v = final velocity of the sprinter, which is 2.0 m/s

u = initial velocity of the sprinter, which is 0 m/st = time for which the foot is on the ground, which is 0.40 s

Substituting these values, we get:2.0

= 0 + a(0.40)Simplifying, we get:

2.0 = 0.4a

Dividing both sides by 0.4, we get:

a = 5 m/s² Substituting the values, we get:

F = 60 × 5F = 300 N

Therefore, the magnitude of the friction force is 300 N.

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Explanation:

Velocity = displacement / time

v = √((58 m)² + (135 m)²) / (12 min × 60 s/min)

v = 0.20 m/s

The city of Charleston, WV will have the largest gravitational field strength.

The space around a material object in which its gravitational force can be experienced is known as gravitational field.

The gravitational field strength at a point in this field is the force experienced on unit mass placed at that point.

Here,

The data obtained at different geographical locations of earth are given in the table. The latitude of the geographical areas are provided.

Gravitational field strength,  I = -GM/r²

i.e, it follows the inverse square law.

The variation of gravitational field strength with change in latitude has been studied and the studies proved that:

As an  object moves away from the surface of earth, the gravitational force  between the object and earth decreases and therefore the gravitational field strength also decreases.

Therefore considering the latitudes of the geographical places mentioned, the place at the lowest latitude will have the strongest gravitational field strength. Charleston, WV will have largest gravitational field strength.

Hence, Charleston, WV which is at the lowest latitude will have the strongest gravitational field strength.

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Answer:

\(29861.23\ \text{m/s}\)

Explanation:

\(R=\text{Radius of Earth's orbit}=1.5\times10^{11}\ \text{m}\)

\(T=\text{Time taken by the Earth to complete the orbit}=365.3\ \text{days}\)

Assuming the orbit is of circular shape the distance the Earth has to travel is the circumference

\(C=2\pi R\\\Rightarrow C=2\pi\times 1.5\times10^{11}\\\Rightarrow C=942477796076.938\ \text{m}\)

Velocity is given by

\(v=\dfrac{C}{T}\\\Rightarrow v=\dfrac{942477796076.938}{365.3\times 24\times 60\times 60}\\\Rightarrow v=29861.23\ \text{m/s}\)

The speed of the Earth around the Sun is \(29861.23\ \text{m/s}\)

Answer:

A battery

Explanation:

A battery puts energy through wire to power flashlight

Answer:

Your answer would be (A) Battery

Explanation:

A battery is found in most flashlights, and the flashlight is too small for a plugin.

A motor would be unreasonable, and you would have to put in the battery anyway. The resistor just slows down the speed of electron currents, and all the switch does is start and stop the flow of electron currents.

Conclusion:

I hope this helped! Please give Brainliest if I gave the best answer :)

Tell me if I had the wrong answer, and I'll fix it.

The use of H II regions and Cepheid variables to find a galaxy's distance differs in that H II regions are used for more distant galaxies, while Cepheid variables are used for closer ones due to their higher brightness and more predictable period-luminosity relationship.

A galaxy is a gravitationally bound system of stars, stellar remnants, interstellar gas, dust, and dark matter, and often has a supermassive black hole at its center.

H II regions are large, low-density clouds of ionized gas in the interstellar medium, usually found in the spiral arms of galaxies, and powered by high-energy photons from nearby hot, young stars.

According to the guven information:

The use of H II regions to find a galaxy's distance differs from the use of Cepheid variables in a few ways. H II regions are areas of ionized gas surrounding newly formed hot stars, and their brightness can be used to estimate the galaxy's distance. However, this method is less accurate than using Cepheid variables. Cepheid variables are pulsating stars that have a known period-luminosity relationship, meaning their brightness is directly related to their pulsation period. By measuring the period of a Cepheid variable, astronomers can accurately determine the distance to a galaxy. This method is considered more reliable than using H II regions, as Cepheid variables have a well-established relationship between their period and luminosity. Additionally, Cepheid variables can be used to determine distances to much greater distances than H II regions, making them a more versatile tool for studying the universe.

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Answer:

m = 3.8 kg

Explanation:

p = m × v

95 = m × 25

25m = 95

m = 95/25

m = 3.8 kg

According to the question the length of the solenoid. For this problem is \(4.56 * 10^{-3\) J.

A solenoid is an electrical device that is used to convert electrical energy into mechanical energy. It consists of a coil of wire wound around a metal core, and when electric current passes through it, a magnetic field is created. This magnetic field then causes a metal plunger to move in and out of the coil, creating a mechanical force. Solenoids are commonly used in applications such as electric door locks, automatic valves, and electric actuators.

The magnetic energy stored in a solenoid is given by the formula \(U = (1/2) \mu n^2I^2L\)L, where μ is the permeability of free space (\(\mu = 4\pi*10^{-7} Tm/A\)), n is the number of turns, I is the current, and L is the length of the solenoid. For this problem, \(U = (1/2)(4pi*10^{-7})(1210)^2(165\times10{^-3})^2(17.2\times10^{-2}) = 4.56 * 10^{-3} J.\).

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The volume of water is 2500m³ and the fractionof the water is 73.5% of the water contained in that portion of the aquifer would have been removed.

What is aquifer?
An aquifer is a subterranean layer of porous, water-bearing rock, rock fissures, or unconsolidated materials. A water well can be used to obtain groundwater from aquifers. The features of aquifers vary widely. Aquitard is a low-permeability bed along an aquifer, while aquiclude (or aquifuge) is a solid, impermeable region below or covering an aquifer, the pressure of which could form a restricted aquifer.

Area of the unconfined aquifer=10000m².
water table drops by 1m
porosity = 34%
specific yield= 25%
Volume of water removed= Sy× volume
                                          = 0.25×10000×1
                                          = 2500m³

Fraction of water removed = 25/34

                                             = 0.735
                                             = 73.5% of water removed

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Answer: The tension in the cable that will give the 100-lb block a steady acceleration of 5 ft/sec² up the incline is 760 lb.

Explanation: We can solve this problem using Newton's second law and free-body diagrams.

First, let's draw a free-body diagram for the 100-lb block.

     N

          |

          |

          |

          |

          |       m×g

          |<--------------

          |

          |

          |

          |

          |

         100 lb

Here, N is the normal force exerted by the incline on the block, m is the mass of the block, g is the acceleration due to gravity, and the arrow pointing down represents the weight of the block.

Next, let's draw a free-body diagram for the pulley.

          |<----P---->|

          |                |

          |                |

          |                |

          |                |

          |                |

          |                |

          |                |

          |                |

          |                |

          |                |

          |                |

          |                |

          O              |

Here, P is the tension in the cable, and O is the center of the pulley.

Since the block is accelerating up the incline, there must be a net force in the upward direction. Using Newton's second law, we can write:

F_net = m×a

where F_net is the net force acting on the block, m is the mass of the block, and a is the acceleration of the block.

The only forces acting on the block are the weight (mg) and the component of the normal force parallel to the incline (Nsinθ). Using trigonometry, we can write:

Nsinθ = mg×sinθ

The net force in the x-direction is given by:

F_net = P - mgsinθ

Using the equation F_net = m×a and substituting the values given in the problem, we get:

P - mgsinθ = m×a

Substituting the given values of m, g, sinθ, and a, we get:

P - (100 lb)(32.2 ft/s² )(0.6) = (100 lb)×(5 ft/s² )

Simplifying and solving for P, we get:

P = (100 lb)(5 ft/s² ) + (100 lb)(32.2 ft/s² )*(0.6)

P = 760 lb

Therefore, the tension in the cable that will give the 100-lb block a steady acceleration of 5 ft/sec² up the incline is 760 lb.

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Answer:

900 windings

Explanation:

Applying,

Vs/Vp = Ns/Np............. Equation 1

Where Vs = Secondary voltage, Vp = primary voltage, Ns = Number of turns in the secondary circuit, Np = number of turns in the primary circuit

make Ns the subject of the equation

Ns = VsNp/Vp........... Equation 2

From the question,

Given: Vs = 240 V, Np = 300 windings, Vp  = 80 V

Substitute these values into equation 2

Ns = (240×300)/80

Ns = 900 windings

The time it takes for the ball to strike the water is approximately 3.9 seconds.

To solve this problem, we can use the equation of motion for vertical displacement, which is given by:

  y = y0 + v0t + (1/2)at²

where y is the final vertical displacement, y0 is the initial vertical displacement, v0 is the initial vertical velocity, a is the acceleration due to gravity, and t is the time.

In this case, we have:

Plugging these values into the equation and rearranging for t, we get:

  0 = 24.0 + 13.0t + (1/2)(-9.8)t²

  0 = -4.9t² + 13.0t + 24.0

Using the quadratic formula, we can solve for t:

  t = (-13.0 ± √(13.0² - 4(-4.9)(24.0)))/(2(-4.9))

  t = (-13.0 ± √(169 + 470.4))/(-9.8)

  t = (-13.0 ± √639.4)/(-9.8)

  t = (-13.0 ± 25.3)/(-9.8)

The two possible solutions for t are:

  t = (-13.0 + 25.3)/(-9.8) ≈ -1.3 s (this solution is not physically possible)

  t = (-13.0 - 25.3)/(-9.8) ≈ 3.9 s (this is the correct solution)

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The given position equation of a particle is, s=102−23t+t2Here, t is in seconds.The first derivative of s is its velocity: v = ds/dt - 23 + 2tThe second derivative of s is the particle's acceleration:

The total distance traveled is the sum of all distance travelled in each interval of time: D = ∫|v|dt + ∫|v|dt + ... (From t 0 s to t = 17 s)From the graph of the velocity, the particle is moving to the left and toward the right side. The velocity-time graph is linear, which means that the acceleration is constant and uniform. Hence, the conclusion we can draw is that the particle is moving with uniform acceleration.  a = dv/dt = 2The given equations are: s=102−23t+t2v

=−23+2ta

=2Plot of s-t and v-t graphs:

Net displacement (Δs) during the interval of 17 seconds can be calculated as:Δs = s(17) - s(0)Δs 

= 102 - (2 × 3² / 2) - (23 × 3) + (17² / 2) - 102Δs 

= -4 mmThe particle moves to the left side.

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The time needed to generate an energy of 456 J using a power of 76 W is 6.0 seconds.

Power is the quantity of energy transferred per unit time. It can be expressed as;

Power = energy / time

Given the data in the question;

To determine the required time, plug the given values into the formula above and solve for t.

Power = energy / time

Time = energy / power

Time = 456kgm²/s² / 76kgm²/s³

Time = 6.0s

Therefore, the required time is 6.0 seconds.

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To create a customized error alert in cell G5 Data Validation" dialog box, go to the "Settings", show error alert after invalid data is entered and Choose "Stop" from the "Style".

To create a customized error alert in cell G5 using the Stop style with the title "Input Error" and the message text "Value must be a whole number from 1 to 5", follow these steps:

1. Select cell G5 in your Excel worksheet.
2. Click on the "Data" tab located in the ribbon at the top.
3. In the "Data Tools" group, click on "Data Validation" and then select "Data Validation" from the dropdown menu.
4. In the "Data Validation" dialog box, go to the "Settings" tab.
5. In the "Allow" dropdown menu, choose "Whole number".
6. In the "Data" dropdown menu, choose "between".
7. Set the "Minimum" value to 1 and the "Maximum" value to 5.
8. Click on the "Error Alert" tab.
9. Make sure the "Show error alert after invalid data is entered" checkbox is ticked.
10. Choose "Stop" from the "Style" dropdown menu.
11. Enter "Input Error" as the error alert title in the "Title" text box.
12. Enter "Value must be a whole number from 1 to 5" as the message text in the "Error message" text box.
13. Click "OK" to apply the settings.

Now, if a user enters an invalid value in cell G5, a customized error alert with the Stop style will appear, displaying the title "Input Error" and the message text "Value must be a whole number from 1 to 5".

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If all of the variables in Coulomb's law are increased to 7 times bigger, the resulting force is 49 times larger than the prior force.

The formula for Coulomb's law is:

F=k(q1q2)/r²

Where

F is the electrostatic force,

q1 and q2 are the charges,

r is the separation of the charges, and

k is the Coulomb constant.

The Coulomb constant is equal to 8.98755 × 10^9 N·m^2/C^2.

The resultant force is 7*7=49 times greater than the initial force if all of Coulomb's law's variables are multiplied by a factor of 7.

According to Coulomb's law:

F=k(q1q2)/r²

The distance r is not specified, so let's assume it remains constant.

Therefore, we only need to consider the charges, q1 and q2.

Suppose the charges are increased to 7q1 and 7q2.

Then, the new force F' is:

F'=k(7q1)(7q2)/r²

F'=49(kq1q2/r²)

Thus, the new force is 49 times larger than the previous force.

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For the semi-major axis of the asteroid's orbit, we can use the relationship between the period (T) and the semi-major axis (a) of an elliptical orbit.

The formula relating these two quantities is given by Kepler's third law:

\(T^2 = (4\pi ^2 / GM) * a^3,\)

where T is the period of the orbit, G is the gravitational constant, and M is the mass of the central body (in this case, the Sun).

Rearranging the equation to solve for a:

\(a = [(T^2 * GM) / (4\pi ^2)]^{(1/3)}.\)

Given that the period T is 7.85 years and the eccentricity e is 0.250, we can substitute these values into the equation to calculate the semi-major axis a.

After obtaining the value of a, we can state the answer based on requirements .

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Answer:

I think lead is the heaviest one

Answer:

7 days or a week

Explanation:

The distance your suitcase is dragged before it rides smoothly on the belt at an airport conveyor belt depends on the coefficient of static friction between the belt and your suitcase.

When you place your suitcase on the conveyor belt, it starts moving slowly with the belt. However, due to the friction between the belt and the suitcase, the suitcase tends to slide backward. The frictional force between two surfaces depends on the normal force pressing them together and the coefficient of friction.

The static friction coefficient is the value of the coefficient of friction between two surfaces when they are at rest, while the kinetic friction coefficient is the value of the coefficient of friction between two surfaces when they are moving. The static friction force acts to oppose the motion of the suitcase, preventing it from sliding backward, while the kinetic friction force acts to reduce the suitcase's velocity.

When the static friction force between the suitcase and the conveyor belt is greater than the force trying to move the suitcase, it remains at rest. Once the force pushing the suitcase becomes larger than the static friction force, the suitcase starts to slide, and the kinetic friction force comes into play. The distance your suitcase is dragged before it starts moving depends on the coefficient of static friction between the suitcase and the belt.

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Answer:

heat is a measure of how energy flows from hot to Cold object. It means the same thing as temperature

Heat is a measure of how much energy flows from hotter objects to cold objects. It flow the same thing as temperature.

Temperature is a physical quantity which measures hotness and coldness of a body. Temperature measures the degree of vibration of molecule in a body. Temperature is measured in centigrade (°C), Fahrenheit (°F) and Kelvin (K) in which Kelvin (K) is a SI unit of temperature. Absolute scale of temperature means Kelvin scale of temperature. relation between Kelvin(K) and centigrade (°C), °C= K - 273.15 from equation, 273.15 K means 0 °C, which is freezing point of water (ice). when we give temperature to the body, its molecule or atom absorbs thermal energy and vibrate about their mean position. Amplitude of vibration get increases as we go on increasing temperature and for higher temperature force of attraction between molecules gets weaker. Hence for higher temperature, due to weaken the force of attraction between molecule, solid goes into liquid state. and further increase in temperature liquid goes into gaseous state.

Heat flows from high temperature to low temperature

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Answer:

pizza dont got no bone in it

Explanation:

Answer:

Pizza have no bones

Explanation:

Because it would be yucky

(a) To determine the position of the image created by lens 1, we can use the lens formula:

1/f = 1/do + 1/di

where f is the focal length of lens 1, do is the object distance, and di is the image distance.

Given:
f1 = 4.8 cm
do,1 = -28.5 cm (since the object is placed to the left of lens 1, the distance is negative)

Plugging the values into the lens formula, we have:

1/4.8 = 1/-28.5 + 1/di,1

Simplifying and solving for di,1:

1/di,1 = 1/4.8 + 1/28.5

di,1 = 1 / (1/4.8 + 1/28.5)

di,1 ≈ 4.54 cm

The position of the image created by lens 1 is approximately 4.54 cm to the right of lens 1.

(b) The magnification, M1, of lens 1 can be calculated using the formula:

M1 = -di,1 / do,1

Plugging in the values:

M1 = -4.54 cm / (-28.5 cm)

M1 ≈ 0.159

The magnification of lens 1 is approximately 0.159, with a negative sign indicating an inverted image.

(c) To determine the description of the image created by lens 1, we need to consider the magnification and the position of the image. In this case, the image is formed on the same side as the object (positive image distance) and has a magnification less than 1 (0.159), indicating a reduced in size image. Therefore, the best description for the image created by lens 1 is a reduced, inverted image.

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The tail shape of a surfboard greatly affected the board's interaction with the wave's face and the flowing of water flowing.

The tail shape of a surfboard affects how the board depends on the wave's face, and the water flowing between it. More comprehensive, thicker tail shapes have more surface area and assist the board to float and create lift - allowing the surfboard to plane over the surface of the water more efficiently.

The shape of both the surfboard and its fin swap the way the water moves around it if you can grab a wave as well as the turning ability of the surfboard.

So we can conclude that Surfboard bottom outlines are also essential. Concave and V-shaped contours have similar performances, for all opposite designs.

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