Part G
Find the force constant of the spring. Assume that the angle that the ramp makes with the horizontal is 22° Recall that the mass of the puck is
0. 180 kg and g = 9. 80 m/s
Answers
A force constant, also known as a spring constant, is the amount of force required to extend or compress a spring a certain distance. It is given by the formula: k = F / x Where F is the applied force and x is the displacement of the spring.
We can use this formula to find the force constant of the spring in this scenario. First, we need to calculate the force acting on the puck. We know the mass of the puck is 0.180 kg and the acceleration due to gravity is 9.80 m/s². Therefore, the force acting on the puck is:
F = m × g
F = 0.180 kg × 9.80 m/s²
F = 1.764 N
Next, we need to find the displacement of the spring. We know that the ramp makes an angle of 22° with the horizontal, so the height of the ramp is given by:
h = l × sin θ
where l is the length of the ramp and θ is the angle it makes with the horizontal.
We are not given the length of the ramp, but we can assume it is long enough that the puck reaches its maximum height before coming back down. Therefore, the height of the ramp is also the maximum displacement of the spring.
x = h = l × sin 22°
Now, we can use the formula for the force constant:
k = F / x k = 1.764 N / (l × sin 22°)
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Related Questions
Drag each label to the correct location on the table.
Sort the processes based on the type of energy transfer they involve.
Answers
The correct processes based on the type of energy transfer they involve can be linked as ;
condensation - thermal energy removedfreezing -thermal energy removeddeposition - thermal energy removedsublimation - thermal energy addedevaporation - thermal energy addedmelting - thermal energy addedWhat is energy transfer ?Conduction, radiation, and convection are the three different ways that thermal energy is transferred. Only fluids experience the cyclical process of convection.
The total amount of energy in the universe has never changed and will never change because it cannot be created or destroyed.
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A Six Flags students notice that all of the roller coasters use motors to pull the cars to their highest point at the first hill, and then release the cars down the hill and for the rest of the trip. Why must the first hill of a rollercoaster ride be the highest? Answer with a claim, evidence and reasoning.
Answers
According to the conservation of energy
\(Total\text{ energy = Potential energy +Kinetic energy}\)At the top of the hill, only the potential energy will work as it is at rest.
Also, potential energy increases with height, so if the height of the first hill is the highest, the total energy will be more.
when loading a trailer, what percent of the weight should be in the front?
Answers
The percentage of weight that should be in front of the trailer is 60%
According to the GMC Trailering Guide, to get the right trailer tongue weight, you should concentrate about 60% of the load evenly on the front half of the trailer. 60% of the trailer load should be in front of the axle and 40% behind it. This ensures the correct weight of the tongs and prevents the trailer from rocking. Weight distribution should be as efficient as possible by placing 60% of the weight in the front of the trailer and 40% in the rear. There are some additional safety precautions to consider.
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in what section should you look to determine what type of lab equipment is required to perform an experiment
Answers
When trying to determine what type of lab equipment is needed to perform an experiment, the section to look for is the materials and methods section.
This section will typically list all of the necessary equipment and materials required to carry out the experiment.
It will also often include specific instructions for how to use the equipment and how to prepare the materials.
It is important to carefully read through this section to ensure that you have all the necessary equipment and that you understand how to use it properly.
Failure to have the correct equipment or to use it incorrectly can lead to inaccurate results and potentially dangerous situations.
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let's compare this to what keplerian rotation would look like. in the case of the solar system, almost all the mass is concentrated at the center. leaving the first dark matter density slider at the best-matched value to the rotation curve, adjust the rest down to 0. how much mass is enclosed in this case? use scientific notation, as before. include one place after the decimal.
Answers
In the case of Keplerian rotation, with all the mass concentrated at the center like in the solar system, adjusting the dark matter density sliders to zero would enclose approximately 0.0 kilograms of mass.
When we consider the concept of Keplerian rotation, we are examining a system where most of the mass is concentrated at the center, as observed in the solar system. To simulate this scenario, we adjust the dark matter density sliders to zero, effectively removing any additional mass beyond what is already present. By doing so, we eliminate the contribution of dark matter to the overall mass enclosed.
In the context of the given question, the objective is to determine the amount of mass enclosed under these conditions. When the dark matter density sliders are set to zero, it means that no additional mass is added to the system. Therefore, the total mass enclosed would be equal to the mass of the central object, which in this case is the sun.
The main answer, stating that the mass enclosed is approximately 0.0 kilograms, indicates that without the presence of dark matter, the only mass considered is that of the central object, which in the solar system is the sun. This suggests that the mass enclosed is negligible when compared to the total mass of the solar system.
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How is muscular strength calculated?
Answers
Muscle strength is measured by estimating a person's one repetition maximum (1RM).
1RM is a measurement of the greatest load (in kilograms) that one can move means it can be lifted, pushed, or pulled once without failure or injury.
1RM is calculated by counting the maximum number of exercises that you can do in repetition by the use of a load that is just less than the maximum amount that can be moved. This number is known as the repetitions to fatigue (RTF) – you are required to stop counting the repetitions when you feel you can no longer do the exercise in a proper way or when you slow down or can't keep a steady pace.
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If the region between the plates is filled with a material whose dielectric constant is 5.6, what is the new capacitance (in pf)?
Answers
The new capacitance can be calculated by multiplying the original capacitance by the dielectric constant of the material.
The capacitance of a parallel plate capacitor is given by the formula C = ε₀A/d, where C is the capacitance, ε₀ is the permittivity of free space, A is the area of the plates, and d is the distance between the plates.
When a dielectric material is inserted between the plates, the capacitance increases due to the material's ability to store electric charge. The dielectric constant, also known as the relative permittivity, represents the ratio of the capacitance with the dielectric material to the capacitance without the dielectric material.
To find the new capacitance, we can multiply the original capacitance by the dielectric constant. So, the new capacitance (C') can be calculated as C' = ε₀εrA/d, where εr is the dielectric constant of the material.
In this case, since the dielectric constant is given as 5.6, we can simply multiply the original capacitance by 5.6 to obtain the new capacitance. The units for capacitance are typically measured in farads (F), but since the given options are in picofarads (pF), we need to convert the capacitance to picofarads.
Therefore, the new capacitance (in pF) is equal to the original capacitance multiplied by 5.6.
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If a paper airplane has a forward velocity of 2 m/s, but air resistance has a velocity of 1 m/s acting against the paper airplane, then what is the resultant forward velocity of the paper airplane?
Answers
Answer:
F_{resultant} = 1 [m/s]
Explanation:
These types of problems can be solved by means of relative velocities, where vectors (forces or velocities) are necessarily handled, these velocities depending on the velocity are added or subtracted.
Forces to the right are taken as positive and negative to the left.
\(F_{velocity}-F_{air}=F_{resultant}\\2-1 = F_{resultant}\\\\F_{resultant} = 1 [m/s]\)
A student drops a rock in a pond and notices that her reflection in the water becomes less clear. Which statement best explains the student’s observation?(1 point)
Responses
The water is not a smooth surface after the rock is dropped in the pond.
The surface of the water is not shiny after the rock is dropped in the pond.
The water is not able to reflect waves after the rock is dropped in the pond.
The surface of the water is no longer hard after the rock is dropped in the pond.
Answers
The statement that best explains student’s observation: The water is not a smooth surface after rock is dropped in the pond.
What happens when a rock is dropped in a pond?When rock is dropped into the water, it creates ripples on the surface of water. These ripples disturb the smooth surface of water and cause reflection to become less clear.
Waves on the surface of water scatter the light that is reflecting off the surface, causing image to become distorted and less clear. Degree to which the reflection is affected by the ripples will depend on size and intensity of the waves created by rock's impact.
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Fill in the blanks with suitable pronouns.
1. Baby bird learns to fly
2. The two line intersect _______ at the middle position.
3. ______ had the courage to stand against the unjust treatment to the poor.
4. _______ is on the line?
5. smitha works in a gym ____ is my trainer
Answers
1)Baby bird cannot fly. Their mother has to feed \bf\underline{them}them
2. Vijay likes riding my bicycle. I sometimes lend \bf\underline{it}it to \bf\underline{him}him
3. Sooraj and I are brothers. \bf\underline{we\:both}weboth share the same bedroom.
4. Ravina isn't well. Dad is taking to the doctor. (No personal pronouns required)
5. My sister is a teacher. \bf\underline{She}She teaches Maths.at some point in space a plane electromagnetic wave has the electric field = (381 j^ 310 k^ ) n/c. caclulate the magnitude of the magnetic field a that point.
Answers
The magnitude of the magnetic field at that point is approximately 1.65 x 10⁻⁶ Tesla.
The magnitude of the magnetic field at the given point, we can use the relationship between the electric and magnetic fields in an electromagnetic wave: E = cB, where E is the electric field, B is the magnetic field, and c is the speed of light.
We can rearrange this equation to solve for B: B = E/c
Plugging in the given values, we get:
B = (381 j + 310 k) n/c / 3 x 10⁸ m/s
To calculate the magnitude of this vector, we can use the Pythagorean theorem: |B| = sqrt(Bj² + Bk²)
where |B| represents the magnitude of B.
Plugging in the values we get:
|B| = sqrt((381/3 x 10⁸)² + (310/3 x 10⁸)²)
|B| = 4.04 x 10⁻⁹ T (rounded to 3 significant figures)
B = E / c
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Which of the following is the minimum amount of work done by a hydraulic lift
to raise a 150-kg aluminum block 2.0 m vertically?
Answers
Answer: 300 J
Explanation:
Force = 150 KJ
Distance = 2.0 m
The minimum amount of work done by a hydraulic lift to raise a 150-kg aluminum block 2.0 meters vertically would be 2940 Joules, as the work done is the product of the force applied to the displacement of the object, therefore the correct answer is option B.
What is work done?The total amount of energy transferred when a force is applied to move an object through some distance
The work done is the multiplication of applied force with displacement.
Work Done = Force × Displacement
As given in the problem we have to find out the minimum amount of work done by a hydraulic lift to raise a 150-kg aluminum block 2.0 meters vertically.
The minimum work done = 150 × 9.8 × 2
= 2940 Joules
Thus, The minimum amount of work done by a hydraulic lift to raise a 150-kg aluminum block 2.0 meters vertically would be 2940 Joules.
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The distance needed for steering around an object is shorter than the distance needed to brake for the object at speeds over 25. T or F?
Answers
The statement is False.
The distance needed for steering around an object is typically longer than the distance needed to brake for the object, especially at higher speeds.
Braking distance depends on factors such as the speed of the vehicle, the condition of the brakes and tires, and the road surface, while the distance needed for steering around an object also depends on the speed of the vehicle, the size of the object, and the maneuverability of the vehicle.
However, in general, it is easier to slow down or stop a vehicle than it is to maneuver it around an object. Therefore, at speeds over 25, the distance needed to brake for an object is likely to be shorter than the distance needed to steer around the object.
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A sled and a rider slide down a snow-covered hill that makes
an angle of 30° with the horizontal. The total mass of the sled
and the rider is 70 kg. Neglecting friction, their acceleration is
m/s2. Round to the nearest tenth.
Answers
Answer: 4.9 m/s
Explanation:
What kinds of food can’t your body break down
Answers
Answer:
fiber
Explanation:
which forces are contact forces give one example of each
Answers
Answer:
A contact force is any force that requires contact to occur. Contact forces are ubiquitous and are responsible for most visible interactions between macroscopic collections of matter. Pushing a car up a hill or kicking a ball across a room are some of the everyday examples where contact forces are at work.
how far from an 8.00 µc point charge will the potential be 300 v? m at what distance will it be 6.00 ✕ 102 v? m
Answers
The potential will be 6.00 x\(10^2\) V at a distance of 1.20 x \(10^4\) meters from the 8.00 µC point charge.
We can use the formula for electric potential due to a point charge:
V = k * q / r
where V is the potential, k is Coulomb's constant (9.0 x \(10^9\) N·m²/C²), q is the charge, and r is the distance from the charge.
For the first part of the question:
300 = 9.0 x \(10^9 *\) 8.00 x\(10^-6\) / r
r = 9.0 x \(10^9\) * 8.00 x \(10^-6\) / 300 = 240 m
Therefore, the potential will be 300 V at a distance of 240 meters from the 8.00 µC point charge.
For the second part of the question:
6.00 x 10² = 9.0 x \(10^9\) * 8.00 x 10⁻⁶ / r
r = 9.0 x 10⁹ * 8.00 x \(10^-6\)/ (6.00 x 10²) = 1.20 x \(10^4\)m
Therefore, the potential will be 6.00 x\(10^2\) V at a distance of 1.20 x \(10^4\)meters from the 8.00 µC point charge.
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How is the answer D?
Answers
The graph that corresponds to 0.1 s in one complete cycle is graph D.
option D is the correct answer.
What is the period of a wave?The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.
Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.
From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;
Period = 1 s / 10
Period = 0.1 s
From the graphs, the only option that has one complete cycle in one second is option D.
Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.
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gravity acts to __________ the expansion of the universe, and dark energy acts to __________ the expansion
Answers
Gravity acts to slow down the expansion of the universe, while dark energy acts to accelerate it, resulting in a complex interplay between these two forces in shaping the evolution of the cosmos.
Gravity acts to slow down the expansion of the universe, while dark energy acts to accelerate the expansion.
According to the theory of general relativity, gravity is a fundamental force that influences the dynamics of the universe on large scales. The gravitational pull between galaxies, galaxy clusters, and other massive objects tends to counteract the expansion of the universe, causing it to slow down over time.
On the other hand, dark energy is a hypothetical form of energy that is thought to permeate all of space and contribute to the accelerated expansion of the universe. Dark energy exerts a repulsive gravitational effect, counteracting the attractive force of gravity at cosmological distances. This leads to an expansion that accelerates over time, pushing galaxies and other cosmic structures apart from each other at an increasing rate.
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a 5.0 kg cannonball is fired horizontally at 62 m/sm/s from a 18 m-high cliff. a strong tailwind exerts a constant 12 n horizontal force in the direction the cannonball is traveling. how much extra distance does the cannonball travel due to the wind?
Answers
The cannonball has to travel 4.4 m extra due to the wind.
The cannonball is fired. So it acquired some velocity. Then there must be some resistance from the air or wind resistance. And here we ignore such resistances and assume everything to be negligible. But, in this case we need to find the extra distance that cannonball had to travel due to wind.
The cannonball is dropped in vertical from the rest.
Given,
mass of cannonball = 5 kg
velocity of cannonball = 62 m/s
Height of the cliff = 18 m high cliff
Force = 12 N
So,
t = √ (2h/g) = √(2(18)/9.8) = 1.89 s
Without the tail wind, the cannonball travels horizontally
d = vt = 62 x (1.89) = 117 m
The tailwind exerts a constant acceleration on the cannonball of
a = F/m = 12/5.0 = 2.4 m/s²
The average horizontal velocity during the flight is
v(avg) = (62 + (62 + 2.4(1.89)) / 2 = 64.25 m/s
so the distance with tailwind of cannonball is
d = v(avg)t = 64.25(1.89) = 121.432 m
The extra distance is 121.432 - 117 = 4.432 = 4.4 m
Thus, the extra distance the cannonball travels due to the wind is 4.4m.
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what do you think the forces are on the fan cart are on the frictionless surface vs. on the wooden surface?
Answers
When the fan cart is on a frictionless surface and a wooden surface, the forces acting on it are different. When the fan cart is placed on a frictionless surface, the force acting on it is the thrust force created by the fan, and there is no friction.
On the other hand, when the fan cart is placed on a wooden surface, the force acting on it is the thrust force created by the fan, and there is friction between the cart and the surface. Due to the presence of friction, the fan cart may take longer to come to a stop when placed on a wooden surface. The amount of friction acting on the fan cart on the wooden surface depends on the type of surface and the force of the thrust created by the fan.
When there is no friction on the surface, the cart will move without being interrupted, whereas when the cart is placed on a wooden surface, friction will act against it. The frictional force will vary based on the type of surface and the force exerted by the thrust generated by the fan.
Therefore, the forces acting on the fan cart will be different based on the surface it is placed on. When it is on a frictionless surface, there is no friction acting on it, and when it is on a wooden surface, there is a force of friction acting against it.
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Why is a magnetic fleld a vector quantity?
Answers
A 600-kg car makes a 90° turn. its speed before the turn is 24.0 m/s and after the turn it is 19.0 m/s. what is the magnitude of the change in the car's momentum during the turn?
Answers
The magnitude of the change in the car's momentum during the turn is 3,000 kg·m/s.
To find the magnitude of the change in the car's momentum during the turn, we can use the principle of conservation of momentum. The momentum of an object is given by the product of its mass and velocity. The change in momentum is equal to the final momentum minus the initial momentum.
Given:
Mass of the car (m) = 600 kg
Initial speed of the car (v1) = 24.0 m/s
Final speed of the car (v2) = 19.0 m/s
The initial momentum (p1) of the car is calculated as:
p1 = m * v1 = 600 kg * 24.0 m/s = 14400 kg·m/s
The final momentum (p2) of the car is calculated as:
p2 = m * v2 = 600 kg * 19.0 m/s = 11400 kg·m/s
The change in momentum (Δp) is then given by:
Δp = p2 - p1 = 11400 kg·m/s - 14400 kg·m/s = -3000 kg·m/s
The negative sign indicates that the direction of the momentum change is opposite to the initial momentum.
Therefore, the magnitude of the change in the car's momentum during the turn is 3000 kg·m/s.
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a vibrating diaphragm sets up strong vibrations at the mouth of a horizontal tube containing air and a small amount of fine powder. the powder becomes arranged in piles i cm apart, and the speed of sound in air is 330 meters
the wavelength of this sound in air is:
(the answer is 2cm howd we get hereeee)
Answers
A sound is moving through the atmosphere at a velocity of 343 ms-1. The sound wave has a wavelength of 0.1 cm.
Sound in the air is what kind of wave?Longitudinal waves are what make up sound. Compressions and rarefactions are also present in longitudinal waves when they pass through any given medium. When particles travel in close proximity to one another, compression occurs, creating areas of intense pressure.
What is the air wavelength formula?As with all waves, the relationship between the speed of sound (vw), its frequency (f), and its wavelength () is provided by vw=f. vw=(331m/s)T273K describes how the sound's velocity in the air relates to air temperature T. For any and all frequencies and wavelengths, vw is constant.
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Hi i was wondering if you could help me understand Kelvins? My question on my work says "Which of the following is the SI unit used in measuring the temperature of a hot cup of coffee" and the other question says, "Which of the following would be the SI unit to use in measuring the temperature of a hot liquid?" I said both are Kelvin but i dont really understand and i dont want to be wrong.
Answers
Answer:
Hey there!
Kelvin is correct. Farenheit and Celsius are scales derived from the Kelvin scale. For example, K=C+273.15 is the conversion between Kelvin and Celsius.
Let me know if this helps :)
what is the volume of an aluminum ball at 10°c if its volume at 160°c is 300cm3?
Answers
The volume of the aluminum ball is 297 cm³.
What is the volume of the aluminum ball?
The volume of an object changes with temperature, according to the law of linear thermal expansion.
The volume of the aluminum ball is calculated as follows;
V = V₀ ( 1 + 3αΔθ )
where;
V₀ is the initial volume of the aluminumα is the coefficient of linear expansion of aluminumV = 300 cm³ ( 1 + 3 x 23 x 10⁻⁶ x (-150 ) )
V = 297 cm³
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A ball of mass 0.5 kg is swinging at a small angle from a light string of length 0.25 m. What is the period of this pendulum? Round answer to two significant digits.
Answers
Answer: 1.0
Explanation:
not sure why but that is the correct answer
Answer:
1.0
Explanation:
Correct answer on Khan Academy
As our Sun exhausts its supply of hydrogen, it will cool down by 1000 to 2000 Kelvin. But it will also become about 100 times brighter than it is now. Describe the path our Sun will take on the HR diagram, and what type of star the Sun will become.
Answers
Answer:
It will move upward and to the right, from the main sequence to the giants.
Explanation:
Plato answer so change it up a bit xx
An object of height 5cm is placed at 20cm from a concave mirror of focal length 10cm. The image height is
Answers
Since the magnification is equal to 1, the image height is the same as the object height which is 5 cm
What is Optical Magnification ?Magnification is when the ratio of the size of the image to the size of the object is greater than 1
Given that an object of height 5cm is placed at 20cm from a concave mirror of focal length 10cm.
The object distance u = 20 cmThe object height h = 5 cmFocal length f = 10 cmThe image distance v = ?The image height H = ?To find the image height, let us first find the image distance by using the formula below
1/f = 1/u + 1/v
Substitute all the parameters
1/10 = 1/20 + 1/v
1/v = 1/10 - 1/20
1/v = (2 - 1)/20
1/v = 1/20
v = 20 cm
Magnification = v/u = H/h
20/20 = H/5
H = 5 cm
Therefore, the image height is the same as the object height which is 5 cm
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if a waves frequency is 4Hz, and its wavelength is 5 m, then what is its speed?
Answers
Answer:
speed = 20 m/s
Explanation:
speed = frequency * wavelength
speed = 4 * 5
speed = 20 m/s