PLEASE HELP!

How much blood is in your body if it masses at 6.36x10³ grams and has a density of 1.06 g/cm³.

The half-life gives the time  after which a give unstable substance decays

to half the initial quantity.

Reasons:

The mass of the sample of the radioactive isotope, m = 60-g

The number of half lives that passes = 2 half lives

Required:

The pair of percentages that describes the sample.

Solution:

The half-life is the time half of an unstable radioactive substance decays into a stable substance.

Therefore, after one half life, the pair of percentages we have are;

50% unchanged and 50% stable

After the second half life, the 50% of the sample decays further by half to give; 25%  stable substance and 25% unchanged substance

Therefore, after two half-lives, we get;

(50% + 25%) stable substance and 25% unchanged sample

75% stable substance and 25% unchanged

The correct option is; 25% unchanged and 75% stable.

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Answer:

B on edge

Step-by-step explanation:

Answer:

64 square centimeters

Step-by-step explanation:

The surface are of a pyramid is found by finding the sum of the area of the four sides and the base.

Finding the triangular face:

Area of triangle = \(\frac{1}{2} b h\) = \(\frac{1}{2}*4*6 = 12\)

12 * 4 (4 sides) = 48 square cm

Finding the Base = \(w * l = 4 * 4 = 16\)

Finally, we add it together. 48 + 16 = 64

True. The cost feasibility of a systems development project is indeed dependent on the project's scope.

The cost feasibility of a systems development project refers to the evaluation of whether the project can be completed within the allocated budget. One of the key factors influencing cost feasibility is the scope of the project. The scope defines the boundaries and objectives of the project, including the features, functionalities, and deliverables that are expected to be developed.

When the scope of a project is well-defined and limited, it tends to be more cost-feasible. A smaller scope usually requires fewer resources, less development time, and ultimately, lower costs. On the other hand, projects with a broader or more complex scope often involve a larger number of requirements, greater integration challenges, and increased development efforts, which can drive up the costs.

Therefore, the scope of a systems development project plays a crucial role in determining its cost feasibility. Project managers and stakeholders need to carefully analyze and define the project's scope to ensure that it aligns with the available resources and budget, thereby increasing the chances of successful and cost-effective project completion.

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If X has the hypergeometric distribution, the minimum value that X can take is option (e) 0

The hypergeometric distribution models the probability of getting a certain number of successes in a fixed-size sample drawn without replacement from a finite population containing a known number of successes and failures.

The minimum value that X can take depends on the specific parameters of the distribution.

If the population size is N, the number of successes in the population is K, and the sample size is n, then the minimum value that X can take is max(0, n - (N - K)).

This is because the sample can contain at most n items, and if all of them are failures (i.e., none of them are successes), then X would be 0. On the other hand, if there are fewer than n failures in the population, then the sample can contain at most n - (N - K) successes. If n - (N - K) is negative, then there are more successes than failures in the population, and X can take any value between 0 and n, inclusive.

Therefore, the correct option is (e) 0

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4.3-3(4r-3(=0.7(6r-10

We move all terms to the left:

4.3-3(4r-3(-(0.7(6r-10)=0

The limits of integration of ∬R(8x+5y)2dA = ∫BA∫DC(8x+5y)2dxdy ∬R(8x+5y)2dA = ∫AB∫CD(8x+5y)2dxdy are A = (-1, 0), B = (1, 0), C = (-1, 1), D = (0, 1). The integral in part (a) is 5832/5.

(a) The vertices of the triangle R are (-1, 0), (0, 1), and (1, 0). We can find the limits of integration by considering the bounds of x and y in the region.

The line segment connecting (-1, 0) and (0, 1) has equation y = x + 1, so y ranges from 0 to x + 1. The line segment connecting (0, 1) and (1, 0) has equation y = -x + 1, so y ranges from 0 to -x + 1. The x-values of the left and right sides of the triangle are -1 and 1, respectively, so x ranges from -1 to 1.

Therefore, the limits of integration are:

A = (-1, 0)

B = (1, 0)

C = (-1, 1)

D = (0, 1)

(b) We have:

∬R(8x+5y)2dA=∫AB∫CD(8x+5y)2dxdy

= ∫_{-1}¹ ∫_0^{x+1} (8x+5y)² dy dx + ∫_{-1}⁰ ∫_0^{-x+1} (8x+5y)² dy dx

To evaluate the inner integral with respect to y, we can use the substitution u = 8x + 5y, du/dy = 5, and y = (u - 8x)/5. When y = 0, u = 8x, and when y = x+1 or -x+1, u = 8x + 5(x+1) = 13x+5 or 8x - 5(-x+1) = 13x + 5, respectively. Therefore, we have:

∫_0^{x+1} (8x+5y)² dy = ∫_{8x}^{13x+5} u² (1/5) du = (1/15)(u³)|_{8x}^{13x+5} = (1/15)(2197x³ + 7025)

∫_0^{-x+1} (8x+5y)² dy = ∫_{8x}^{13x+5} u² (1/5) du = (1/15)(2197x³ + 7025)

Substituting these integrals and limits of integration into the original expression, we get:

∬R(8x+5y)2dA = ∫_{-1}^1 [(1/15)(2197x³ + 7025) + (1/15)(2197x³ + 7025)] dx

= (2/15) ∫_{-1}¹ (4394x³ + 14050) dx

= (2/15) [(1098x⁴)/4 + 14050x]_{-1}^1

= (2/15) [(1098/4) + 14050 - (-1098/4) - 14050]

= 5832/5

Therefore, the integral is 5832/5.

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Answer:

area = 11 17/21 cm²

Step-by-step explanation:

area = length x width

area = 2 2/7 x 5 1/6 = 16/7 x 31/6 = 496/42 = 11 34/42 = 11 17/21 cm²

Answer: something

Step-by-step explanation: you are welcome

Answer:

The values of x are:

x : -3, -2, -1, 0, 1, 2, 3

Let's solve each by putting each value of x into each equation:

a \(y = 2^x\)

> x = -3

=> y = 2^(-3) = 1/8

> x = -2

=> y = 2^(-2) = 1/4

> x = -1

=> y = 2^(-1) = 1/2

> x = 0

=> y = 2^0 = 1

> x = 1

=> y = 2^1 = 2

> x = 2

=> y = 2^2 = 4

> x = 3

=> y = 2^3 = 8

b. \(y = -2^x\)

> x = -3

=> y = -2^(-3) = -1/8

> x = -2

=> y = -2^(-2) = -1/4

> x = -1

=> y = -2^(-1) = -1/2

> x = 0

=> y = -2^0 = -1

> x = 1

=> y = -2^1 = -2

> x = 2

=> y = -2^2 = -4

> x = 3

=> y = -2^3 = -8

c. \(y = (3)(2^x)\)

> x = -3

=> y = 3 * 2^(-3) = 3 * 1/8 = 3/8

> x = -2

=> y = 3 * 2^(-2) = 3 * 1/4 = 3/4

> x = -1

=> y = 3 * 2^(-1) = 3 * 1/2 = 3/2

> x = 0

=> y = 3 * 2^0 = 3 * 1 = 3

> x = 1

=> y = 3 * 2^1 = 3 * 2 = 6

> x = 2

=> y = 3 * 2^2 = 3 * 4 = 12

> x = 3

=> y = 3 * 2^3 = 3 * 8 = 24

Input these values into the table.

Answer:

a y = 2^x

> x = -3

=> y = 2^(-3) = 1/8

> x = -2

=> y = 2^(-2) = 1/4

> x = -1

=> y = 2^(-1) = 1/2

> x = 0

=> y = 2^0 = 1

> x = 1

=> y = 2^1 = 2

> x = 2

=> y = 2^2 = 4

> x = 3

=> y = 2^3 = 8

b. y = -2^x

> x = -3

=> y = -2^(-3) = -1/8

> x = -2

=> y = -2^(-2) = -1/4

> x = -1

=> y = -2^(-1) = -1/2

> x = 0

=> y = -2^0 = -1

> x = 1

=> y = -2^1 = -2

> x = 2

=> y = -2^2 = -4

> x = 3

=> y = -2^3 = -8

c. y = (3)(2^x)

> x = -3

=> y = 3 * 2^(-3) = 3 * 1/8 = 3/8

> x = -2

=> y = 3 * 2^(-2) = 3 * 1/4 = 3/4

> x = -1

=> y = 3 * 2^(-1) = 3 * 1/2 = 3/2

> x = 0

=> y = 3 * 2^0 = 3 * 1 = 3

> x = 1

=> y = 3 * 2^1 = 3 * 2 = 6

> x = 2

=> y = 3 * 2^2 = 3 * 4 = 12

> x = 3

=> y = 3 * 2^3 = 3 * 8 = 24

Step-by-step explanation:

the area of the dartboard is approximately 254.34 square inches.

The area of a dartboard can be calculated using the formula for the area of a circle, which is given by:

Area = π * \(radius^2\)

Given that the radius of the dartboard is 9 inches, we can substitute this value into the formula:

Area = π * \(9^2\)

Area = π * 81

To calculate the area, we need to use the value of π (pi). Pi is an irrational number and is commonly approximated as 3.14. Using this approximation, we can calculate the area:

Area ≈ 3.14 * 81

Area ≈ 254.34 square inches

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The potential solutions of logarithmic function using the logarithmic properties are found as -9 and 4.

The product of the log rule says that the sum of number of logarithm functions is equal to the log function of product of all the numbers, given  that base is same.

The given logarithmic function in the problem is,

\(\log_6x+\log(6x+5)=2\)

Using the product rule of logarithmic function, the above equation can be written as,

\(\log_6(x\times(x+5))=2\\\log_6(x^2+5x))=2\)

Using the equality rule of logarithmic function, the above equation can be written as,

\(x^2+5x=6^2\\x^2+5x=36\)

Take all the terms one side of the equation as,

\(x^2+5x-36=0\)

Find the factors of above equation using the split the middle term method as,

\(x^2+9x-4x-36=0\\x(x+9)-4(x+9)=0\\(x+9)(x-4)=0\)

By equating these factor to the zero one by one, we get the potential solution as -9 and 4.

Thus, the potential solutions of logarithmic function using the logarithmic properties are found as -9 and 4.

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Answer:

-9 and 4

Step-by-step explanation:

Did it on edge :)

Answer:

CHEEEEEEEEESE

Step-by-step explanation:

Yes, you can show significant differences using superscripts in an ANOVA (Analysis of Variance) single-factor test.

In an ANOVA test, superscripts are commonly used to indicate significant differences between the means of different groups or treatments.

Typically, letters or symbols are assigned as superscripts to denote which groups have significantly different means. These superscripts are usually presented adjacent to the mean values in tables or figures.

The specific superscripts assigned to the means depend on the statistical analysis software or convention being used. Each group or treatment with a different superscript is considered significantly different from groups with different superscripts. On the other hand, groups with the same superscript are not significantly different from each other.

By including superscripts, you can visually highlight and communicate the significant differences between groups or treatments in an ANOVA single-factor test, making it easier to interpret the results and identify which groups have statistically distinct means.

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Answer:

Step-by-step explanation:

\( \frac{4f^{2} }{3} \div \frac{1}{4f} \)

\( \frac{4 {f}^{2}}{3} (4f)\)

\(4 \frac{4 {f}^{2} }{3} f\)

\( \frac{16 {f}^{2} }{3} f\)

\( \frac{16 {f}^{3} }{3} \)

The answer is using y<8 using inequality

what is inequality?

The mathematical expressions with inequalities are those with unequal sides on both sides. Unlike equations, we compare two values when we work with inequality. The equal sign is substituted between by the less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

It's not always necessary to balance an equation in mathematics by using the "equal to" symbol on both sides. When something is more than or less than another, it can sometimes be said that the two are not equal. When two numbers or other mathematical expressions are compared unequally, this is referred to as an inequality in mathematics. Inequalities are a type of mathematical expression that belongs to algebra.

4y <32

y<32/4

y<8

Hence the value of y should be less than 8.

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Seraphina's speed has increased by a factor of around 23% compared to the first hour.

What Is a Change in Percentage?

The ratio of the difference in the amount to its starting value multiplied by 100 is known as the percentage change. When a number's final value is determined by increasing or decreasing a percentage of its starting value, the percentage change of that quantity will always change.

How can you determine the percentage to the closest tenth?

Rounding to the closest tenth entails adding one integer after the decimal point. The number in the thousandths place, or the second number from the right of the decimal, must be considered while rounding. If the amount is five or more, we add one percent to the number in the tenth position.

Percent Change Formula = \(\frac{ (Final value -Initial value)}{ (Initial value)}\)× 100

Percent Change               = \(\frac{(74-60)}{60}\)× 100

…                                     = \(\frac{14}{60}\) × 100

...                                     ≈ 0.23333 × 100

Percent Change             ≈ 23.33%

The pace of Seraphina increased by around 23% in the second hour compared to the first.

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The function f(r) = 80e converges and can be used as a comparison function to show that the integral I converges.

To show that the integral I converges, we need to find a function that serves as an upper bound and converges. By noting the symmetry of the integral Se-r' dr = 2 80e dr, we can focus on showing the convergence of the latter integral.

One option is to choose the function f(r) = 80e as a comparison function. This function is defined for r ≥ 0 and is always positive. By comparing the integrand of I to f(r), we can establish that the integral I is bounded above by the convergent integral of f(r).

Since f(r) = 80e is a well-defined and convergent function, and it bounds the integrand of I from above, we can conclude that the integral I converges.

Using the comparison test allows us to determine the convergence of improper integrals by comparing them to known convergent functions. In this case, we have found a suitable function, f(r) = 80e, that is defined piecewise and provides an upper bound for the integrand. By establishing the convergence of f(r), we can confidently assert the convergence of the integral I.

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Step-by-step explanation:

Set the parameters,

Let the width be 'X' inhes

Therefore,

Length = "5X" inches

According to the given condition,

Perimeter = sum of the sides = 2(l+b) = 40 inches,

Equation = 2(5X+X) = 40

2(6X) = 40

12X= 40

X= 3.33

Therefore,

Width = X = 3.33 inches

To calculate the total charge within the cylinder with dimensions r=1.5 and h=3, we use the potential function V = 5r + 4 cos Ø in cylindrical coordinates.

The total charge can be obtained by integrating the charge density over the volume of the cylinder.

The potential V within the cylinder is given by V = 5r + 4 cos Ø, where r represents the radial distance from the axis of the cylinder and Ø represents the angle in the cylindrical coordinate system. To calculate the total charge within the cylinder, we need to integrate the charge density over its volume.

The charge density ρ can be related to the potential by ρ = -∇²V, where ∇² is the Laplacian operator. In cylindrical coordinates, the Laplacian operator takes the form:

∇² = (1/r) ∂/∂r (r ∂/∂r) + (1/r²) ∂²/∂ز + ∂²/∂z²

Since the potential function V does not depend on the z coordinate, the Laplacian reduces to:

∇² = (1/r) ∂/∂r (r ∂/∂r) + (1/r²) ∂²/∂ز

Applying this operator to the potential function V, we find:

∇²V = (1/r) ∂/∂r (r ∂V/∂r) + (1/r²) ∂²V/∂ز

To find the charge density, we substitute this expression into ρ = -∇²V:

ρ = -(1/r) ∂/∂r (r ∂V/∂r) - (1/r²) ∂²V/∂ز

To calculate the total charge, we integrate the charge density ρ over the volume of the cylinder:

Q = ∫∫∫ ρ dV = ∫∫∫ -(1/r) ∂/∂r (r ∂V/∂r) - (1/r²) ∂²V/∂ز dV

The integration is performed over the cylindrical coordinates r, Ø, and z, with appropriate limits. Evaluating this integral will give us the total charge within the cylinder.

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Answer:

to add on to what the other dude said its 4

Step-by-step explanation:

Answer:

∠ 2 = 40°

Step-by-step explanation:

∠ 1 and ∠ 2 are corresponding angles and congruent, thus

∠ 2 = ∠ 1 = 40°

The linear factors of the given cubic polynomial are (x-1)(x+4)(x+5).

The linear factors of a polynomial are the first-degree equations that are the building blocks of more complex and higher-order polynomials.

Given a cubic polynomial, x³+8x²+11x-20

x³+8x²+11x-20 = (x-1)(x²+9x+20)

= (x-1)(x²+4x+5x+20)

= (x-1){x(x+4)+5(x+4)}

= (x-1)(x+4)(x+5)

Hence, The linear factors of the given cubic polynomial are (x-1)(x+4)(x+5).

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Answer:

120 square centimeters

Step-by-step explanation:

Given the topological spaces X = {D, O, R, K} with the topology Tx and Y = {M, A, T, H} with the topology Jy, we are asked to determine whether the set E = {0, K} is open in X and open in Y.

To determine whether the set E = {0, K} is open in the topological spaces X and Y, we need to check if E belongs to the respective topologies, Tx and Ty.

In X, the topology Tx is given by: Tx = {Ø, {0}, {D, O}, {O, R}, {D, O, R}, X}. We can see that E = {0, K} is not explicitly listed in Tx. Therefore, E is not open in X since it does not belong to the topology.

In Y, the topology Ty is given by: Jy = {0, {M}, {M, A}, {M, A, T}, Y}. Again, E = {0, K} is not explicitly listed in Ty. Hence, E is not open in Y as it does not belong to the topology.

In both cases, the set E = {0, K} is not open in the respective topological spaces X and Y because it is not a member of the defined topologies.

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Answer:

the answers to this problem are x-2 and -2-x+2x

Step-by-step explanation:

i took the k12 test so i hope this helps

Answer:

i can comfirm its -2 - x +2x and 2-x

Step-by-step explanation:

took the quiz trust me