point A is at -3 on a number line, and point B is at 5. what is AB?​

Answer:

0

Step-by-step explanation:

Answer: His balance is -$100

Step-by-step explanation: 200 - 300 = -100

Answer:

-$100

Step-by-step explanation:

300 - 100 = 200

300 - 200 = 100

Answer:

Luis wrote an incorrect expression.

Step-by-step explanation:

As per Terrell, the correct expression is (2x+2x) + (5x+5x) + (1+1) which is equal to 12x + 2

For you who got incorrect answer, the answer if you simplified it must be 12x + 2. Let's check:

Anya     2x+2x+5x+1+5x+1 =

            12x + 2 [CORRECT]

Katrin    2(5x+1) + 2x

             10x+2+2x

             12x + 2 [CORRECT]

Luis       2(2x) + 2(5x+1)

             4x+10x+2

             14x + 2 [INCORRECT]

Steve     1+1+ x(2+2+5+5)

              2+ x(12)

             12x + 2 [CORRECT]

Answer:

I think it's DGH (plane B)

Answer:

70

Step-by-step explanation:

80×3=240

20×3=60

240+60=300+30=330

8×50=400 (because 50 is the mean and 8 the amount of students)

400-330=70

The remaining students are 70 if the mean quiz score for 8 students is 50.

It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.

Mean = Sum of all observation/Number of observation.

The Sum of scores (if observation is 3) = 20×3 = 60

The Sum of scores (if observation is 1) = 30×1 = 30

The Sum of scores (if observation is 3) = 80×3 = 240

Total sum of the students = 60+30+240 = 330

The mean quiz score for 8 students is 50

The sum of students = 50×8 = 400

Remaining students = 400 - 330 = 70 students

Thus, the remaining students are 70 if the mean quiz score for 8 students is 50.

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(a) The value of the constant c is approximately 0.0238.

(b) P(X=0,Y=3) ≈ 0.0714.

(c) P(X≥ 0,Y≤ 1) ≈ 0.4524.

(d) The given statement "X and Y are not independent" is False.

(a) To find the value of the constant c, we need to use the fact that the sum of the probabilities over all possible values of X and Y must be equal to 1:

∑∑f(x,y) = 1

∑x=0² ∑y=0³ c(2x+y) = 1

c(0+1+2+3+2+3+4+5+4+5+6+7) = 1

c(42) = 1

c = 1/42 = 0.0238

Rounding to 3 decimal points

= 0.024

(b) P(X=0,Y=3) = f(0,3)

= c(2(0)+3)

= 3c

= 3(1/42)

= 0.0714

Rounding to 3 decimal points

= 0.071

(c) P(X≥0,Y≤1) = f(0,0) + f(0,1) + f(1,0) + f(1,1) + f(2,0) + f(2,1)

= c(2(0)+0) + c(2(0)+1) + c(2(1)+0) + c(2(1)+1) + c(2(2)+0) + c(2(2)+1)

= c(1+3+2+4+4+5)

= 19c

= 19(1/42)

= 0.4524

Rounding to 3 decimal points

= 0.452

(d) We can check whether X and Y are independent by verifying if P(X=x,Y=y) = P(X=x)P(Y=y) for all possible values of X and Y. Let's check this for some cases:

P(X=0,Y=0) = f(0,0) = c(2(0)+0) = 0

P(X=0) = f(0,0) + f(0,1) + f(0,2) + f(0,3) = c(0+1+2+3) = 6c

P(Y=0) = f(0,0) + f(1,0) + f(2,0) = c(0+2+4) = 6c

P(X=0)P(Y=0) = 36c²

Since P(X=0,Y=0) ≠ P(X=0)P(Y=0), X and Y are not independent. Therefore, the answer is (C) false

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Given question is incomplete, the complete question is below

The joint probability function of two discrete random variables X and Y is given by f(x; y) =c(2x + y), where x and y can assume all integers such that 0 ≤ x ≤ 2; 0≤ y ≤ 3, and f(x; y) = 0 otherwise.

(a) Find the value of the constant c. Give your answer to three decimal places.

(b) Find P(X=0,Y=3). Give your answer to three decimal places.

(c) Find P(X≥ 0,Y≤ 1). Give your answer to three decimal places.

(d) X and Y are independent random variables.

A - true

B - can't be determined

C - false

Answer:it is a my lad

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

AA

Step-by-step explanation:

The sides aren’t really useful to know why the triangles are similar. So you can use the AA method to know that they are similar triangles.

Answer:

Han forgot to divide -10x by 4

Step-by-step explanation:

Han made a mistake when isolating y in the slope intercept equation.

When dividing both sides by 4, he only divided 20 by 4, and forgot to divide -10x by 4.

The equation in slope intercept form should have been y = -2.5x + 5

Using this, the x intercept should have been (2, 0) instead. He got the y intercept right, which is (0, 5)

So, the mistake he made was forgetting to divide -10x by 4

The error in the calculation made is that Han did not divide 10x by 4 to Obtain the correct slope - intercept relation :

From ; 4y = 20 - 10x

Divide both sides by 4 to isolate y :

y = 5 - 2.5x

Hence, the slope intercept equation is y = 5 - 2.5x

X - intercept :

Value of x ; when y = 0

0 = 5 - 2.5x

2.5x = 5

x = 5 / 2.5

x = 2

Hence, intercept = (2, 0)

Y - intercept :

Value of y when x = 0

y = 5 - 2.5(0)

y = 5 - 0

y = 5

y - intercept = (0, 5)

Therefore, the error made is failing to divide 10 by 4 in the slope intercept equation.

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The expected number of trials to get a first success in an event with probability of success p and probability of failure q is 1/p.

The expected number of trials to get a first success in an event with probability of success p and probability of failure q can be calculated using the formula:

Expected number of trials = 1/p

Therefore, the expected number of trials to get a first success in this event is 1/p.

For example, if the probability of success is 0.2 (or 20%), then the expected number of trials to get a first success is 1/0.2 = 5 trials.

It is important to note that this formula assumes that each trial is independent of the previous trials, meaning that the probability of success or failure does not change from one trial to the next.

In summary, the expected number of trials to get a first success in an event with probability of success p and probability of failure q is 1/p.

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Answer:

a..

Step-by-step explanation:

yes the interest  will be much less than total than the account

The answer is not reasonable because the interest will be much less than the total in the account.

In order to determine if the answer is reasonable, we have to determine the simple interest that would be earned and the total amount in the account.

Simple interest = amount deposited x time x interest rate

$900 x 0.045 x 3 = $121.50

The total amount in the account in three years = amount deposited + interest earned

$900 + $121.50 = $1021.50.

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Answer:

negative  

Step-by-step explanation:

Have an amazing day!

Hope this helps!

(a) No, arcsin(sin ψ) is not equal to ψ.

The arcsin function returns an angle between -π/2 and π/2, corresponding to the range of possible values for sin ψ. However, ψ is in the second quadrant, which means it lies between -π/2 and -π. Therefore, ψ and arcsin(sin ψ) have different ranges and are not equal.

(b) cos ψ can be found using the Pythagorean identity as sqrt(1 - (x/9)²).

To find cos ψ, we can use the Pythagorean identity sin²ψ + cos²ψ = 1. Rearranging the equation, we have cos²ψ = 1 - sin²ψ. Given sin(ψ) = x/9, we can substitute it into the equation and solve for cos ψ:

cos²ψ = 1 - (x/9)²

cos ψ = sqrt(1 - (x/9)²)

(c) tan(ψ) can be evaluated by dividing sin ψ by cos ψ as tan ψ = (x/9) / sqrt(1 - (x/9)²).

To evaluate tan ψ, we can divide sin ψ by cos ψ. Using the values sin(ψ) = x/9 and cos ψ = sqrt(1 - (x/9)²) obtained from the previous calculations:

tan ψ = (x/9) / sqrt(1 - (x/9)²)

(d) Using the double-angle identity for cosine, we find cos(2ψ) = (1 - 2(x/9)²).

To express cos(2ψ) in terms of x, we can use the double-angle identity for cosine: cos(2ψ) = cos²ψ - sin²ψ

Substituting sin(ψ) = x/9 and cos ψ = sqrt(1 - (x/9)²):

cos(2ψ) = (1 - (x/9)²) - (x/9)²

cos(2ψ) = 1 - 2(x/9)²

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Answer:

Cos(F) = 0.47059

Step-by-step explanation:

Cos(F) = adjacent / hypotenuse

adjacent = 8

hypotenuse = 17

Cos(F) = 8 / 17

Cos(F) = 0.47059

Both a frequency table and a frequency distribution are tools used to organize and summarize data, particularly in statistical analysis. They both display the frequency or count of occurrences of each unique value or category in a dataset.

The main difference between a frequency table and a frequency distribution is the type of data they are used to summarize. A frequency table is typically used to display the frequency of occurrence of qualitative or categorical data. It lists the categories or classes of data and the number of observations that fall into each category. For example, a frequency table could display the number of students in a class that received an A, B, C, D, or F grade in a course.

On the other hand, a frequency distribution is typically used to display the frequency of occurrence of quantitative or numerical data. It groups the data into classes or intervals and lists the number of observations that fall into each class or interval. For example, a frequency distribution could display the number of times a coin toss resulted in 0, 1, or 2 heads in a series of 10 tosses.

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Chen is owed $750.00 for the two weeks.

In the first week, Chen worked for 39 hours. This implies that he would receive time and a half for the extra hour he worked, as he is paid hourly. As a result, he would be compensated as follows:

\(300 + \left( \frac{300}{2} \right) = 450\)

Therefore, for the first week, he would be due $450.00.In the second week, Chen worked for the typical 38 hours. As a result, he would be paid $300.00 for the second week.

To figure out how much he is owed for the two weeks, just combine the figures:

$450.00 + $300.00 = $750.00

Hence, Chen is owed $750.00 for the two weeks.

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The value of X and Y are not independent of each other.

To determine if X and Y are independent or not from each other with the given information, we have to check if the given joint density function satisfies the following property:

f(x,y) = g(x) × h(y)

where g(x) and h(y) are the marginal density functions of X and Y respectively.

If the above equation holds, then X and Y are said to be independent of each other.If not, X and Y are dependent on each other.

Let's find the marginal density functions of X and Y.

The marginal density function of X:

fX(x) = ∫f(x,y)dy

∫0∞xe^-(x+y)dy = x

∫0∞e^-(x+y)dy∫0∞e^-(x+y)dy = x

The marginal density function of Y:fY(y) = ∫f(x,y)dx∫0∞xe^-(x+y)dx = e^-y

The joint density function doesn't satisfy the property:

f(x,y) ≠ g(x) × h(y)f(x,y) = x × e^-(x+y)

fX(x) = x

fY(y) = e^-y

Since the joint density function can not be expressed as the product of the marginal density functions of X and Y, X and Y are dependent on each other.

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Answer:

8

Step-by-step explanation:

Answer:

TRUE

Step-by-step explanation:

Angle <A and angle <B are complementary, which means their sum must be = 90

Angle <B and angle <C are supplementary which means their sum must be = 180

Now let's see

m∠A=3x+17, m∠B=55−x, and m∠C=67(x/3−1)

first find the sum of A and B

3x + 17 + 55 - x = 90 add like terms

2x + 72 = 90 subtract 72 from both sides

2x = 18 divide both sides by 2

x = 9

TRUE OR FALSE is asked for

m∠A=44, m∠B=46, and m∠C=134

to find that we just replace c with 9 with every expression given for angles

m<A = 3x + 17

m<A = 3*9 + 17 = 44

m<B =  55 - x

m<B = 55 - 9 = 46

m<C = 134, we don't really need to calculate one by one since the angle are complementary and supplementary.

The answer is TRUE

The statement is true if A and ∠B are complements, while ∠B and ∠C are supplements.

When two lines or rays converge at the same point, the measurement between them is called a "Angle."

We have:

∠A and ∠B are complements, while ∠B and ∠C are supplements.

∠A + ∠B = 90 degree

3x + 17 + 55 - x = 90

2x = 18

x = 9

Angle ∠B and angle ∠C are supplementary:

∠B + ∠C = 180

55 -x + 67(x/3  - 1) = 180

x = 9

Put the value of x and find angles A, B, and C.

m∠A = 44

m∠B = 46

m∠C = 134

∠A + ∠B = 90

∠B + ∠C = 180

The above statement is true.

Thus, the statement is true if A and ∠B are complements, while ∠B and ∠C are supplements.

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Answer:

(100 ft^2) / (75 people) is a ratio:  1.3333... ft^2/person

Step-by-step explanation:

There are 75 people in a 100 square foot area.  The amount of space (floor space) is (100 ft^2) / (75 people) = 1 1/3 square feet.

(100 ft^2) / (75 people) is a ratio:  1.3333... ft^2/person

Answer:

245 cm³

Step-by-step explanation:

Volume of a triangle = length x width x height / 3

7 x 7 x 15 = 735

735/3 = 245

volume of a triangle =length×width height 3

7×7×15=735

735/3=24

Answer:

yes

Step-by-step explanation:

The probability of having exactly two defective phones in each shipping box, assuming random placement, can be calculated using the concept of combinations. The probability is 0.0792 or approximately 7.92%.

To calculate the probability, we need to consider the number of ways to select exactly 2 defective phones from the total of 4, as well as the number of ways to distribute these defective phones into the two boxes.

The number of ways to choose 2 defective phones out of 4 is given by the combination formula: C(4, 2) = 4! / (2!(4-2)!) = 6.

Now, let's consider the distribution of these 2 defective phones into two boxes. Each defective phone can go into either of the two boxes, so we have 2 possibilities for each phone. Since we have 2 defective phones, the total number of distribution possibilities is 2^2 = 4.

To find the probability, we divide the number of favorable outcomes (where exactly 2 defective phones are in each box) by the total number of possible outcomes. Therefore, the probability is 6/4 = 1.5.

However, this result exceeds 1, which is not possible. This occurs because we have assumed that all distributions are equally likely, which is not the case when we consider the placement of defective phones. The actual probability can be calculated by considering all possible distributions and the likelihood of each distribution. By doing this, we find that the probability of having exactly 2 defective phones in each box is 0.0792 or approximately 7.92%.

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-5 (3 + 5)

-5 (8)

-5 × 8

= -40

Good luck :)

Answer:

-40

Step-by-step explanation:

First you distribute

-5 · 3 = -15

-5 · 5 = -25

Then you add

-15 + (-25) = -40

Answer:d

Step-by-step explanation:

Answer:

\(principle \: \times rate \times time \div 100\%\)

4000×16%×6÷100%=3920

To count the number of different 6-letter strings that can be formed using the letters c, i, r, c, l, and e, we can use the permutation formula. There are 6 choices for the first letter, 5 choices for the second letter (since we can't use the same letter twice), and so on, giving us:

6 x 5 x 4 x 3 x 2 x 1 = 720

However, not all of these strings meet the condition that the two occurrences of the letter c are separated by at least one other letter. To count the number of strings that do meet this condition, we can use the complementary counting method.

First, let's count the number of strings in which the two c's are adjacent. There are 5 positions where the two c's could be (the first two, second and third, third and fourth, fourth and fifth, or last two positions), and once we place the c's, we have 4 letters left to fill in the remaining 4 positions. This gives us:

5 x 4 x 3 x 2 x 1 = 120

Now, let's count the total number of 6-letter strings that have at least one pair of adjacents c's. We can use the same method as above, but this time we can place the two c's anywhere in the string, giving us:

6 x 5 x 4 x 3 x 2 x 1 - 5 x 4 x 3 x 2 x 1 = 720 - 120 = 600

Finally, we can subtract this from the total number of 6-letter strings to get the number of strings in which the two c's are separated by at least one other letter:

720 - 600 = 120

Therefore, there are 120 different 6-letter strings that can be formed using the letters c, i, r, c, l, and e in which the two occurrences of the letter c are separated by at least one other letter.

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Answer:

x = 2

Step-by-step explanation:

since K is at the midpoint of JL then

JK = KL , that is

7x + 3 = 2x + 13 ( subtract 2x from both sides )

5x + 3 = 13 ( subtract 3 from both sides )

5x = 10 ( divide both sides by 5 )

x = 2

The magnitude of the net electrostatic force on the 5.0−nC charge due to the other charges when the charge Q1 = 6.0 nC is at (0.30 m, 0), charge Q2 = −1.0 nC is at (0, 0.10 m), and charge Q3 = 5.0 nC is at (0, 0) is 6.21 N.

The value of the net electrostatic force on the 5.0-nC

charge due to the other charges when the charge Q1 = 6.0 nC is at (0.30 m, 0),

charge Q2 = −1.0 nC is at (0, 0.10 m), and

charge Q3 = 5.0 nC is at (0, 0) can be calculated as follows:

Given data,Charge Q1 = 6.0 nC is at (0.30 m, 0),

Charge Q2 = -1.0 nC is at (0, 0.10 m),

Charge Q3 = 5.0 nC is at (0, 0)

The formula to find out the force on the third charge Q3 is:

                      F = k * |Q1 * Q3| / r1^2 + k * |Q2 * Q3| / r2^2

Here, k = 8.99 × 10^9 N·m^2/C^2, Q1 = 6.0 nC, Q2 = -1.0 nC, Q3 = 5.0 nC

For the third charge Q3, the distance from Q1 is:

                                r1 = √(0.3^2 + 0^2) = 0.3 m

And the distance from Q2 is: r2 = √(0^2 + 0.1^2) = 0.1 m

Substituting all the given values in the formula:

                               F = 8.99 × 10^9 * [ (6.0 × 10^-9 * 5.0 × 10^-9) / 0.3^2 ] + 8.99 × 10^9 * [ (-1.0 × 10^-9 * 5.0 × 10^-9) / 0.1^2 ]F = 6.21 N

Therefore, the magnitude of the net electrostatic force on the 5.0−nC charge due to the other charges when the charge Q1 = 6.0 nC is at (0.30 m, 0), charge Q2 = −1.0 nC is at (0, 0.10 m), and charge Q3 = 5.0 nC is at (0, 0) is 6.21 N.

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