Solve for x.&X-3 / 4X+3.--8x 4xWhen angles form a linear pair, their sum is 180°.8x – 3 + 4x + 3 = 18012x + 0 = 18012x = 180Hint: Divide both sides ofthe equation by 12 to solve x = [?]for the final value of x.-

The result of the given terms is -2/5 as per the given question from complex numbers.

There is a multiplicative inverse for every nonzero complex number. As a result, complex numbers are a field with real numbers as a subfield. The complex numbers also form a two-dimensional real vector space with 1, I as the standard basis.

Because of this standard basis, the complex numbers form a Cartesian plane known as the complex plane. This allows for a geometric interpretation of complex numbers and operations, as well as the expression of geometric features and constructions in terms of complex numbers. Real numbers, for example, constitute the real line, which corresponds to the complex plane's horizontal axis.

=(((3/5)+(1/5)i)+((4/5)-(2/5)i) -((9/5)-(1/5)i))

=((3/5)+(4/5)-(9/5))-i((1/5)+i((1/5)-(2/5)+(1/5))

=(-2/5)+i(0)

= -2/5

Therefore, the result of the given terms is -2/5

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Answer:

x = - 1

Step-by-step explanation:

P = \(\frac{x-2}{x+1}\)

the denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that x cannot be.

x + 1 = 0 ( subtract 1 from both sides )

x = - 1

P is undefined when x = - 1

Answer:

$462.5

Step-by-step explanation:

Given the cost function expressed as;

C = 37000/100−p

To get C(20), we will substitute p = 20 into the expression and get C as shown;

C(20) = 37000/100-20

C(20) = 37000/80

C(20) = 462.5

Hence the cost needed to clean 20% of the stream is $462.5

Answer:

7:01

29%

Doyan of low

Shiman 1-R-1

Flous 1-1 Gambe 1-4-20

12 dual purpose

Martins 1-2-3 Flores 1-2, 1-3, 14

Gamba 2-1-5

Custand 1-4, 2-1

Conditions " humanitarian groups Salahiel 1-1-1, 1-1-2, 1-2-3 1-R-5, 2-L-2, 2-L-3, 2-14, 2-1-5, 2-RI

Flores 1-30

Munting 1-2-4

Gumbon 1-1-3 CDP 1-1-3

Status oppose ending 742 Montoya 1-1, 1-2, 1-3

federal courts challenge

Gamboa 1-R-2 Custom 1-7

CDP 1-L-36, 1-2-4

de Vogue 1-2-1, 2-1-5, 2-L-6

7 expulsions at boders

root causes textul Amer.

Cop 1-L-34, 1-1-2, 1-R-4

Border Report 1-2

CDP 1-R-2, 1-R-3 Montoya 1-8

Custarda 2-2

=

CLOSE

Hopes this helps :)

Answer:

x = 6  and y = 3

Step-by-step explanation:

A parallelogram is a quadrilateral (has four sides) in which opposite sides are parallel to each other. Also for a parallelogram, the opposite sides and angles are equal to each other.

Hence for parallelogram with vertices at A(1, 2), B(4,y), C(x, 6) and D(3, 5)

Let O be the midpoint of the diagonal AC and O be the midpoint of diagonal BD, hence:

For AC:

x coordinate of O = (x + 1) / 2  

y coordinate of O = (6 + 2) / 2  = 8/2 = 4

The coordinate of O is [(x + 1)/2, 4]

For BD:

x coordinate of O = (3 + 4) / 2  = 7/2

y coordinate of O = (y + 5) / 2

The coordinate of O is [7/2, (y + 5) / 2 ]

Therefore: [(x + 1)/2, 4] = [7/2, (y + 5) / 2 ]

(x + 1)/2 = 7/2        and       (y + 5) / 2 = 4

x + 1 = 7,          and         y + 5 = 8

x = 7 - 1         and y = 8 - 5

x = 6  and y = 3

Answer:

17/k

Step-by-step explanation:

The algebraic expression is to divide 17 by k

17/k  This can't be simplified because there is a variable in the denominator.

Answer:

C: EAF Is the correct answer

Answer:

d =  C/ 2  −  1/ 6

Step-by-step explanation:

Answer:

7 schools have fewer than 50 classrooms.

Answer:

b,c

Step-by-step explanation:

b is written  in the written form properly and  is is extended using the right place values

Answer:

she is charged 80 in interest for 4 years, the total she has to pay back is 480

Step-by-step explanation:

The missing dimensions from the given expression should be completed with the following:

(81.) A) 2

(82.) AD) x

(83.) E) 12

The expression as a product should be written as: DE) 2(x + 12).

In Mathematics and Geometry, a factored form can be defined as a type of quadratic expression that is typically written as the product of two (2) linear factors and a constant.

In this scenario and exercise, we would complete the table above by showing the factored form and expanded form of each of the given expressions as follows;

        x           12

2      2x         24

Note: 2x/2 = x.

         24/2 = 12.

(2x + 24) = 2(x + 12).

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Answer:

D

Step-by-step explanation:

Just apply the rules for exponents. I hope it helps.

Answer:

(5,1) (4,2) (1,3)

Step-by-step explanation:

since is going a clockwise rotation the -x(5,4,1) all will become positive

\(11.3 > \frac{b}{4.3} \\ = >11.3 \times 4.3 > b \\ = > 48.59 > b\)

Answer:

b < 48.59

Hope you could understand .

If you have any query, feel free to ask and sorry for my previous answer.

Answer:

12

Step-by-step explanation:

You simply add the coefficients together.
3 + 4 + 5 = 12

Answer:

Step-by-step explanation:

H-23=53

H=76

Answer:

H - 23 = 53

+23. +23

H = 76

Step-by-step explanation:

Add 23 to both sides with that h = 76

The tangent are tangent 7 value of X is 15.

The value of X, we need to use the fact that segments that appear to be tangent are actually tangent. This means that the line that contains segment AB is tangent to the circle at point C, and the line that contains segment DC is tangent to the circle at point E.
We can use the properties of tangent lines and the circle to find the value of X. First, we know that the tangent to a circle at any point is perpendicular to the radius that passes through that point. This means that angle ACB is a right angle, and angle CED is a right angle as well.
Next, we can use the fact that angles in a circle that intercept the same arc are congruent. Since arc AB and arc DE are congruent (they are both half of the circle), angles ABD and EDC are also congruent

We know that angle ABD is equal to 3X, and angle EDC is equal to 7X - 60
\(3X = 7X - 60\)
Subtracting 3X from both sides gives:
\(-4X = -60\)
Dividing both sides by -4 gives:
\(X = 15\)

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They each pay $11.20

Answer:

Wind

Hydroelectric Power

Solar

Geothermal

Answer:

A.2) \(q->p\)

B.2) \(-p\)

C.1) It is Wednesday and there are not students in the library.

Step-by-step explanation:

Hope this helped!

brainliest please!

It is WEDNESDAY and there are NOT students in the library.

So your're right! Good Job..!

ANSWER

83.1

EXPLANATION

We have the number 83.105

First, we have to locate the number that is after the tenth place value.

The number in the tenth place value is 1.

The number after the tenth place value is 0.

When rounding:

=> if the number after the needed place value is greater than 4, we add one to the place value we need.

=> if the number after the needed place value is less than or equal to 4, we round down to 0.

So, since the number after the tenth place value is less than 4 (0), we will add nothing to the number and the new number is:

83.1

The number has been rounded to the nearest tenth.

a) The angles outside the side PQ measure 65° and 25°

The angles outside the side QR measure 85° and 95°

The angles outside the side PR measure 55° and 35°

b) The arc PR, PQ and PR measure 120°

a)

Let us assume that the inscribed square be ABCD and equilateral triangle is PQR.

Let side PR of triangle intersects the quadrilateral at points M and N.

So, we get a triangle DMN outside the equilateral triangle.

Here, ∠DMN = 55°, ∠D = 90°

So, ∠MND = 180 - (90 + 55)

                 = 35°

Similarly,  side PQ of triangle PQR intersects the quadrilateral at points X and Y.

So, we get a triangle AXY outside the equilateral triangle.

From triangle PXM we get the measure of angle PXM which is 65 degrees.

As angle PXM and angle AXY are opposite angles, the measure of angle AXY = 65°

∠A = 90°

So, ∠AYX = 180° - (∠A + ∠AXY )

                 = 180° - (90° + 65°)

                 = 25°

Let the side QR of triangle PQR intersects the quadrilateral at points L and K.

so we get new quadrilateral LKBC

In this quadrilateral ∠B = 90°, ∠C = 90°

From triangle QYL, we get the measure of angle QLY = 95°

So, the measure of ∠KLB = 95° .......(∠QLY and ∠KLB opposite angles)

So, the remaining angle LKC of quadrilateral LKBC would be,

∠LKC = 360° - (∠B + ∠C + ∠KLB)

∠LKC = 360° - (90 °+ 90° + 95°)

∠LKC = 85°

b)

We know that he angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.

so, the measure of arc PR = 120°

the measure of arc PQ = 120°

the measure of arc RQ = 120°

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Answer:

3

Step-by-step explanation:

Well the square root of 12 is 3.464 and 12 squared is 144, and an intiger is a whole number no decimal or fraction. So round 3.464 to the nearest whole is 3. Hope this helps(:

Answer:

The equation g² + 42 = 0 has two real solutions.

To solve this equation, we can start by subtracting 42 from both sides to get g² = -42. Then, we can take the square root of both sides to get |g| = √42. Since the square root of a number is positive, this means that g = √42 or g = -√42. These are the two solutions to the equation.

Answer:

$29,000

Step-by-step explanation:

To calculate the cost of merchandise sold, you can use the following formula:

Cost of Merchandise Sold = Sales - (Beginning Inventory + Purchases - Purchase Discounts - Ending Inventory)

Plugging in the values from the data provided, the cost of merchandise sold would be:

Cost of Merchandise Sold = $50,000 - ($6,000 + $20,000 - $1,000 - $4,000)

Cost of Merchandise Sold = $50,000 - $21,000

Cost of Merchandise Sold = $29,000

So, the cost of merchandise sold would be $29,000.

Answer:

B

Step-by-step explanation:

Standard deviation is the average distance away from the mean, thus B is correct

Using z-scores, it is found that due to the higher z-score, Bryant had the better performance.

In a normal distribution with mean \(\mu\) and standard deviation \(\sigma\), the z-score of a measure X is given by:

\(Z = \frac{X - \mu}{\sigma}\)

For Maravich, we have that the parameters are \(X = 2273, \mu = 1198, \sigma = 379\), hence:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{2273 - 1198}{379}\)

Z = 2.84.

For Bryant, we have that the parameters are \(X = 2832, \mu = 1123, \sigma = 433\), hence:

\(Z = \frac{X - \mu}{\sigma}\)

\(Z = \frac{2832 - 1123}{433}\)

Z = 3.95.

Due to the higher z-score, Bryant had the better performance.

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Therefore , the solution of the given problem of expressions comes out to be  potential energy at 550 metres of altitude is roughly 2,798.46 Joules.

Instead of producing estimates at random, it is preferable to use expanding, decreasing, & blocking moving numbers. They were only able to assist one another by exchanging resources, knowledge, or answers to problems. In addition to arithmetic operations like addition, negation, synthesis, and combination, a truth statement may also contain formulas, components, and notations. It is feasible to evaluate and analyse both sentences as words.

Here,

The gravitational potential energy of the bird at a height of 550m can be determined using the following formula, assuming you meant to say "0.52 kg bird" instead of "0.52k bird":

Mass times gravity times height equals gravitational potential energy.

where mass is measured in kilogrammes, gravity is the force of gravity, which accelerates objects near the Earth's surface at a rate of around 9.81 m/s2, and height is measured in metres.

Inputting the values provided yields:

The gravitational potential energy is equal to

=> 0.52 kg * 9.81 m/s2 *550 m,

=> 2,798.46 joules.

Hence, the bird's gravitational potential energy at 550 metres of altitude is roughly 2,798.46 Joules.

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