Solve the math problem

Answer:

Step-by-step explanation:

The combined standard deviation of workers' wages in the firm is  7.484 (approximately).

The information about male worker's wage in a firm are as follows,

Mean wage, \(x_{1}\) = 63 ; Standard deviation of wages, \(SD_{1}\) = 6 ; Number of workers, \(n_{1}\) = 50

The information about female worker's wage in a firm are as follows,

Mean wage, \(x_{2}\) = 54 ; Standard deviation of wages, \(SD_{2}\) = 6 ; Number of workers, \(n_{2}\) = 40

The combined mean of all the male and female workers can be calculated with the formula,

Combined mean, \(x_{12}\) = {\(n_{1}x_{1} + n_{2}x_{2}\)} / (\(n_{1} + n_{2}\))

= { 50*63 + 40*54 }/ (50+ 40)

= 5310/90

= 59

The combined standard deviation of all the male and female workers can be calculated with the formula,

Combined standard deviation, \(SD _{12}\) = √ \([\frac{n_{1}(SD_{1}^{2} + d_{1}^{2}) + n_{2}(SD_{2}^{2} + d_{2}^{2}) }{n_{1}+ n_{2}} ]\)

where, \(d_{1} = x_{12} - x_{1}\) = (59 - 63) = -4 and \(d_{2} = x_{12} - x_{2}\) = (59- 54) = 5

\(SD _{12}\) = √ [ \([\frac{50(6^{2} + (-4)^{2}) + 40(6^{2} + 5^{2}) }{50+ 40} ]\)

= √56 = 7.484 (approximately)

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Answer:

8x+11=5x+2

8x-5x=2-11

3x=-9

÷by 3 both sides

x=-3

The probability that at least one of the four Indiana adults selected is a gun owner is approximately 0.52.

To find the probability that at least one of the four Indiana adults selected is a gun owner, you can use the complementary probability principle, which states that the probability of an event occurring is equal to 1 minus the probability of the event not occurring.

In this case, the probability that none of the four Indiana adults selected is a gun owner is \((1 - 0.338)^4 = 0.48\) Therefore, the probability that at least one of the four Indiana adults selected is a gun owner is 1 - 0.48 = 0.52.

Therefore, the probability that at least one of the four Indiana adults selected is a gun owner is approximately 0.52.

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The equation of the function graphed is y = asec(bx) + c or y = acsc(bx) + c, where a ≠ 0 and b > 0.

The given function graphed can be of two forms: y = asec(bx) + c or y = acsc(bx) + c. In both forms, a represents a non-zero constant, and b represents a positive constant. The term "sec" represents the secant function, which is the reciprocal of the cosine function, and "csc" represents the cosecant function, which is the reciprocal of the sine function.

In the first form, y = asec(bx) + c, the graph will have vertical asymptotes at x-values where sec(bx) = ±∞, which occur when the cosine function is zero. The graph will have a vertical shift of c units, determined by the constant c.

In the second form, y = acsc(bx) + c, the graph will have vertical asymptotes at x-values where csc(bx) = ±∞, which occur when the sine function is zero. Again, the graph will have a vertical shift of c units.

The equation provided is a general representation of the given graph, and the specific values of a, b, and c need to be determined based on the graph's characteristics and points.

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Answer:

slope = - 3

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (- 6, 6) and (x₂, y₂ ) = (- 3, - 3)

m = \(\frac{-3-6}{-3-(-6)}\) = \(\frac{-9}{-3+6}\) = \(\frac{-9}{3}\) = - 3

If f(x, y, z) = xyzi + yj + zk, the divergence of the curl of the vector field f is zero.

To find the divergence of the curl of the vector field f(x,y,z) = xyzi + yj + zk, we first need to compute the curl of f, which is given by:

curl f = (∇ × f) = ∂(zk)/∂y - ∂(yj)/∂z + (∂(yj)/∂x - ∂(xyzi)/∂y)k + (∂(xyzi)/∂z - ∂(zk)/∂x)j + (∂(zk)/∂x - ∂(yj)/∂y) i

Simplifying this expression, we get:

curl f = (-z)i + xj + yk

Next, we need to find the divergence of the curl of f, which is given by:

div(curl f) = ∇ · (∇ × f) = ∂(∂(zk)/∂y - ∂(yj)/∂z)/∂x + ∂(∂(yj)/∂x - ∂(xyzi)/∂y)/∂y + ∂(∂(xyzi)/∂z - ∂(zk)/∂x)/∂z

Substituting the values from the curl f expression, we get:

div(curl f) = ∂(-z)/∂x + ∂(x)/∂y + ∂(y)/∂z

Simplifying this expression, we get:

div(curl f) = 0

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Answer:

Factors of 65: 1, 5, 13, and 65.

Prime Factorization of 65: 65 = 5 × 13.

Step-by-step explanation:

hope this helps!

Answer:

1, 5, 13, and 65.

Step-by-step explanation:

Answer:

140 is the amount  of money for the tip

Step-by-step explanation:

Answer:

$140

Step-by-step explanation:

20=0.2

700×0.2=140

I mean like that is a big tip for a person.

plzz mark it brainliest, need it to level up

The solution to the associated homogeneous system is vector \(x=\left[\begin{array}{ccc}y+5z\\y\\z\end{array}\right]\) where y and z can take any real values.

To find the row-reduced echelon form (RREF) of the given system:

\(x-y-5z=1\\-2-y-z=1\\y+3z=-1\)

Step 1: Use row operations to eliminate the x term in the second equation:

Multiply the first equation by 2 and add it to the second equation:

\(x-y-5z=1\\0x-3y-9z=3\\y+3z=-1\)

Step 2: Use row operations to eliminate the y term in the third equation:

Multiply the second equation by -1/3 and add it to the third equation:

\(x-5y-z=1\\0x-3y-9z=3\\0x+0y+0z=0\)

Step 3: Simplify the equations:

\(x-5y-z=1\\0=0\\0=0\)

Now, let's solve the associated homogeneous system AX=0 using the RREF:

x - 5y - z = 1

0 = 0

0 = 0

Step 2: Solve for the variables:

From the RREF, we can see that we have two free variables (y and z). We can express the solutions in terms of these variables:

x = 5 + yz

y = y

z = z

Therefore, the solution to the associated homogeneous system is vector,

\(x=\left[\begin{array}{ccc}y+5z\\y\\z\end{array}\right]\), where y and z can take any real values.

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The probability that there will be two long-furred dogs and three long-furred cats will be 0.2728.

Number of animals = 30

Number of dogs with long fur = 12/15 = 0.8

Number of cats with long fur = 11/15 = 0.73

The probability that there will be two long-furred dogs and three long-furred cats will be:

= (0.8)³ × (0.73)²

= 0.512 × 0.5339

= 0.2728

Therefore, the probability that there will be two long-furred dogs and three long-furred cats will be 0.2728.

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The paintball will hit the disc after around 2.16 seconds.

To find the time it takes for the paintball to hit the disc, we need to find the common value of t when the height of the disc and the path of the paintball are equal.

Setting the two functions equal to each other, we get:\(5t^2 - (149/5)t + 1 = 0\).

Rearranging the equation, we have:\(5t^2 - (149/5)t + 1 = 0\).

This is a quadratic equation. By solving it using the quadratic formula, we find that t ≈ 2.16 seconds.

Therefore, it will take approximately 2.16 seconds for the paintball to hit the disc.

In conclusion, the paintball will hit the disc after around 2.16 seconds.

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To solve the matrix equation X = [1 -1 2; -14 -2 0; 4 0 1; 9 -5 11], where X is a 4 x 3 matrix, we can utilize the given structure of the matrix equation. By equating the corresponding elements of the matrices on both sides, we can find the values of the matrix X.

The given matrix equation X = [1 -1 2; -14 -2 0; 4 0 1; 9 -5 11] implies that the matrix X has four rows and three columns. To solve this equation, we can write the matrix X as a block matrix:

X = [k₁ 0 0 0; 0 k₂ 0 0; 0 0 k₃ 0; 0 0 0 k₄]

By equating the corresponding elements of X and the given matrix on the right-hand side, we can solve for the values of k₁, k₂, k₃, and k₄. Comparing the first row, we have:

k₁ = 1, 0 = -1, and 0 = 2

These equations do not hold true, indicating that there is no solution for the matrix equation. Therefore, the system of equations is inconsistent, and we cannot find a matrix X that satisfies the given equation.

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The propositions among the given options are: \( \exists x P(x) \) and \( (\exists x S(x)) \vee R(x) \). A proposition is a declarative statement that can be either true or false.

In the first option, \( \exists x(S(x) \vee R(x)) \), the statement is not a proposition because it contains a quantifier (\( \exists \)) without specifying the domain of discourse. This makes it unclear whether the statement is true or false.

The second option, \( \exists x P(x) \), is a proposition. It states that there exists an \( x \) for which \( P(x) \) is true. This statement can be evaluated as either true or false, depending on the specific meaning and truth value of \( P(x) \).

The third option, \( P(x) \vee(\forall x Q(x)) \), is not a proposition because it contains a mixture of a universal quantifier (\( \forall \)) and an existential quantifier (\( \exists \)) without a clear domain of discourse.

The fourth option, \( (\exists x S(x)) \vee R(x) \), is a proposition. It states that either there exists an \( x \) such that \( S(x) \) is true, or \( R(x) \) is true. This statement can be evaluated as either true or false, depending on the specific meanings and truth values of \( S(x) \) and \( R(x) \).

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the equation s=700+0.07c models between his weekly sales in dollars and the amount of his sales in dollars. pastels salary in dollars for a week when his sales were 0$ is $700.

Pastels weekly salary includes base pay plus commission of his sales.

the equation s=700+0.07c models between his weekly sales in dollars and the amount of his sales in dollars.

find pastels salary in dollars for a week when his sales were 0$

the model is given as

s=700+0.07c

let us solve for c, the sales made

s =700 +0.07c given sales is 0$

then s=700

Hence , the equation s=700+0.07c models between his weekly sales in dollars and the amount of his sales in dollars. pastels salary in dollars for a week when his sales were 0$ is $700.

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Answer:

here you go

Step-by-step explanation:

The storm rainfall flux is 0.00127 m2/hr, 1.27 kg liquid water/m2hr, 2.8 lb liquid water/m2hr, 1.27 liters liquid water/m2hr, and 0.335 gallons liquid water/m2hr. The amount of liquid water fell on the garden is 80.6 L, 21.3 gallons.

Dimensions of outdoor vegetable garden = 2 m × 2 m

Storm rainfall = 0.8 inches of rain

Time of storm = 1 hr(

a) The rainfall flux is the amount of rainfall per unit area and unit time. It is given as:

Rainfall flux = (Amount of rainfall) / (Area × Time)

Given the area of the garden is 2 m × 2 m, and the time is 1 hr, the rainfall flux is:

Rainfall flux = (0.8 inches of rain) / (2 m × 2 m × 1 hr)

Converting inches to meters, we get:

1 inch = 0.0254 m

Therefore,

Rainfall flux = (0.8 × 0.0254 m) / (2 m × 2 m × 1 hr) = 0.00127 m/hr

Converting the rainfall flux to other units:

In kg/hr:

1 kg of water = 1000 g of water

Density of water = 1000 kg/m3

So, 1 m3 of water = 1000 kg of water

So, 1 m2 of water of depth 1 m = 1000 kg of water

Therefore, 1 m2 of water of depth 1 mm = 1 kg of water

Therefore, the rainfall flux in kg/hr = (0.00127 m/hr) × (1000 kg/m3) = 1.27 kg/m2hr

In lbs/hr:

1 lb of water = 453.592 g of water

So, the rainfall flux in lbs/hr = (0.00127 m/hr) × (1000 kg/m3) × (2.20462 lb/kg) = 2.8 lbs/m2hr

In liters/hr:

1 m3 of water = 1000 L of water

So, 1 m2 of water of depth 1 mm = 1 L of water

Therefore, the rainfall flux in L/hr = (0.00127 m/hr) × (1000 L/m3) = 1.27 L/m2hr

In gallons/hr:

1 gallon = 3.78541 L

So, the rainfall flux in gallons/hr = (0.00127 m/hr) × (1000 L/m3) × (1 gallon/3.78541 L) = 0.335 gallons/m2hr

(b) To calculate the amount of water that fell on the garden, we need to calculate the volume of water.

Volume = Area × Depth.

The area of the garden is 2 m × 2 m.

We need to convert the rainfall amount to meters.

1 inch = 0.0254 m

Therefore, 0.8 inches of rain = 0.8 × 0.0254 m = 0.02032 m

Volume of water = Area × Depth = (2 m × 2 m) × 0.02032 m = 0.0806 m3

Converting the volume to other units:

In liters:

1 m3 of water = 1000 L of water

Therefore, the volume of water in liters = 0.0806 m3 × 1000 L/m3 = 80.6 L

In gallons:

1 gallon = 3.78541 L

Therefore, the volume of water in gallons = 80.6 L / 3.78541 L/gallon = 21.3 gallons.

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Answer:

28cm^2

Step-by-step explanation:

The area of a trapezoid is the bases added divided by two times the height.

(9+5)/2*4=7*4=28

28cm^2

Answer:

I will change my awnser when you tell me but what are the awnser choices

Step-by-step explanation:

The graph which represents the function y = 2x - 4​ is shown below.

Function is a type of relation, or rule, that maps one input to specific single output.

In mathematics, a function is an expression, rule, or law that describes the relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable). In mathematics and the physical sciences, functions are indispensable for formulating physical relationships.

Linear function is a function whose graph is a straight line

We are given that;

y = 2x - 4​

Now,

To find four points of y = 2x - 4, we can choose any four values of x and plug them into the equation to find the corresponding values of y. For example, if we choose x = -2, 0, 1, and 2, we get:

When x = -2, y = 2(-2) - 4 = -8 - 4 = -12. So (-2,-12) is a point on the line.

When x = 0, y = 2(0) - 4 = 0 - 4 = -4. So (0,-4) is a point on the line.

When x = 1, y = 2(1) - 4 = 2 - 4 = -2. So (1,-2) is a point on the line.

When x = 2, y = 2(2) - 4 = 4 - 4 = 0. So (2,0) is a point on the line.

Therefore, by the given function answer will be shown below.

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2 will be the output of the following code snippet.

What is a snippet in coding?

What does a code snippet look like?

The output will be 2 because when two integers are divided in Java, the decimal portion is always truncated.

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The complete question is -

The following snippet of code would produce what outcome? public static void main(String 2 [] args) { int day = 5; switch (day) { case 1: System.out.println("Monday "); case 2: System.out.println("Tuesday "); case 3: System.out.println("Wednesday "); case 4: System.out.println("Thursday "); case 5: System.out.println("Friday "); case 6: System.out.println("Saturday "); case 7: System.out.println("Sunday "); break; default: System.out.println("Invalid Day "); } } Invalid Day Friday Saturday Sunday Invalid Day Friday Friday Saturday Sunday What will be the output of the following code: int x = 20; int y = 40; if (x > 10) { if (y > 50) { System.out.println("Hello, Friend."); } else { System.out.println("Goodbye, Friend."); } } else { if (y > 50) { System.out.println("Hello, Enemy:"); } else { System.out.println("Goodbye, Enemy."); } } Hello, Friend. Hello, Enemy. Goodbye, Friend. Goodbye, Enemy.

Answer:

x = 12.81

Step-by-step explanation:

Because this is a right triangle, we can use the Pythagorean Theorem to solve for x. We have 10² + 8² = x² → 100 + 64 → x² = 164 → x = 12.81. Hope this helps!

Step-by-step explanation:

using Pythagoras relationship

\( {x}^{2} = {10}^{2} + {8}^{2} \\ {x}^{2} = 100 + 64 \\ {x}^{2} = 164 \\ x = \sqrt{164} \\ x = 12.806 \\ x = 12.8\)

The probability that a family with 4 children has no more than 3 boys is 15/16.

To find the probability that a family with 4 children has no more than 3 boys, we can use the binomial distribution.

The binomial distribution is used to calculate the probability of obtaining a certain number of successes (boys in this case) in a fixed number of trials (children in this case), where each trial has only two possible outcomes (boy or girl) and the trials are independent.

Let X be the number of boys in the family. We want to find P(X ≤ 3), which is the probability of having no more than 3 boys. Since the probability of having a boy is 1/2 and the trials are independent, we can use the binomial distribution formula:

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= (1/2)⁴ + 4(1/2)⁴ + 6(1/2)⁴ + 4(1/2)⁴

= 15/16

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Answer:

Let y=34 and x=3

Step-by-step explanation:

y = 8x + 10

34 = 8 (3) + 10

34 = 24 + 10

34 = 34

Hence,3 and 34 satisfies this equation.

The number of possible sets of heads and tails that have 2 heads is 11.

Given,

There is one coin and it is flipped five times.

First, we have to list out the outcome when we toss the coin five times.

(HHHHH), (HHHHT), (HHHTT), (HHTTT), (HTTTT), (TTTTT), (TTTTH), (TTTHH), (TTHHH), (THHHH), (THTHT), (HTHTH), (THHTT), (THHHT), (HTTTH), (HTTHH), (HTHHH), (THTTT), (TTHTH), (TTTHT), (TTHHT), (HHTHH), (TTHTT), (HHTTH), (HHTHT), (HTHTT), (THTHH), (THTTH), (HTHHT), (HHHTH)

Now, we can list out the possible sets with 2 heads.

(HHTTT), (TTTHH), (THTHT), (HTTHT), (HTTTH), (THHTT), (TTHHT), (TTHTH), (HTHTT), (THTTH), (HTHTT)

So, the number of possible sets of heads and tails that have 2 heads is 11.

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Answer:

Step-by-step explanation:

hello,

let's say that the number we are looking for is n

the sentence means

5n-40=50

hope this helps

Answer:

The question is simply a written version of an equation.

Where it says "a number", let us use the variable x.

5 * x - 40 = 50

5x - 40 = 50

x - 8 = 10

x = 18

I am not sure which of the equations are depicted, but I hope this helps!

Answer:

m= gradient gradient = slope so its -3

The most appropriate choice for profit and loss will be given by

Uncle Ben will feed his cows 2 pounds of grain supplement.

What is profit and loss?

If the selling price is more than the cost price, then the difference between the selling price and the cost price will give the profit.

If the selling price is less than the cost price, then the difference between the selling price and the cost price will give the loss.

Here,

For 1 pound

Cost price of grain supplement  = \(0.70 \times 1\)

                                                      = $\($0.70\)

Selling price of milk = \(0.20 \times 5\)

                                 = $\(1\)

Profit = $(\(1 - 0.70\))

         = $0.30

For 2 pounds

Cost price of grain supplement  = \(0.70 \times 2\)

                                                      = $\($1.40\)

Selling price of milk = \(0.20 \times 9\)

                                 = $\(1.80\)

Profit = $(\(1.80 - 1.40\))

         = $0.40

For 3 pounds

Cost price of grain supplement  = \(0.70 \times 3\)

                                                      = $\($2.10\)

Selling price of milk = \(0.20 \times 12.3\)

                                 = $2.46

Profit = $(\(2.46 - 2.10\))

         = $0.36

For 4 pounds

Cost price of grain supplement  = \(0.70 \times 4\)

                                                      = $\($2.80\)

Selling price of milk = \(0.20 \times 15.5\)

                                 = $3.1

Profit = $(\(3.1 - 2.80\))

         = $0.30

For 5 pounds

Cost price of grain supplement  = \(0.70 \times 5\)

                                                      = $\($3.50\)

Selling price of milk = \(0.20 \times 18\)

                                 = $3.60

Profit = $(\(3.60 - 3.50\))

         = $0.10

For 6 pounds

Cost price of grain supplement  = \(0.70 \times 6\)

                                                      = $\($4.20\)

Selling price of milk = \(0.20 \times 20\)

                                 = $4

Loss = $(\(4.20 - 4\))

         = $0.20

For 7 pounds

Cost price of grain supplement  = \(0.70 \times 7\)

                                                      = $\(4.90\)

Selling price of milk = \(0.20 \times 21.5\)

                                 = $\(4.30\)

Loss = $(\(4.90 - 4.30\))

         = $0.60

For 8 pound

Cost price of grain supplement  = \(0.70 \times 8\)

                                                      = $\($5.60\)

Selling price of milk = \(0.20 \times 22.5\)

                                 = $\(4.50\)

Loss = $(\(5.60 - 4.50\))

         = $1.10

For 9 pounds

Cost price of grain supplement  = \(0.70 * 9\)

                                                      = $\(6.30\)

Selling price of milk = \(0.20 * 23\)

                                 = $\(4.60\)

Loss = $(\(6.30 - 4.60\))

         = $1.70

Since profit from 2 pounds of grain supplement is the most, Uncle Ben will feed his cows 2 pounds of grain supplement.

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Complete Question

Farmer Ben knows that feeding a grain supplement to his cows will produce more milkaccording to the following schedule:

ignoring all other issues, how many pounds of grain supplement should farmer ben feed his cows if the price of milk is $0.20 per pound and the price of grain supplement is $0.70 per pound?

The table has been attached here

a) The percentage of chocolate bars that will have between 446 and 454 grams of chocolate is 68%.

b) The manufacturer will lose money on 2.5% of the chocolate bars.

c) The mass of chocolate bar in the 90th percentile is 462 grams.

a) The mass of chocolate in a chocolate bar is normally distributed with a mean of 450 g and a standard deviation of 2 g. This means that 68% of the chocolate bars will have a mass between 446 g and 454 g.

To calculate the percentage of chocolate bars that will have between 446 g and 454 g, use the following formula:

Percentage = (1 - z²) × 100%

where:

z is the z-score

z = (446 - 450) / 2 = -2

Substituting these values into the formula:

Percentage = (1 - (-2)²) × 100% = 68%

b) The manufacturer will lose money on 2.5% of the chocolate bars. This is because 2.5% of the data in a normal distribution falls more than 1 standard deviation above the mean.

To calculate the percentage of chocolate bars that will have a mass more than 455 g, use the following formula:

Percentage = z × 100%

where:

z = z-score

z = (455 - 450) / 2 = 2.5

Substituting these values into the formula:

Percentage = 2.5 × 100% = 2.5%

c) The mass of chocolate bar in the 90th percentile is 462 g. This is because 90% of the data in a normal distribution falls below 462 g.

To calculate the mass of chocolate bar in the 90th percentile, use the following formula:

z = (1 - 0.9) × 1.645 = 0.725

where:

z = z-score

0.9 = percentile

1.645 = z-score for the 90th percentile

Substituting these values into the formula:

z = 0.725

(450 - 0.725 × 2) = 462 g

Therefore, the mass of chocolate bar in the 90th percentile is 462 g.

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\(\huge\text{Hey there!}\)

\(\huge\text{x + x(x + y) + y}\)

\(\huge\text{= 4 + 4(4 + 1) + 1}\)

\(\huge\text{= 4 + 4(5) + 1}\)

\(\huge\text{= 4 + 20 + 1}\)

\(\huge\text{= 24 + 1}\)

\(\huge\text{= 25}\)

\(\huge\boxed{\textsf{Therefore, your answer is: 25}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

~\(\huge\boxed{\frak{Amphitrite1040:)}}\)

Hi,

we need to substitute 4 and 1 in the equation, so for every y, we replace it with a 1 and every X with 4 as X= 4, Y = 1

equation: X + X (X + Y) + Y

equation after substituting the numbers: 1 + 1 (1 + 4) + 1

Bidmas rules apply.

expand the bracket first. 1 (1 + 4)=

1 X 1= 1

1 X 4= 4

1 + 4 = 5

then the equation becomes: 1 + 5 + 1= 7

your answer is 7 if you want to evaluate it.

your answer is 1 + 1 (1 + 4) + 1 if you need the equation.

, hope that helps :)