Suppose a student graduates from college with a civil engineering degree and is now employed to grade papers, answer the phone, and make copies-tasks that are below the graduate's capabilities. The graduate can best be classified as

Answer: 11

Step-by-step explanation:

Substitute x with 5.

3(5)-4=11

Answer:

11

Step-by-step explanation:

Plug in 5 for x to get the following expression:

3(5) - 4

Then just solve:

15 - 4

11

To obtain a Maclaurin series for the given function f(x) = sin x, we can use the known Maclaurin series for sin x, which is:
sin x = x - (x^3)/3! + (x^5)/5! - (x^7)/7! + ...

Multiplying this series by x^3 gives:
sin x 3 = x^3 - (x^6)/3! + (x^8)/5! - (x^10)/7! + ...
Therefore, the Maclaurin series for f(x) = sin x 3 is:
f(x) = x^3 - (x^6)/3! + (x^8)/5! - (x^10)/7! + ...
To find the associated radius of convergence r, we can use the ratio test. The nth term of the series is given by:
a_n = (-1)^(n-1) * (x^3)^(2n-1) / (2n-1)!
Using the ratio test, we have:
lim |a_(n+1) / a_n| = lim |(-1)^n+1 * (x^3)^(2n+1) / (2n+1)!| / |(-1)^n * (x^3)^(2n-1) / (2n-1)!|
= lim |(-1) * x^6 / ((2n+1)(2n))| = 0
Since the limit is less than 1 for all values of x, the series converges for all x. Therefore, the radius of convergence is infinity, which is consistent with the fact that sin x has an infinite radius of convergence.

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Answer:

aₙ= 3n+1

Step-by-step explanation:

4 ,1 -2, -5 ,-8

AP with a₁=4 and d= -3

----------------

aₙ= 4+3*(n-1)= 4+3n-3= 3n+1

aₙ= 3n+1

Triangle A'B'C' is the result of dilating Triangle ABC using the origin as the center of dilation and a scale factor of 0.5.

Vertex A'= (0, 1)

Vertex B'= (1, 3)

Vertex C'= (2, 1)

What is dilation of triangle?

The definition of a dilation is a transition in which the pre-image and the picture have the same shape but different sizes.

The image formed after the dilation is larger than the pre-image and is referred to as a "Enlargement" when the scale factor is more than 1.

The picture formed after the dilation is smaller than the pre-image and is referred to as a "Reduction" when the scale factor is between 0 and 1.

In this case you know that the triangle ABC was dilated by this scale factor: 0.5

With the origin as the center of dilation.

Since:

0< 0.5< 1

It is a Reduction.

The vertices of the triangle ABC are:

A(0,2), B(26) and C(4,2)

So you need to multiply the coordinates of each vertex  of the triangle ABC by 0.5, in order to get the coordinates of the triangle A'B'C. Then, you get:

A'(0(0.5), 2(0.5))= A'(0, 1)

B'(2(0.5), 6(0.5))= B'(1, 3)

C'(4(0.5), 2(0.5))= C'(2, 1)

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Using the unit circle the degree measure giving  cosθ =  -√3/2, are θ = 150° and θ = 210°

A unit circle is a circle of radius one unit

In a unit circle, we have that

Now, using a unit circle, we desire to find what are the degree measures of all angles with the given cosine = -√3/2. We proceeed as follows.

Since cosθ =  -√3/2, we know that cosine is negative in the second and theird quadrant.

So, we have that

cos(180° - θ) = √3/2 and cos(180° + θ) = √3/2

Taking inverse cosine of both sides, we have that

cos(180° - θ) =  √3/2 and cos(180° + θ) =  √3/2

180° - θ =  cos(√3/2) and 180° + θ) =  cos(√3/2)

180° - θ = 30°  and 180° + θ = 30°

θ = 180° - 30° and θ = -180° + 30°

θ = 150° and θ = -150°

θ = 150° and θ = -150° + 360°

θ = 150° and θ = 210°

So, the degree measure are θ = 150° and θ = 210°

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Answer:

150° and 210°

Step-by-step explanation:

The unit circle is a circle with a radius of 1 unit, centered at the origin (0,0) in a coordinate plane. In the unit circle, the cosine of an angle is represented by the x-coordinate of the point on the circle corresponding to that angle.

To determine the degree measures of angles with a cosine of -√3/2, we can refer to the unit circle and identify the angles where the x-coordinate (cosine) is equal to -√3/2.

In the unit circle, there are two such points where the x-coordinate is equal to -√3/2:

\(\left(-\dfrac{\sqrt{3}}{2},\dfrac{1}{2}\right)\;\; \textsf{and}\;\;\left(-\dfrac{\sqrt{3}}{2},-\dfrac{1}{2}\right)\)

These points correspond to angles 150° and 210°.

Answer:

6 students have a cellphone and data to search for the author’s name.

That is less than 1/3 of the entire class.

Step-by-step explanation:

30 total students. Half is 15. 40% of 15 is 6. One third of 30 is 10. Which is more than 6.

Answer:

No- se p-ero quiero pun-tos

Step-by-step explanation:

por -favor :D

The greatest common factor of 14c³, 70c⁴, and 28c² is 14c².

To find the greatest common factor (GCF) of 14c³, 70c⁴, and 28c², we need to determine the highest power of c that divides each term and the highest common factor of the numerical coefficients.

Let's analyze the powers of c in each term:

14c³ = 2 * 7 * c * c * c

70c⁴ = 2 * 5 * 7 * c * c * c * c

28c² = 2 * 2 * 7 * c * c

To find the GCF of the powers of c, we take the minimum power of c that appears in all terms, which is c².

Now let's consider the numerical coefficients:

The GCF of 14, 70, and 28 is 14.

Combining the GCF of the powers of c (c²) with the GCF of the numerical coefficients (14), we get the GCF of the given terms:

GCF(14c³, 70c⁴, 28c²) = 14 * c²

Therefore, the greatest common factor of 14c³, 70c⁴, and 28c² is 14c².

The question is:

What is the greatest common factor of 14c³, 70c⁴, and 28c²?

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Answer:

3x+8=2x-5

3x+8-8=2x-5-8

x= -13

The 99% confidence interval for the mean amount of money this bank's customers keep in their checking accounts is approximately $766 ± $19.33, or between $746.67 and $785.33.

To calculate the 99% confidence interval for the mean amount of money this bank's customers keep in their checking accounts, we can use the formula:

Confidence interval = mean ± (critical value) * (standard deviation / √sample size)

First, we need to find the critical value for a 99% confidence level. Since the sample size is large (n > 30), we can assume the sampling distribution is approximately normal and use the Z-distribution.

The critical value for a 99% confidence level is approximately 2.576.

Next, we can substitute the values into the formula:

Confidence interval = $766 ± (2.576) * ($85 / √128)

Calculating the expression inside the parentheses:

$85 / √128 ≈ $7.51

Now, we can substitute this value into the formula:

Confidence interval = $766 ± (2.576) * ($7.51)

Calculating the expression inside the parentheses:

(2.576) * ($7.51) ≈ $19.33

Therefore, the 99% confidence interval for the mean amount of money this bank's customers keep in their checking accounts is approximately $766 ± $19.33, or between $746.67 and $785.33.

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Answer:

Step-by-step explanation:

Dont do it. Just take the detention

Using trigonometric identities, it is found that the exact value of the secant of the angle is given by:

c. \(\sec{\theta} = - \sqrt{5}\)

According to the following identity:

\(\sec^2{\theta} = 1 + \tan^2{\theta}\)

The tangent is the inverse of the cotangent, hence in this problem, we have that:

\(\tan{\theta} = -2\)

Then, the secant is given as follows:

\(\sec^2{\theta} = 1 + (-2)^2\)

\(\sec^2{\theta} = 5\)

\(\sec{\theta} = \pm \sqrt{5}\)

The angle is in the second quadrant, where the cosine is negative, hence the secant also is and option c is correct, that is:

c. \(\sec{\theta} = - \sqrt{5}\)

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Answer:

the mean is $80

Step-by-step explanation:

Answer:

Third option is the correct answer

\(y = -(2)x+ 3\)

Step-by-step explanation:

Given functions are:

\(y=3(2)x\\ y = 3(3)x\\ y = -(2)x+ 3\\ y = (2)x-3\)

To find:

The function which has a range \(y <3\) ?

Solution:

First of all, let us learn about the terms Domain and Range for a function:

\(y = f(x)\)

Domain is the value of \(x\) which is given as input to the function and gives a valid value of output as \(y\) (i.e. function is defined).

Range of a function is the value \(y\) that comes as output when given a valid value of \(x\) as input.

Now, let us consider the given options above.

Third option is the correct answer.

\(y = -(2)x+ 3\)

As we can see, \((2)x\) is subtracted from 3 so \(y\) will have a value which is lesser than 3.

i.e. range will be \(y <3\).

No other function has such condition present in it.

\(y = -(2)x+ 3\) is the correct answer.

Answer:

slope = - 7, y- intercept = (0, 5 )

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 7x + 5 ← is in slope- intercept form

with slope m = - 7 and y- intercept c = 5 ⇒ (0, 5 )

Answer:

1- GIK

2- DG

3- obtuse

4- complement 160° , supplement 70°

Step-by-step explanation:

question 1 : GIK are Collinear point cause they are on the same line

question 2 : DG is the parallel segment to CF cause the segment CD is parallel to the segment FG

question 3 : the angle A is obtuse cause it's 93° the obtuse angle is between 90° and 180°

question 4 : the complement is the add of 2 angle that equal 180°

the supplement is the add of 2 angle that equal 90°

complement 160° + 20° = 180°

supplement 70°+ 20° = 90°

The lines given do not intersect, therefore, there is no point of intersection, and the plane determined by these lines is degenerate.

The given lines are:

Line 1: z = 2t + 8

Line 2: -8

To find the point of intersection, we need to set the equations of the lines equal to each other:

2t + 8 = -8

Solving for t:

2t = -16

t = -8

Now, we can substitute the value of t back into either equation to find the corresponding values of x, y, and z. Let's use Line 1:

z = 2t + 8

z = 2(-8) + 8

z = -16 + 8

z = -8

Therefore, the point of intersection of the lines is (-8, -8, -8).

To find the plane determined by these lines, we can use the point of intersection and the direction vectors of the lines.

The direction vector of Line 1 is (0, 0, 2), and the direction vector of Line 2 is (0, 0, 0) (since it is a constant value).

To determine the normal vector of the plane, we can take the cross product of the direction vectors:

n = (0, 0, 2) x (0, 0, 0) = (0, 0, 0)

Since the cross product yields the zero vector, the normal vector of the plane is (0, 0, 0), which means the plane is degenerate. Therefore, the plane determined by these lines is a degenerate plane, meaning it is not a well-defined plane in three-dimensional space.

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The same financial document number range can be assigned to several document types. Financial document number ranges defined at client level should NOT overlap. Financial document number ranges are defined at company code level.

Financial statements are official records of a person, business, or other entity's financial situation and actions. An easy-to-understand style is used to provide pertinent financial data in a systematic manner. Financial papers, usually referred to as financial statements, are used to present financial data about an organization in a consistent way. They come with a cash flow statement, an income statement, and a balance sheet. A balance sheet is a moment in time snapshot of your company's financial health.

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Answer:

y=-4

Step-by-step explanation:

The answer is going to be -4 as when y=-16 x=8.

Answer:

The complete system of inequalities to model this scenario is s ≥ 0, l ≥ 0, 8s + 12l ≤ 160, and s - l < 30.

Step-by-step explanation:

Answer:  8s + 12l ≤ 160.

Step-by-step explanation: I would explain.. but I figured maybe I'd spare you the struggle and give you the answer. If you NEED steps, DM me.

If a distribution of scores is shown in a bar graph, it suggests that the scores were measured on an ordinal scale of measurement.

An ordinal scale is a type of measurement scale that categorizes and orders variables or data points based on their relative ranking or position. In this case, the bar graph represents the frequencies or counts of different categories or ranges of scores, indicating an ordered arrangement of the data. However, the bar graph alone does not provide information about the exact numerical differences between the scores or their precise magnitudes.

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Answer:

can you give me the brainliest please

Step-by-step explanation:

5)x=-5,y=19

6)x=2,y=0

7)x=-1,y=-7

8)x=2,y=-10

9)No solutions

10)No solutions

Answer:

see explanation

Step-by-step explanation:

(5)

y = - 3x + 4 →  (1)

y = - 2x + 9 → (2)

since both equations express y in terms of x , equate the right sides

- 2x + 9 = - 3x + 4 ( add 3x to both sides )

x + 9 = 4 ( subtract 9 from both sides )

x = - 5

substitute x = - 5 into either of the 2 equations

substituting x = - 5 into (1)

y = - 3(- 5) + 4 = 15 + 4 = 19

solution is (- 5, 19 )

(6)

y = 2x - 4 → (1)

y = 3x - 6 → (2)

both equations express y in terms of x , so equate right sides

3x - 6 = 2x - 4 ( subtract 2x from both sides )

x - 6 = - 4 ( add 6 to both sides )

x = 2

substitute x = 2 into either of the 2 equations

substituting x = 2 into (1)

y = 2(2) - 4 = 4 - 4 = 0

solution is (2, 0 )

(7)

y = 3x - 4 → (1)

4x - y = 3 → (2)

substitute y = 3x - 4 into (2)

4x - (3x - 4) = 3

4x - 3x + 4 = 3

x + 4 = 3 ( subtract 4 from both sides )

x = - 1

substitute x = - 1 into (1)

y = 3(- 1) - 4 = - 3 - 4 = - 7

solution is (- 1, - 7 )

(8)

7x - 4y = 54 → (1)

y = - 6x + 2 → (2)

substitute y = - 6x + 2 into (1)

7x - 4(- 6x + 2) = 54

7x + 24x - 8 = 54

31x - 8 = 54 ( add 8 to both sides )

31x = 62 ( divide both sides by 31 )

x = 2

substitute x = 2 into (2)

y = - 6(2) + 2 = - 12 + 2 = - 10

solution is (2, - 10 )

(9)

y = 6x - 5 → (1)

12x - 2y = - 8 → (2)

substitute y = 6x - 5 into (2)

12x - 2(6x - 5) = - 8

12x - 12x + 10 = - 8 ( subtract 10 from both sides )

0 = - 18 ← false statement

this indicates the system has no solution

(10)

24x + 4y = - 8 → (1)

y = - 6x - 2 → (2)

substitute y = - 6x - 2 into (1)

24x + 4(- 6x - 2) = - 8

24x - 24x - 8 = - 8 ( add 8 to both sides )

0 = 0 ← true statement

this indicates the system has an infinite number of solutions

Answer: f(x)=(x-1)^2+2

Step-by-step explanation:

The exponential model that calculates the concentration of bacteria after x weeks can be represented by the equation B(x) = 2.1 million * (3^x), the concentration after 1.6 weeks would be approximately 14.87 million bacteria per milliliter.

This equation assumes that the concentration triples each week, starting from the initial concentration of 2.1 million bacteria per milliliter.

To estimate the concentration after 1.6 weeks, we can substitute x = 1.6 into the exponential model. B(1.6) = 2.1 million * (3^1.6) ≈ 14.87 million bacteria per milliliter. Therefore, after 1.6 weeks, the estimated concentration of bacteria in the river would be approximately 14.87 million bacteria per milliliter.

The exponential model B(x) = 2.1 million * (3^x) represents the concentration of bacteria after x weeks, where the concentration triples each week. By substituting x = 1.6 into the equation, we estimate that the concentration after 1.6 weeks would be approximately 14.87 million bacteria per milliliter.

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well, let's recall that a year has 12 months, so 9 months is really 9/12 of a year

\(~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$1413\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\to \frac{9}{12}\dotfill &\frac{3}{4} \end{cases} \\\\\\ I = (1413)(0.05)(\frac{3}{4}) \implies I = 1413(\frac{3}{80})\implies I\approx 52.99\)

For the first sample {2.038 2.054 2.053 2.055 2.059 2.059 2.009 2.042 2.053 2.047}, the process is still "in order," while for the second sample {2.022 1.997 2.044 2.044 2.032 2.045 2.045 2.047 2.030 2.044}, the process might be "out of order."

To determine whether the process is still "in order" or "out of order," we can compare the current sample of output to the known mean and standard deviation of the process.

For the first sample {2.038 2.054 2.053 2.055 2.059 2.059 2.009 2.042 2.053 2.047}:

Calculate the sample mean by summing up all the values in the sample and dividing by the number of values (n = 10):

Sample mean = (2.038 + 2.054 + 2.053 + 2.055 + 2.059 + 2.059 + 2.009 + 2.042 + 2.053 + 2.047) / 10 = 2.048.

Compare the sample mean to the known process mean (2.050):

The sample mean (2.048) is very close to the process mean (2.050), indicating that the process is still "in order."

Calculate the sample standard deviation using the formula:

Sample standard deviation = sqrt(sum((x - mean)^2) / (n - 1))

Using the formula with the sample values, we find the sample standard deviation to be approximately 0.019 liters.

Compare the sample standard deviation to the known process standard deviation (0.020):

The sample standard deviation (0.019) is very close to the process standard deviation (0.020), further supporting that the process is still "in order."

For the second sample {2.022 1.997 2.044 2.044 2.032 2.045 2.045 2.047 2.030 2.044}:

Calculate the sample mean:

Sample mean = (2.022 + 1.997 + 2.044 + 2.044 + 2.032 + 2.045 + 2.045 + 2.047 + 2.030 + 2.044) / 10 ≈ 2.034

Compare the sample mean to the process mean (2.050):

The sample mean (2.034) is noticeably different from the process mean (2.050), indicating that the process might be "out of order."

Calculate the sample standard deviation:

The sample standard deviation is approximately 0.019 liters.

Compare the sample standard deviation to the process standard deviation (0.020):

The sample standard deviation (0.019) is similar to the process standard deviation (0.020), suggesting that the process is still "in order" in terms of variation.

In summary, for the first sample, the process is still "in order" as both the sample mean and sample standard deviation are close to the known process values.

However, for the second sample, the difference in the sample mean suggests that the process might be "out of order," even though the sample standard deviation remains within an acceptable range.

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Answer:

y = 40             x = 80

Step-by-step explanation:

520 = 3.25x + 6.5y     and   x+y=120

x+y=120

x = 120-y

520 = 3.25(120-y)+6.5y

520 = 390-3.25y+6.5y

520 = 390+3.25y

130=3.25y

40 = y

x = 120-y

x = 120-(40)

x = 80

here's a graph