the galileo spacecraft measured that the moon ganymede had a magnetic field, indicating that its interior was at least partly melted and warm. what do scientists think is the most likely reason for this? a. ganymede is so far away from jupiter, it is an independent world, and can compress its core without interference b. ganymede has thousands of volcanoes, which then send material downward to heat up its interior c. ganymede is a relatively small moon, and therefore much easier to heat up than its neighbor moons d. ganymede is heated by tidal forces from jupiter e. scientists have no idea what causes the inner part of ganymede to be warm; this is an unsolved mystery'

Answer:

Just get searched then go back to class

Explanation: similar situation

Hubble's law expresses a relationship between the distance of a galaxy and the speed at which it is moving away from us.

Hubble’s law is the observation in physical cosmology that the movement of galaxies takes place away from the Earth at speeds that are proportional to their distance. In other words, the farther a galaxy is, the faster it would move away from Earth. Furthermore, the determination of the velocity of the galaxies takes place by their redshift, a shift of the light emitted toward the spectrum’s red end. Experts consider the Hubble’s law as the first observational basis for the expansion of the universe. Currently, it serves as one of the pieces of evidence that experts cite most often in support of the Big Bang model. Furthermore, Hubble’s flow refers to the motion of astronomical objects that take place solely due to this expansion.

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Hubble's Law expresses a relationship between the distance of a galaxy and the speed it's moving away from us. The law states that these two quantities are directly proportional, paving the way for the theory that the universe is expanding.

Hubble's Law, formulated by astronomer Edwin Hubble, expresses a specific relationship between the distance of a galaxy and the speed at which it is moving away from us. The law states that a galaxy's recession velocity (the speed at which it is moving away) is directly proportional to its distance from us. This concept is commonly expressed in the equation v = H × d, where 'v' is the galaxy's velocity, 'H' is Hubble's constant, and 'd' is the distance of the galaxy from us.

The Hubble's constant, estimated to be about 22 km/s per million light-years, is a crucial factor. This means that if a galaxy is 1 million light-years farther away, it will move away 22 km/s faster. Key evidence supporting this law includes the observed redshift of distant galaxies' spectral lines, implying that they are moving away from us.

Finally, it’s important to note that Hubble's Law is the foundation of the assertion that the universe is expanding. Thus, it profoundly impacts our understanding of the origin and evolution of the universe.

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Answer:

D) the preformence of mucles for long periods of time

Answer:

Potential

Explanation:

The water in the bathtub has more potential energy than that in the tea cup because it has a greater number of water molecules.

Mass is a parameter that is very instrumental in determining potential energy.

The potential energy of a body is the energy due to the position of that body.

   Potential energy  = mass x acceleration due gravity x height

Mass is the amount of matter in a substance. Water in the tub will have more mass and contain a greater number of water molecules there in.

Since potential energy is directly proportional to mass, then, it will have a greater amount of potential energy.

1.24% percentage of parts will not meet the weight specs amd the sample means will fall between 25.046 and 25.354 ounces.

a. To determine the percentage of parts that will not meet the weight specifications, we need to calculate the probability of a part weighing less than 24.7 ounces or more than 25.7 ounces. First, we need to calculate the z-scores for these values using the formula:

z = (x - μ) / σ

where x is the value, μ is the mean, and σ is the standard deviation. For 24.7 ounces:

z1 = (24.7 - 25.2) / 0.20 = -2.50

For 25.7 ounces:

z2 = (25.7 - 25.2) / 0.20 = 2.50

Using Table-A (Z-score table), we can find the area under the standard normal curve corresponding to these z-values. From the table, the area to the left of -2.50 is 0.0062, and the area to the right of 2.50 is also 0.0062. Therefore, the total probability of a part not meeting the weight specs is:

P(z < -2.50 or z > 2.50) = P(z < -2.50) + P(z > 2.50) = 0.0062 + 0.0062 = 0.0124

So, the percentage of parts that will not meet the weight specs is .

b. To determine the values within which 99.74% of the sample means will fall, we need to calculate the margin of error for a sample mean. The margin of error is given by the formula:

E = z * (σ / sqrt(n))

where E is the margin of error, z is the z-score corresponding to the desired level of confidence (in this case, 99.74% corresponds to a z-score of 2.75), σ is the standard deviation, and n is the sample size.

Plugging in the values:

E = 2.75 * (0.20 / sqrt(10)) ≈ 0.154

The range of sample means will be within ±E of the population mean. Therefore, the values within which 99.74% of the sample means will fall are:

25.2 ± 0.154 = (25.046, 25.354)

So, for samples of size 10, 99.74% of the sample means will fall between 25.046 and 25.354 ounces.

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Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 8 × 2

We have the final answer as

Hope this helps you

No, because the evidence was offered before a grand jury, not a court is why the indictment can't be squashed.

This is referred to when an individual is accused of a crime. The evidence is usually brought before a grand jury which comprises of grand jurors.

A grand jury votes an indictment if at least 12 grand jurors see enough evidence against the individual which is why it can't be squashed.

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To make 4 amperes flow through a resistance of 20 ohms, 80 volts of voltage are required.

Ohm's law states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. In other words, the greater the voltage, the greater the current that flows through a given resistance.

The voltage required to make 4 amperes flow through a resistance of 20 ohms can be calculated using Ohm's law:

Voltage (V) = Current (I) x Resistance (R)

Therefore, V = 4 A x 20 Ω = 80 V

So, to make 4 amps flow through a resistance of 20 ohms, 80 volts of electricity are required.

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Answer:

Newton's first law of motion

Explanation:

Newton's first law of motion states that an object will continue to remain at rest or move with uniform motion unless it is acted upon by an external force.

This law is known as the law of inertial.

Unless a net force greater than zero acts on a body, it will continue to remain at rest or move uniformly.

This is very correct and has a wide range of application for many mechanics studies. In that we know that an object can only change motion or accelerate by adding external force to act on it.

The voltage across a capacitor with the value c = 5 f is given by the waveform, the waveform for the current in the capacitor for the time interval 0s ≤ t ≤ t2 is 11s.

We need to determine the waveform of the current through the capacitor in the time interval 0s ≤ t ≤ t2, given t2 = 11s. To find out the current through the capacitor, we use the following equation, which is known as the capacitive current equation. i = C (dv/dt), where, i = current through the capacitor,  C = Capacitance of the capacitor,

dv/dt = Rate of change of voltage with respect to time. Let's differentiate the waveform equation of voltage across the capacitor, given in the figure as follows:

dv/dt = 4/3 for 0s ≤ t ≤ 2s
dv/dt = -4/3 for 2s ≤ t ≤ 4s
dv/dt = -4/3 for 4s ≤ t ≤ 7s
dv/dt = 4/3 for 7s ≤ t ≤ 11s

Now substitute these values in the equation of the capacitive current equation as shown below:i = C (dv/dt)

Therefore, for 0s ≤ t ≤ 2s, i = 5 x (4/3) = 20/3 A (charging)
For 2s ≤ t ≤ 4s, i = 5 x (-4/3) = -20/3 A (discharging)
For 4s ≤ t ≤ 7s, i = 5 x (-4/3) = -20/3 A (charging)
For 7s ≤ t ≤ 11s, i = 5 x (4/3) = 20/3 A (discharging).

So therefore, the waveform for the current in the capacitor for the time interval 0s ≤ t ≤ t2 = 11s.

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Answer:

The slope of a distance - time graph is equal to Speed.

Answer:

1.5 A

Explanation:

Applying

V = IR'....................... Equation 1

make I the subject of the equation

I = V/R'.................. Equation 2

Where V = Voltage, I = current, R' = Total resistance.

From the question,

In a series connection,

R' = 0.2+0.3+0.5+5 = 6 ohm.

Given: V = 9V

Substitute into equation 2

I = 9/6

I = 1.5 A.

Note: Since all the resistors are connected in series, thesame current flows through them

Therefore the current flowing through the 5 ohm resistor = 1.5 A

\(2v_{0}\) speed should he have given the ball.

here,

initial speed of the ball is v₀

let the resistive force be f and the distance of the hole be d

when  it cover distance d/4

using work energy theorem

work done grass force = change in kinetic energy

F × d/4 = 0.5 × m × \(v_{0} ^{2}\)

F = 2 ×m×\(\frac{v_{0} ^{2} }{d}\)                                        (1)

for covering the distance d

let the velocity be v

work done grass force = change in kinetic energy

F ×d = 0.5 × m × \(v^{2}\)

putting F from (1)

2 ×m× \(\frac{v^{2} _{0} }{d}\)×d = 0.5 ×m × \(v^{2}\)

4 × \(v_{0} ^{2}\) =    \(v^{2}\)

v =  \(2v_{0}\)

What is work-energy theory and how is it supported?

According to the work-energy theorem, the work done by the net force exerted on a body equals the change in kinetic energy. W = kf - ki is the simplest way to express it. The work energy theorem equation is the one shown above. If the body's kinetic energy declines, the net work done W becomes negative.

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Answer:

D

Explanation:

Answer:

Image distance () = - 9.08 cm

Image height () = 1.02 cm

Given: (object distance) , (object height) , (focal length)

Required: image distance () and image size ()

Equations:

Eqn 01:  (mirror equation)

Eqn 02:  (magnification equation)

Solution:

Solving for the image distance:

Solving for the image height / size:

there are 3 significant figures (35.5 is 3, 4.00 is 3,  -12.2 is 3),  therefore,

Answer:

Image distance () = - 9.08 cm

Image height () = 1.02 cm

Given that the asteroid takes 924.137 days to orbit the Sun, we need to find its orbital radius in millions of kilometers. We will use Kepler's third law of planetary motion to find the distance.

Kepler's third law of planetary motion is given by:T² ∝ R³Where T is the time period of the orbit and R is the mean distance of the object from the center of mass of the system.So, T² = kR³Where k is a constant of proportionality, which is the same for all the planets and satellites orbiting the same star.

Using the given data,T = 924.137 days The time period of one earth year = 365.2422 days Therefore, the time period of the asteroid in earth years = 924.137/365.2422 = 2.5299 yearsTaking k = 1, we getT² = R³2.5299² = R³6.4203 = R³Therefore, the orbital radius R = ∛6.4203 million km ≈ 1.906 million kmHence, the orbital radius of the asteroid is approximately 1.906 million km.

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This is the density function of I when C and D are independent. It describes the distribution of intensities at a given point, given the distribution of light power from the source and the distance from the source to the point.

To find the density function of I, we need to determine the probability density function (PDF) of the random variable I.

Given that C and D are independent, we can use the concept of change of variables to find the density function of I.

First, we know that I = C/D^2. We can rearrange this equation to express D in terms of I: D = (C/I)^(1/2).

Now, we can find the derivative of D with respect to I to obtain the Jacobian of the transformation: dD/dI = -(1/2)*(C/I)^(3/2).

Since C is uniformly distributed in the interval (1,2), its density function fC(c) is constant within that range and zero outside. Thus, fC(c) = 1 for 1 ≤ c ≤ 2, and fC(c) = 0 otherwise.

Using the formula for change of variables, the density function of I, fI(i), can be obtained as follows:

fI(i) = fC(C/I)(dD/dI)

= 1 * (-(1/2)(C/I)^(3/2))

= -(1/2)*(C/I)^(3/2)

where C is restricted to the range (1,2) and D is calculated as D = (C/I)^(1/2).

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ANSWER

EXPLANATION

Parameters given:

Initial velocity, v0 = 78.4

Angle of projectile, θ = 52 degrees

(a) To find the flight time of the tennis ball, apply the formula:

where g = acceleration due to gravity

Hence, the total flight time of the tennis ball is:

(b) To find the maximum altitude of the ball during its flight, apply the formula:

Therefore, the maximum height attained by the tennis ball is:

(c) To find the horizontal distance the tennis ball travels, apply the formula:

Hence, the horizontal distance traveled by the tennis ball is:

(d) To find the final velocity of the tennis ball, apply the formula:

where h = initial height = 0 m

Hence, the final velocity of the tennis ball just before impact is:

Answer:

because these units are derived from combinations of two or more of the seven base units

Answer:

Angular Speed = pi/7 or 0.449 rad/s

Explanation:

\(\frac{4rev}{14s}*\frac{2\pi }{1rev} = \frac{\pi }{7} or 0.449 rad/s\)

Answer:

C

Explanation:

b is 55 miles per hour south  or 55mph[South]

the important part to understand is that velocity is a vector meaning it also has to have a direction, in this case south. That is why a (2m/s) is not a velocity, however 2m/s is a speed.

The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

To find the answer, we have to know about the pressure.

                 \(P=\frac{F}{A}\)

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.

             \(P=1atm=1.013*10^5Pascals\)

            \(F=mg=P*A=1.013*10^5*4.5=4.56*10^5N\)

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

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Answer:

\(\boxed {\boxed {\sf 96 \ m/s}}\)

Explanation:

We are asked to find the final velocity of the car given the acceleration and time. We can use the following kinematics equation to calculate the final velocity.

\(v_f=v_i+(a \times t)\)

The car starts from rest, so the initial velocity is 0 meters per second. It accelerates a rate of 40 meters per square second over a period of time of 2.4 seconds.

Substitute the values into the formula.

\(v_f= 0 \ m/s + ( 40 \ m/s^2 \times2.4 \ s)\)

Solve inside the parentheses.

\(v_f= 0 \ m/s + (96 \ m/s)\)

Add.

\(v_f= 96 \ m/s\)

The final velocity of the car is 96 meters per second.

Answer:

F = 592238.09 N

Explanation:

To find the mean force you first calculate the acceleration by using the following kinematic equation:

\(v^2=v_o^2+2ax\\\\v_o=0m/s\\\\v=10km/h\\\\x=8.4m\\\\\)

you do "a" the subject of the equation and replace the values of the other parameters:

\(a=\frac{v^2}{2x}=\frac{10000m/s}{2(8.4m)}=595.23\frac{m}{s^2}\)

next, the force, by using the second Newton law is:

\(F=ma=(1000kg)(595.23\frac{m}{s^2})=595238.09\ N\)

hence, the force is 592238.09 N

- - - - - - - - - - - - - - - - - - - - - - - - - - -

TRANSLATION:

Para encontrar a força média, primeiro calcule a aceleração usando a seguinte equação cinemática:

você faz "a" o assunto da equação e substitui os valores dos outros parâmetros:

Em seguida, a força, usando a segunda lei de Newton, é:

portanto, a força é 592238.09 N

Answer:

tbh vector does not have any direction at all the answer is 0

The mass and energy of the wood before burning would be equal to the energy and matter of the ash, soot, heat and light after burning.

The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.

While burning of wood, the chemical energy in the wood is released as heat because of the chemical reaction of wood and oxygen.

This type of chemical reaction is called combustion and it requires oxygen. Combustion converts the stored chemical energy in the wood into heat and light energy.

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Answer:

the answer should be field.

Answer:

Explanation:

F = ma. For us, this looks like

60 = 30a and

a = 2 m/s/s

If the force goes up to, say, 90, then

90 = 30a and

a = 3...if the force goes up, the acceleration also goes up.

If the mass goes up to say, 60, and the force stays the same, then

60 = 60a and

a = 1...if the mass goes up, the acceleration goes down.

The  pressure on the upper wing surface is 4.10 x 10^3 Pa.

The lift force on an airplane wing is due to the pressure difference between the upper and lower surfaces of the wing. According to Bernoulli's principle, the pressure of a fluid decreases as its speed increases. Therefore, the air moving over the curved upper surface of the wing must have a lower pressure than the air moving over the flat lower surface of the wing.

The lift force can be calculated using the formula:

L = Cl * ρ * A * v^2 / 2

where L is the lift force, Cl is the lift coefficient, ρ is the density of the air, A is the area of the wing, and v is the speed of the air.

Since the airplane is in level flight, the lift force is equal to the weight of the airplane:

L = mg

where m is the mass of the airplane and g is the acceleration due to gravity.

We can use these two equations to find the speed of the air over the wing:

mg = Cl * ρ * A * v^2 / 2

v^2 = 2mg / (Cl * ρ * A)

v = sqrt(2mg / (Cl * ρ * A))

Let's assume that the lift coefficient is the same for both the upper and lower surfaces of the wing. Then, the lift force on each wing is:

L/2 = Cl * ρ * A * v^2 / 4

The pressure difference between the upper and lower surfaces of the wing can be found using the formula:

ΔP = 2 * (L/2) / A

Substituting the expressions for L/2 and v^2, we get:

ΔP = Cl * ρ * v^2

ΔP = Cl * ρ * (2mg / (Cl * ρ * A))

ΔP = 2mg / A

Substituting the given values, we get:

ΔP = 2 * (1.10 x 10^4 kg) * 9.81 m/s^2 / (39.0 m^2)

ΔP = 5.59 x 10^4 Pa

Since the pressure on the lower wing surface is given as 6.00 x 10^4 Pa, the pressure on the upper wing surface is:

Pupper = Plower - ΔP

Pupper = (6.00 x 10^4 Pa) - (5.59 x 10^4 Pa)

Pupper = 4.10 x 10^3 Pa

Therefore, the pressure on the upper wing surface is 4.10 x 10^3 Pa.

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