The Hu Family goes out for lunch, and the price of the meal is $53. The sales tax on the meal is 7%, and the family also leaves a 15% tip on the pre-tax amount. What is the total cost of the meal?

PLEASE HELP I WILL MARK BRAINLIEST

Answer:

I think the awnser is 27.9

Step-by-step explanation:

4.5*6.2=27.9

The square with the side length 26 is the Square C.

The square with the side length 11 is the Square B.

The square with the side length 4.2 is the Square A.

As,

4.2<11<26

to simply plot the graph using tre-position on the pitcher's mound.

Around the pitching rubber, the mound is flat. The mound slopes downward at a rate of one inch every foot for a distance of at least six feet, beginning six inches in front of the rubber or 60 feet from home plate.

A raised patch of earth in the middle of the infield where a pitcher stands and tosses from is known as the pitcher's mound in baseball. It is slightly sloping, like a small hill, which is why it is called a mound. Continue reading to discover more about baseball's pitching circle.

For pitchers in high school to the Major League, the mound is an 18-foot-diameter circle that is 10 inches above home plate.

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An object is moving along the x x -axis. At t t = 0 it is at x x = 0. Its x x -component of velocity vx v x as a function of time is given by vx(t)=αt−βt3 v x ( t ) = α t − β t 3 , where α= α = 7.2 m/s2 m / s 2 and β= β = 4.8 m/s4 m / s 4  the nonzero time at which x = 0 is 1.22 seconds.

To find the time at which the object is again at x=0, we need to solve the equation vx(t) = 0, which gives us:

αt - βt^3 = 0

t(α - βt^2) = 0

The solutions to this equation are t = 0 (which corresponds to the initial position) and t = ±√(α/β). Since we're looking for a nonzero time, we can discard the t = 0 solution and take t = √(α/β):

t = √(α/β) = √(7.2 m/s^2 / 4.8 m/s^4) = √(1.5 s^2) = 1.22 s

Therefore, the object is again at x=0 after a time of 1.22 seconds.

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Answer:

no because they do not go up by the same number  plz mark brainiest

Step-by-step explanation:

1 - 8x = 4x - x + 12

Subtract the Like Terms.

1 - 8x = 3x + 12

Take the RHS to LHS.

1 - 8x - 3x - 12 = 0

Now, Subtract the Like Terms.

-11 - 11x = 0

Now, Take -11 to the LHS.

The value of a number changes when we take something to the other side of the equation.

-11x = 11

x = 11/-11

x = -1

x = -1

Answer:

g(-2) = -7

Step-by-step explanation:

To find g(-2), plug -2 into g(x).

g(x) = -4x² + 3x + 15

g(-2) = -4(-2)² + 3(-2) + 15

g(-2) = -4(4) + 3(-2) + 15

g(-2) = -16 + (-6) + 15

g(-2) = -1 + (-6)

g(-2) = -7

16 is a perfect square

16 = 2 × 2 × 2 × 2

16 = (2 × 2) × (2 × 2)

16 = 4 × 4

Perfect squares numbers whose squares are whole numbers. Square root of 16 gives 4.

Hence, 16 is a perfect square

Taxpayers in California may need to calculate the itemized deduction limitation when filing their state income taxes. This limitation sets a cap on the amount of itemized deductions that can be claimed, based on the taxpayer's federal adjusted gross income (AGI) and other factors.

Calculating the California itemized deduction limitation involves several steps and considerations to ensure compliance with the state tax regulations. To calculate the California itemized deduction limitation, taxpayers should first determine their federal AGI. This can be found on their federal tax return. Next, they need to identify any federal deductions that are not allowed for California state tax purposes, as these will be excluded from the calculation. Once the applicable deductions are determined, taxpayers must compare their federal AGI to the threshold specified by the California Franchise Tax Board (FTB). The limitation is typically a percentage of the federal AGI, and the percentage may vary depending on the taxpayer's filing status. If the federal AGI exceeds the threshold, the itemized deductions will be limited to the specified percentage. Taxpayers should consult the official guidelines and instructions provided by the California FTB or seek professional tax advice to ensure accurate calculation and compliance with the state tax regulations. Calculating the California itemized deduction limitation is an important step in accurately reporting and calculating state income taxes. It helps determine the maximum amount of itemized deductions that can be claimed, ensuring that taxpayers adhere to the tax laws and regulations of the state.

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Answer:

The transformed function is

g(x)=2*|x-4|-6

Step-by-step explanation:

First, you would have to stretch it vertically which is g(x)=2*f(x)

Then you would have to move it 6 units down and 4 units to the right which is g(x)=2*f(x-4)-6

resulting in the actual function

g(x)=2*|x-4|-6

Just type that function into the DESMOS calculator and you should be good

The population of rabbits by the year 2023  is 13985.

We have to use the following exponential function. This will be:

y = a b^t

In 2008 means, t=0

So we have 7100 = a b^0

a = 7100

y = 7100b^t

In 2013 means t = 2013-2008 =5

8900 = 7100 b⁵

b⁵ = 89/71

b = 1.046

So the equation will be

y = 7100 (1.046)^t

For 2023, t=2023-2008= 15

y = 7100(1.046)¹⁵

= 13985

The population is 13985.

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Answer: 6

Step-by-step explanation:

To calculate the fifth term of the sequence defined by f(n) = 3n - 9, we have to put 5 as the value of n in the equation. This will be:

f(n) = 3n - 9

f(5) = 3(5) - 9

= 15 - 9

= 6

Therefore, the fifth term is 6.

The correct options are:

Oy=-x-2

2x + 5y = -10

2x - 5y = -10

What is the slope-intercept?

The slope-intercept form of a line is a linear equation that is written in the form of b

The equation of the line that is perpendicular to the line 5x - 2y = -6 and passes through the point (5,-4) can be found using the point-slope form of a line, where the slope of the line perpendicular to the original line will have a negative reciprocal slope.

The slope-intercept form of the original line is y = (5/2)x + b, where b can be found by substituting the point (5,-4) into the equation:

-4 = (5/2)(5) + b

-4 = 12.5 + b

-16.5 = b

So, the slope-intercept form of the original line is y = (5/2)x - 16.5. The slope of this line is 5/2. The negative reciprocal of this slope is -2/5.

Using the point-slope form, the equation of the line perpendicular to the original line and passing through the point (5,-4) is:

y - (-4) = -2/5 (x - 5)

y + 4 = -2/5 x + 10

Multiplying both sides by 5, we get:

5y + 20 = -2x + 50

Adding 2x to both sides, we get:

5y + 2x + 20 = 50

So, the equation of the line that is perpendicular to the line 5x - 2y = -6 and passes through the point (5,-4) is 5y + 2x + 20 = 50.

Thus, the correct options are:

Oy=-x-2

2x + 5y = -10

2x - 5y = -10

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There are 4 terms in the simplified equation making it a quadrinomial

The result is Quadrinomial cubic

Start by simplifying the polynomial using the FOIL method:

Multiply one by one:

First multiply the term:

\((2a-5)(a^2-1)=(2a)(a^2-1) -5(a^2-1)\)

And, split out the terms, we get

\((2a-5)(a^2-1)=(2a)(a^2)+(2a)(-1)+(-5)(a^2)+(-5)(-2)\\\\(2a-5)(a^2-1)=2a^3-2a-5a^2+5\)

Now, the degree is equivalent to the highest exponent in the polynomial. So, the degree for this polynomial is 3 meaning its a cubic.

There are 4 terms in the simplified equation making it a quadrinomial

Hence, The result is Quadrinomial cubic .

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The first scenario is an example of Newton's first law, the second scenario is an example of Newton's second law.

Finally, if Beatriz Pushed with more force than Gustavo, the door would move in the direction in which Beatriz is pushing.

Remember Newton's first law of motion:

"if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force."

Now, in the first scenario given, both persons push the door with the same force and in opposite directions, thus, the net force on the door is 0 (because we can directly add the forces).

Then the first example is an example of the first law of motion, where because the net force on the door is 0, the door does not move.

Now, for the second law, we know that the force applied to an object is equal to the object's acceleration times the object's mass.

So, in the second case where Gustavo pushes the door with more force than Beatriz, the net force is not 0, so here the door will move in the direction in which Gustavo is pushing, this is an example of the second law of motion.

Finally, if Beatriz Pushed with more force than Gustavo, the door would move in the opposite direction than in the case above.

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Answer:

a balanced force

Unbalanced forces

move

Step-by-step explanation:

I got it right

Answer:

Step-by-step explanation:

given that the function to predict the price is

y = 5.92x + 119.21

x= the number of year,

given that we are predicting from 1995-2015

the difference is 20years

So put x=20 in the expression we have

y = 5.92(20) + 119.21

y=118.4+119.21

y=237.61

the median price is $237.61

It will take approximately 11.62 years to reach a population of 7000 mice.

To solve this problem, we can use the formula for exponential growth:

\(\mathrm{N = N_0 \times e^{(r \times t)}}\)

Where:

N = Final population size

N₀ = Initial population size

r = Growth rate

t = Time (in years)

Let's calculate the growth rate (r):

N₀ = 100

N = 4000

\(\mathrm{r = ln(N/N_0) / t}\)

\(\mathrm {r = ln(4000/100) / 10}\\\\\mathrm {r = ln(40) / 10}\\\\\mathrm {r \approx 0.3688}\)

Now, let's find the time required to reach 7000 mice:

\(\mathrm {N = 7000}\\\\\mathrm {t = ln(N/N_0) / r}\)

\(\mathrm {t = ln(7000/100) / 0.3688}\\\\\mathrm {t \approx 11.52 \ years}\)

Therefore, it will take approximately 11.62 years to reach a population of 7000 mice.

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Adjust the parameters as needed, such as the step size (h) and the final x-value (xn), and run the code to obtain the solution for y(x).

The resulting plot will show the solution curve.

To solve the given set of differential equations using the Runge-Kutta method in MATLAB, we need to convert the second-order differential equations into a system of first-order differential equations.

Let's define new variables:

y = y(x)

z = dz/dx

Now, we have the following system of first-order differential equations:

dy/dx = z (1)

dz/dx = -k/(2y) (2)

To apply the Runge-Kutta method, we need to discretize the domain of x. Let's assume a step size h for the discretization. We'll start at x = 0 and proceed until x = infinite.

The general formula for the fourth-order Runge-Kutta method is as follows:

k₁ = h f(xn, yn, zn)

k₂ = h f(xn + h/2, yn + k₁/2, zn + l₁/2)

k₃ = h f(xn + h/2, yn + k₂/2, zn + l₂/2)

k₄ = h f(xn + h, yn + k₃, zn + l₃)

yn+1 = yn + (k₁ + 2k₂ + 2k₃ + k₄)/6

zn+1 = zn + (l₁ + 2l₂ + 2l₃ + l₄)/6

where f(x, y, z) represents the right-hand side of equations (1) and (2).

We can now write the MATLAB code to solve the differential equations using the Runge-Kutta method:

function [x, y, z] = rungeKuttaMethod()

   % Parameters

   k = 1;              % Constant k

   h = 0.01;           % Step size

   x0 = 0;             % Initial x

   xn = 10;            % Final x (adjust as needed)

   n = (xn - x0) / h;  % Number of steps

   % Initialize arrays

   x = zeros(1, n+1);

   y = zeros(1, n+1);

   z = zeros(1, n+1);

   % Initial conditions

   x(1) = x0;

   y(1) = 0;

   z(1) = 0;

   % Runge-Kutta method

   for i = 1:n

       k1 = h * f(x(i), y(i), z(i));

       l1 = h * g(x(i), y(i));

       k2 = h * f(x(i) + h/2, y(i) + k1/2, z(i) + l1/2);

       l2 = h * g(x(i) + h/2, y(i) + k1/2);

       k3 = h * f(x(i) + h/2, y(i) + k2/2, z(i) + l2/2);

       l3 = h * g(x(i) + h/2, y(i) + k2/2);

       k4 = h * f(x(i) + h, y(i) + k3, z(i) + l3);

       l4 = h * g(x(i) + h, y(i) + k3);

       y(i+1) = y(i) + (k1 + 2*k2 + 2*k3 + k4) / 6;

       z(i+1) = z(i) + (l1 + 2*l2 + 2*l3 + l4) / 6;

       x(i+1) = x(i) + h;

   end

   % Plotting

   plot(x, y);

   xlabel('x');

   ylabel('y');

   title('Solution y(x)');

end

function dydx = f(x, y, z)

   dydx = z;

end

function dzdx = g(x, y)

   dzdx = -k / (2*y);

end

% Call the function to solve the differential equations

[x, y, z] = rungeKuttaMethod();

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Answer:

y=9x+75

Step-by-step explanation:

since we know that the slope must be the same for two lines to be proportional, we are gonna start there.

so our equation is: y= 9x + b

we need to find b to complete our equation, so substitute in the points we were given.

3 = 9(-8) + b

so now,

3 = -72 + b

now we have to isolate b to find out what it is,

3  =  -72 + b

+72   +72

so now: 75= b

Put that back into the starting equation: y = 9x + 75

The DE dy/dx = ln(1 + y^2) at the point (0, 0) does not have a unique solution.

The DE dy/dx = x - y at the point (2, 2) has a unique solution.

The DE (2 - x)dy/dx = y at the point (1, 0) has a unique solution.

To determine if the Theorem of Existence and Uniqueness implies the existence of a unique solution for each differential equation (DE) at the given point, we need to check if the DEs satisfy the conditions of the theorem. The theorem states that for a first-order DE of the form dy/dx = f(x, y) with initial condition (x0, y0), if f(x, y) is continuous and satisfies the Lipschitz condition in a neighborhood of (x0, y0), then there exists a unique solution.

Let's analyze each DE separately:

dy/dx = ln(1 + y^2) at the point (0, 0):

The function f(x, y) = ln(1 + y^2) is continuous for all values of y. However, it does not satisfy the Lipschitz condition in a neighborhood of (0, 0) since its partial derivative with respect to y, ∂f/∂y = (2y) / (1 + y^2), is unbounded as y approaches 0. Therefore, the theorem does not imply the existence of a unique solution for this DE at the point (0, 0).

dy/dx = x - y at the point (2, 2):

The function f(x, y) = x - y is continuous for all values of x and y. Additionally, it satisfies the Lipschitz condition in a neighborhood of (2, 2) since its partial derivative with respect to y, ∂f/∂y = -1, is bounded. Therefore, the theorem implies the existence of a unique solution for this DE at the point (2, 2).

(2 - x)dy/dx = y at the point (1, 0):

Rearranging the equation, we have dy/dx = y / (2 - x). The function f(x, y) = y / (2 - x) is continuous for all values of x and y except at x = 2. However, at the point (1, 0), the function is continuous and satisfies the Lipschitz condition. Therefore, the theorem implies the existence of a unique solution for this DE at the point (1, 0).

dx/dy = y / (x - 1) at the point (0, 1):

The function f(x, y) = y / (x - 1) is not defined at x = 1. Therefore, the function is not continuous in a neighborhood of the point (0, 1), and the theorem does not imply the existence of a unique solution for this DE at that point.

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The conditional probability that the outcome of the coin toss was heads can be calculated using Bayes' theorem. The conditional probability that the outcome of the toss was heads given that a white ball was selected is 26/63.

Let's denote H as the event that the outcome of the coin toss was heads, and W as the event that a white ball was selected. We want to find P(H|W), the probability of the coin toss being heads given that a white ball was selected.

According to Bayes' theorem, we have:

P(H|W) = P(W|H) * P(H) / P(W)

P(W|H) is the probability of selecting a white ball given that the outcome of the coin toss was headed. Since the first mug is chosen in this case, which contains two white balls out of a total of nine balls, P(W|H) = 2/9.

P(H) is the probability of the coin toss being heads, which is 1/2 since the coin is fair.

P(W) is the probability of selecting a white ball, regardless of the outcome of the coin toss. There are a total of seven white balls out of thirteen balls (two from the first mug and five from the second mug), so P(W) = 7/13.

Therefore, substituting these values into Bayes' theorem:

P(H|W) = (2/9) * (1/2) / (7/13)

Simplifying this expression:

P(H|W) = 26/63

Therefore, the conditional probability that the outcome of the toss was heads given that a white ball was selected is 26/63.

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The answer is:

\(\large\textbf{They aren't equivalent.}}\)

In-depth explanation:

To determine the answer to this problem, we will use one of the exponent properties:

\(\sf{x^{-m}=\dfrac{1}{x^m}}\)

And

\(\sf{\dfrac{1}{x^{-m}}=x^m}\)

Now we apply this to the problem.

What is 4⁻³ equal to? Well according to the property, it's equal to:

\(\sf{4^{-3}=\dfrac{1}{4^3}}\)

And this question asks us if 4⁻³ is the same as 1/4⁻3.

Well according to the calculations performed above, they're not equivalent.

Answer:

(7,5) and (10,8)

Step-by-step explanation:

x = y+2

4(y+2)^2 -(y+2) - 67y + 146 = 0

4(y^2+4+4y) -y - 2 - 67y + 146 = 0

4y^2+16y+16 - 68y + 144 = 0

4y^2 -52y + 160= 0

y^2 - 13y+40 = 0

(y-8)(y-5) = 0

y = 8

y = 5

x = 5+2 = 7

x = 8 + 2 = 10

Answer:

BC = 25

Step-by-step explanation:

I'm gonna assume that the triangle is an isosceles triangles, so sorry if this doesn't help!

4x + 1 = 2x + 23

2x + 1 = 23

2x = 22

x = 11

3(11) - 8

33 - 8

= 25

The four ways to care for our nervous system are exercise, meditation, proper sleep and healthy food.

There are many ways to care and protect our nervous system. But some of the basics and the most important ways to care for our nervous system are to follow a basic routine which includes regular exercise, practicing meditation daily, having proper sleep for at least seven hours a day and having healthy food mostly.

Now, doing exercise means that we are constantly engaged in some kind of physical activity and healthy food also means to have a balanced lifestyle.

Hence, the four ways to care for our nervous system are exercise, meditation, proper sleep and healthy food.

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Answer:

ill help 3

Step-by-step explanation:

Answer:

the answer is 16

Step-by-step explanation:

5^2-3^2

25-9

16

Answer:

\(y = 4 \cos(4\pi \: t + \frac{\pi}{4} ) \)

\(y = a\cos(w\: t + \alpha ) \)

\(w = 4\pi\)

\(2\pi \: f = 4\pi\)

\(f = 2\)

Answer:

\(\displaystyle 2\)

Step-by-step explanation:

\(\displaystyle y = Acos(Bx - C) + D\)

When working with a trigonometric equation like this, always remember the information below:

\(\displaystyle Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A|\)

So, the first procedure is to find the period of this graph, and when calculated, you should arrive at this:

\(\displaystyle \boxed{\frac{1}{2}} = \frac{2}{4\pi}\pi\)

You will then plug this into the frequency formula, \(\displaystyle T^{-1} = F.\) Look below:

\(\displaystyle \frac{1}{2}^{-1} = F \\ \\ \boxed{2 = F}\)

Therefore, the frequency of motion is two hertz.

I am delighted to assist you at any time.

Reason:

Complementary events have their probabilities add to 1.

P(A)+P(B) = 1

P(B) = 1 - P(A)

For example,

P(A) = the chance it rains = 30% = 0.30

P(B) = the chance it doesn't rain

P(B) = 1 - P(A) = 1 - 0.30 = 0.70 = 70%

The equation that relates the probability of A and B is P(B) = 1 - P(A).

A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1.

As per the given data:

We are given two events, event A and event B.

We are also given the relationship between the two events.

It's given that A and B are complements of each other.

Let's assume that the probability of the event B is P(B).

The sample space for this situation when only 2 events are there will be

(A, B)

We are given that A and B are complements of each other.

This means that the complement of A is equal to the probability of event B.

P(A') = 1 - P(A)

P(B) = P(A')

∴ P(B) = 1 - P(A)

The equation that relates the probability of A and B is P(B) = 1 - P(A).

Hence, The equation that relates the probability of A and B is P(B) = 1 - P(A).

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Answer:

254.5

Step-by-step explanation:

area of circle = pi (3.142) x 9squared

answer 254.5 or 81 pi