The initial kinetic energy imparted to a 0.25 kg bullet is 1066 J. The acceleration of gravity is 9.81 m/s 2 . Neglecting air resistance, find the range of this projectile when it is fired at an angle such that the range equals the maximum height attained. Answer in units of km.

The melting point of the substance in the heating curve is 20°C.

1) The melting point of the substance is the temperature at the point where, the substance is having a phase change from solid state to liquid. So, the temperature at point B, 20°C is its melting point.

2) The boiling point of the substance is the temperature at the point where, the substance is having a phase change from liquid state to gaseous state. So, the temperature at point D, 90°C is its boiling point.

3) The point A is where the substance is at solid state.

4) The substance is at liquid state at the point C.

5) The substance is at gaseous state at the point E.

6) At point B, solid state is changing to liquid state.

7) At point D, liquid state is changing to gaseous state.

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Answer:

The amplitude of a wave is a measure of the displacement of the wave from its rest position. The amplitude is shown on the graph below. Amplitude is generally calculated by looking on a graph of a wave and measuring the height of the wave from the resting position. The amplitude is a measure of the strength or intensity of the wave.

Explanation:

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a ) The x and y-components of average velocity and average acceleration between points A and B are 3.8 m/s, 3.8 m/s and 0.46 m/s², - 0.46 m/s²

e ) The magnitude of the runner’s average velocity between A and B is

t = 2 π r / v

t = 2 * 3.14 * 50 / 6

t = 52.4 s for full lap

t per quarter = 52.4 / 4 = 13.1 s

v = Δx / Δt

a = Δv / Δt

a ) From A to B,

vx = ( 0 - ( - 50 ) ) / 13.1

vx = 3.8 m / s

vy = ( 50 - 0 ) / 13.1

vy = 3.8 m / s

ax = ( 6 - 0 ) / 13.1

ax = 0.46 m / s²

ay = ( 0 - 6 ) / 13.1

ay = - 0.46 m / s²

b ) From A to C,

t = 52.4 / 2

t = 26.2 s

vx = ( 50 - ( - 50 ) ) / 26.2

vx = 3.8 m / s

vy = 0

ax = 0

ay = ( - 6 - 6 ) / 26.2

ay = - 0.46 m / s²

c ) From C to D,

t = 13.1 s

vx = ( 0 - 50 ) / 13.1

vx = - 3.8 m / s

vy = ( - 50 - 0 ) / 13.1

vy = - 3.8 m / s

ax = ( - 6 - 0 ) / 13.1

ax = - 0.46 m / s²

ay = ( 0 - ( - 6 ) ) / 13.1

ay = 0.46 m / s²

d ) From A to A,

Since the starting and ending points are exactly the same, there is no displacement. So the average velocity will be zero. Due to no change in velocity, there will be no acceleration

e ) From A to B,

v = √ vx² + vy²

v = √ 3.8² + 3.8²

v = 5.4 m / s

Displacement is the shortest distance between two points. So it will basically be a straight line. But the athlete runs in a circular motion. So distance will be larger than the displacement. So speed will be higher than velocity.

s = 6 m / s

v = 5.4 m / s

s > v

f ) At constant speed in a circular motion, only the magnitude is constant. Its direction keeps changing. So velocity cannot be constant in a circular motion.

Therefore,

a ) vx = 3.8 m / s, vy = 3.8 m / s ; ax = 0.46 m / s², ay = 0.46 m / s²

b ) vx = 3.8 m / s, vy = 0 ; ax = 0, ay = - 0.46 m / s²

c ) vx = - 3.8 m / s, vy = - 3.8 m / s ; ax = - 0.46 m / s², ay = 0.46 m / s²

d ) vx = 0, vy = 0 ; ax = 0, ay = 0

e ) v = 5.4 m / s

f ) Due to change in direction.

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Answer:

The acceleration is a negative as the ball is now moving in the opposite direction.

The velocity would decrease as the ball moves upward

Acceleration remains constant and velocity is negative and decreasing as per the given scenario. The correct option is B.

In mechanics, acceleration is defined as the rate of change of an object's velocity with respect to time.

Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.

Velocity is the directional speed of a moving object as an indication of its rate of change in position as observed from a specific frame of reference and measured by a specific time standard.

The rate of displacement of an entity known as its velocity. It is measured in meters per second. The rate of change in velocity of an object is defined as acceleration.

According to the scenario, acceleration remains constant while velocity decreases and is negative.

Thus, the correct option is B.

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Your question seems incomplete, the missing options are:

Lower frequencies (red) move faster in a glass prism than higher frequencies.

Light of all colors moves at the same speed in a vacuum. However, light travels at different speeds in many media, including water.

Red light moves through glass at the fastest speed, whereas violet light moves at the slowest speed.

Red light bends the least of all the colors because it moves at the fastest speed, whereas violet light moves at the slowest speed and bends the most.

Wavelength and speed are directly proportional. Speed also rises with increasing wavelength. Light that has a maximal wavelength therefore moves at its fastest.

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Answer:

Explanation:

m=p/v

where m is mass, p is momentum and v is velocity

For an area of 350 kcmil, the next larger standard size conductor is 500 kcmil. When selecting a conductor size, it is important to match the next larger standard size conductor for the minimum cmil area calculated.

A conductor is an object or substance that allows electricity to flow through it. It can be a metal such as copper or aluminum, or a non-metallic material such as rubber or plastic. Conductors are essential components in any electrical circuit.

The size of a conductor is determined by its circular mil area (cmil). The larger the cmil, the larger the conductor size. When selecting a conductor size, it is important to match the next larger standard size conductor for the minimum cmil area calculated.

For example, if the minimum cmil area calculated is 9,543 cmil, the next larger standard size conductor is 14,435 cmil. This is the size that should be chosen.

For an area of 83,542 cmil, the next larger standard size conductor is 107,218 cmil. For an area of 177,645 cmil, the next larger standard size conductor is 211,914 cmil.

Finally, for an area of 350 kcmil, the next larger standard size conductor is 500 kcmil. It is important to note that kcmil stands for kilo circular mils, which is the same as 1,000 cmil.

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Answer: 4.6

Explanation:

Answer:

4.6

Explanation:

Answer: -0.10m/s

Explanation:

khan academy

Answer :

(a). The final temperature of the gas in the cylinder A is 320 K.

(b). The final temperature of the gas in the cylinder B is 233.7 K.

(c). The final volume of the gas in the cylinder A is \(7.86\times10^{-3}\ m^3\)

(d). The final volume of the gas in the cylinder B is \(5.7\times10^{-3}\ m^3\)

Explanation :

Given that,

Number of mole n = 0.30 mol

Initial temperature = 320 K

Pressure = 3.0 atm

Final pressure = 1.0 atm

We need to calculate the initial volume

Using formula of ideal gas

\(P_{1}V_{1}=nRT\)

\(V_{1}=\dfrac{nRT}{P_{1}}\)

Put the value into the formula

\(V_{1}=\dfrac{0.30\times8.314\times320}{3.039\times10^{5}}\)

\(V_{1}=2.62\times10^{-3}\ m^3\)

(a). We need to calculate the final temperature of the gas in the cylinder A

Using formula of ideal gas

In isothermally, the temperature is not change.

So, the final temperature of the gas in the cylinder A is 320 K.

(b). We need to calculate the final temperature of the gas in the cylinder B

Using formula of ideal gas

\(T_{2}=T_{1}\times(\dfrac{P_{1}}{P_{2}})^{\frac{1}{\gamma}-1}\)

Put the value into the formula

\(T_{2}=320\times(\dfrac{3}{1})^{\frac{1}{1.4}-1}\)

\(T_{2}=233.7\ K\)

(c). We need to calculate the final volume of the gas in the cylinder A

Using formula of volume of the gas

\(P_{1}V_{1}=P_{2}V_{2}\)

\(V_{2}=\dfrac{P_{1}V_{1}}{P_{2}}\)

Put the value into the formula

\(V_{2}=\dfrac{3\times2.62\times10^{-3}}{1}\)

\(V_{2}=0.00786\ m^3\)

\(V_{2}=7.86\times10^{-3}\ m^3\)

(d). We need to calculate the final volume of the gas in the cylinder B

Using formula of volume of the gas

\(V_{2}=V_{1}(\dfrac{P_{1}}{P_{2}})^{\frac{1}{\gamma}}\)

\(V_{2}=2.62\times10^{-3}\times(\dfrac{3}{1})^{\frac{1}{1.4}}\)

\(V_{2}=0.0057\ m^3\)

\(V_{2}=5.7\times10^{-3}\ m^3\)

Hence, (a). The final temperature of the gas in the cylinder A is 320 K.

(b). The final temperature of the gas in the cylinder B is 233.7 K.

(c). The final volume of the gas in the cylinder A is \(7.86\times10^{-3}\ m^3\)

(d). The final volume of the gas in the cylinder B is \(5.7\times10^{-3}\ m^3\)

Answer:

Land pollution touches essentially every area of the living world, including: Water that isn't safe to drink. Polluted soil, which leads to a loss of fertile land for agriculture. Climate change, which causes an onslaught of disastrous problems, including flash floods and irregular rainfalls.

Explanation:

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Answer:

Look at any ecosystem and there could be multiple forms of contamination—streams full of toxic chemicals from industrial processes, rivers overloaded with nutrients from farms, trash blowing away from landfills, city skies covered in smog. Even landscapes that appear pristine can experience the effects of pollution sources located hundreds or thousands of miles away.

Pollution may muddy landscapes, poison soils and waterways, or kill plants and animals. Humans are also regularly harmed by pollution. Long-term exposure to air pollution, for example, can lead to chronic respiratory disease, lung cancer and other diseases. Toxic chemicals that accumulate in top predators can make some species unsafe to eat. More than one billion people lack access to clean water and 2.4 billion don’t have adequate sanitation, putting them at risk of contracting deadly diseases.

Air pollution brings to mind visions of smokestacks billowing black clouds into the sky, but this pollution comes in many forms. The burning of fossil fuels, in both energy plants and vehicles, releases massive amounts of carbon dioxide into the atmosphere, causing climate change. Industrial processes also emit particulate matter, such as sulfur dioxide, carbon monoxide and other noxious gases. Indoor areas can become polluted by emissions from smoking and cooking. Some of these chemicals, when released into the air, contribute to smog and acid rain. Short term exposure to air pollution can irritate the eyes, nose and throat and cause upper respiratory infections, headaches, nausea and allergic reactions. Long-term exposures can lead to chronic respiratory disease, lung cancer, and heart disease. Long-term exposures also can lead to significant climatic changes that can have far reaching negative impacts on food, water and ecosystems. #SAVE OUR WORLD

Answer: C-  The intensity increases by a factor 9

Explanation: The intensity of a sound wave follows an inverse square law, that means that it is inversely proportional to the square of the distance: so  the new distance is the intensity will increase by a factor 9.

My sentence- I hope that helped!

Intensity of a sound wave decreases by a factor of 9, if the distance from the source is increased by a factor of 3. Hence option B is correct.

Intensity of Sound is inversely proportional to the square of the distance from the sound source. Since sound waves carry its energy though a two-dimensional or three-dimensional medium, the intensity of the sound wave decreases with increasing as second power of distance form the source.

Mathematically,

Intensity I ∝ 1/D²

If the distance from the source is increased by a factor of 3, Then

I ∝ 1/3² ∝ 1/9

Intensity ∝  1/9

Hence option B is correct.

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Answer:

True. If you bring a bowling ball away from earth it would weigh less because the less gravity pushing down on it.

Answer:

f

Explanation:

Answer:75.3 seconds

Explanation:

Using conservation of momentum, the initial momentum of the cannon and the projectile is equal to the final momentum of the cannon and the projectile:

m_cannon * v_cannon = (m_cannon + m_projectile) * v_final

where m_cannon is the mass of the cannon, v_cannon is the initial velocity of the cannon, m_projectile is the mass of the projectile, and v_final is the final velocity of the cannon and projectile together.

Substituting the given values gives:

210 kg * 0 m/s - 1 kg * 610 m/s = (210 kg + 1 kg) * v_final

Solving for v_final gives:

v_final = -1.83 m/s

The negative sign indicates that the cannon and projectile are moving in the opposite direction after the firing.

The time required to bring the cannon to rest can be found using the equation:

F_resistive = m_cannon * a

where F_resistive is the resisting force, m_cannon is the mass of the cannon, and a is the acceleration of the cannon.

Substituting the given values gives:

1,700 N = 210 kg * a

Solving for a gives:

a = 8.10 m/s^2

The time required to bring the cannon to rest can be found using the kinematic equation:

v_final = v_initial + a * t

where v_initial is the initial velocity of the cannon, which is equal to the muzzle velocity of the projectile, and v_final is zero. Solving for t gives:

t = -v_initial / a

Substituting the given values gives:

t = -610 m/s / 8.10 m/s^2 = 75.3 s

Therefore, the time required to bring the cannon to rest is 75.3 seconds.

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The minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

Deceleration is defined as  the decrease in speed as the body moves away from the starting point.

The minimum deceleration required can be calculated using the equation of motion:

d = v^2 / (2 * a)

where d is the distance, v is the initial velocity, and a is the acceleration.

Rearranging the equation to solve for a:

a = v^2 / (2 * d) = (3500 m/s)^2 / (2 * 35 m) = 40000 m/s^2

In conclusion, , the minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

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Answer:

Hey I go to GOC send me your number

Explanation:

Answer:

Efficiency is the percent of work put into a machine by the user (input work) that becomes work done by the machine (output work). The output work is always less than the input work because some of the input work is used to overcome friction. Therefore, efficiency is always less than 100 percent.

Inquiry-based pedagogy empowers students to explore, question, and construct knowledge through active engagement. It encourages curiosity, critical thinking, and independent investigation, fostering a deeper understanding of concepts and skills that extend beyond the classroom.

Inquiry-based pedagogy is an approach to teaching and learning that emphasizes the active engagement of students in the exploration of meaningful questions, problems, or phenomena. It encourages students to ask questions, investigate, and construct their own knowledge through critical thinking, problem-solving, and hands-on experiences. Here's an example to illustrate the concept of inquiry-based pedagogy:

Example: Exploring Ecosystems

In a biology class, the teacher introduces the topic of ecosystems using an inquiry-based approach. The teacher poses a driving question to the students: "How do living organisms interact with their environment to form ecosystems?"

1. Questioning and Investigation: Students begin by generating their own questions related to ecosystems. They might wonder about the roles of different organisms, energy flow, or the impact of human activities. Guided by their questions, they conduct research, gather information from various sources, and share their findings.

2. Hands-on Exploration: The teacher organizes hands-on activities to allow students to observe and explore ecosystems firsthand. For example, they could set up mini-ecosystems in terrariums or conduct field trips to local habitats. Through these experiences, students can make observations, collect data, and analyze patterns.

3. Collaborative Learning: Students work in groups or pairs to analyze the data they have collected and draw conclusions. They engage in discussions, share their ideas, and challenge each other's thinking. This collaborative learning environment promotes critical thinking, communication, and teamwork.

4. Reflection and Presentation: Students reflect on their findings and insights gained from their investigations. They are encouraged to synthesize their learning into presentations, reports, or visual representations. These presentations provide opportunities for students to articulate their understanding and demonstrate their learning outcomes.

By engaging in inquiry-based learning, students develop essential skills such as critical thinking, problem-solving, communication, and self-directed learning. They become active participants in their own education, taking ownership of their learning process and developing a deeper understanding of the subject matter.

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Answer:

I know that it is A

Explanation:

Answer: 12,339

Explanation:

Explanation:

Moral duties are the duties performed by the people on the basis of humanity and moral values. The following are some of the moral duties :

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Answer:

  v₀ = 6.64 m / s

Explanation:

This is a projectile throwing exercise

          x = v₀ₓ t

          y = y₀ + v_{oy} t - ½ g t²

In this case they indicate that y₀ = 1.8 m and the point of the basket is x=4.9m y = 3.0 m

the time to reach the basket is

        t = x / v₀ₓ

we substitute

        y- y₀ = \(\frac{ v_o \ x \ sin \theta }{ v_o \ cos \theta} - \frac{1}{2} g \ \frac{x^2 }{v_o^2 \ cos^2 \theta }\)

        y - y₀ = x tan θ - \(\frac{ g \ x^2 }{ 2 \ cos^2 \theta } \ \frac{1}{v_o^2 }\)

we substitute the values

        3 -1.8 = 3.0 tan 60 - \(\frac{ 9.8 \ 3^2 }{2 \ cos^2 60 } \ \frac{1}{v_o^2}\)

        1.2 = 5.196 - 176.4 1 / v₀²

        176.4 1 / v₀² = 3.996

        v₀ = \(\sqrt{ \frac{ 176.4}{3.996} }\)

        v₀ = 6.64 m / s

Explanation:

i think it's more of a molecule, combination of atoms to form the simplest part of a substance, likewise a sandwich is the combination of bread and vegs to form a whole appetizer, in ratios, so it'll probably be more of a molecule than an atom

Molecule because, the combination of bread and veggies make it more likely to be a molecule.

Molecular function refers to processes that take place at the molecular level, such as catalysis or binding. GO molecular function words do not describe the location, timing, or context of an action; rather, they indicate activities rather than the objects (molecules or complexes) that carry them out.

One or more atoms make up molecules. They may have the same atoms (for example, an oxygen molecule has two oxygen atoms) or different atoms if they have more than one (a water molecule has two hydrogen atoms and one oxygen atom). Biological molecules like DNA and proteins can include thousands of atoms.

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The power dissipated by a resistor can be calculated using the formula P = I^2 * R, where P is the power, I is the current, and R is the resistance.

If the current through a resistor is increased by a factor of 4, then the new current is 4 times the original current. Let's call the original current I and the new current 4I.

The new power dissipated by the resistor can be calculated as follows:

P_new = (4I)^2 * R

= 16I^2 * R

The ratio of the new power to the original power is:

P_new/P_old = 16I^2 * R / I^2 * R

= 16

Therefore, the power dissipated by the resistor increases by a factor of 16 when the current through it is increased by a factor of 4. The correct answer is D) increases by a factor of 16.

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The net force exerted on the 2.0 kg object by the 3.0 kg object is 14 N.

The net force acting on the 3.0 kg object is determined as follows:

Frictional force on acting on the 1.0 kg object = 0.2 * 1.0 * 10 = 2 N

Net force = 24 - 2 = 22 N

Net force acting at the end of the 2 kg object is determined as follows:

Net  force = applied force - frictional force

Frictional force on acting on the 1.0 kg and 3.0 kg object = 0.2 * 4.0 * 10 = 8 N

Net force = 22 - 8  = 14 N

Therefore, the net force exerted on the 2.0 kg object by the 3.0 kg object is 14 N.

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Answer:

0.47m3

Explanation:

Volume = Mass / Density

In this case:

Mass - 1280 kg

Density - 2700kg/m3

1280 / 2700 = 0.4740741m3

When this is rounded off ( 2 d.p ):

0.47 m3

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Answer:

6.003×10¯⁶ N

Explanation:

We'll begin by converting 1 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

1 cm = 1 cm × 1 m / 100 cm

1 cm = 0.01 m

Finally, we shall determine the gravitational attraction. This can be obtained as follow:

Mass 1 (M₁) = 3 Kg

Mass 2 (M₂) = 3 Kg

Distance apart (r) = 0.01 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of attraction (F) =?

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 3 × / 0.01²

F = 6.003×10¯¹⁰ / 1×10¯⁴

F = 6.003×10¯⁶ N

Thus the gravitational attraction is 6.003×10¯⁶ N

Answer:

Workdone = 147Nm

Explanation:

Given the following data;

Mass = 5kg

Height = 3m

We know that acceleration due to gravity is 9.8m/s²

First of all, we would find the force applied;

\( Force = mass * acceleration \)

Force = 5*9.8

Force = 49N

Now, to find the workdone;

\( Workdone = force * distance \)

Substituting into the equation, we have;

Workdone = 49 * 3

Workdone = 147Nm