The reaction 2HgO (s)→2Hg (I)+O2 (g) has a percent yield of 50%. You want to produce 100 g of Hg.

How much HgO do you need?
A)54g
B)108g
C)216g
D)432G

\(\Large \text{1)}\)

\(\textbf{Use the formula and substitute the values}\)

\(\displaystyle 0.3\ mol/L = \frac{n \ mol}{10 \times 10^{-3}\ L}\)

\(\textbf{Solve for the number of moles}\)

\(n = 0.003\ mol\)

\(\textbf{Calculate final volume }\)

\(40+10=50\ mL\)

\(\textbf{Number of moles remains same. Solve for concentration}\)

\(\displaystyle C=\frac{0.003\ mol}{50 \times 10^{-3}\ L} =0.06\ mol/L\)

\(\Large \text{2)}\)

\(\displaystyle DF=\frac{V_f}{V_i}\)

\(\displaystyle DF=\frac{50}{10}=5\)

Answer:

240.17 g Ba3(PO4)2

Explanation:

1. Determine the limiting reactant.

2H3PO4 + 3Ba(OH)2 --> Ba3(PO4)2 + 6H2O

moles H3PO4 = M x V = 3 x 0.286 = .858 moles H3PO4

moles Ba(OH)2 = M x V = 1.4 x 0.855 = 1.197 moles Ba(OH)2

ratio Ba(OH)2 : H3PO4 = 1.197: .858 = 1.39: 1

stoichiometric ratio Ba(OH)2 : H3PO4  = 3:2

Ba(OH)2is the limiting reactant

MM Ba3(PO4)2 = 601.92 g/mol

g Ba3(PO4)2 = moles Ba(OH)2 x(1 mol Ba3(PO4)2/3 moles Ba(OH)2) x (MM Ba3(PO4)2/ 1mol Ba3(PO4)2) = 1.197 x 1/3 x 601.92 = 240.17 g Ba3(PO4)2

Answer:

66 grams of ice would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C.

Explanation:

To calculate the amount of ice that would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C, we need to use the formula:

Q = m_water * c_water * ΔT_water + m_ice * Lf

where,
Q = the amount of heat transferred,
m_water = the mass of water, c_water is the specific heat capacity of water,
ΔT_water = the change in temperature of water, m_ice = the mass of ice,
Lf = the specific latent heat of fusion of ice.

First, let's calculate the amount of heat transferred to the water:

Q = m_water * c_water * ΔT_water
Q = 352 g * 1.0 cal/(g*°C) * (15-0) °C
Q = 5,280 cal

Next, we can use the specific latent heat of fusion of ice, which is 80 cal/g, to calculate the amount of heat required to melt the ice:

Q = m_ice * Lf
Q = m_ice * 80 cal/g
m_ice = Q / Lf
m_ice = 5,280 cal / 80 cal/g
m_ice = 66 g

There are approximately 6.022 × 10^23 atoms in 12 grams of Carbon-12 (12C).

The number of atoms in a given amount of a substance can be calculated using Avogadro's number, which represents the number of atoms or molecules in one mole of a substance. Avogadro's number is approximately 6.022 × 10^23.

Carbon-12 is a specific isotope of carbon, with an atomic mass of 12 atomic mass units (amu). One mole of Carbon-12 has a mass of 12 grams. Since one mole of any substance contains Avogadro's number of particles, in the case of Carbon-12, it contains 6.022 × 10^23 atoms.

Therefore, if we have 12 grams of Carbon-12, which is equal to one mole, we can conclude that there are approximately 6.022 × 10^23 atoms in this amount of Carbon-12.

In summary, 12 grams of Carbon-12 contains approximately 6.022 × 10^23 atoms. Avogadro's number allows us to relate the mass of a substance to the number of atoms or molecules it contains, providing a fundamental concept in chemistry and enabling us to quantify and understand the microscopic world of atoms and molecules.

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When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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The amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

To find the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C, we can use the equation Q = mcAT.
First, we need to find the value of m, which is the mass of the water in grams. In this case, it is given as 200 grams.
Next, we need to find the value of AT, which is the change in temperature in degrees Celsius.

This can be calculated by subtracting the initial temperature from the final temperature, which gives us 60 C - 20 C = 40 C.
The specific heat capacity of water, C, is given as 4.18 Joules per gram per degree Celsius.
Now we can plug in the values into the equation:
Q = mcAT
Q = (200 g) x (4.18 J/g°C) x (40°C)
Q = 33,440 J
Therefore, the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

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The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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The most well-known feature of mica is arguably their flawless cleavage into thin elastic sheets. The sheet structure mentioned manifests as the cleavage.

The silicate mineral family known as micas is distinguished by the ease with which individual mica crystals can break into incredibly thin, elastic plates. Perfect basal cleavage is the term used to describe this feature.

Mica is very reflective and has good cleavage, which allows it to separate into thin, resilient sheets that are the mineral group's defining feature. Thin sheets are translucent or transparent if they are deeply colored.

Thus, The most well-known feature of mica is arguably their flawless cleavage into thin elastic sheets.

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Answer:

Graham's law of effusion was formulated by Scottish physical chemist Thomas Graham in 1848. Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. This formula can be written as: , where: Rate₁ is the rate of effusion for the first gas.

Explanation:

r1 = rate of effusion for gas 1

r2 = rate of effusion for gas 2

M1 = molar mass of gas 1

M2 = molar mass of gas 2

Answer:

silicon tetrachloride or tetrachlorosilane

Adenine-thymine base pairs can be found in nucleic acid #1 but they are absent from nucleic acid #2.

Additionally to certain viruses, it is present in all cells. A wide range of tasks are performed by nucleic acids, including the production of new cells, the processing and storage of genetic data, the synthesis of proteins, and the production of energy cells.

The genetic information contained in nucleic acids, including deoxyribonucleic acid (DNA) and ribonucleic acid (RNA), is read by cells to produce the RNA and proteins necessary for life. This data may be replicated and passed on to the following generation thanks to the DNA double helix's well-known structure.

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1

1

The general molecular formula for phenol is C6H5OH. It is an aromatic organic compound with a hydroxyl group bonded to a carbon atom of a cyclic structure. The ring structure has alternate double and single bonds. The formula of phenol is C6H5OH. Benzene has the formula C6H6. It is a hexagonal ring of six carbon atoms bonded with alternate single and double bonds. Each carbon atom in benzene has a bond with a hydrogen atom. In phenol, a hydroxyl group replaces one of the hydrogen atoms.

The reaction of CuCl2, HNO3, and AgNO3 is a redox reaction. In a redox reaction, one substance loses electrons and is oxidized, while another substance gains electrons and is reduced. In this reaction, CuCl2 is oxidized to Cu2+, HNO3 is reduced to NO, and AgNO3 is reduced to Ag.

The balanced equation for the reaction is:

CuCl2 + 2HNO3 + 2AgNO3 → Cu2+ + 2NO + 2AgCl

The products of the reaction are copper(II) ions, nitrogen monoxide gas, and silver chloride precipitate.

Here are some of the properties of phenol:

Phenol is a white crystalline solid that is soluble in water.

Phenol has a strong, characteristic odor.

Phenol is a mild acid.

Phenol is toxic and can cause burns to the skin and eyes.

Phenol is used in a variety of products, including disinfectants, antiseptics, and plastics.

Can be used to calculate the y-component of the electric field in N/C produced by a positive point charge at coordinate (0,0) in water. Therefore, the positive point charge in water at coordinate (1.01, -3.55) produces a total electric field in N/C with a y-component of -4.55 x 105 N/C.

An electrically charged object can produce an electromagnetic field that has an impact on other electrically charged objects nearby. Lines of force radiating from the charged object and interacting with other charged objects can be used to represent this field. As the charged object is moved further away, the electric field's strength weakens in direct proportion to the charge. A fundamental idea in physics, the electric field is utilised to explain how charged particles interact. It is measured in units of N/C and is a vector quantity (Newtons per Coulomb). Coulomb's law, which states that the force between two charged objects is proportional to the product of the electric field can be used to compute the electric field.

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Answer:

Because while our lakes are Great, they're comparatively much smaller than oceans. And the gravitational pull isn't strong.

Answer:

6 mol CO2

Explanation:

According to the equation, 6 moles of O2 will produce 6 moles of CO2, so the ratio is 1:1

therefore 6 moles of O2 will produce 6 moles of CO2

Answer: \(5.15\times 10^5kg\)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

Putting in the values we get:

\(\text{Number of moles}=\frac{1.00\times 10^{31}}{6.023\times 10^{23}}=0.166\times 10^{8}moles\)

1 mole of phosphorous \(P\) weighs = 31 g

Thus \(0.166\times 10^8\) moles of phosphorous \(P\) weigh=\(\frac{31}{1}\times 0.166\times 10^8=5.15\times 10^8g=5.15\times 10^5kg\)

Answer:

A

Explanation:

has properties that are different from the original substances.

Answer:The oxygen molecules are more loaded and heavier which weighs down and the molecules and don't allow the same amount of moving ability as the hydrogen moles have.

Explanation:

The pressure will increase on increasing the temperature of container. is the correct answer

What is pressure ?

Pressure is a measure of the force applied perpendicular to a surface per unit area. The unit of pressure in the International System of Units (SI) is the pascal (Pa), but other units, such as atmospheres (atm), bar, torr, and pounds per square inch (psi), are also commonly used, depending on the context. Pressure can be generated by many different sources, including the weight of a column of a fluid, the compression of a gas, and the tension in a solid object. In physics and engineering, pressure is often used to describe the state of a fluid in a container, such as a gas in a cylinder or a liquid in a tank. In this context, pressure is related to the height of the fluid column and the density of the fluid.

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The balanced chemical equation for the reaction is:

2NaOH(aq) + FeCl₂(aq) --> 2NaCl(aq) + Fe(OH)₂(s)

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

Sodium hydroxide => NaOH

Iron (II) chloride => FeCl₂

2NaOH(aq) + FeCl₂(aq) --> 2NaCl(aq) + Fe(OH)₂(s)

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Answer:

Explanation:

Limiting is HCl and excess is Ca(OH)2

excess is 296 grams Ca(OH)2

2 moles H2O will be formed

55.03 moles of KCI are produced when 6743 grams of \(KClO_{3}\) decomposes

To determine the number of moles of KCl produced when 6743 grams of \(KClO_{3}\) decomposes, we need to use the concept of molar mass and the balanced chemical equation.

First, let's calculate the molar mass of \(KClO_{3}\)

The molar mass of potassium (K) is approximately 39.10 g/mol.

The molar mass of chlorine (Cl) is approximately 35.45 g/mol.

The molar mass of oxygen (O) is approximately 16.00 g/mol.

So, the molar mass of \(KClO_{3}\) is:

(39.10 g/mol) + (35.45 g/mol) + (3 * 16.00 g/mol) = 122.55 g/mol.

Now, we need to calculate the number of moles of \(KClO_{3}\):

Number of moles = Mass / Molar mass

Number of moles = 6743 g / 122.55 g/mol = 55.03 mol.

According to the balanced chemical equation:

2\(KClO_{3}\) -> 2 KCl + 3 O2,

we can see that for every 2 moles of \(KClO_{3}\), we obtain 2 moles of KCl.

Therefore, the number of moles of KCl produced will be equal to the number of moles of \(KClO_{3}\) since the ratio is 1:1. Thus, 55.03 moles of KCl will be produced.

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Answer:

700,000 holes

Explanation:

When heat energy occurs to produce free electrons, the number of free electrons produced is directly proportional and equal to the number of holes it produces at that time.

Hence, if silicon crystal (pure) has 700,000 free electrons, then the number of holes it have is also 700,000.

Answer:

C₂H₆(g) + 7/2 O₂(g) → 2 CO₂ + 3 H₂O

Explanation:

To balance equations of combustion (Chemical + O₂ producing CO₂ and water you must do:

1. Write as CO₂ as carbons in the chemical you have:

For the reaction:

C₂H₆(g) + O₂(g) → CO₂ + H₂O

As you have 2 carbons in ethane:

C₂H₆(g) + O₂(g) → 2 CO₂ + H₂O

2. Write the half of H₂O as hydrogen you have:

There are 6 hydrogens → You must place 3 H₂O:

C₂H₆(g) + O₂(g) → 2 CO₂ + 3 H₂O

3. The last step is to write the half of oxygens you have in products.

4 Oxygens from CO₂ and 3 from water:

To answer this question, we need to know the concentration of the RbOH solution. Without this information, we cannot determine the amount of RbOH present in the 28.3 mL sample.
However, if we assume that the concentration of the RbOH solution is known, we can use the formula:
moles of solute = concentration x volume

To find the number of moles of RbOH in the 28.3 mL sample. From there, we can use the molar mass of RbOH (102.47 g/mol) to calculate the mass of RbOH in the sample.
For example, if the concentration of the RbOH solution is 0.1 M, then:
moles of RbOH = 0.1 M x 0.0283 L = 0.00283 moles
mass of RbOH = 0.00283 moles x 102.47 g/mol = 0.290 g
So, a 28.3 mL sample of a 0.1 M RbOH solution would contain 0.290 g of RbOH.
In summary, the amount of RbOH present in a 28.3 mL sample of a solution depends on the concentration of the solution. Without knowing the concentration, we cannot determine the amount of RbOH in the sample.

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Answer:

\(pH = - log(7.6 \times {10}^{ - 5} ) \\ pH = 4.12\)

The frequency of this radiation of a quantum of energy 4.14 *10-14 J is calculated to be 2.58 *10-15 Hz.

The Photoelectric Effect occurs when electrons are released from a metal surface when light strikes it. It was once thought that the greater the intensity of incoming light, the greater its energy, independent of hue. The light was viewed and treated as a wave, however, the wave phenomenon could not explain light's photoelectric actions.

The Quantum, according to Max Planck, is the smallest unit of energy that is released or absorbed in the form of electromagnetic radiation. The energy released or absorbed is proportional to the frequency of the radiation. It may be expressed mathematically as:

E= hc/λ

or

E= hf        ( because, f = c/λ)

where,

E= Energy of the particle

h= Planck's constant

c= speed of light

λ= wavelength of the particle

f = frequency of the radiation

Thus, E= hf

Given,

E = 4,14*10-14J

E= 1.71017356 * 10^20 eV

h= 6.626 *10-34 m2Kg/s

E=hf

f= E/h

f= (1.71017356 * 10^20 eV) / (6.626 *10-34 m2Kg/s)

f= C

Thus, the frequency of this radiation is 6.626 *10-34 m2Kg/s.

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The fuel released 90 calories of heat.

Let suppose that water experiments an entirely sensible heating. Hence, the heat released by the fuel is equal to the heat absorbed by the water because of principle of energy conservation. The heat released by the fuel is expressed by the following formula:

\(Q = m\cdot c \cdot \Delta T\) (1)

Where:

If we know that \(m = 10\,g\), \(c = 1\,\frac{cal}{g\cdot ^{\circ}C}\) and \(\Delta T = 9\,^{\circ}C\), then the heat released by the fuel is:

\(Q = (10\,g)\cdot \left(1\,\frac{cal}{g\cdot ^{\circ}C} \right)\cdot (9\,^{\circ}C)\)

The fuel released 90 calories of heat.

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