The total height of a building, b, and the antenna tower on top of it, t, is 425 feet. The difference in heights of the building and the antenna tower is 324 feet. The following system of equations represents the situation.
b + t = 425 b- t = 324
a. Solve the system of equations using elimination. Explain your process in your own words.
b. What is the height of the antenna tower?

The output when three workers are hired is 5 units..

To find the output when three workers are hired, we need to first determine the total cost and then use the marginal cost to calculate the output.

Find the total cost when three workers are hired.
Average total cost (ATC) = Total cost (TC) / Output (Q)
$50 = TC / Q
Since fixed cost (FC) is $130 and the marginal cost (MC) is $40 per worker, the total cost can be found by adding the fixed cost and the cost of the three workers.
TC = FC + 3(MC)
TC = $130 + 3($40)

Calculate the total cost.
TC = $130 + $120
TC = $250

Use the total cost and average total cost to find the output.
$50 = $250 / Q
Q = $250 / $50
Q = 5

Therefore, the output when three workers are hired is 5 units.

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Then the answer is C. not a real number

An exponent of 1/2 is equivalent to the square root, so we can write:

√-25

That is the square root of a negative number, so we will get the complex numbers ±i

Then the answer is C.

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Answer:

Step-by-step explanation:

i dont know im 11

Answer:

its a i belive

Step-by-step explanation:

they deleted it for some reason

Now we need to apply the given boundary conditions to obtain the specific solution for u(x, y):

Boundary conditions in x-direction:
X(2) = X(27) = 0

Boundary conditions in y-direction:
Y(0) = Y(2m) = 0

1. Identify the Poisson equation and boundary conditions.
2. Use the method of separation of variables to solve the equation.
3. Apply the boundary conditions to obtain the specific solution.

Step 1: Identify the Poisson equation and boundary conditions
The given Poisson equation is:
Δu + 2g = 27 - 1,
where Δu is the Laplacian of the potential function u(x, y).

The provided boundary conditions are:
u(2, 0) = u(2, 2m) = 0,
u(0, y) = u(27, y) = 0.

Step 2: Use the method of separation of variables
We assume that the solution u(x, y) can be written as a product of two functions, one depending on x and the other depending on y, i.e., u(x, y) = X(x)Y(y).

Now, let's substitute this into the Poisson equation:
Δu + 2g = 27 - 1,
which becomes
(X''(x)/X(x) + Y''(y)/Y(y)) + 2g = 26.

Separate the variables:
X''(x)/X(x) = -Y''(y)/Y(y) - 2g = λ,
where λ is the separation constant.

This gives us two ordinary differential equations:
X''(x) = λX(x),
Y''(y) = -(λ + 2g)Y(y).

Step 3: Apply the boundary conditions
Now we need to apply the given boundary conditions to obtain the specific solution for u(x, y):

Boundary conditions in x-direction:
X(2) = X(27) = 0

Boundary conditions in y-direction:
Y(0) = Y(2m) = 0

Solving these equations with their respective boundary conditions will give us a specific solution for the potential function u(x, y). However, it is important to note that solving these equations involves solving eigenvalue problems and possibly infinite series expansions. The full solution process is quite involved and goes beyond the scope of this answer.

Nevertheless, I hope this outline of the solution method helps you understand the process of solving the Poisson equation with given boundary conditions.

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Hey ⊂hcpsibekweou⊃

Answer:

( 6 , 2 )

Step-by-step explanation:

Based on the image we can see that P' is in quadrant 4.

Coordinate plane:

As you may know reflection is known as a flip.

For example: (-5, 4) in quadrant 1  reflects to ( -5, -4 ) quadrant 3.

From the given we can see that P' is (6, -2 ),    Therefore the reflection of             ( 6, - 2) is ( 6 , 2 ).

xcookiex12

4/19/2023

Answer:

She must pay $500 for the materials, and $14 per lawn, then:

We know that the total cost is (assuming that they work for 8 weeks, 6 days per week, and 3 times per day)

C = $500 + $14*(8*6*3) = $2,516.

The total revenue that she can make (with the same assumptions as before) is:

R = N*(8*6*3)

Where N is the amount she charges for each lawn that they mowed.

R = N*144

Now, we do not know how much she charges, so the value of N is unknown.

Now, the profit is equal to the difference between the revenue and the cost, this means that the profit is:

P = R - C = N*144 - ($2,516)

P(N) = N*144 - ($2,516)

If we have, for example, N = $20, the total profit will be:

P($20) = $20*144 - ($2,516) = $364

Answer:

it can't be in a whole number since it is a fraction and will go in decimals

Answer:

(0,0), (0,1), (1,2), (1,3)

Step-by-step explanation:

To determine what makes ordered pairs a function, we have to make sure each input (x) goes to exactly one output (y).

The reason this is the answer is that each input doesn't have exactly one output. (0 goes to 0 and 1. 1 goes to 2 and 3).

Answer:

x=2

Step-by-step explanation:

3(x+2) = 12

Divide by 3

3/3(x+2) = 12/3

x+2 = 4

Subtract 2 from each side

x+2-2 = 4-2

x =2

Answer:

The value of x is equal to 2.

Step-by-step explanation:

3(x + 2) = 12

Distribute 3 to (x + 2)

3x + 6 = 12

Subtract 6 from both sides of the equation.

3x = 6

Divide 3 on both sides of the equation.

x = 2

The value of x is 2

The largest possible volume of this box is 1687.5 cm³ with a base edge of 15 cm and a height of 7.5 cm

Let w = length of the base edge

h = height of the box

A box with a square bottom and an open top is to be made from 675 cm² of material. Hence,

675 cm² = w² + 4wh

4wh = 675 cm² - w²

h = (675 cm² - w²)/4w

The volume of the box is the product of the area of the square base and its height. Hence,

V = w²h

Substitute the expression of h to the equation of volume.

V = w²(675 cm² - w²)/4w

V = (675/4)w - (1/4)w³

To obtain the largest volume possible, the first derivative of the volume should be equal to zero.

V'(w) = 0

V = (675/4)w - (1/4)w³

675/4 - (3/4)w² = 0

Simplify and solve for the value of w.

675/4 - (3/4)w² = 0

(3/4)w² = 675/4

w² = 225

w = 15

length of the base edge = 15 cm

Solve for the value of h.

h = (675 cm² - w²)/4w

h = (675 cm² - (15)²)/4(15)

h = 7.5 cm

height of the box = 7.5 cm

Solve for the volume of the box.

V = w²h

V = (15 cm)²(7.5 cm)

V = 1687.5 cm³

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Answer:

The answer is C) 6-⁵ it is a equivalent expression to 1/6⁵

Answer:

Step-by-step explanation:

Given

When video is posted 5 people watched it

Next day number of viewers doubled

Suppose this trend continues i.e. No of viewers doubled each day

So on 2 nd day no of viewers is \(2\times 5\)

On 3rd day , viewers \(2^2\times 5\)

on n th day , viewers is \(2^{n-1}\times 5\)

So no of viewers in 1 year i.e. on 365 day

\(=2^{365-1}\times 5\)

\(=2^{364}\times 5\)

(ii)Day on which 640 people seen the video

\(2^{n-1}\times 5=640\)

\(2^{n-1}=128\)

\(2^{n-1}=2^7\)

Therefore

\(n-1=7\)

\(n=8\ days\)

Answer:

Let x = the number of lbs of Type A coffee.

We know that this month's blend used 3 times as many pounds of type B coffee as type A coffee.

Total lbs of coffee = x + 3x

The total cost then is:

($ cost for Type A)(x) + ($ cost for Type B)(3x) = $717.60

$5.65x + $4.25(3x) = $717.60

$5.65x + $12.75x = $717.60

$18.40x = $717.60

x = 39 lbs

Simplifying the given expression, the passcode would be: CDOPWR.

To simplify an expression means to solve to find the value in its simplest form.

Simplify the given expression as explained below:

P. 1/2 + 2/3 - 4.25

= 1.17 + 4.25 [addition]

= 5.42

R. -7 * -4 + 3.5

28 + 3.5 [multiply before adding based on PEMDAS]

= 31.5

D. -5.6 + 2.7 - 3.2 = -6.1

W. 3/4 - 0.25 + 6.8

0.75 - 0.25 + 6.8 = 7.3 [apply PEMDAS]

C. -2 * 4.3 - 7.1 [apply PEMDAS]

= -8.6 - 7.1

= -15.7

O. 1/2 + 0.5 - 2/5 [convert all fractions to decimals]

0.5 + 0.5 - 0.4 = 0.6

From the least to the greatest, the passcode would be: CDOPWR.

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There is no such vector-valued function r(t) that satisfies the given condition.

I. There is no such vector ū that satisfies u + ū = (1, 2) because if we add any vector to u, we change its direction and magnitude, but the vector ū should have the same magnitude and opposite direction to u.

II. Let v = (1, 3, -1). Then u + v = (2+1, 1+3, 3-1) = (3, 4, 2) and u x v = (-5, 7, -1). So u x v = u + v. Therefore, v satisfies the given condition.

III. There is no such vector-valued function r(t) because if r(t) = (x(t), y(t)) satisfies the condition that r'(t) = 2r(t), then we have:

x'(t) = 2x(t) and y'(t) = 2y(t)

These are two separate first-order differential equations, which have general solutions of the form:

x(t) = c1e^(2t) and y(t) = c2e^(2t)

where c1 and c2 are constants determined by the initial conditions. However, the vector-valued function r(t) = (x(t), y(t)) cannot have a constant magnitude because its components are functions of t that grow exponentially with time. Therefore, there is no such vector-valued function r(t) that satisfies the given condition.

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The null hypothesis is \(H_0:\mu=3\) and the alternative hypothesis is \(H_1:\mu > 3\)

There are two hypothesis considered in a statistical test. They are:

Formulation of null and alternative hypothesis are considered as the first step of a statistical procedure. The whole procedure, then, continues on testing whether to accept or reject these hypotheses.

Null Hypothesis is the actual hypothesis which is tested. Alternative hypothesis, as its name suggests, is the hypothesis accepted when the null hypothesis is rejected in the test carried out.

Here the sociologist is carrying out the test on the mean number of cars, \(\mu\).

So to check whether the families own more than 3 cars in average,

the null hypothesis will be ,\(\bold{H_0:\mu=3}\)  

and the alternate hypothesis will be,  \(\bold{H_1:\mu > 3}\)

So if the null hypothesis is rejected, then there is the possibility for only more than 3 cars in average.

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3 + 4x > -5 = x > -2

First, subtract 3 from both sides of the equation.

3 - 3 + 4x > -5 - 3

= 4x > -8

Now, divide 4 from both sides of the equation.

= x > -2

5(2 - b) > -3(b - 3) = b < 1/2

First multiply the coefficient by the numbers/variables in the parentheses.

10 - 5b > -3b + 9

Now, add 3b to both sides and subtract 10 from both sides of the equation.

-2b > -1

Now divide -1 by -2, but in an inequality, when you divide by a negative number, the sign gets flipped. So, > will turn into <.

b < 1/2

-1.5a + 8 ≥ 17 = a ≤ 6

First, subtract 8 from both sides of the equation.

-1.5a ≥ 9

Now divide 9 by -1.5, but, again, because the number is negative, the sign gets flipped.

a ≤ 6

5w/3 ≥ 6w/4 + 11/2 = w ≥ 22

First, you need to find a common denominator or LCD. In this case, the LCD is 12. So multiply all the fractions by 12 and eliminate factors of 12.

12(5w/3) ≥ 12(6w/4) + 12(11/2)

4(5w) ≥ 3(6w) + 6(11)

20w ≥ 18w + 66

2w ≥ 66

w ≥ 22

Answer:

t-5=12

Step-by-step explanation:

Answer:

-1 - 22m

Step-by-step explanation:

Answer:

Pie charts

Step-by-step explanation:

A Pie Chart. Pie charts are best to use when you are trying to compare parts of a whole.

Answer:a Pie Chart. Pie charts are best to use when you are trying to compare parts of a whole.

Step-by-step explanation:a Pie Chart. Pie charts are best to use when you are trying to compare parts of a whole.

To calculate the percent of variance that age at first birth shares with highest grade completed, we can use the coefficient of determination (R-squared). R-squared measures the proportion of the total variance in one variable that can be explained by another variable.

First, we need to perform a regression analysis to obtain the R-squared value. This can be done using statistical software or tools like Excel or SPSS.

Once you have the R-squared value, you can interpret it as the percentage of variance that age at first birth shares with highest grade completed. For example, if the R-squared value is 0.5, it means that 50% of the variance in age at first birth can be explained by the highest grade completed.

In conclusion, the R-squared value obtained from the regression analysis will provide the percentage of variance that age at first birth shares with highest grade completed. The higher the R-squared value, the stronger the relationship between the two variables.

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Answer:

C=3/2

Step-by-step explanation:

C4-1=5

Add 1 onto both sides

C4=6

Divide each side by 4

C=6/4

Simplify (Divide by 2)

C=3/2

The coordinates of K so that the ratio of JK to KL is of 2/7 are given as follows:

K(3,-4).

The coordinates of K are obtained applying the proportions in the context of the problem.

The ratio of JK to KL is of 2/7, hence the equation is given as follows:

K - J = 2/9(L - J).

Then the x-coordinate of K is obtained as follows:

x + 3 = 2/9(24 + 3)

x + 3 = 6

x = 3.

The y-coordinate of K is obtained as follows:

y - 4 = 2/9(-32 - 4)

y - 4 = -8

y = -4.

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Answer:

d = 1000

Step-by-step explanation:

88,000 divided by 88 is 1000

The density of an object is 10490kg/m^3.

Density is like rate. It tells you how much of a thing is available for each unit other thing which contains the first thing.

Density = (Total amount available)/(total space which contains that amount)

Given;

The mass of object= 73,430 kilograms

The volume of object= 7m^3

Now

D=mass/volume

D=73430/7

D=10490

Therefore, the density will be 10490kg/m^3.

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The expression f(x)=g(x) indicate the points in the graph where the two functions intersect, i.e. when they cross

In this graph, g(x) cuts f(x) in two points (-4,4) and (0,4)

Now f(x) is a contstant, it has no slope and is equal to 4, always.

Since g(x) cuts f(x) in point (-4,4), you can say that f(-4)= g(-4)

Second cut is in point (0,4), this means f(0)= g(0)

The correct option is number 2 f(-4)= g(-4) and f(0)= g(0)

\((\stackrel{x_1}{-6}~,~\stackrel{y_1}{-7})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{ \cfrac{3}{2}}(x-\stackrel{x_1}{(-6)}) \implies y +7 = \cfrac{3}{2} ( x +6) \\\\\\ y+7=\cfrac{3}{2}x+9\implies {\Large \begin{array}{llll} y=\cfrac{3}{2}x+2 \end{array}}\)