The ___________ was used to find a Jupiter-sized planet through careful measurements of the changing position of a star in the sky.

Answers

Answer 1

A planet the size of Jupiter was discovered using the astrometric approach by taking meticulous measurements of how a star's location changed over time.

A planet the size of Jupiter was discovered through astrology. use exact measurements of a star's shifting sky position. Its goal is to track the motion of such bodies against the background of other stars, making this technique the best for discovering very big planets that are orbiting stars other than their own. Big astral bodies, stars that are nearby, and astral bodies that are close to Earth are the greatest targets for this technique. Measurement is the quantifying of characteristics of an event or thing so that they can be compared to those of other events or objects.

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Related Questions

What are the standard international (si) units of distance

Answers

Answer:

meter

Explanation:

Answer: The International System of Units is a system of measurement based on 7 base units

Explanation: the metre, kilogram, second, ampere, Kelvin, mole, and candela. These base units can be used in combination with each other.

On a frictionless horizontal air table, puck A (with mass 0.251 kg ) is moving toward puck B (with mass 0.371 kg ), which is initially at rest. After the collision, puck A has velocity 0.120 m/s to the left, and puck B has velocity 0.654 m/s to the right.

What was the speed vAi of puck A before the collision?

Calculate ΔK , the change in the total kinetic energy of the system that occurs during the collision.

Answers

(a) The speed  of puck A before the collision is determined as 0.847 m/s.

(b) The change in the total kinetic energy of the system that occurs during the collision is 0.009 J.

Speed of puck A before the collision

The speed of puck A before the collision is calculated from the principle of conservation of linear momentum as follows;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

0.251u₁ + 0.371(0) = 0.251( -0.12) + 0.371(0.654)

0.251u₁ = 0.2125

u₁ = 0.2125/0.251

u₁ = 0.847 m/s to the right

Change in the total kinetic energy of the system

Initial kinetic energy = ¹/₂ x 0.251 x (0.847)² + ¹/₂ x 0.371 x (0) = 0.09 J

Final kinetic energy = ¹/₂ x 0.251 x (-0.12)² + ¹/₂ x 0.371 x (0.654)² = 0.081 J

ΔK.E = 0.081 - 0.09 = 0.009 J ≈ 0 J

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astronaut A can cover 10 meters per minute walking with the heavy shovel. What does
this sentence describe?
a) None of these things
b) Both speed and velocity
C) The velocity of the astronaut
d) The speed of the astronaut

Answers

Answer:

d) The speed of the astronaut

Explanation:

The sentence describes the speed of the astronaut. This speed value is 10meters per minute.

Now let us understand why;

Speed is the distance divided by time. It is a scalar quantity without regard for direction but it has magnitude. The value 10meters per minute clearly shows this instance. We do not know the direction the astronaut is moving towards. Velocity, like speed is the displacement of a body with time. It is a vector quantity and it shows the direction of motion. For example, 10m/s due west is a velocity value because we know the direction.

Therefore, since there is no directional sense, the value indicates speed.

The given sentence describes the speed of the astronaut. Hence, option (d) is correct.

Given data:

The distance covered by the astronaut A is, d = 10 m.

the time interval is, t = 1 min = 60 s.

Clearly,  the given sentence describes the speed of the astronaut. This speed value is 10 meters per minute.  This is because of following reason:

Speed is the distance divided by time. It is a scalar quantity without regard for direction but it has magnitude. The value 10meters per minute clearly shows this instance. We do not know the direction the astronaut is moving towards. Velocity, like speed is the displacement of a body with time. It is a vector quantity and it shows the direction of motion. For example, 10m/s due west is a velocity value because we know the direction.

Thus, we can conclude that the given sentence describes the speed of the astronaut. Hence, option (d) is correct.

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What will the reading of the voltmeter be at the instant the switch returns to position a if the inertia of the d'Arsonval movement is negligible

Answers

Answer:

hello your question is incomplete attached below is the complete question

answer :

20.16 v

Explanation:

The reading of the voltmeter at the instant the switch returns  to position a

L = 5H

i ( current through inductor ) = 1/L ∫ V(t) d(t) + Vo

                                               = 1/5 ∫ 3*10^-3  d(t)  + 0 = 0.6 * 10^-3 t

iL ( 1.6 s ) = 0.6 * 10^-3 * 1.6 = 0.96 mA

Rm ( resistance ) = 21 * 1000 = 21 kΩ

 The reading of the voltmeter ( V )

V = IR

   = 0.96 mA * 21 k Ω  = 20.16 v

What will the reading of the voltmeter be at the instant the switch returns to position a if the inertia

In golf par is the
A. number of golfers who can play a hole at a time
B. typical number of strokes needed to complete a hole .
C. typical number of golfers who pass the course
D. number of holes in a golf course

Answers

In golf, par is the (B) typical number of strokes needed to complete a hole.

Par is a term used in golf to describe the number of strokes a skilled golfer should be able to complete a particular hole or course in. It is determined based on the length and difficulty of the hole or course. A golfer's score for a particular hole is then compared to the par for that hole to determine whether they scored above par (meaning they took more strokes than the expected number), below par (took fewer strokes), or at par (took the expected number of strokes). The overall score for a round of golf is also compared to the total par for the course to determine a golfer's performance.

Answer:

B. typical number of strokes needed to complete a hole.

An object has a coefficient of static friction of 0.3 and a normal force of 30 N. Find the force of static friction.

Answers

Answer:

9N

Explanation:

static friction=normal force x coefficient of static friction

so static friction =30N x 0.3= 9N

Explanation:

9N is the static friction

Which heart rate zones are generally anaerobic in nature?

Answers

Answer:

Below

Explanation:

Not sure what numbers you have been taught to use, but heart rates (BPM) above 80% of your maximum heart rate is anaerobic

  your approximate Max heart rate = ( 220 - age in years)

      so if you are 20 y/o    max = 220 - 20 = 200 bpm

            80% of this is 160 beats per min <===above this is anaerobic

in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting

Answers

It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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A 15,000 kg railroad car. A, traveling a speed of 32.0 m/s strikes an identical car, B, at rest. If the cars lock together as result of the collision, what is their common speed just afterwards?

Answers

The speed of the cars as they stuck together is 16 m/s.

What is the speed after Collison?

We know that the momentum after the Collison must be equal to the total momentum before the Collison and thus is what we call the principle of the conservation of linear momentum and that is what we are going to apply here so that it can help us to solve this problem at hand here.

Given that;

Momentum before Collison= Momentum after Collison

Then we have;

( 15,000 kg * 32.0 m/s) + (15,000 kg * 0 m/s) = (15,000 kg + 15,000 kg)v

v = ( 15,000 kg * 32.0 m/s) / (15,000 kg + 15,000 kg)

v = 16 m/s

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List two types of current

Answers

Answer:

static and current electricity

A 7.30 kg sign hangs from two wires. The first wire is attached to the left end, and pulls 28.0 N directly left. What is the y-component of the force of the second wire?

Answers

Answer:

Approximately \(71.6\; {\rm N}\) (assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\).)

Explanation:

Refer to the diagram attached. Forces on this object are:

Tension on the left, from the wire on the left end.Tension on the right, from the wire on the other end.Weight, from the planet.

Assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\), the magnitude of the weight of the sign would be:

\(\begin{aligned}(\text{weight}) &= m\, g \\ &= (7.30\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-1}}) \\ &\approx 71.6\; {\rm N}\end{aligned}\).

Note that weight points downwards (negative) and is entirely in the vertical direction. As a result, the \(y\)-component of weight would be equal to \((-71.6)\; {\rm N}\).

Hence, the \(y\)-component of these forces would be:

\(0\; {\rm N}\) for the wire on the left end, since this tension is entirely horizontal (entirely in the \(x\)-direction,)\((-71.6)\; {\rm N}\) for the weight, which points downwards, andNot yet found for the tension from the other wire.

Since forces on the object to be balanced, forces need to be balanced in each component. For forces in the \(y\)-component to be balanced, forces in the vertical direction need to add up to \(0\; {\rm N}\):

\(0\; {\rm N} + (-71.6)\; {\rm N} + (\text{$y$-component of tension on the right}) = 0\; {\rm N}\).

Hence, the \(y\)-component of the tension from the wire on the right end would be \(71.6\; {\rm N}\).

A 7.30 kg sign hangs from two wires. The first wire is attached to the left end, and pulls 28.0 N directly

Compare the time it
takes the light to travel from your
teacher to your eye with the time
it takes sound to travel the same
distance.

Answers

Answer:

Light takes less time than sound.

Explanation:

Let's say, the teacher and the student are at a distance "d" from each other.

The medium around them would be air.

And,

The speed of light in air is approx. 3× 10 m/s

while, the speed of sound in air is approx. 330 m/s

We have a formula that establishes the relation between speed, distance and time.

\( \boxed{ \mathsf{speed = \frac{distance}{time} }}\)

Our hunt for time — Speed in both the scenarios is known to us whereas the distance is same.

Sound

\( \mathsf{330 = \frac{d}{time_{s}} }\)

\( \underline{\mathsf{time _{s} = \frac{d}{330} }}\)

Light

\( \mathsf{3 \times {10}^{8} = \frac{d}{time _{l} } }\)

\( \underline{ \mathsf{ time _{l} = \frac{d}{3 \times {10}^{8}} }}\)

The best way of comparison is finding their ratio.

\( \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ \frac{d}{330} }{ \frac{d}{3 \times {10}^{8} } } }\)

simplifying the fraction

\( \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{d \times (3 \times {10}^{8} )}{330 \times d}}\)

d gets canceled and we're left with the following expression

\( \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ (3 \times10 \times {10}^{7} )}{330}}\)

30, being a common factor in the numerator as well as denominator, gets canceled out. and in its place remains 1/ 11

(why?

=> 30÷330 = 1÷11)

\( \implies \mathsf{\frac{ time_{s}}{time_{l} } = \frac{ 1\times {10}^{7} }{11}}\)

taking time to the numerator on the other side.

\( \implies \mathsf{time_{s} = \frac{ 1\times {10}^{7} }{11}\times time_{l}}\)

Therefore, we get timeₛ is approx. 10⁶ times the timeₗ.

That's a big difference, no wonder light's way much faster than sound.

As lesser the time taken to cover a distance, faster is the wave.

The sound takes about 874,000 times MORE time than the light takes.

ectile mo
A rifle is aimed horizontally at a target 35.0 m away. The bullet hits the target hits the
target 2.10 cm below the aiming point. a) What is the bullet's time of flight? b) What is
its muzzle velocity?

Answers

the velocity of the muzzle would be 15 becuase you divide the target and the target below

The Sun is only an average sized star. Why does it appear so much brighter than any other star?

Answers

Because it's so much closer to us than any other star.

Which type of wall would make the best soundproofing for room?
A.
1.0 centimeter thick glass
OB.
two layers of 0.5 centimeter thick glass with 0.5 centimeters of air between them
C.
two layers of 0.5 centimeter thick glass with 0.3 centimeters of vacuum between them
OD.
1.0 centimeter thick steel

Answers

Among the options given, the choice that would make the best soundproofing for a room is option C: two layers of 0.5 centimeter thick glass with 0.3 centimeters of vacuum between them.

Soundproofing is achieved by reducing the transmission of sound waves from one side of the wall to the other. In this case, the combination of two layers of glass with a vacuum between them helps to reduce sound transmission effectively.

Glass is a denser material compared to air or vacuum, so it naturally provides some sound insulation. Adding an extra layer of glass creates a barrier that helps to further dampen sound vibrations. The vacuum between the glass layers acts as an additional sound barrier, as sound waves have difficulty propagating through a vacuum due to the absence of a medium for transmission.

On the other hand, a single layer of 1.0 centimeter thick glass (option A) or two layers of 0.5 centimeter thick glass with 0.5 centimeters of air between them (option B) would provide some sound reduction but not as effective as the combination of glass layers with a vacuum in option C.

1.0 centimeter thick steel (option D) would have high density and mass, which could help with sound insulation to some extent. However, steel can still transmit vibrations and might not be as effective as the combination of glass layers with a vacuum in option C for soundproofing a room.

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A ball is thrown from the catcher to the 3rd baseman with a speed of 20
meters per second. If it travels 30 m, how long did it take to get to the 3rd
baseman?

Answers

Answer:

The ball took 1.5 seconds to get to the 3rd baseman

Explanation:

Constant speed motion

If a body travels the same distance per unit of time, the body has a constant speed. The equation for the distance x is:

x=v.t

Where v is the constant speed and t is the time.

Solving for t:

\(\displaystyle t=\frac{x}{v}\)

The ball is thrown with a speed of v= 20 m/s and travels x=30 m, thus the time taken is:

\(\displaystyle t=\frac{30}{20}=1.5\)

The ball took 1.5 seconds to get to the 3rd baseman

A 0.140-kg baseball traveling 34.0 m/s strikes the catcher's mitt, which, in bringing the ball to rest, recoils backward 19.0 cm ​

Answers

Add then subtract then u will get ur answer

What makes the molecular shape of CO2 and NH3 different?

Answers

Answer:

Explanation:

CO2 is linear whereas NH3 has a trigonal pyramidal shape. NH3 is sp3 hybridized and the lone pairs on nitrogen repel other groups around nitrogen thus the bond angle becomes less than 109.5 (typically around 106.7).

CO2 is also sp hybridized and both O are equally pulling on both sides rendering the molecule to be non polar and linear with a bond angle of 180.

Consider the equal and opposite charges located on the y-axis as shown in the figure, where a = 0.35 m and |Q| = 3.3 μC.

Answers

At point P, the electric potential is 0. This is due to the fact that the positive and as a result, at point P, their electric potentials are cancelled.

What are the contrasting fees?

Positive and negative electrical charges are referred to as opposite forms of charge. A positively charged object will draw a negatively charged object, in accordance with our core concept of charge interaction.

We can apply the following equation to find the electric potential at point P: V = kQ/r1 - kQ/r2.

where:

k = Coulomb's constant (9 x 10⁹ N m²/C²),Q = magnitude of the charge (3.3 μC = 3.3 x 10⁻⁶ C), r1 = distance from the positive charge to point P (a = 0.35 m), r2 = distance from the negative charge to point P (a = 0.35 m)

Using these values, we can calculate the potential at point P as follows:

V = (9 x 10⁹ N m²/C²) * (3.3 x 10⁻⁶  C) / (0.35 m) - (9 x 10⁹ N m²/C²) * (3.3 x 10⁻⁶ C) / (0.35 m)

V = 0.

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I have a physics question.
The planet Mercury has a radius of about 0.38 Earth radii and a mass of only 0.055 Earth masses. Estimate g on Mercury.

Answers

By Newton's second law, the gravitational force F between an object of mass m and a planet of radius r and mass M is on the surface of the planet is

F = G M m / r ² = m a

where

G = 6.67 × 10⁻¹¹ N•m²/kg², the universal gravitational constant

a = the acceleration of the object (not the planet; note that the right side is m times a, and not M times a)

The object's mass cancels on either side, leaving you with

a = G M / r ²

and this acceleration is due to gravity. On Earth, a = g.

Let M be the mass of Earth and r its radius; then

g (Earth) = G M / r ² ≈ 9.80 m/s²

To find g on Mercury, replace r with 0.38r and M with 0.055M :

g (Mercury) = G (0.055M) / (0.38r )² = 0.055/0.38² G M / r ²

g (Mercury) ≈ 0.38 g (Earth) ≈ 3.73 m/s²

a)Levers work because some forces produce a ______

plss helppp

Answers

Answer:

Force

Explanation:

What is albedo? What on Earth has high albedo?

Answers

Answer:

The fraction of incident light or radiation reflected by a surface or body, commonly expressed as a percentage.

2.

biology The whitish inner portion of the rind of citrus fruits that is a source of pectin, commonly referred to as the pith.

Explanation:

PLEASE HELP ME!!!!!!!!!!!!!

PLEASE HELP ME!!!!!!!!!!!!!

Answers

Answer:

D gravity

Explanation:

please mark me brainliest

Answer:

D. The force that the branch applies to the kitten

Explanation:

I just took the quiz and got it correct!

It would be greatly appreciated if you help me answer this question on my worksheet.

It would be greatly appreciated if you help me answer this question on my worksheet.

Answers

Take into account that the total linear momentum must conserve, that it, it is equal before and after the collision:

p_before = p_after

or by using the expression for the momentum p = mv, you have for the given situation:

\(m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}_\)

Based on the given information you have:

m1 = 7.05kg

m2 = 1.52kg

v1i = 8.24m/s

v2i = 0m/s

v1f = ?

v2f = 13.2m/s

m1 is the mass of the ball, m2 is the mass of the pin, v1i and v1f makes reference to speed of ball before and after the collision, v2i and v2f makes reference to the speed of pin before and after the collision:

By solving the equation above for v1f, you get:

\(v_{1f}=\frac{m_1v_{1i}+m_2v_{2i}-m_2v_{2f}}{m_1}\)

By replacing the values of the parameters:

\(\begin{gathered} v_{1f}=\frac{(7.05kg)(8.24\frac{m}{s})+(1.52kg)(0\frac{m}{s})-(1.52kg)(13.2\frac{m}{s})}{7.05kg} \\ v_{1f}\approx5.34\frac{m}{s} \end{gathered}\)

Hence, the speed of the ball after the collision is approximately 5.34m/s

The scale on the horizontal axis is 8 s per division and on the vertical axis 5 m per division. What is the time represented by the third tic mark on the horizontal axis

Answers

Answer:

24 s

Explanation:

8 s / tic    *    3 tic = 24 sec from origin

If you are driving 80 km/h along a straight road and you look to the side for 1.7 s , how far do you travel during this inattentive period?
Express your answer using two significant figures.

Answers

Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.

How far did the driver travel during the inattentive period?

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

Speed = 80 km/hTime = 1.7sDistance travelled = ?

First, convert 1.7 seconds to hours.

Time = 1.7s = (1.7 / (60×60)hr = 1.7/3600 hrs

Now, find the distance traveled during the inattentive period.

80 km/h = Distance ÷ 1.7/3600 hrs

Distance = 80 km/h × 1.7/3600 hrs

Distance = 136/3600 km

Distance = 0.037 km.

Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.

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If an airplane is accelerating down a runway at 2.5 m/s^2, how much is it’s velocity changing each second?

If an airplane is accelerating down a runway at 2.5 m/s^2, how much is its velocity changing each second?

Answers

If an airplane is  is accelerating down a runway at 2.5 m/s². It's velocity changes 2.5 m/s in each second.

What is acceleration?

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.

Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

Hence, the velocity of the airplane changes 2.5 m/s in each second  when it  is accelerating down a runway at 2.5 m/s².

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how do you organize things or concepts

Answers

To organize things and concepts:-

speak thoughts in a principal place. begin via growing a primary area wherein you gather and share thoughts.Label your lists of ideas. To hold thoughts simply organized, streamline them by using subject matter.ensure a pacesetter owns every listing.deal with your concept bank like an inbox.

To organize an essay, begin by writing a thesis assertion that makes a completely unique statement about your subject matter. Then, write down every one of the points you need to make that support your thesis announcement. as soon as you've got all of your primary factors, enlarge them into paragraphs the use of the records you observed throughout our studies.

Without a clear organizational pattern, your reader may want to become burdened and get bored. The way you shape your essay facilitates your readers to draw connections between the body and the thesis, and the structure also maintains our target as you plan and write the essay.

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Consider six proposed properties of electromagnetic radiation: wave speeds of 3.00X10^8

Answers

Because of the way our eyes have developed, we can only detect waves that have the specific duration and frequency that define them; this is why we can really see white light but not electromagnetic radiation or gamma radiation.

Bands : "Wavelength of 0.11 nm" for band "X ray band alone".

band "visible light band only": speed of \(3\) × \(10^{8} m/s\)  frequency of \(2.331. 10^{16}\)Hz, frequency of  \(5.48 10^{14}\) Hz. a wave length of 637 nm.

The aforementioned waves share any characteristics with the other band. We might be able to view the X-rays if they were like that.

band "neither band": "speed of 3 × \(10^{8} km/s"\). The light moves more quickly than anything else.

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4. A disobedient student dropped his Physics textbook (mass 0.1kg) from the window (15m above the ground). How fast was it going when it hit the ground?

Answers

Answer:

v= 17.15 m/s

Explanation:

mass of the book=0.1 Kg

height above ground, h= 15 m

Using conservation of energy

Potential energy is converted into kinetic energy

\(mgh = \frac{1}{2}mv^2\)

\(v=\sqrt{2gh}\)

\(v=\sqrt{2\times 9.8\times 15}\)

\(v=\sqrt{294}\)

v= 17.15 m/s

Hence, the book will hit the ground at the speed of 17.15 m/s.

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