To find the values of f(x) at each given value of x, draw a vertical line on each given value of x and check which value of y corresponds to that value of x using the graph of f(x).
The problem says that the function is an even function. This means that:
\(f(x)=f(-x)\)Then, the function for negative values of x is the same that the function evaluated on the corresponding positive values.
For x=-1, we know that:
\(f(-1)=f(1)\)From the graph, we can see that f(1)=1
Repeating this procedure for x=-3, -5 and -6 we find that:
\(\begin{gathered} f(-1)=f(1)=1 \\ f(-3)=f(3)=1 \\ f(-5)=f(5)=3 \\ f(-6)=f(6)=3 \end{gathered}\)Y=-3 Y=Ax2+4x-4 In the system of equations above, a and b are constants. For which of the following values of a and b does the system of equations have exactly two real solutions?
A) -4
B) -2
C) 2
D) 4
For constant A to be -4 (option 1) the system of equations have exactly one real solution.
NOTE: We are working with the problem statement: Y=-3 Y=Ax2+4x-4 In the system of equations above, a is constant. For which of the following values of a does the system of equations have exactly one real solution?
We have given, y=-3
y= Ax^2+4x-4
Therefore, -3= Ax^2+4x-4
or, Ax^2+4x-1=0
For second order equation of ax^2+bx+c=0 have a solution for
x= [-b± (√b^2-4ac)]/2a] [Ax2 + Bx + C = 0 is the Sridharacharya equation, where a, b, and c are real values and a 0. The Sridharacharya formula, which is stated as x = (-b (b2 - 4ac)) / 2a, provides the answer to the Sridharacharya equation.]
For single solution b^2-4ac=0
here, Ax^2+4x-1=0
4^2 - 4a(-1)=0
16+4a=0
a= -(16)/4
a= -4
option A is correct .
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This is only true equation when A is equal to -2. Therefore, the correct answer is B) -2.
B) -2
The given system of equations can be written as:
Y = A*x^2 + 4*x - 4
We can solve this equation by using the Quadratic Formula. The Quadratic Formula states that the solutions to the equation are given by:
x = [-b +/- sqrt(b^2-4ac)]/2a
where a, b, and c are the coefficients of the equation. In this case, a = A, b = 4, and c = -4.
Substituting these values into the equation, we get:
x = [-4 +/- sqrt(4^2-4*A*(-4))]/2A
Simplifying this, we get:
x = [-4 +/- sqrt(16 + 16A)]/2A
For the system of equations to have two real solutions, the value of the square root must be greater than or equal to zero. This means that 16 + 16A must be greater than or equal to zero.
This is only true when A is equal to -2. Therefore, the correct answer is B) -2.
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8k = 0
A.)8
B.)16
C.)0
D.)4
Answer:
C
Step-by-step explanation:
Anything divided by 0 is equal to 0.
The measured width of the office is 30mm. If the scale of 1: 800 is used, calculate the actual width of the building in metres
Answer:
Step-by-step explanation:
This Venn diagram has three regions. In which region does any rectangle belong? A B C
Answer:
A
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
A) Find an equation for the line perpendicular to the tangent line to the curve y=x^3-4x+6 at the point (2,6)
-The equation is y=
b) What is the smallest slope on the curve? At what point on the curve does the curve have this slope?
-The smallest slope on the curve is
-The curve has the smallest slope at the point
c) Find equations for the tangent lines to the curve at the points where the slope of the curve is 8.
Answer:
f(x) = x³ - 4x + 6
f'(x) = 3x² - 4
a) f'(2) = 3(2²) - 4 = 12 - 4 = 8
6 = 8(2) + b
6 = 16 + b
b = -10
y = 8x - 10
b) 3x² - 4 = 0
3x² = 4, so x = ±2/√3 = ±(2/3)√3
= ±1.1547
f(-(2/3)√3) = 9.0792
f((2/3)√3) = 2.9208
c) 3x² - 4 = 8
3x² = 12
x² = 4, so x = ±2
f(-2) = (-2)³ - 4(-2) + 6 = -8 + 8 + 6 = 6
6 = -2(8) + b
6 = -16 + b
b = 22
y = 8x + 22
f(2) = 6
y = 8x - 10
The equation perpendicular to the tangent is y = -1/8x + 25/4
-The smallest slope on the curve is 2.92
The curve has the smallest slope at the point (1.15, 2.92)
The equations at tangent points are y = 8x + 16 and y = 8x - 16
Finding the equation perpendicular to the tangentFrom the question, we have the following parameters that can be used in our computation:
y = x³ - 4x + 6
Differentiate
So, we have
f'(x) = 3x² - 4
The point is (2, 6)
So, we have
f'(2) = 3(2)² - 4
f'(2) = 8
The slope of the perpendicular line is
Slope = -1/8
So, we have
y = -1/8(x - 2) + 6
y = -1/8x + 25/4
The smallest slope on the curveWe have
f'(x) = 3x² - 4
Set to 0
3x² - 4 = 0
Solve for x
x = √[4/3]
x = 1.15
So, we have
Smallest slope = (√[4/3])³ - 4(√[4/3]) + 6
Smallest slope = 2.92
So, the smallest slope is 2.92 at (1.15, 2.92)
The equation of the tangent lineHere, we set f'(x) to 8
3x² - 4 = 8
Solve for x
x = ±2
Calculate y at x = ±2
y = (-2)³ - 4(-2) + 6 = 6: (-2, 0)
y = (2)³ - 4(2) + 6 = 6: (2, 0)
The equations at these points are
y = 8x + 16
y = 8x - 16
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At times 6 x 10 To the six power cubic feet of water go over Niagara Falls every minute there are 1440 minutes and one day at this rate how many cubic feet of water would go over Niagara Falls in one day
Answer:
6.718464×10^13 / 67184640000000
Step-by-step explanation:
6×10^6 = 46656000000 × 1440 = 67184640000000
Which best explains the forces acting on the objects?
Answer:
this answer is not avaliable because i didnt have any options.
Step-by-step explanation:
Answer:
The answer is B: Objects W and Y have balanced forces, and objects X and Z have unbalanced forces.
Step-by-step explanation:
i need to solve this so can you pls hlp
Answer: D
Step-by-step explanation: x is a variable, and so is the number of tractors he sells. he is going to get paid $1000 for sure each month.
So 150x(the number of tractors) + 1000(his pay each month)
Together, Steve and Tom sold 125 raffle tickets for their school. Steve sold 17 more than three times as many raffle tickets as Tom. How many raffle tickets did each boy sell?
Tom sold 27 raffle tickets and Steve sold 98 raffle tickets.
What is an equation?Two algebraic expressions having the same value and symbol '=' in between are called an equation.
Given:
Together, Steve and Tom sold 125 raffle tickets for their school.
Steve sold 17 more than three times as many raffle tickets as Tom.
Let s be the number of raffle tickets sold by Steve and t be the raffle tickets sold by Tom.
So,
3t + 17 + t = 125
4t = 108
t = 27
And s = 98
Therefore, Steve sold 98 and Tom sold 27 tickets.
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When posted overseas to country A at age r, the employees of
a large company are subject to a force of mortality such that, at exact duration
†years after arrival overseas (1 = 0, 1,2, 3,4),
The probability that an employee posted to country A at age 30 will survive to age 40 if she remains in that country is 2 x 10⁻⁶³
Probability is a mathematical concept that describes the likelihood of a specific event occurring within a set of possible outcomes
Let's start by defining some terms. The force of mortality, also known as the death rate, is the number of deaths per unit time per unit of population.
The probability of survival is the chance that an individual will live past a certain age. In our case, we want to know the probability of surviving from age 30 to age 40 while living in country A.
To calculate the probability of survival, we will use the formula:
\(P(x) = e^{-qx}\)
Where P(x) is the probability of survival at age x and qx is the force of mortality at age x.
First, we will calculate the force of mortality for the first five years after arrival in country A using the equation given in the question:
90x+1 = (6 - 1)9x+1
For x = 30, we have:
90(30) + 1 = (6 - 1)9(30) + 1
2701 = 5 * 891 + 1
2701 = 4445 + 1
2700 = 4445
So, q30 = 4445/30 = 148.5
Next, we will use this value to calculate the probability of survival for the first five years in country A:
\(P30 = e^{-q3} = e^{-148.5} = 1.2 \times 10^{-64}\)
Since the force of mortality for those who have lived in country A for at least five years is 50% greater than the US Life Tables, 2002, Females, we can calculate the force of mortality for the next 10 years as follows:
qx = 1.5 x qx from US Life Tables
Using the values from Table 3.11, we have:
q31 = 1.5 x 98,424 = 147,636
q32 = 1.5 x 98,362 = 147,543
q33 = 1.5 x 98,296 = 147,444
q34 = 1.5 x 98,225 = 147,338
q35 = 1.5 x 98,148 = 147,222
q40 = 1.5 x 97,500 = 146,250
Finally, we can use these values to calculate the probability of survival from age 31 to age 40:
\(P31 = e^{-q31} = e^{-147,636} = 1.3 \times 10^{-65}\\ \\P32 = e^{-q32} = e^{-147,543} = 1.4 \times 10^{-66}\\\\P33 = e^{-q33} = e^{-147,444} = 1.5 \times 10^{-67}\\\\P34 = e^{-q34} = e^{-147,338} = 1.6 \times 10^{-68}\\\\P35 = e^{-q35} = e^{-147,222} = 1.7 \times 10^{-69}\\\\P40 = e^{-q40} = e^{-146,250} = 2.0 \times 10^{-63)}\\\\\)
Complete Question:
When posted overseas to country A at age x, the employees of a large company are subject to a force of mortality such that, at exact duration t years after arrival overseas (t = 0,1,2,3,4), 90x+1 = (6 - 1)9x+1 where qx+t is on the basis of US Life Tables, 2002, Females. For those who have lived in country A for at least five years the force of mortality at each age is 50% greater than that of US Life Tables, 2002, Females, at the same age. Some lx values for this table are shown in Table 3.11.
An extract from the United States Life Tables, 2002,
Females. Age,
x 30 31 32 33 34 35 40
1x 98,424 98,362 98,296 98,225 98,148 98,064 97,500
Calculate the probability that an employee posted to country A at age 30 will survive to age 40 if she remains in that country.
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I Н. G. A F B 00 Darat h E C D The regular octagon ABCDEFGH rotates 135° clockwise about its center to form octagon ABCDEFGH. Point A' of the image coincides with point of the preimage. Point B of the image coincides with point of the preimage. I Н. G. A F B 00 Darat h E C D The regular octagon ABCDEFGH rotates 135 ° clockwise about its center to form octagon ABCDEFGH . Point A ' of the image coincides with point of the preimage . Point B of the image coincides with point of the preimage .
The point A' of the image coincides with point of the preimage of point D.
What is a transformation of geometry?A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.
Rotation does not change the size and shape of the geometry.
The regular octagon ABCDEFGH rotates 135° clockwise about its center to form octagon A'B'C'D'E'F'G'H'.
Then the point A' of the image coincides with point of the preimage of point D.
The diagram is given below.
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23. Which number below could not be used to
PLEASEE HELP!!
which could be a possible root of 3x4 10x3 9x2 40x 12 0
\(\left(3x-1\right)\left(x-3\right)\left(x+2\right)\left(x-2\right)\) is the possible root
What is a root ?
Mathematicians refer to a number as having a root if it can be multiplied by itself to give the original number. The square root of 49, for instance, is 7, as 77=49. 7 is referred to as the square root of 49 in this instance because it takes 49 to multiply 7 by itself twice. Considering that 333=27, the cube root of 27 is 3.
Quadratic equation's roots The roots of a quadratic equation are the values of the variables that fulfill the equation. In other words, if f() = 0, then x = is a root of the quadratic equation f(x). The x-coordinates of the sites where the curve y = f(x) intersects the x-axis are the real roots of an equation f(x) = 0.
3x^4 -10x^3 -9x^2 + 40x - 12
=\(\left(3x-1\right)\frac{3x^4-10x^3-9x^2+40x-12}{3x-1}\)
=\(\left(3x-1\right)\left(x^3-3x^2-4x+12\right)\)
= \(\left(3x-1\right)\left(x-3\right)\left(x+2\right)\left(x-2\right)\)
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Solve y = ax² + c for x.
O x
x= ± √ay-c
O
O
x = ±₁
X=
X=
у-с
a
y
y + c
a
In the quadratic equation y = a\(x^{2}\) + c ,the value of x = ± \(\sqrt \frac{y-c}{a}\)
A quadratic equation is any equation containing one term wherein the unknown is squared and no term wherein it's far raised to a higher power.
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax2 + bx + c = 0, in which a and b are the coefficients, x is the variable, and c is the constant term.
To find the value of x
Assuming \(a\neq o\)
First, subtract c from both the sides to get:
\(y-c=ax^{2}\)
then, divide both sides by \(a\) and transpose to get:
\(x^{2} =\frac{y-c}{a}\)
So, \(x\) must be a square root of \(\frac{y-c}{a}\) and we can deduce:
\(x=\) ± \(\sqrt \frac{y-c}{a}\)
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The Venn diagram here shows the cardinality of each set. Use this to find the cardinality of the given set.
With the help of the given Venn diagram, the answer of n(A∪B) is 44 respectively.
What is the Venn diagram?A Venn diagram is a visual representation that makes use of circles to highlight the connections between different objects or limited groups of objects.
Circles that overlap share certain characteristics, whereas circles that do not overlap do not.
Venn diagrams are useful for showing how two concepts are related and different visually.
When two or more objects have overlapping attributes, a Venn diagram offers a simple way to illustrate the relationships between them.
Venn diagrams are frequently used in reports and presentations because they make it simpler to visualize data.
So, we need to find:
A ∪ B
Now, calculate as follows:
The collection of all objects found in either the Blue or Green circles, or both, is known as A B. Its components number is:
8 + 7 + 14 + 6 + 1 + 8 = 44
n(A∪B) = 44
Therefore, with the help of the given Venn diagram, the answer of n(A∪B) is 44 respectively.
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A special drill is used at a construction site to dig holes. A hole is dug to a depth of 2.75 feet when the drill hits rock. The progress slows to 5/6 feet per hour of digging. The depth of the hole must be at least 10 1/2 feet by the end of the day to stay on schedule. What is the minimum amount of time the drill must continue at its present rate to complete the hole on schedule? Select from the drop-down menus to correctly complete the statement.
Answer:
9.3 hrs to finish
Step-by-step explanation:
(10.5 - 2.75)ft / (5/6 ft/hr) = 9.3 hrs to go
Which is the better buy? 2-quart carton of non-dairy creamer for $9.96 2-pint carton of non-dairy creamer for $3.94
2-quart carton = $9.96
2-pint carton = $3.94
1 quart ------------------ 2 pints
2 quarts --------------- x
x = 4 pints
Now, divide the rpice by the number of pints
a) 9.96/4 = $2.49/pint
b) 3.94/2 = $1.97 pint
Then, it's cheaper to buy a 2-pint carton of non-dairy creamer
To find the 95% confidence interval for the population standard deviation using the bootstrap method. You repeatedly sample with replacement from the sample, tens of thousands of times. For each sample, you compute the sample standard deviation. What is the next step? Group of answer choices
what does it mean?
?????????????????????????
PLS HELP IM BEING TIMED
Answer: am so sorry but I don’t know nothing
Step-by-step explanation:
What is the value in simplest form 8*4/9
Answer:
32/9 or 3.55555555556
hope this answer helps you!
Trina has a credit card that uses the adjusted balance method. For the first 10
days of one of her 30-day billing cycles, her balance was $780. She then
made a purchase for $170, so her balance jumped to $950, and it remained
that amount for the next 10 days. Trina then made a payment of $210, so her
balance for the last 10 days of the billing cycle was $740. If her credit card's
APR is 17%, which of these expressions could be used to calculate the
amount Trina was charged in interest for the billing cycle?
OA. (30)($780)
365
B.
O C.
D.
0.17
365
0.17
365
0.17
365
30
30
(10 $780+10 $950 +10 $210)
30
10
$780+10$950+10 $740
30
•30) ($570)
The expression that could be used to calculate the amount Trina was charged in interest for the billing cycle is (APR / 365) x 30 days x adjusted balance.
What is the adjusted balance method?The adjusted balance method is one of the methods for computing the finance charge (interest and other fees) for credit cards.
The adjusted balance is the ending balance determined after adjusting the opening balance with purchases and payments.
Credit card interest method = adjusted balance method
Beginning balance = $780
Purchase = $170
Payment = $210
Adjusted balance, AB = $740 ($780 + $170 - $210)
APR = 17% = 0.17 (17/100)
The interest charged = (APR / 365) x 30 days x adjusted balance
= $10.34 [(0.17/365) x 30 x $740]
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Find the mass and center of mass of the lamina that occupies the region D and has the given density function ?.
D is bounded by y = (1 ? x^2) and y = 0;
?(x, y) = 7ky
m =
(x bar, y bar)=
To find the mass of the lamina, we need to integrate the density function over region D. The density function is given by? (x, y) = 7ky, where k is a constant. The region D is bounded by y = \((1 ? x^2)\) and y = 0, and the limits of integration are \(0 < = y < = (1 - x^2)\) .
So, the mass of the lamina is:
\(m = ∫∫?(x, y) dx dy = ∫∫ 7ky dx dy\\= 7k ∫∫ y dx dy = 7k * ∫ (1 - x^2) dy dx\\= 7k * ∫(0 to 1 - x^2) y dy\\= 7k * (1/2 * ∫(0 to 1 - x^2) y^2 dy)\\= 7k * (1/2 * [y^3/3] evaluated at y = (1-x^2) and y=0)\\= 7k * (1/2 * [((1-x^2)^3/3] - 0))= 7k * (1/2 * (1/3 - x^6))\)
To find the center of mass (x bar, y bar) of the lamina, we need to find the x and y coordinates of the center of mass.
The x-coordinate is given by
\((x bar) = 1/m * ∫∫ x ?(x, y) dx dy = 1/m * ∫∫ x * 7ky dx dy \\= 7k * ∫ (x * y) dx dy\\= 7k * (x * 1/2 * ∫(0 to 1 - x^2) y^2 dy)\\= 7k * (x * 1/2 * [y^3/3] evaluated at y = (1-x^2) and y=0)\\= 7k * (x * (1/2 * (1/3 - x^6))\\The y-coordinate is given by\\(y bar) = 1/m * ∫∫ y ?(x, y) dx dy = 1/m * ∫∫ y * 7ky dx dy= 7k * ∫ (y^2) dx dy\\= 7k * (1/3 * ∫(0 to 1 - x^2) y^3 dy)\\= 7k * (1/3 * [y^4/4] evaluated at y = (1-x^2) and y=0)\\= 7k * (1/3 * (1/4 - x^6/2))\)
It's worth noting that the mass and center of mass of the lamina depend on the constant k, which is not specified in the problem.
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which inequality statement below is true?
7.745966… > √59
7.745966… < √59
The inequality statement 7.745966… < √59 is true.
The symbol √59 represents the square root of 59, which is approximately 7.681146. The value 7.745966… is a decimal representation of the square root of 59 that has been rounded to three decimal places. Because 7.681146 is less than 7.745966, the inequality statement 7.745966… < √59 is true.
What
is an arithmetic sequence with a common difference of −2?
Answer:
An arithmetic sequence with a common difference of −2 is 20,18,16,14,12..
Step-by-step explanation:
An arithmetic sequence is a sequence of numbers in which the difference between consecutive terms is same. Here, the common difference is -2, which means that each term in the sequence is obtained by subtracting 2 from the previous term.
To find the arithmetic sequence with a common difference of -2, you can start with an first term and then subtract 2 successively to find the subsequent terms.
Let the initial term is 20. Subtracting 2 from 20, we get 18. Subtracting 2 from 18, we get 16. Continuing this pattern, we subtract 2 from each subsequent term to generate the sequence. The arithmetic sequence with a common difference of -2 starting from 20 is
20,18,16,14,12
In this sequence, each term is obtained by subtracting 2 from the previous term, resulting in a common difference of -2.
Look for factors that will help you determine what type of economy exists in Country A.
Based on the clues in this passage, what type of economy does Country A have?
developed
developing
transitioning
command
Based on the limited information provided, it is not possible to definitively determine the type of economy in Country A. More specific details and factors would be necessary to make a conclusive determination.
Write the equation of a line that passes through the point (-5,-4) and has a slope of 1/5
Typically, linear equations are written in slope-intercept form:
\(y=mx+b\)
m = slopeb = y-intercept (the value of y when the line crosses the y-axis)To find the equation of a line given a point and the slope:
Plug the slope into y=mx+b as mPlug the point into y=mx+b as (x,y)Solve for bPlug b back into y=mx+b along with mSolving the Question
We're given:
\(m=\dfrac{1}{5}\)Passes through (-5,-4)\(y=mx+b\)
⇒ Plug in the slope, \(\dfrac{1}{5}\):
\(y=\dfrac{1}{5}x+b\)
⇒ Plug in the point (-5,-4) and solve for b:
\(-4=\dfrac{1}{5}(-5)+b\\\\-4=-1+b\\\\b=-3\)
⇒ Therefore, the y-intercept of the line is -3. Plug this back into our original equation as b:
\(y=\dfrac{1}{5}x-3\)
Answer\(y=\dfrac{1}{5}x-3\)
Find the domain and the range of the relation shown on the
graph to the right. Use the vertical line test to determine whether
the graph is the graph of a function.
Find the domain of the relation. Select the correct choice below and fill in the answer box to complete your choice.
O A. The domain of the relation is the single value { }
(Type an integer or simplified fraction.)
OB. The domain of the relation is the interval
(Type your answer in interval notation.)
(ANSWER QUICKLY)
The domain of a graph is the possible values of x, the graph can take.
(b) The domain of the relation is the interval [-10,10]
From the attached graph, we have the following observations on the x-axis.
The value of x starts from -10The value of x ends at 10So, the domain of x is from -10 to 10
Using interval notation, the domain of the relation is: \([-10,10]\)
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You bought a box of cake mix for $3.25 and two cans of icing. You spent a total of $7.45. How much was
each can of icing? You must write an equation and solve it for full credit.
Answer:
$2.10
Step-by-step explanation:
Is (7,-6) a solution to this system of equations?
y = 1/7x+ 7
X = 7
yes
no
Suppose that the function g is defined, for all real numbers, as follows. Find g(-5) ,g (-2), and g(-1)
If the function g(x) is defined for all real-numbers, then the value of g(-5) is 7/2, g(-2) is -1 and g(-1) is 0.
A piecewise function is a function that is defined by different rules or formulas on different parts of its domain. The piecewise function "g(x)" is given as :
g(x) = {-(1/2)x + 1, for x<-2
= {-(x+1)², for -2≤x≤1
= {4 for x>1
We have to find the value of g(-5) ,g (-2), and g(-1),
For x = -5, the number -5 is less than -2, so the first function "-(1/2)x + 1" will be used,
⇒ g(-5) = -(1/2)(-5) + 1 = 5/2 + 1 = 7/2,
For x = -2, the number -2 lies in the interval "-2≤x≤1", so second function
"-(x+1)²" will be used,
⇒ g(-2) = -(x+1)² = -(-2+1)² = -(-1)² = -1,
For x = -1, the number -1 lies inn the interval "-2≤x≤1", so second function "-(x+1)²" will be used,
⇒ g(-1) = -(x+1)² = -(-1+1)² = -(0)² = 0,
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