-to avoid excessive formation of byproduct -At higher temperatures there is a greater chance of getting more than one nitro group substituted onto the ring (dinitro)-To minimize some side reactions, which occur at a slower rate, while allowing the desired reaction to proceed

If the net force remains the same while the mass increases, the acceleration will be reduced.

The equation representing this relationship is

a = Fnet / m

Where "a" is the acceleration, "Fnet" is the net force, and "m" is the mass.

In the given scenario, the net force stays constant, meaning Fnet remains the same. However, the mass of the system increases.

When the mass of the system increases while the net force remains constant, the acceleration of the system decreases. This can be observed from the equation: if mass increases, the denominator of the equation increases, leading to a smaller overall result for acceleration.

In simpler terms, a larger mass requires more force to achieve the same acceleration. So, if the net force remains the same while the mass increases, the acceleration will be reduced.

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Answer:

true

Explanation:

Answer: True

Explanation:

Answer:

A = 0.44 [m^2]

Explanation:

To solve this problem we must remember that pressure is defined as the relationship between Force and area, so we have the following equation:

P = F/A

where:

P = pressure = 180 [pa]

F = force = 80 [N]

A = area [m^2]

Now replacing and solving:

180 = 80/A

A = 80/180

A = 0.44 [m^2]

The greatest distance the person can stand from the mirror and still see their image clearly is 2.0 meters.

The far point of a person's eyes refers to the maximum distance at which they can see objects clearly without the aid of corrective lenses. If the far point is given as 2.0 m, it means that the person can see objects clearly up to a distance of 2.0 m.

To determine the greatest distance the person can stand from the mirror and still see their image clearly, we need to consider the concept of the virtual image formed by a mirror. When we look into a mirror, our eyes perceive a virtual image as if it were formed behind the mirror.

In this case, the person's eyes can focus clearly up to a distance of 2.0 m. To see their image clearly in the mirror, the person needs the virtual image formed by the mirror to be within this range.

Since the virtual image formed by a mirror is the same distance behind the mirror as the object is in front of it, the person needs to stand at a distance from the mirror equal to the maximum distance they can focus clearly.

Therefore, the greatest distance the person can stand from the mirror and still see their image clearly is 2.0 meters.

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Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of options. However, one material that is good candidate for conducting electricity without reacting with other materials is metallic vanadium dioxide. This is because of the inability of this electrical conductor to conduct heat (an unusual property for all other electrical conductors) and thus makes it difficult for it to react with other materials (since an increase in temperature increases possibility of a reaction).

Answer:

Sorry for the bad drawing, as you have not specified whether is should be open switch or close I have drawn both

I hope it helps.

Answer:

Based off the word "conserved" I would say

A. Conservation of Momentum.

Explanation:

Answer:

A.) Conservation of Momentum

Answer: Distance:400m Distance:0m

Explanation: Distance: 1(lap)x400 which will obviously be 400m

Displacement: from where you started to where’s you ended so if you ran a full lap around a track and came back to where you started you wouldn’t have ran any Miles’s in displacement.

It might help you more to draw a diagram, but I hope I helped!

The mass of a bocce ball, m=5.0 kg

The initial velocity of the red ball, u=9.0 m/s

The velocity of the red ball after the collision, v₁=7.0 m/s

The mass of the blue ball will be the same as the red ball. And let us assume that the blue ball will be zero before the collision, i.e., it was at rest before the collision.

From the law of conservation of momentum, the total momentum of a system will always remain constant.

Thus,

Where v₂ is the velocity of the blue ball after the collision.

On substituting the known values,

Thus the velocity of the blue ball after the collision is 2.0 m/s.

The train accelerates to 25 m/s from rest in 30 seconds. Search for: The train's acceleration. The train accelerates at 0.83 m/s2 after 30 seconds.

According to the equations a = v/t, acceleration (a) seems to be the product of the variation in velocity (v) and the changes in time (t).

Acceleration is the term for the rate of change in speed. In most cases, but not always, acceleration denotes a shift in speed. The object keeps accelerating because the direction of its velocity is changing even while it travels in a circular motion.

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Experiment 1 Understanding of low voltage electrical apparatus: Purpose of the experiment1) Master the usage of common electrical tools.2) Master the common identification methods of low pressure.3) Master the function of low-voltage electrical apparatus and their correct application. Experiment contents and requirements

The experiment requires observing common low-voltage apparatus and understanding their structure. The following requirements are required:1. Drawing electrical symbols2. Writing text symbols3. Describing the basic working principle and function of low-voltage electrical components that are observed in the experiment report and content for the experiment report, follow this steps:1. Purchase the uniform standard experimental report paper in the academic affairs office.2. Fill in according to the items specified in the test report.3. Draw the electrical symbols and write the text symbols according to the observed low-voltage electrical components.4.

According to the observed low-voltage electrical components, the basic working principle and function are briefly described.

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Average speed of the car be 25 meter/second.

Speed is characterized as the rate at which an object's position changes in any direction.

The distance travelled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity. SI unit of speed be meter/second.

Given parameters:

Distance travelled by the car: s = 500 m.

Time taken by the car: T = 20 second.

So, speed of the car be = distance travelled/time taken

= 500/20 meter/second

= 25 meter/second.

Hence, its average speed be 25 meter/second.

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Answer:

Sheikh Hasina is the prime minister of Bangladesh.

Answer:

her name is Sheikh Hasina

Answer:

Arsenic

Explanation:

Arsenic is in group 5 and period 4. Group numbers tell us the number of valence electron and period number tells us the number of shells in an element.

44.58% is the maximum theoretical efficiency possible for an engine operating between 100°c and 400°c

The ratio of useful work completed to heat produced is used to determine an engine's efficiency. is the task finished.

Please be aware that the phrase "work done" refers to the force applied to the clutch or driveshaft. This implies that the work produced by thermodynamic expansion is reduced by the friction and other losses.

Given

T1 = 100 +273 = 373K

T2 = 400 + 273 = 673 K

Formula for efficiency = (T2 -T1/T2) × 100

Put the values of T1 and T2

We get

Efficiency = (673 - 373 /673) × 100

Efficiency = 44.58%

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Answer:

RT = 341.62 Ohms

Explanation:

Given the following data;

R1 = 420 Ohms

R2 = 320 Ohms

R3 = 160 Ohms

To find the equivalent resistance;

From the circuit, we can see that R1 and R2 are connected in parallel;

Mathematically, the total equivalent resistance of resistors connected in parallel is given by the formula;

\( RT = \frac {R1*R2}{R1 + R2} \)

Substituting into the formula, we have;

\( RT1 = \frac {420*320}{420 + 320} \)

\( RT1 = \frac {134400}{740} \)

RT1 = 181.62 Ohms

Next, we resolve the resistors to form a series circuit.

RT = RT1 + R3

RT = 160 + 181.62

RT = 341.62 Ohms

a) The centerline velocity is V = (ΔPπ)/(3.2768 x 10⁻¹¹ μ) and the velocity 0.5 cm from the wall is V = (ΔPπ)/(3.2768 x 10⁻¹¹ μ).

b) Pressure drop over a 10 m length is ΔP = (128μ(10 m)V)/(3.2768 x 10⁻¹¹ π).

The Reynolds number for water flowing in a circular pipe of diameter 2 cm is 600. This can be calculated using the following equation:

Re = (ρVD)/μ

Where Re is the Reynolds number, ρ is the density of the fluid, V is the average velocity of the fluid, D is the diameter of the pipe, and μ is the dynamic viscosity of the fluid.

To find the centerline velocity and velocity 0.5 cm from the wall, we can use the Hagen-Poiseuille equation:

V = (ΔPπD⁴)/(128μL)

Where V is the average velocity of the fluid, ΔP is the pressure drop over the length of the pipe, D is the diameter of the pipe, μ is the dynamic viscosity of the fluid, and L is the length of the pipe.

a. The centerline velocity and velocity 0.5 cm from the wall can be found by substituting the values into the Hagen-Poiseuille equation:

V = (ΔPπ(2 cm)⁴)/(128μ(10 m))

V = (ΔPπ(0.02 m)⁴)/(128μ(10 m))

V = (ΔPπ(0.000016 m⁴))/(128μ(10 m))

V = (ΔPπ(0.000000000256 m^4))/(128μ(10 m))

V = (ΔPπ)/(128μ(10 m)(0.000000000256 m^4))

V = (ΔPπ)/(3.2768 x 10⁻¹¹μ)

The centerline velocity is V = (ΔPπ)/(3.2768 x 10⁻¹¹ μ) and the velocity 0.5 cm from the wall is V = (ΔPπ)/(3.2768 x 10⁻¹¹ μ).

b. The pressure drop over a 10 m length can be found by rearranging the Hagen-Poiseuille equation and substituting the values:

ΔP = (128μLV)/(πD⁴)

ΔP = (128μ(10 m)V)/(π(2 cm)⁴

ΔP = (128μ(10 m)V)/(π(0.02 m)⁴)

ΔP = (128μ(10 m)V)/(π(0.000016 m⁴))

ΔP = (128μ(10 m)V)/(π(0.000000000256 m⁴))

ΔP = (128μ(10 m)V)/(3.2768 x 10^-11 π)

The pressure drop over a 10 m length is ΔP = (128μ(10 m)V)/(3.2768 x 10⁻¹¹ π).

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Water flowing in a circular conduit with a diameter of 2 cm has a Reynolds number of 600. The pressure drop over a 10 m length is 0.76 Pa.

To solve the given problem, we need to use the formula for the Reynolds number, which is given by:

Re = ρVD/μ

where ρ is the density of the fluid, V is the velocity, D is the diameter of the pipe, and μ is the dynamic viscosity of the fluid.

Given that the Reynolds number for water flowing in a circular pipe of diameter 2 cm is 600, we can use the formula to find the velocity V:

600 = (1000)(V)(0.02)/0.001

V = 0.2 m/s

a. The centerline velocity is 0.2 m/s. To find the velocity 0.5 cm from the wall, we can use the formula for velocity distribution in laminar flow:

V(r) = (2Vmax/π) * (1 - r/R)

where r is the radial distance from the centerline, R is the radius of the pipe, and Vmax is the maximum velocity at the centerline.

At the centerline, r = 0, so Vmax = 0.2 m/s. At r = 0.005 m (0.5 cm from the wall), we have:

V(0.005) = (2 * 0.2 / π) * (1 - 0.005/0.01)^0.5

V(0.005) = 0.13 m/s

b. To find the pressure drop over a 10 m length, we can use the Hagen-Poiseuille equation:

ΔP = 32μLQ/πD^4

where L is the length of the pipe, Q is the flow rate, and ΔP is the pressure drop.

Assuming a fully developed laminar flow, the flow rate is given by:

Q = πR^2V

Q = π(0.01)^2(0.2)

Q = 0.000125 m^3/s

Substituting the values in the equation, we get:

ΔP = (32)(0.001)(10)(0.000125) / π(0.02)^4

ΔP = 0.76 Pa

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Answer:

La fuerza resultante sobre q₃ es  -1.2245 × 10⁻¹⁵ i  + -0.24 × 10⁻¹⁵ j

La magnitud de la fuerza resultante sobre q₃ es aproximadamente 1.25 × 10⁻¹⁵ N

Explanation:

q₁ = -45 μC = -45 × 10⁻⁶ C

r₁₂ = 30 mm = 30 × 10⁻³ m

q₂ = 25 μC = 25 × 10⁻⁶ C

r₂₃ = 50 mm = 50 × 10⁻³ m

q₃ = 20 μC = 20 × 10⁻⁶ C

k = 9×10⁻⁹ N·m²/C²

Por lo tanto;

r₁₃ = √(50² + 30²) = 10·√(34)

F₁₂ = 9×10⁻⁹ × (-45 × 10⁻⁶)×(25 × 10⁻⁶)/(30 × 10⁻³)² = -1.125 × 10⁻¹⁴

F₁₂ = -1.125 × 10⁻¹⁴ N

F₂₃ = 9×10⁻⁹ × (20 × 10⁻⁶)×(25 × 10⁻⁶)/(50 × 10⁻³)² = 1.8 × 10⁻¹⁵ j

F₁₃ = 9×10⁻⁹ × (-45 × 10⁻⁶)×(20 × 10⁻⁶)/(10·√34 × 10⁻³)² = -2.38× 10⁻¹⁵

Los componentes de F₁₃ son;

-2,38 × 10⁻¹⁵ × cos (arctan (30/50)) = -2,04 × 10⁻¹⁵ j

-2,38 × 10⁻¹⁵ × sin (arctan (30/50)) = -1,2245 × 10⁻¹⁵ i

La fuerza resultante sobre la carga q₃, \(\left | \underset {F_3} \rightarrow \right |\) = \(\underset{F_{13}}{\rightarrow}\) + \(\underset{F_{23}}{\rightarrow}\)

∴ \(\left | \underset {F_3} \rightarrow \right |\) = 1.8 × 10⁻¹⁵ j + -1.2245 × 10⁻¹⁵ i + -2.04 × 10⁻¹⁵ j

La fuerza resultante sobre q₃ es \(\left | \underset {F_3} \rightarrow \right |\)  = -1.2245 × 10⁻¹⁵ i  + -0.24 × 10⁻¹⁵ j

La magnitud de la fuerza resultante sobre q₃,

\(\left | F_3 \right |\) = √((-1.2245 × 10⁻¹⁵)² + (-0.24 × 10⁻¹⁵)²) ≈ 1.25 × 10⁻¹⁵

La magnitud de la fuerza resultante sobre q₃, \(\left | F_3 \right |\) ≈ 1.25 × 10⁻¹⁵ N.

Answer:

n = 3.1x10¹²

Explanation:

To find the number of electrons we need to find first the charge (q):

\( I = \frac{q}{\Delta t} \rightarrow q = I*\Delta t \)    (1)

Where:

I: is the electric current = 0.59 A

t: is the time

The time t is equal to:

\(v = \frac{\Delta x}{\Delta t} \rightarrow \Delta t = \frac{\Delta x}{v}\)   (2)

Where:

x: is the displacement

v: is the average speed = 2.998x10⁸ m/s

The displacement is equal to the perimeter of the circumference:

\( \Delta x = 2\pi*r = \pi*d \)     (3)

Where d is the diameter = 80.0 m

By entering equations (2) and (3) into (1) we have:

\(q = I*\Delta t = I*\frac{\Delta x}{v} = \frac{I\pi d}{v} = \frac{0.59 A*\pi*80.0 m}{2.99 \cdot 10^{8} m/s} = 4.96 \cdot 10^{-7} C\)      

Now, the number of electrons (n) is given by:

\( n = \frac{q}{e} \)

Where e is the electron's charge = 1.6x10⁻¹⁹ C  

\( n = \frac{q}{e} = \frac{4.96 \cdot 10^{-7} C}{1.6 \cdot 10^{-19} C} = 3.1 \cdot 10^{12} \)

Therefore, the number of electrons in the beam is 3.1x10¹².

I hope it helps you!

The change in gravitational potential energy of the spacecraft as it moves from point B to point A is 8.3x10^9 J.

The change in gravitational potential energy of the spacecraft as it moves from point B to point A can be calculated using the formula:

                    \(ΔPE = -GMm(1/rA - 1/rB)\) , where

ΔPE is the change in gravitational potential energy,

G is the gravitational constant,

M is the mass of the planet,

m is the mass of the spacecraft,

rA is the distance from the planet's center at point A, and

rB is the distance from the planet's center at point B.

Using the given values, we have:

\(ΔPE = -(6.67x10^-11 Nm^2/kg^2)(1.50x10^24 kg)(650 kg)(1/5.00x10^7 m - 1/0)\)\(ΔPE = -(6.67x10^-11 Nm^2/kg^2)(1.50x10^24 kg)(650 kg)(1/5.00x10^7 m - 1/0)\)

Simplifying the expression, we get:

\(ΔPE = -8.3x10^9 J\)

Therefore, the change in gravitational potential energy of the spacecraft as it moves from point B to point A is \(8.3x10^9\)J, which is a negative value because the spacecraft is moving closer to the planet and its gravitational potential energy is decreasing.

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Answer:

here's the answers!

Explanation:

A mover carries a box up a flight of stairs.

A mover carries a box across a room.

A weightlifter lifts a barbell off the ground.

hope it helps u!

Answer:

A, D, E

Explanation:

Did it

There is the need for topographic maps to be updated because it makes resources and environment monitoring more significant

This is referred to as a type of map which shows the shape of the Earth's surface through the use of contour lines. The geographical representation is also important in the socio-economic development of a country or place.

In developing countries , there is the need to monitor the resources and environment due to different changes occurring as a result of high human activity influence such as mining, pollution etc in which the government has to discover methods to control it and avoid resources depletion.

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There are roughly 9.22 moles of Cl2 gas in 5.55 x \(10^{24\) molecules of Cl2 gas.

Divide the given number of molecules by Avogadro's number to get the amount of moles of Cl2 gas.

To solve for the amount of moles of Cl2 gas in 5.55 x \(10^2^4\) molecules of Cl2 gas, we need to use Avogadro's number, which is the number of particles in one mole of a substance.

Avogadro's number is approximately 6.022 x \(10^2^3\) particles per mole.

To find the amount of moles of Cl2 gas, we simply divide the given number of molecules by Avogadro's number.

So, 5.55 x \(10^2^4\) molecules of Cl2 gas divided by 6.022 x \(10^2^3\) particles per mole equals approximately 9.22 moles of Cl2 gas.

Therefore, the amount of moles of Cl2 gas in 5.55 x \(10^2^4\) molecules of Cl2 gas is approximately 9.22 moles.

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The power output of the ultrasound is 0.225W.

Ultrasound of intensity 1.50×10^2 W/m is produced by the rectangular head of a medical imaging device measuring 3.00 by 5.00 cm.

The intensity (I) of the ultrasound is given as: I = Power/Area; where power is P, and area is A.  We are given that intensity (I) is 1.50×10^2 W/m. Area (A) of the rectangular head is given as 3.00 cm x 5.00 cm; which is 0.03 m x 0.05 m. Therefore, Power output (P) is given as:P = I x A; where P = 1.50 x 10^2 W/m x 0.03 m x 0.05 m = 0.225W.

Hence, the power output of the ultrasound is 0.225W.

Ultrasound is a type of sound with a higher frequency than what humans can hear. It has many applications, including medical imaging, cleaning, and welding.

Medical ultrasound is the most well-known application of ultrasound. Ultrasound is used to create images of the internal organs of the body. It is a non-invasive technique that does not involve radiation, unlike x-rays. Medical ultrasound machines generate ultrasound waves that penetrate the body and bounce back when they encounter tissue boundaries. These waves are then translated into an image of the internal organs.

The intensity of the ultrasound produced is determined by the power output of the ultrasound machine. Power is the rate at which energy is transferred or transformed, measured in watts. Power is determined by multiplying the voltage by the current. When a medical ultrasound machine is in operation, the power is converted into ultrasound waves.

The intensity of the ultrasound waves is determined by the power output of the machine. Intensity is the power per unit area, measured in watts per square meter (W/m²). In this question, the power output of the ultrasound machine is calculated using the intensity and area of the rectangular head of the device.

The power output of an ultrasound machine can be determined using the intensity and area of the rectangular head of the device. Ultrasound waves are created when the power is converted into them. Medical ultrasound machines generate ultrasound waves that penetrate the body and bounce back when they encounter tissue boundaries. These waves are then translated into an image of the internal organs. Medical ultrasound is a non-invasive technique that does not involve radiation, unlike x-rays.

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The difference in the mass of carbon dioxide in 500 kg of air in 2013 compared to 1800 is 0.06 Kg

Mass = percent × mass of air

Mass of CO₂ = 0.028% × 500

Mass of CO₂ = 0.14 Kg

Mass = percent × mass of air

Mass of CO₂ = 0.040% × 500

Mass of CO₂ = 0.2 Kg

Difference = mass in 2013 - mass in 1800

Difference = 0.2 - 0.14

Difference = 0.06 Kg

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The equation for the equivalent resistance of resistors in series can be derived using Ohm's law and Kirchhoff's loop rule. The equivalent resistance (Req) is calculated by adding up the individual resistances (R1, R2, R3, etc.) in series.

In a series circuit, resistors are connected end-to-end, meaning the current flows through each resistor consecutively. According to Ohm's law, the voltage across a resistor (V) is equal to the product of the current (I) passing through it and the resistance (R): V = I * R.

Applying Kirchhoff's loop rule, which states that the sum of the potential differences around a closed loop is equal to zero, we can derive the equation for the equivalent resistance.

Considering a series circuit with resistors R1, R2, R3, and so on, the total voltage (V) applied to the circuit is equal to the sum of the individual voltage drops across each resistor.

By rearranging Ohm's law for each resistor and substituting the values into Kirchhoff's loop rule, we can express the equation as follows:

V = I * Req

V = I * (R1 + R2 + R3 + ...)

Since the current (I) is constant in a series circuit, we can simplify the equation to:

Req = R1 + R2 + R3 + ...

Therefore, the equivalent resistance (Req) for resistors in series is obtained by adding up the individual resistances.

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Answer:

Presión = 11111,11 N/m

Explanation:

Dados los siguientes datos;

Diámetro = 1,5 cm a metros = 1,5 / 100 = 0,015 m

Fuerza = 2N

Para encontrar la presión;

En primer lugar, determinaríamos el área del círculo usando la fórmula;

Área del círculo = πr²

Radio = diámetro/2 = 0.015/2 = 0.0075 m

Área de la jeringa = 3.142 * 0.0075²

Área de la jeringa = 3.142 * 0.00005625

Área de la jeringa = 0.00018 metros

Ahora, podemos encontrar la presión usando la fórmula;

Presión = fuerza/área

Presión = 2/0.00018

Presión = 11111,11 N/m

Answer:

A

Explanation:

It’s a because a electrolyte reproduces

Answer:

The British were determined to crush the rebellion.

They were criminals and made achieving independence more difficult.

Explanation:

Mau-mau were rebellions and wanted to push out British and other Europeans out of Kenya. Mau mau were also the members of the Kikuyu and were making independence more difficult, due to their rebellion attitude. They were a secret society of Kikuyu.

2) The British were determined to crush the rebellion.

3) They were criminals and made achieving independence more difficult.

After British victory in World War II, Kenyatta received a request to return to Kenya in September 1946, sailing back that month. He decided not to bring Edna—who was pregnant with a second child —with him, aware that if they joined him in Kenya their lives would be made very difficult by the colony's racial laws. On his arrival in Mombasa, Kenyatta was greeted by his first wife, Grace Wahu and their children. He built a bungalow at Gatundu, near to where he was born, and began farming his 32-acre estate.

(a) The British were determined to crush the rebellion.

(b) They were criminals and made achieving independence more difficult.

Mau-mau were rebellions and wanted to push out British and other Europeans out of Kenya. Mau mau were also the members of the Kikuyu and were making independence more difficult, due to their rebellion attitude. They were a secret society of Kikuyu.

2) The British were determined to crush the rebellion.

3) They were criminals and made achieving independence more difficult.

After British victory in World War II, Kenyatta received a request to return to Kenya in September 1946, sailing back that month. He decided not to bring Edna—who was pregnant with a second child —with him, aware that if they joined him in Kenya their lives would be made very difficult by the colony's racial laws.

On his arrival in Mombasa, Kenyatta was greeted by his first wife, Grace Wahu and their children. He built a bungalow at Gatun, near to where he was born, and began farming his 32-acre estate.

Thus the British were determined to crush the rebellion.They were criminals and made achieving independence more difficult.

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