to determine whether felonies tend to be committed more often on weekends (saturday and sunday) than on weekdays (monday through friday), a sociologist classifies a random sample of records of convicted felons in terms of these two categories. the appropriate statistical test is

The type of variable for,

a. The number of counties in California: Quantitative discrete.

b. The stages of childhood: Qualitative ordinal.

c. In the scenario above, 23 minutes is a statistic, because 28 students is a sample.

d. Between 6 minutes and 8 minutes: Approximately 68% of the athlete's mile times are expected to be between 6 and 8 minutes, according to the empirical rule.

e. Between 4 minutes and 7 minutes: Approximately 68% of the athlete's mile times are expected to be between 4 and 10 minutes, according to the empirical rule.

f. Less than 9 minutes: Approximately 84% of the athlete's mile times are expected to be less than 9 minutes, according to the empirical rule.

In statistics, variables can be categorized into two types: qualitative and quantitative.

Qualitative variables describe characteristics or qualities that cannot be measured numerically, such as gender or hair color.

Quantitative variables, on the other hand, represent numerical values that can be measured or counted.

There are two types of quantitative variables: continuous and discrete. Continuous variables can take any numerical value within a range, such as age or weight.

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Answer:

60

Step-by-step explanation:

bb-a

(8)(8)-4

64-4=60

simple substitution

Answer:

So first we need to determine what the exponential growth function would look like.  Exponential growth functions look like \(P(t) = P_0*e^{r*t}\) and in our case \(P_0\) would be the initial population which is 6.63 million.  R is the next variable that we need to fill out which is the rate of change which in our case is 3.01% or 0.0301.

This is how our function should look now \(P(t)=6.63*e^{0.0301*t}\)

Moving onto part b, we need to estimate the population of the city in 2018 which 6 years from 2012 and we plug that into t and solve.

\(P(t) = 6.63 * e^{0.0301*6}\)

\(P(t) = 6.63*e^{0.1806}\)

\(P(t) = 6.63 *1.1979\)

\(P(t) = 7.9423\ million\)

Moving onto part c, we need to find when the population of the city will be 11 million which will be done by setting P(t) to 11 million and solving for t.

\(11 = 6.63*e^{0.0301*t}\)

\(\frac{11}{6.63} = \frac{6.63*e^{0.0301*t}}{6.63}\)

\(1.659=e^{0.0301*t}\)

\(ln(1.659)=ln(e^{0.0301*t})\)

\(\frac{0.506}{0.0301}=\frac{0.0301*t}{0.0301}\)

\(16.818\ years = t\)

Moving onto part d, we need to find the doubling time.  This will be similar to the previous part but we will be finding the time it takes to double our population.  So instead of putting 11 million for P(t) we put 6.63 * 2 in there which is 13.26.

\(13.26 = 6.63*e^{0.0301*t}\)

\(\frac{13.26}{6.63} = \frac{6.63*e^{0.0301*t}}{6.63}\)

\(2=e^{0.0301*t}\)

\(ln(2)=ln(e^{0.0301*t})\)

\(\frac{0.693}{0.0301}=\frac{0.0301*t}{0.0301}\)

\(23.028\ years = t\)

Hope this helps!  Let me know if you have any questions

There are a total of 9 items to divide among 3 people, so the number of ways to divide the items is 84.

In mathematics, a combination is a selection of elements from a bigger group where the arrangement of the elements is irrelevant. Consider a collection of three letters, A, B, and C, for illustration. Two of these letters, AB, AC, and BC, can be chosen in one of three ways. "Combinations" of the letters A, B, and C are what these three options are referred to as.

C(n, k)=n!/(k!*(n-k))!

where the product of all positive integers from 1 to n, denoted by the symbol n!, is the factorial of n. For instance, 5! equals 1 + 2 + 3 + 4 + 5 = 120.

For example, three people divide among themselves six identical apples, one orange, one plum, and one tangerine.

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Answer:

3/5 or 1.6666666667

pls mark me brainliest

Answer:

\(x^3 + 3x\²y + 3xy^2 + y\) \(=283\)

\(When\ x = 3\ and\ y = 4\)

Step-by-step explanation:

Given

\(x^3 + 3x\²y + 3xy^2 + y\)

Required

Solve when x = 3 and y = 4

To do this, we simply substitute  3 for x and 4 for y in \(x^3 + 3x\²y + 3xy^2 + y\)

\(3^3 + 3 * 3^2 * 4 + 3 * 3 * 4^2 + 4\)

\(27 + 3 * 9 * 4 + 3 * 3 * 16 + 4\)

\(27 + 108 + 144+ 4\)

\(283\)

Hence:

\(x^3 + 3x\²y + 3xy^2 + y\) \(=283\)

\(When\ x = 3\ and\ y = 4\)

Answer:

2 vertical and -11 horizontal

Step-by-step explanation:

Answer:

IT is B

Step-by-step explanation:

edge duh

Check the picture below.

\(\textit{Law of Cosines}\\\\ \cfrac{a^2+b^2-c^2}{2ab}=\cos(C)\implies \cos^{-1}\left(\cfrac{a^2+b^2-c^2}{2ab}\right)=\measuredangle C \\\\[-0.35em] ~\dotfill\\\\ \cos^{-1}\left(\cfrac{21^2+32^2-26^2}{2(21)(32)}\right)=\measuredangle J \implies \cos^{-1}\left(\cfrac{ 789 }{ 1344}\right)=\measuredangle J\implies \boxed{54.1^o\approx \measuredangle J}\)

Make sure your calculator is in Degree mode.

The values of x and y the triangles to the fight congruent are x = 3 and

y = 1.

What is congruent triangles?

Triangles with the same size and shape are said to be congruent. This implies that the corresponding sides and angles are both equal. Without comparing every angle and side of the two triangles, we can determine whether two triangles are congruent.

If given these triangles are congruent then all corresponding side must be equal

As we can see that both triangle are right triangle

Therefore hypotenuse of one triangle equal to another

x+1  = 4y   ..... (A)

And lenght ( height)  of one  must equal to another triangle

x = y +2          .... (B)

therefore

Plug the value of x = y + 2 in equation A

y + 2 + 1 = 4y

        3y = 3

          y = 1

and x = y+2

x = 1 + 2

x = 3

Hence, the values of x and y the triangles to the fight congruent are

x = 3 and y = 1.

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Complete question:

Complete question is attached below.

The required growth factor that models the hourly growth of this bacteria is 2/5

Some things develop at a predictable rate. As the overall number increases, certain things, like money or the offspring of mated rabbits, can expand exponentially faster. Growth is exponential when it accelerates in proportion to the expanding total population.

We have,

50 sq mm of bacteria and they are increased to 70 sq mm in 1 hour.

Then,

To find the factor Divide the increased value by initial value.

So

increased value = 70 - 50 = 20 sq mm

And initial value = 50

Then,

= 20 / 50

= 2/5

Thus, required growth factor is 2/5.

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Answer: $571.20

Step-by-step explanation:

In this question, you're gonna use multiplication to figure out the tax and the tip. 

If the dinner is $476 and the tax is 5%, multiply the two to figure out how much the sales tax is. 

476 • 0.05 = 23.80

Then, multiply the $476 and 15% to figure out the tip. 

476 • .15 = 71.40

Add them all up. 

476 + 71.40 + 23.80 = 571.20

In this case, the Striton family paid $571.20 altogether.

Answer:

she would need 6.25 cups of chocolate chips

Step-by-step explanation:

32/2= 16

each cup can make 16 cookies

100/16=6.25

this should be right, have a good day

Answer: 227/ 60 = 3 47/60 OR 3.783

Note: If you don't get the right answer because of the extra 3 in 3.783 then simply remove the extra 3 at the end.

Explanation:

Step 1: Multiply the whole number 2 by the denominator 6. Whole number 2 equally.

Step 2: Add the answer from the previous step 12 to the numerator 5. New numerator is 12 + 5 = 17

Step 3: Write a previous answer (new numerator 17) over the denominator 6

Message: If you found this helpful let me know by giving a thanks! :)

Answer:

14 km

Step-by-step explanation:

6 = M - .25M = .75M

M = 6/.75 =  8 km  in the  morning  

8 + 6 = 14

【Rep.】The least common multiple of 12 and 24 is 24.

                             \(\red{ {\hspace{50 pt}\above 1.2pt}\boldsymbol{\mathsf{Procedure}}{\hspace{50pt}\above 1.2pt}}\)

To obtain the least common multiple (lcm) we must do it by simultaneous decomposition.

This method consists of extracting the common and uncommon prime factors, then

   \(\large\displaystyle\text{$\begin{gathered}\sf \left.\begin{matrix} \blue{12 \ \ \ 24}\\ \ 6 \ \ \ 12\\ \ 3 \ \ \ \ 6\\ \ 3 \ \ \ \ 3\\ \ 1 \ \ \ \ 1 \end{matrix}\right|\begin{matrix} 2\\ 2\\ 2\\ 3\\ \: \end{matrix} \end{gathered}$}\)

                                 \(\sf{L.c.m.(12,24)=2\times2\times2\times3}\)

                                       \(\sf{L.c.m.(12,24)=2^{3}\times3 }\)

                                       \(\boxed{\boxed{\sf{L.c.m.(12,24)=24}}}\)

The graph of the quadratic equation is in the form of parabola.

In mathematics, a parabola is a roughly U-shaped, mirror-symmetrical planar curve. The same curves can be defined by a number of seemingly unrelated mathematical definitions, which all correspond to it.

A line and a point (the focus) are two components of one definition of a parabola (the directrix). There is less emphasis on the directrix. The parabola is the subset of sites in that plane that are equally spaced apart from both the directrix and the focus.

A parabola, also referred to as a continuous line, is formed when a right ring conical surface and a plane transverse to another plane that is also tangential to the conical surface cross.

The parabola has the equation y = (x + 2)² - 1

Using the general form of the parabola we can define the vertex of the parabola at (-2,-1) .

The graph of the parabola is attached below.

The graph passes the x axis at (-1,0) and (-3,0)  and (0,3) .

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The rejection region for a hypothesis test can be found, we need to specify the significance level (α) and the test statistic distribution.

Given that the question mentions "t" and asks us to round to three decimal places, we can infer that we are dealing with a t-test and should use the t-distribution.

The rejection region for a t-test is located in the tails of the t-distribution. The specific critical values depend on the degrees of freedom and the significance level (α).

Since the question does not provide the degrees of freedom or the significance level, we cannot provide a specific answer. However, I can explain the general procedure:

1. Determine the degrees of freedom based on the sample size and test conditions.
2. Determine the critical value(s) for the desired significance level (α) from the t-distribution table or a statistical software.
3. If the calculated test statistic (t) falls within the rejection region (tails of the t-distribution), we reject the null hypothesis (H0). Otherwise, we fail to reject the null hypothesis.

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The camper should take 3 units of food, 1 first-aid kit, and 1 piece of clothing within the given constraints.

To determine the optimal number of each item the camper should take, we need to maximize the total benefit while considering the capacity constraint of the backpack.

Let's assume the camper takes x units of food, y first-aid kits, and z pieces of clothing.

The backpack has a capacity of 9 ft^3, and each unit of food takes up 2 ft^3. Therefore, the constraint for food is 2x ≤ 9, which simplifies to x ≤ 4.5. Since x must be a whole number and the camper needs at least one unit of food, the camper can take a maximum of 3 units of food.

Similarly, for first-aid kits, since each kit occupies 1 ft^3 and the camper must take at least one, the constraint is y ≥ 1.

For clothing, each piece takes 3 ft^3, and the constraint is z ≤ (9 - 2x - y)/3.

Now, we need to maximize the total benefit. The benefit of food is assigned as 7, first aid as 5, and clothing as 6. The objective function is 7x + 5y + 6z.

Considering all the constraints, the possible combinations are:

- (x, y, z) = (3, 1, 0) with a total benefit of 7(3) + 5(1) + 6(0) = 26.

- (x, y, z) = (3, 1, 1) with a total benefit of 7(3) + 5(1) + 6(1) = 32.

- (x, y, z) = (4, 1, 0) with a total benefit of 7(4) + 5(1) + 6(0) = 39.

- (x, y, z) = (4, 1, 1) with a total benefit of 7(4) + 5(1) + 6(1) = 45.

Among these combinations, the highest total benefit is achieved when the camper takes 3 units of food, 1 first-aid kit, and 1 piece of clothing.

Therefore, the camper should take 3 units of food, 1 first-aid kit, and 1 piece of clothing to maximize the total benefit within the given constraints.

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~Kindly see the attached picture!

✧ Hope I helped ! ✧

Have a wonderful day / night ! ♡

Let me know if you have any questions regarding my answer ツ

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Answer:

1st answer

Step-by-step explanation:

Answer:

\(3x^3 - 5x + 1 - \frac{10}{x + 3}\)

or

3x^3 - 5x + 1

Remainder: -10

Step-by-step explanation:

Please see attached image for full explanation!

1.) Write the coefficient of each term.

2.) Beginning with 3, multiply by -3, or x + 3 = 0 (the divisor.)

3.) Add the product to the next coefficient and repeat until you get to the last number, -7.

4.) You should have the numbers 3, 0, -5, 1, and -10.

5.) Rewrite this quotient as an equation:

3x^3 - 5x + 1

Note that the highest power is 3, one less than that of the highest power in the original equation.

6.) Don't forget the remainder!

You can include this in the equation or not, depending on the instructions.

Therefore, the final answer is 3x^3 - 5x + 1 - 10/x+3 or 3x^3 - 5x + 1 R: -10.

Answer:

The numbers of measure of music played are 1 and 7

Step-by-step explanation:

Given

\(s = 10|x - 4| + 50\)

Required

Solve for x when s = 80

Substitute 80 for x

\(80 = 10|x - 4| + 50\)

Subtract 50 from both sides

\(80 - 50= 10|x - 4| + 50 - 50\)

\(30= 10|x - 4|\)

Divide through by 10

\(\frac{30}{10}= \frac{10|x - 4| }{10}\)

\(3= |x - 4|\)

Reorder

\(|x - 4| = 3\)

This can be split into

\(x - 4 = 3\) or \(x - 4 = -3\)

Solve for x

\(x = 4 + 3\) or \(x = 4 - 3\)

\(x = 7\) or \(x = 1\)

Hence:

The numbers of measure of music played are 1 and 7

Answer: f(|x|+3)=||x|+3|

Step-by-step explanation:

The exact value of cscθ is (35 * √(1190)) / 1190.

To find the value of cscθ (cosecant θ) given that cosθ = 1/√35 and sinθ < 0, we can use the reciprocal relationship between sine and cosecant.

Recall that cscθ is the reciprocal of sinθ. Since sinθ is negative, we can determine its value based on the quadrant in which θ lies.

In the unit circle, the cosine is positive in the first and fourth quadrants, while the sine is negative in the third and fourth quadrants.

Given that cosθ = 1/√35 and sinθ < 0, we can conclude that θ lies in the fourth quadrant.

Using the Pythagorean identity, sinθ = √(1 - cos^2θ), we can calculate the value of sinθ:

sinθ = √(1 - (1/√35)^2)

     = √(1 - 1/35)

     = √(34/35)

     = √34 / √35

     = (√34 / √35) * (√35 / √35)     [Multiplying numerator and denominator by √35 to rationalize the denominator]

     = √(34 * 35) / 35

     = √(1190) / 35

Now, since cscθ is the reciprocal of sinθ, we have:

cscθ = 1 / sinθ

     = 1 / (√(1190) / 35)

     = 35 / √(1190)

     = (35 * √(1190)) / 1190.

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The car gets 214.3 miles per gallon of gasoline in the city and 27.8 miles per gallon of gasoline on the highway.

Let the number of miles per gallon that the car gets in the city be x. Hence, the number of miles per gallon that the car gets on the highway would be 3x.

A salesperson purchased a car that is advertised as getting 3 times as many miles per gallon of gasoline on the highway than it does in the city. On a recent sales trip that covered 1500 miles in total, the car used up 18 gallons on the highway and 7 gallons in the city.

Calculation of miles per gallon of gasoline in the city:7 gallons of gasoline cover city distance: x miles is covered by 1 gallon of gasoline.

Thus, 7 gallons will cover 7x miles. Hence, we can equate: 7x = 1500 ....(1)

Calculation of miles per gallon of gasoline on the highway:18 gallons of gasoline cover the highway distance.3x miles is covered by 1 gallon of gasoline.

Thus, 18 gallons will cover 54x miles.

Hence, we can equate: 54x = 1500 ....(2)

Dividing equation (1) by 7:7x/7 = 1500/7x

= 214.3 miles per gallon of gasoline in the city.

Dividing equation (2) by 54:54x/54

= 1500/54x

= 27.8 miles per gallon of gasoline on the highway.

Therefore, the car gets 214.3 miles per gallon of gasoline in the city and 27.8 miles per gallon of gasoline on the highway.

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Answer:

f[g(1)]=6.

Explanation:

Given f(n) and g(n) defined below:

First, we evaluate g(1):

Therefore:

Therefore, f[g(1)]=6.

To find f(g(x)), substitute g(x) into f(x). Simplifying gives f(g(x)) = log6(36g(x)). For range of y in f(x) + g(x), Take possible values . Since log6(36x) is defined for x > 0, and 6 is positive, the range of y is (0, ∞).

a) To find f(g(x)), we substitute g(x) into f(x):

f(g(x)) = f(6x) = log6(36(6x)) = log6(216x) = log6(6^3x) = 3log6(6x) = 3(log6(6) + log6(x)) = 3(1 + log6(x)) = 3 + 3log6(x).

Thus, f(g(x)) simplifies to 3 + 3log6(x).

(b) To find the range of y in f(x) + g(x), we need to consider the possible values of f(x) and g(x). Since log6(36x) is defined for x > 0, and 6* is always positive, the range of f(x) is (0, ∞). Similarly, g(x) = 6* is always positive, so the range of g(x) is also (0, ∞).When we add f(x) and g(x), we are adding two positive functions, resulting in values greater than 0. Therefore, the range of y in f(x) + g(x) is (0, ∞).

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