TRUE OR FALSE! Please help

Answer:

An acid is any hydrogen-containing substance that is capable of donating a proton (hydrogen ion) to another substance. A base is a molecule or ion able to accept a hydrogen ion from an acid.

Answer:

1.Sour in taste

2. Tum blue litmus into red

3. Acids change methyl orange to red

4.Phenolphthalein remains colourless

5. Acids do not give soapy touch

6. Give hydrogen ions in solution

Bitter in taste

Answer:

474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

Replacing:

1.00 atm* 150 L= n*0.08206 \(\frac{atm*L}{mol*K}\) *273 K

Solving:

\(n=\frac{1.00 atm* 150 L}{0.08206 \frac{atm*L}{mol*K}*273 K}\)

n= 6.69 moles

Being Cl= 35.45 g/mole, the molar mass of chlorine gas is:

Cl₂=2*35.45 g/mole= 70.9 g/mole

So if 1 mole has 70.9 grams, 6.69 moles of the gas, how much mass does it have?

\(mass=\frac{6.69 moles*70.9 grams}{1 mole}\)

mass= 474.321 grams ≅ 474 grams

474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C

Answer:

Mass=Moles × RFM

Mass= 0.28M× 164

Mass= 45.92 grammes

Answer :]

This is an oxidation-reduction (redox) reaction:

S0 + 2 e- → S-II (reduction)

2 K0 - 2 e- → 2 KI (oxidation)

S is an oxidizing agent, K is a reducing agent.

Answer:

K

Explanation:

Here, in this reaction 2 moles of potassium react with 1 mole of sulfur to form 1 mole of potassium sulfide.

Let's compare the electronic configurations of both elements :

⇒ K = {2, 8, 8, 1}

⇒ K can attain noble gas configuration by losing one electron

⇒ K exists as : K⁺

⇒ S = {2, 8, 6}

⇒ S can attain noble gas configuration by the addition of 2 electrons

⇒ S exists as S²⁻

Now, we know that will lose protons when oxidized. Hence, here the substance which is oxidized is K

A molecular compound is defined as a molecule whose formula states the actual number of atoms bonded together in the molecule.

The atoms are joined to give a definite shape which is defined by the angles between the bonds and by the bond lengths. Molecular compounds can contain discrete molecules, which are held together by sharing electrons in covalent bonding.

Examples of molecular compounds are water, which contains H2O molecules; methane contains CH4 molecules; and hydrogen fluoride, which contains HF molecules.

As a rule of thumb, compounds that are involved in a metal binding with either a non-metal or a semi-metal will display ionic bonding.

Compounds can be composed with only non-metals or semi-metals and non-metals will display covalent bonding and will be classified as molecular compounds.

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There are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

To determine the number of moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3, we need to consider the stoichiometry of the compound.

The formula of aluminum sulfate (Al2(SO4)3) indicates that for every 1 mole of the compound, there are 2 moles of aluminum ions (Al3+). This means that the mole ratio of Al3+ to Al2(SO4)3 is 2:1.

Given that we have 0.42 mol of Al2(SO4)3, we can calculate the moles of Al3+ as follows:

Moles of Al3+ = 0.42 mol Al2(SO4)3 x (2 mol Al3+ / 1 mol Al2(SO4)3)

Moles of Al3+ = 0.42 mol Al2(SO4)3 x 2

Moles of Al3+ = 0.84 mol Al3+

Therefore, there are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

It's important to note that the stoichiometry of the compound determines the mole ratio between the different species involved in the chemical formula. In this case, the 2:1 ratio of Al3+ to Al2(SO4)3 allows us to determine the number of moles of Al3+ based on the given amount of Al2(SO4)3.

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Answer:

final volume = 10.5 Liters N₂(g) at 21°C and 823Torr*

Explanation:

*Note=>No specified mass value of N₂(g) is defined in the problem. Therefore for a starting point, the gas sample is assumed to be 1.00 mole N₂(g) at STP conditions  22.4L

Determine volume of  N₂(g) at 21°C(=294K) and 823 Torr (= 2.286 Atm).

Start with Volume of N₂(g) at 0°C and 1 Atm pressure => 22.4L and adjust to final volume of  N₂(g) based upon 21°C(=294K) and 823 Torr (= 2.286 Atm).

V(final) = 22.4L(294K/273K)(360 Torr/823 Torr) = 22.4L(294/273)(360/823) = 10.55 Liters final volume.

Note: The volume of 1 mole (assumed) of any gas at STP (0°C/1 Atm) is 22.4 Liters. To convert to non-STP conditions, convert temperature and pressure factors (changes) that reflect what happens when the gas is expanded or decreased; but, these adjustments are taken independently for each variable of interest.  The following notes explain.

For the increase in temperature from 0°C(=273K) to 21°C(=294K) one must apply a temperature ratio that will increase volume. That is, the change in volume due to the temperature change is 294K/273K. If a 273K/294K ratio were used the volume would have decreased. Not so for heating a sample of gas.

For the increase in pressure one should expect a decrease in volume. Therefore apply a pressure ration that will effectively decrease the volume of the gas. That is, to decrease a 22.4L sample at STP multiply the standard volume by a ratio of pressures that will decrease 22.4L to a smaller volume. That is, V(final by pressure effects) multiply by 360Torr/823Torr to decrease the STP VOLUME (22.4L) to the new non-standard volume. If 823Torr/360Torr were used, the final volume would not be smaller, but larger. Such is the physical effect of an increasing pressure change.

This exercise is related to the subject of Structured Thinking. See the definition of structured thinking below.

The process of developing a structured framework to address an unstructured situation is known as structured thinking.

Structured thinking is a strategy of problem-solving that entails breaking a huge problem into smaller ones in order to tackle the larger problem more quickly and effectively.

Categorizing things and identifying themes are two subjects under structured thinking.

To categorize anything requires:

Identifying themes entails:

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Answer:

D.

the father parent shares his genetic information with the mother during sexual intercourse( the sperm and egg)

The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

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Explanation:

Alkali metal refers to group1 elements.

Alkali earth metal refers to group 2 elements.

Non metals refers to elements in grouos 4 to group 7.

Halogen refers to group 17 elements

Transition Metal refers to group 3 to group 12 elements

Noble gases refer to elements in group 18.

To obtain the group number from the electronic configuration, we calculate the total number of electrons in the principal quantum number (coefficient of the letters).

a. [Ne]3s1

Principal quantum number = 3

Number of electrons present = 1

This element belongs to group 1. It is an Alkali Metal.

b. [Ne]3s23p3

Principal quantum number = 3

Number of electrons present = 2 + 3 = 5

This element belongs to group 15 (5A). It is a Non metal

c. [Ar]4s23d104p5

Principal quantum number = 4

Number of electrons present = 2 + 5 = 7

This element belongs to group 17 (7A). It is an Halogen.

d. [Kr]5s24d1

This configuration belongs to the element yttrium and has an incomplete d shell. Hence it is a transition metal.

e. [Kr]5s24d105p6

Principal quantum number = 5

Number of electrons present = 2 + 6 = 8

This element belongs to group 18 (8A). It is a Noble gas.

To determine the specific heat of the unknown substance, we can use the principle of energy conservation. The heat lost by the unknown substance is equal to the heat gained by the water.Therefore, the specific heat of the unknown substance is approximately 2.68 J/g°C.

First, we calculate the heat lost by the unknown substance. Using the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat, and ΔT is the change in temperature, we have:

Q_substance = m_substance * c_substance * ΔT_substance

Next, we calculate the heat gained by the water. Again, using the same formula, we have:

Q_water = m_water * c_water * ΔT_water

Since the system reaches equilibrium, Q_substance = Q_water. Rearranging the equation and substituting the given values, we can solve for c_substance:

m_substance * c_substance * ΔT_substance = m_water * c_water * ΔT_water

c_substance = (m_water * c_water * ΔT_water) / (m_substance * ΔT_substance)

Plugging in the values, we find:

c_substance = (250.00 g * 4.18 J/g°C * (29.000 °C - 23.000 °C)) / (95.00 g * (98.000 °C - 23.000 °C))

c_substance ≈ 2.68 J/g°C

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Answer:

41826.05 Calories

Explanation:

1 J = 0.239006 Calories

175 KJ

= 175 x 1000 J

= 175000 J

175000 J to Calories

= 175000 x 0.239006

= 41826.05 Calories

Answer: 41.8

Explanation:

Acellus verified ✅

Answer:

The ratio of volumes in the given case illustrates the Gay Lussac's Law of Gaseous Volumes.

- The law was given by the french chemist Gay Lussac in the year 1806.

- He stated that when gases are combined or are produced in a chemical reaction, they do so in a simple ratio by volume.

- It is given that 2 volumes of hydrogen combine with 1 volume of oxygen producing 2 volumes of water.

- This is in accordance with this law.

Explanation:

Answer:

the energy of matter implies the motion of masses and the energy of the wave has no moving masses

The energy of the particles (matter) is the ability to do some work, therefore the energy can be of motion in the form of kinetic energy or in a configuration of the system called potential energy, the sum of these two energy is constant .

The wave is formed by a disturbance of the medium by matter, therefore for the formation of the wave matter supply energy, for example: in the form of movement, in the form of fluctuation of electric or magnetic field, etc.

The waves after being formed can move away from the matter that formed them, transporting the energy that alternately has kinetic and potential energy, but the total energy is constant.

Therefore the energy in matter is due to the movement of the same and the energy in the wave does not require the movement of matter, so it is a more efficient way of doing work.

In conclusion, the energy of matter implies the movement of masses and the energy of the wave has no moving masses.

The Voltage is the pressure from the electrical circuit of the power source that passes the current.

The Voltage is defined as the pressure from the electrical circuit of the power source that will passes the charged electrons that is the current through the conducting loop, it will enable them to do work  because of the illuminating the light. The in simple terms is : voltage = pressure, and it is denoted as the volts and the symbol is the V.

The voltage is described as the force that causes the flow of the charged particles. The Voltage is also called as the electromotive force.

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Answer:

 0.5

Explanation:

mol = mass  : MM SiO₂

mol = 0.0102 : 60 g/mol = 0.00017

molecules = 0.00017 x 6.02 x 10²³ = 1.0234 x 10²⁰

Answer:

1. C) Hydrogen of water is separated from oxygen.

2. A) Carbon dioxide

3. D) Mechanical energy to chemical energy

4. B) Glucose

5. B) Respiring while swimming underwater

6. A) Oxygen

7. B) Photosynthesis depends on the carbon dioxide released during cellular respiration.

8. A) It is affected by social concerns.

9. D) Chlorophyll stores chemical energy needed for photosynthesis.

10. Cellular respiration is the process by which organisms use oxygen to break down food molecules to get chemical energy for cell functions.

Brainlist Pls!

A single bond contains two shared electrons.

A nutrient is a substance used by an organism to survive, grow, and reproduce. The requirement for dietary nutrient intake applies to animals, plants, fungi, and protists. Nutrients can be incorporated into cells for metabolic purposes or excreted by cells to create non-cellular structures, such as hair, scales, feathers, or exoskeletons. Some nutrients can be metabolically converted to smaller molecules in the process of releasing energy, such as for carbohydrates, lipids, proteins, and fermentation products (ethanol or vinegar), leading to end-products of water and carbon dioxide. All organisms require water. Essential nutrients for animals are the energy sources, some of the amino acids that are combined to create proteins, a subset of fatty acids, vitamins and certain minerals. Plants require more diverse minerals absorbed through roots, plus carbon dioxide and oxygen absorbed through leaves. Fungi live on dead or living organic matter and meet nutrient needs from their host.

Nuclear Fission

Nuclear fission, subdivision of a heavy atomic nucleus, such as that of uranium or plutonium, into two fragments of roughly equal mass. The process is accompanied by the release of a large amount of energy. In nuclear fission the nucleus of an atom breaks up into two lighter nuclei.

Nuclear fission is a process where the nucleus of an atom is split into two or more smaller nuclei, known as fission products. The fission of heavy elements is an exothermic reaction, and huge amounts of energy are released in the process.

Using the periodic table, THE molecule that has a stable configuration that satisfies the octet rule for all atoms is option B: MgO

MgO (Magnesium Oxide) and (Magnesium Oxide) establish an ionic bond thanks to the electrostatic attraction that develops between them. A MgO molecule contains two atoms with stable octet arrangements.

Note that when we study the octet rule of the MGO Lewis structure. The octet rule is satisfied by the oxygen atoms and magnesium in the MgO Lewis structure. Since oxygen only requires two electrons, the condition transfers two electrons. Oxygen receives these two electrons from magnesium, a metal having two electrons in its valence shell.

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The ammonia formation has been 1.125 mol/L.

Keq is defined as the ratio of the mathematical product of the equilibrium concentrations of the species on the right that is multiplied by the concentrations of the chemical products divided by the mathematical product of the equilibrium concentrations of the species on the left.

This is the reaction that makes ammonia from hydrogen and nitrogen. Only one product is produced in this reaction. This reaction is therefore known as a binding reaction. A small Keq Keq < 1 implies a large concentration of reactants at equilibrium. In this case, the reaction drives the formation of reactants. If Keq ≈ 1 it means that there is a significant amount of reactants and products in equilibrium.

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Keq is equal to the number 4.5

The standard deviation of ksp is 2.646 x 10⁻⁶ and the relative standard deviation kf ksp (%RSD) is 27.56%.

To calculate standard deviation of Ksp, first, find the deviations of each trial's Ksp value from the average Ksp value:

Trial 1 = (10 x 10⁻⁵) - (9.6 x 10⁻⁶) = 9.04 x 10⁻⁶

Trial 2 = (8.0 x 10⁻⁵) - (9.6 x 10⁻⁶) = 7.04 x 10⁻⁵

Trial 3 = (11 x 10⁻⁵) - (9.6 x 10⁻⁶) = 1.04 x 10⁻⁴

Square each deviation and find the average:

(9.04 x 10⁻⁶)² + (7.04 x 10⁻⁵)² + (1.04 x 10⁻⁴)² = 2.098 x 10⁻¹⁰

Average = 2.098 x 10⁻¹⁰ / 3 = 6.993 x 10⁻¹¹

Finally, take the square root of the average to get the standard deviation of Ksp:

Standard deviation of Ksp = √(6.993 x 10⁻¹¹) = 2.646 x 10⁻⁶

To calculate the relative standard deviation of Ksp (%RSD):

%RSD = (standard deviation / average) x 100%

%RSD = (2.646 x 10⁻⁶ / 9.6 x 10⁻⁶) x 100% = 27.56% (rounded to two decimal places)

Therefore, the standard deviation of Ksp is 2.646 x 10⁻⁶ and the relative standard deviation of Ksp (%RSD) is 27.56%.

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The proximity of unsaturated groups (C=C, C=O, aromatic) and electronegative atoms (O, N, halogen) has an impact on the proton NMR chemical shift. Electronegative groups shift to the left (down field; ppm rise).

The chemical shift in nuclear magnetic resonance (NMR) spectroscopy refers to the atomic nucleus' resonant frequency in relation to a standard in a magnetic field. The location and quantity of chemical changes frequently serve as diagnostic indicators of molecular structure.

You take into account the chemically non-equivalent proton(s) one at a time while making chemical shift predictions. Find the origin of each proton or proton pair that is not chemically comparable. Whether the proton(s) is/are linked to a methyl, methene, or methine determines the beginning point.

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Answer:

The property of metals that is the result of light reflecting off the electrons is

A.  shiny

The property of metals that is the result of light reflecting off the electrons is shiny. Hence, option A is correct.

The ability of a material to shine is called lustre. Gold, silver and other metals are examples of lustrous substances.

Metals are readily identified by their most common physical property, the ability to reflect light, known as lustre.

The property of metals that is the result of light reflecting off the electrons is shiny. Hence, option A is correct.

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