What conditions make AG always negative?
O A. AG is always negative when the reaction is exothermic.
O B. AG is always negative when AH is positive and AS is negative.
O C. AG is always negative when the system becomes more random.
D. AG is always negative when A His negative and AS is positive.

Answer:

Boron, Hydrogen, Helium, Lithium, Beryllium, Carbon, Nitrogen, Oxygen, etc.

Explanation:

These are all elements, not all of them.

The number of atoms of gold in the 2.96 mL of the seawater is 4.73×10¹⁰ atoms

1 mole of Gold = 6.02×10²³ atoms

With the above information, we can determine the number of atoms in the seawater. Details below

1 mole of Gold = 6.02×10²³ atoms

Therefore,

7.86×10⁻¹⁴ mole of gold = (7.86×10⁻¹⁴ mole × 6.02×10²³ atoms) / 1 mole

7.86×10⁻¹⁴ mole of gold = 4.73×10¹⁰ atoms

Thus, 4.73×10¹⁰ atoms of gold are present in the seawater

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Answer:Chemistry is important for meeting our needs of food,clothing,shelter,health,energy,and clan air,water,and soil.

The statement that correctly defend or dispute his conclusion is option3:

A physical alteration occurs when salt water evaporates. Since the matter has merely changed states but still remains the same substance, any phase shift is a physical change.

Table salt dissolving in water is an example of a physical change because only the condition of the substance has changed. Frequently, physical changes can be undone. The salt will become solid once the water has evaporated.

It's not a given that salt and water's formation of a single phase indicates a chemical reaction. It simply indicates that the two substances mixed evenly.

Therefore, This is supported by the fact that the mixture's components could be easily separated using a straightforward physical technique called evaporation.

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See full question below
Henry mixed salt and water together in a cup until he observed a clear solution. He measured the mass of the solution. Then he placed the cup outside for several sunny days during the summer. After a week, he observed that only solid salt remained in the cup and the mass had decreased. Henry concluded that a physical and chemical change occurred in this investigation.

Which statements correctly defend or dispute his conclusion?

1- He is correct. Dissolving salt in water is a physical change, but evaporating the water is a chemical change. Formation of a solid is evidence that a chemical change occurred.

He is correct. Evaporation is a physical change, but dissolving salt in water is a chemical change. The change in mass is evidence that a chemical change occurred.

2- He is incorrect. Dissolving salt in water and evaporation of the water are both physical changes. The reappearance of salt is evidence that the change was reversible by a physical change, so it could not be a chemical change.

3- He is incorrect. Dissolving salt in water and evaporation of the water are both chemical changes. The reappearance of salt is evidence that the change was reversible by a chemical change, so it could not be a physical change.

Answer: The Answer Is D, He described light as little packets called photons.

Explanation:

The contribution of Albert Einstein to our understanding of the photoelectric effect is he described light as little packets called photons. The correct option is D.

The theory of relativity, which Albert Einstein developed and is rightfully famous for, transformed our understanding of space, time, gravity, and the cosmos.

Along with his work on relativity, the physicist established the scientific principles behind items like paper towels, lasers, and other everyday items.

Since Einstein first suggested using the use of light quanta to clarify the photoelectric impact, quantum theory accurately portrays the photoelectric impact. The quantum theory of radiation gives this concept a formal formulation.

Therefore, the correct option is D. He described light as little packets called photons.

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Quantum numbers can be shown by;

ℓ

ms

When we talk about the quantum numbers that describe an electron, we are looking at the number that can be used to show the designation of an electron in an atom. Thus the position of the electron that can be found in the atom is shown by the use of the quantum numbers.

There are four sets of quantum numbers and they are;

1) orbital quantum number (l)

2) Spin quantum number (ms)

3) Magnetic quantum number (ml)

4) Principal quantum number (n)

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Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\ \)

From the question we have

\(n = \frac{4.5 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 7.475083056...\)

We have the final answer as

Hope this helps you

Answer:

100 HZ 1,000 HZ 10,000 HZ there you go :)

Answer:

100 hertz, 1,000 hertz, and 10,000 hertz

Explanation:

I took the k12 test :)

The birth weight of cats at the 90th percentile would be approximately 3.7 ounces. b. The birth weight of cats at the 10th percentile would be approximately 2.3 ounces.

There are three main methods of calculating weight:

1. Balance Beam Scale: A balance beam scale is an example of a mechanical weighing system. It uses a set of calibrated weights to measure the weight of an object.

2. Digital Scale: A digital scale uses an electronic or digital readout to display the weight of an object.

3. Calipers: Calipers are devices used to measure the distance between two points, such as thickness or diameter. They come in various sizes and shapes, depending on the type of measurement the user wants to take.

Birth weight is the weight of a baby at the time of birth. It is usually measured soon after delivery, with a special baby scale, though sometimes the baby's weight is estimated. The normal range of birth weight is anywhere between 5 lbs 8 oz and 10 lbs, though preterm or premature babies may be significantly lighter. A baby's birth weight is important because it can provide a clue to the baby's overall health. High birth weights may indicate an underlying medical condition, and low birth weights can be a sign of premature or difficult delivery and health risks associated with such a delivery.

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The pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C is 2.24 × 10⁰ atm.

The pressure of a substance can be calculated using the following formula;

PV = nRT

According to this question, the pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C can be calculated as follows:

P × 2 = 0.1 × 0.0821 × 546

2P = 4.48266

P = 2.24 × 10⁰ atm

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Answer:

Explanation:

⁵⁹₂₆Fe --------- ⁰₋₁e + ⁵⁹₂₇Co

Co- 59 is known as Cobalt

its symbol is ⁵⁹₂₇Co

The name of the product is Cobalt-59 and the symbol of the nuclide is \(^{59}Co_{27}\).

It is a type of radioactive decay in which a beta particle (fast energetic electron or positron) is emitted from an atomic nucleus, transforming the original nuclide to an isobar of that nuclide.

When the nuclide iron-59 undergoes beta decay it will lead to the formation of cobalt-59. The reaction can be represented as:

\(^{59}Fe_{26} --> ^0e_{-1} + ^{59}Co_{27}\\\)

Thus, The name of the product is Cobalt-59 and the symbol of the nuclide is \(^{59}Co_{27}\).

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False.

There is more thermal energy (faster moving particles) in a warmer region, so they spread out over time, warming up the other regions and losing energy.

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Answer:

1. 2.41 × 1023 formula units

2. 122 L

3. 7.81 L

Explanation:

1. Equation of the reaction: 2 Na(NO3) + Ca(CO3) ---> Na2(CO3) + Ca(NO3)2

Mole ratio of NaNO3 to CaCO3 = 2 : 1

Moles of CaCO3 = mass/molar mass

Mass of CaCO3 = 20 g; molar mass of CaCO3 = 100 g

Moles of CaCO3 = 20 g/100 g/mol = 0.2 moles

Moles of NaNO3 = 2 × 0.2 moles = 0.4 moles

1 Mole of NaNO3 = 6.02 × 10²³ formula units

0.4 moles of NaNO3 = 0.4 × 6.02 × 10²³ = 2.41 × 1023 formula units

2. Equation of reaction : 2 H2O ----> 2 H2 + O2

Mole ratio of oxygen to water = 1 : 2

At STP contains 6.02 × 10²³ molecules = 1 mole of water

6.58 × 10²⁴ molecules = 6.58 × 10²⁴ molecules × 1 mole of water/ 6.02 × 10²³ molecules = 10.93 moles of water

Moles of oxygen gas produced = 10.93÷2 = 5.465 moles of oxygen gas

At STP, 1 mole of oxygen gas = 22.4 L

5.465 moles of oxygen gas = 5.465 moles × 22.4 L/1 mole = 122 L

3.Equation of reaction: 6 K + N2 ----> 2 K3N

Mole ratio of Nitrogen gas and potassium = 6 : 1

Moles potassium = mass/ molar mass

Mass of potassium = 90.0 g, molar mass of potassium = 39.0 g/mol

Moles of potassium = 90.0 g / 39.0 g/mol = 2.3077moles

Moles of Nitrogen gas = 2.3077 moles / 6 = 0.3846 moles

At STP, 1 mole of nitrogen gas = 22.4 L

0.3486 moles of oxygen gas = 0.3486 moles × 22.4 L/1 mole = 7.81 L

1. Volume of oxygen 2.41 × 1023   units

2. Nitrogen gas 122 L

3. 7.81 L

Equation of the reaction:

\(\rm 2Na(No_3)+Ca(Co_3)---- > Na_2(Co_3)+Ca(No_3)_2\)

\(NaNo_3\ and \ CaCo_3=\dfrac{2}{1}\)

\(\rm Moles \ of \ CaCo_3=\dfrac{Mass}{Molar\ Mass}\)

Mass of CaCO3 = 20 g; molar mass of CaCO3 = 100 g

\(\rm \ Moles \ of \ CaCo_3=\dfrac{20}{100} =0.2\)

\(Moles \ of \ NaNo_3=2\times 0.2=0.4\ moles\)

\(1\ mole\ of \ NaNo_3=6.02\times10^{23}\)

0.4 moles of NaNO3 = \(0.4\times 6.02\times 10^{23}=2.41\times 10^{23}\)  

2. Equation of reaction :\(2H_2o---- > 2H_2+o_2\)  

The mole ratio of oxygen to water =  \(\dfrac{2}{1}\)

At STP contains

 \(\dfrac{6.02\times 10^{24}\times 1 \ mole \ of \ water}{6.02\times 10^{23}} =10.93\ moles \ of \ water\)

Moles of oxygen gas produced =

\(\dfrac{10.93}{2} =5.465\ Moles \ of \ oxygen \ gas\)

At STP, 1 mole of oxygen gas = 22.4 L

5.465 moles of oxygen gas =    \(5.465\times 22.4=122\ L\)  

3. Equation of reaction:

\(6k+N_2---- > 2K_3N\)6

The mole ratio of Nitrogen gas and potassium =   \(\dfrac{6}{1}\)

\(Moles\ of \ potassium = \dfrac{Mass}{Molar\ Mass}\)

Mass of potassium = 90.0 g,

molar mass of potassium = 39.0 g/mol

\(Moles\ of \ potassium = \dfrac{90}{39}=2.3077\ moles\)

\(Moles\ of \ Nitrogen = \dfrac{ 2.3077}{6}=0.3846\ moles\)

At STP, 1 mole of nitrogen gas = 22.4 L

0.3486 moles of oxygen gas =

\(0.3486\times 22.4=7.81\ L\)

Thus

1. Volume of oxygen 2.41 × 1023   units

2. Nitrogen gas 122 L

3. 7.81 L

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The mass of HF produced from the given amounts of BF₃ and H₂ is 99.5 grams.

To solve this problem, we need to use stoichiometry to determine the amount of HF produced from the given amounts of BF₃ and H₂.

From the balanced equation;

2 BF₃ + 3 H₂ → 2 B + 6 HF

We can see that 2 moles of BF₃ react with 3 moles of H₂ to produce 6 moles of HF. This means that the ratio of BF₃ to HF is 2:6, or 1:3.

First, we need to calculate the number of moles of BF₃ and H₂ from their given masses and molar masses;

n(BF₃) = m(BF₃) / M(BF₃) = 40 g / 67.81 g/mol = 0.59 mol

n(H₂) = m(H₂) / M(H₂) = 5 g / 2.02 g/mol = 2.48 mol

Next, we can determine which reactant is limiting by comparing their mole ratios. The ratio of BF₃ to H₂ is 1:1.67, which means there is not enough H₂ to react with all of the BF₃. This makes H₂ the limiting reactant.

To find the number of moles of HF produced, we use the mole ratio from the balanced equation;

n(HF) = n(H₂) × (6 mol HF / 3 mol H₂) = 2.48 mol × 2

= 4.96 mol

Finally, we calculate the mass of HF produced from its number of moles and molar mass;

m(HF) = n(HF) × M(HF) = 4.96 mol × 20.01 g/mol

= 99.5 g

Therefore, the mass of HF is 99.5 grams.

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The mass of H₂s present in 2.00 L of natural gas at 298 K is 0.002156 g.

The volume hydrogen sulfide in 2.00 L of natural gas at 298 K is calculated as follows:

Volume of hydrogen sulfide = percent composition * volume of natural gas

Volume of hydrogen sulfide = 0.07/100 * 2.00 L

Volume of hydrogen sulfide = 0.014 L

The given temperature is standard temperature.

Density of H₂s at STP is equal to 1.54 g/L.

mass of H₂s = density * volume

mass of H₂s = 0.0014 * 1.54

mass of H₂s = 0.002156 g

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Explanation:

What factors affect purity?

A1: The key parameters that can be controlled in an emew cell are current density, flow rate, electrolyte temperature, and plating time. The current density controls the production rate, while the flow rate, temperature, and plating time can all have an impact on the product

What factors affect yield?

The yield and rate of a chemical reaction depend on conditions such as temperature and pressure. In industry, chemical engineers design processes that maximise the yield and the rate at which the product is produced. They also aim to reduce waste and energy costs at all stages of the process.

HOPE THIS HELPS YOU THANK YOU.

Answer:

26.7%

Explanation:

molar mass of compound = 120 g/ mol

Solving for the percent composition by mass of sulfur.

The formula would be: %S = mass of sulfur / mass of compound x 100%

therefore %S = 32 amu / 120 amu x 100%

%S = 0.266666 x 100%

%S = 26.66%

by rounding off

%s = 26.7%

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The fraction of the  cross-sectional area occupied by the nucleus as a fraction of that occupied by the atom is 3.48 * 10^-9 .

Now we know that the atom is composed of the nucleus that houses the protons and the neutrons while the electrons are found on the shells.

We have the information in the question that the diameter of the atom is given as  1.7 Å or 1.7 * 10^-10 m and the diameter of the nucleus is 1.0×10−4Å or 1.0×10^−14 m.

Area of the atom = 3.142 * ( 1.7 * 10^-10/2)^2 = 2.27 * 10^-20 m^2

Area of the nucleus =  3.142 * (1.0×10^−14/2)^2 = 7.9 * 10^-29 m^2

The fraction of the  cross-sectional area occupied by the nucleus as a fraction of that occupied by the atom is ; 7.9 * 10^-29 m^2 /2.27 * 10^-20 m^2

= 3.48 * 10^-9

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B. The movement of basketball players on a court of the following is an example of quantization

The process of translating continuously infinite values to a more manageable collection of discontinuous finite values is known as quantization. It involves estimating real-world values with a digital representation that places restrictions on a value's precision and range in the context of simulation and embedded computing.

As a general guideline, quantize to the note you've played that is the shortest; for example, if the phrase contains both eighth and quarter notes, use eighth note resolution. Keep in mind that many rhythms may really employ triplets; if things aren't working out, you may try utilising a triplet resolution.

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The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Answer: Nerve cells and muscle cells

Explanation:

The nerve cells and the muscles cells of the body plays important role in the conduction of the signals.

Calcium ion helps in the signal conduction so its role is majorly important in nerve cells and muscle cells.

The calcium signalling can be defined as the use of calcium ions for the cellular signalling, it enters the cytoplasm and exerts allosteric regulatory enzymes in many of the proteins and enzymes.

This derives many intracellular processes and signal transmission is one of the following.

Approximately 70.57 mL of 1.00 M NaOH should be added to 250 mL of 0.50 M CH3CO₂H to produce a buffer with a pH of 4.50.

To determine the volume of 1.00 M NaOH required to produce a buffer with a pH of 4.50 when added to 250 mL of 0.50 M CH3CO₂H, we need to consider the Henderson-Hasselbalch equation and the stoichiometry of the reaction.

The Henderson-Hasselbalch equation for a buffer solution is given as:

pH = pKa + log([A-]/[HA])

In this case, CH3CO₂H (acetic acid) acts as the weak acid (HA) and CH3COO- (acetate ion) acts as its conjugate base (A-). We are given that the desired pH is 4.50, and we can determine the pKa value for acetic acid from reference sources, which is approximately 4.75.

Using the Henderson-Hasselbalch equation, we can rearrange it to solve for the ratio [A-]/[HA]:

[A-]/[HA] = 10^(pH - pKa)

[A-]/[HA] = 10^(4.50 - 4.75) = 10^(-0.25) = 0.5623

This means that the ratio of the acetate ion to acetic acid in the buffer solution should be approximately 0.5623.

To calculate the required volume of NaOH, we need to consider the stoichiometry of the reaction. Acetic acid reacts with hydroxide ions (OH-) to form acetate ions and water:

CH3CO₂H + OH- → CH3COO- + H2O

The stoichiometric ratio between acetic acid and hydroxide ions is 1:1. Therefore, the volume of 1.00 M NaOH needed can be calculated using the equation:

Volume (NaOH) × 1.00 M = Volume (CH3CO₂H) × 0.50 M × 0.5623

Volume (NaOH) = (Volume (CH3CO₂H) × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) = (250 mL × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) ≈ 70.57 mL

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Answer:

1 ➡️ Cells

2 ➡️ Arteries

3 ➡️ Veins

4 ➡️ Heart

Explanation:

The parts of the electric circuit that best correspond to the heart, arteries, veins, and cells have been properly labeled.

The circulatory system involves the transportation of nutrients, oxygen and water by blood to other the parts of the body.

From the electric circuit, we see that arteries transport blood away from the heart to the other cells in the body. The veins actually return the blood back to the heart from the cells. The heart pumps the blood

The electric circuity diagram has the label 1 bulb analogous to cell, label 2 analogous to arteries, label 3 analogous to veins, and label 4 cell analogous to heart.

The electric circuit has been given as the power source and the conducting wires that allows the flow of the current in the circuit.

In the human body, the heart has been transported the oxygenated blood through the arteries to the cell and carried the deoxygenated blood from the cells back to the heart via veins.

In the circuit, the battery has been the source of the power/blood. The current has been carried from the heart to the cell/bulb through the arteries labeled, 2, and transported back to the battery via veins labeled 3.

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Answer:

they remain liquid

Explanation:

because liquid in liquid mostly doesn't have any affect on the state of the matter

as,

water added to juice

remains liquid

Answer:

Option A.

Explanation:

To know which structure is correct, let us name both compound.

In naming the above organic compound, the following must be observed:

1. Locate the functional group. In this case it alkene since it has carbon to carbon double bond (C=C).

2. Locate the longest continuous carbon chain. In this case the compound is a cyclic compound with 6 carbon i.e cyclohexene.

3. Locate the substituents attached to the compound. In this case, bromine (bromo) and chlorine (chloro) are the substituents attached.

4. Locate the position of the substituents and name alphabetically counting from the double bond. In this case, bromo comes before chloro

5. Combine the above to get the name.

For option A, the name is:

4–bromo–5–chlorocyclohexene.

For option B, the name is:

3–bromo–4–chlorocyclohexene.

We can see that Option A gives the correct structure of the compound.

Answer:

C. polar nature

Explanation:

The polarity of water and its ability to hydrogen bonding contributes to it's unique properties

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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The Brnsted-Lowry acid-base hypothesis states that when a molecule gives a proton (H+ ion) to another molecule, it behaves as an acid. As a result, the right response is (3) donates an H+.

The Arrhenius theory states that acid is a chemical that causes water to create hydrogen ions. Base is a chemical that causes water to form hydroxide ions.

A neutralisation reaction takes place during the acid-base titration. Here, the concentration of a particular base or acid is ascertained by neutralisation against an acid or base of known concentration. This kind of titration begins with a drop of an indicator, which changes colour to show the endpoint.

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Answer:

ideal gas law. PV=nRT

Explanation:

pressure x volume = #moles x R (constant of 8.31) x temp

Answer:

C The atoms has a tiny, massive nucleus at its center with electrons surrounding it

Explanation:

From the experiment by Rutherford, he suggested a model of the atom where there is a tiny but massive nucleus at the center with electrons surrounding it.