Answers
Answer:
they..don't cook foood
Related Questions
the velocity of three turtles walking in the park. The x-axis is positive towards the North direction.
1. Rank the accelerations of the three turtles from the smallest to largest
2. Are the turtles go- ing towards North or South direction? Are they changing direction?
Answers
The ranking of their accelerations from smallest to largest is: Turtle C, Turtle A, Turtle B.
How to solveBased on the given accelerations:
Turtle C has the smallest acceleration (0.05 cm/s²).Turtle A has the next smallest acceleration (0.1 cm/s²).Turtle B has the largest acceleration (0.2 cm/s²).So the ranking of their accelerations from smallest to largest is: Turtle C, Turtle A, Turtle B.
Based on the given velocities:
Turtle A is going towards the North direction (positive velocity).Turtle B is going towards the South direction (negative velocity).Turtle C is going towards the North direction (positive velocity).As for the change in direction:
Turtle A is accelerating in the same direction as its velocity (North), so it's not changing direction, but its speed is increasing.
Turtle B is accelerating in the opposite direction of its velocity (North), so it will eventually change direction and start moving North when the acceleration overcomes the initial Southward velocity.
Turtle C is accelerating in the same direction as its velocity (North), so it's not changing direction, but its speed is increasing.
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Three turtles are walking in the park. The x-axis is positive towards the North direction. The velocities of the turtles are as follows:
Turtle A has a velocity of 2 cm/s to the North and an acceleration of 0.1 cm/s².
Turtle B has a velocity of 1 cm/s to the South and an acceleration of 0.2 cm/s².
Turtle C has a velocity of 3 cm/s to the North and an acceleration of 0.05 cm/s².
Rank the accelerations of the three turtles from smallest to largest based on their given accelerations.
Are the turtles going towards the North or South direction? Are they changing direction based on their accelerations?
How much heat is absorbed by a person hand if 100 grams of steam at 100°C is first converted to liquid water at 100°C and then cooled to normal body temperature?
Answers
In order for steam to reach the body temperature, of about 37°C, first it will need to release the latent heat, which is the heat necessary to change from the steam state to the liquid state, and then the sensitive heat, which is actually responsible for the change in temperature.
The latent heat of water on the steam state is of 540 cal/g. Thus, we'll have:
\(Q_1=540*100=54000cal\)Now, we'll need the sensitive heat of water, which is 1 cal/(g°C):
\(Q_2=1*100*(100-37)=6300cal\)Thus, the total heat will be the sum of both, which will result in 60300cal
Demario's biology class has a quiz every other Friday. This is the third time Demario has been so worried about other personal matters that he hasn’t done quite as well on the quizzes as he might have otherwise. What has Demario upset is the fact that the professor leaves the room while the students take the quiz, and over half the class is taking the opportunity to cheat. Demario knows personally several of the other students in the class, and some of the ones Demario hangout with are among those who are cheating. Demario knows that a failure to speak to the professor about the cheating will result in his own grade being lower, since the school grades on the curve system. But if Demario does say something to the professor he will be doing his friends and the others a great harm, since cheating is taken very seriously at the school and can lead to expulsion. If Demario doesn’t “turn in” the classmates, the only other alternative is he will get a worse grade than he deserves. He will also be labled as a snitch among is peers and a cheater at the school, either of which Demario has never done. Further, if the professor somehow discovers that Demario is hiding the cheating of others, Demario will be considered an accessory to the cheating, and may be reprimanded for not turning others in, since the school operates on an honor system.
Critical thinking About Ethics Right vs Wrong
What should Demario do?
Should Demario cheat?
Should Demario turn in the cheating classmates?
Should Demario say nothing and not cheat himself?
Be specific in your answer about exactly what Demario should do. (Remember to use one of the three moral theories to solve this dilemma.)
Answers
1. It is unethical for Demario to cheat
2. Demario should not engage in cheating himself
3. Demario should not turn in cheating classmates without careful consideration
4. Reporting classmates may harm relationships, create animosity, and potentially lead to severe disciplinary actions.
What is ethics?A virtue ethics perspective may also be useful in this circumstance. Demario should make an effort to respect moral principles like honesty, fairness, and integrity while taking the potential repercussions into account and exhibiting empathy for his fellow students.
By employing this strategy, Demario behaves responsibly, deals with the problem subtly, encourages fairness in the educational setting, and upholds his or her own moral standards.
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how much heat is needed to raise 30g of water from 20°c to 50°c
Answers
Answer:
Q = C M ΔT (C = spec. heat, M = mass, ΔT = change in abs temp)
Q = 1 cal/gm-deg C * 30 gm * (50 - 20) deg C = 900 cal
1. an object given an initial velocity,which can move under gravity and is affected by air resistance is an example of projectile motion
A.True. B.False
2.the horizontal component is always equal to the vertical component of the velocity
A.True B.False
3.The formula Vx=Vø tan Ø is used to determine the magnitude of the horizontal component of the velocity
A.True B.False
4.The velocity is directed vertically upward
A.True. B.False
5.when no air acts on a projectile,it's horizontal acceleration is upward gravity
A.True B.False
6.A stone thrown into the air is an example of projectile motion
A.True. B.False
7.The time to reach the top will be 1.5625s if. projectile is thrown at angle 30° above the ground with a velocity of 100ft/s
A.True B.False
Answers
2. B. False
3. A. True
4. B. False
5. B. False
6. A. True
7. B. False
Explanation:
1. The statement is true. Projectiles are objects that are launched into the air and then follow a curved path under the influence of gravity and air resistance.
2. The statement is false. The horizontal component of the velocity is independent of the vertical component of the velocity, and they can have different values.
3. The statement is true. The formula Vx=Vø tan Ø is the formula for the horizontal component of the initial velocity of a projectile.
4. The statement is false. The velocity of a projectile is directed at an angle to the horizontal, with both horizontal and vertical components.
5. The statement is false. When no air acts on a projectile, its horizontal acceleration is zero, because there is no force acting in the horizontal direction. The vertical acceleration is still due to gravity.
6. The statement is true. A stone thrown into the air follows a curved path under the influence of gravity, making it an example of projectile motion.
7. The statement is false. The time to reach the top of the projectile's path depends on the initial velocity and angle of launch, as well as the acceleration due to gravity. The time to reach the top can be calculated using the formula t = Vy/g, where Vy is the vertical component of the initialvelocity, g is the acceleration due to gravity, and t is the time. Using this formula, the time to reach the top of the projectile's path can be calculated as:
t = Vy/g = Vø sin Ø/g = (100 ft/s)(0.5)/(32.2 ft/s²) = 1.55 s (approx.)
Therefore, the statement is false.
An m = 8 kg ball is projected with initial horizontal speed v = 40 m/s from a platform h = 80 meters high.(a) How much time does it take for the ball to reach the ground? s(b) What is the ball's kinetic energy when it reaches the ground? J
Answers
Given,
The mass of the ball, m=8 kg.
The initial horizontal speed of the ball, v=40 m/s
The height of the platform, h= 80 m
As the ball is projected horizontally, the vertical component of the initial velocity will be zero. The ball will be having only horizontal velocity.
(a)
From the equation of the motion,
\(h=v_yt+\frac{1}{2}gt^2\)Where vy is the vertical component of the initial velocity, g is the acceleration due to gravity, and t is the time that the ball takes to reach the ground.
On substituting the known values,
\(\begin{gathered} 80=0+\frac{1}{2}\times9.8\times t^2 \\ \Rightarrow t=\sqrt[]{\frac{80\times2}{9.8}} \\ =4.04\text{ s} \end{gathered}\)Thus the ball will take 4.04 s to reach the ground.
The y-component of the final velocity is given by,
\(u_y=v_y+gt\)On substituting the known values,
\(\begin{gathered} u_y=0+9.8\times4.04 \\ =39.6\text{ m/s} \end{gathered}\)As there is no acceleration on the ball in the horizontal direction, the horizontal component of the velocity will remain the same. That is,
\(u_x=v_x=40\text{ m/s}\)Thus the magnitude of the final velocity is given by,
\(u=\sqrt[]{u^2_x+u^2_y}\)On substituting the known values,
\(\begin{gathered} u=\sqrt[]{39.6^2+40^2} \\ =56.3\text{ m/s} \end{gathered}\)The kinetic energy is given by,
\(K=\frac{1}{2}mu^2\)On substituting the known values,
\(\begin{gathered} K=\frac{1}{2}\times8\times56.3^2 \\ =12.68\times10^3\text{ J} \\ =12.68\text{ kJ} \end{gathered}\)Therefore the kinetic energy of the ball when it reaches the ground is 12680 J
a pound of body fat stores in the amount of chemical energy equivalent to 3500 calories. When sleeping the average adult burns on and expends about 0.45 Cal/h How many calories would a 150 lb person burn during 8 hours of sleep?How how long would the personhave to sleep continuously to lose one pound of body fat
Answers
We know that
• The average is 0.45 calories per hour.
,• The energy stored is 3500 calories per pound of body fat.
,• The mass is 150 pounds.
,• The hours of sleep are 8.
First, we have to multiply the mass 150 lb by the average rate
\(150lb\times0.45=67.5\text{cal}/hr\)This means that this person burns 67.5 calories per hour. Now, we have to multiply this rate by 8 hours.
\(67.5\times8=540\text{cal}\)Therefore, a 150 lb person would burn 540 calories during 8 hours of sleep.Now, we know that 1 pound of body fat is equivalent to 3500 calories. So, let's use a rule of three to find the period of time would take this person to lose one pound of body fat (3500 cal).
\(\frac{67.5\text{cal}}{1hr}=\frac{3500\text{cal}}{x}\)Let's solve for x
\(\begin{gathered} x=\frac{3500}{67.5}hr \\ x\approx51.9hr \end{gathered}\)Therefore, this person would have to sleep continuously for 51.9 hours to lose one pound of body fat.Joe pushes a box rightward with a force of 3 N, causing it to slide 2m across the floor at a constant speed. 1) How many joules (J) of work did Joe do on the box?Answer: _______ J2)How much work (in J) was done by friction on the box?Answer: ________ J
Answers
Given:
The force applied to the box is F = 3 N
The displacement of the box is d = 2 m
The box moves with constant speed.
Required:
1) Work done by Joe on the box.
2) Work done by friction on the box.
Explanation:
1) The work done by Joe on the box can be calculated as
\(\begin{gathered} W=Fd \\ =3\times2 \\ =\text{ 6 J} \end{gathered}\)2) The box moves at a constant speed, so the acceleration will be zero.
The equation of motion can be written as
\(\begin{gathered} F-f=ma \\ F-f=m\times0 \\ F-f=0 \\ F=f \end{gathered}\)Here, f is the force of friction and m is the mass of the box.
The work done by friction can be calculated as
\(\begin{gathered} W=fd \\ =3\times2 \\ =6\text{ J} \end{gathered}\)Final Answer:
1) Work done by Joe on the box is 6 J.
2) Work done by friction on the box is 6 J.
A 310-g air track cart is traveling at 1.25 m/s and a 270-g cart traveling in the opposite direction at 1.33 m/s. What is the speed of the center of mass of the two carts
Answers
Answer:
The speed of the center of mass of the two carts is 0.049 m/s.
Explanation:
Given;
mass of the first cart, m₁ = 310 g = 0.31 kg
speed of the first cart, v₁ = 1.25 m/s
mass of the second cart, m₂ = 270 g = 0.27 kg
speed of the second cart, v₂ = - 1.33 m/s (in opposite direction)
The speed of the center of mass of the two carts is calculated as;
\(v_{CM} = \frac{m_1v_1 \ + \ m_2v_2}{m_1 \ + \ m_2}\\\\ v_{CM} = \frac{(0.31 \times 1.25) \ + \ (0.27 \times -1.33)}{0.31 \ + \ 0.27} \\\\v_{CM} = \frac{0.3875 \ - \ 0.3591}{0.58} \\\\ v_{CM} = \frac{0.0284}{0.58} \\\\v_{CM} = 0.049 \ m/s\)
Therefore, the speed of the center of mass of the two carts is 0.049 m/s.
Use the drop-down menus to complete the sentences.
The first step in a bill becoming a law is for the bill to be
.
Next, the bill goes to
to be marked up, dropped, or sent to the floor.
After that, the bill is debated on the floor and can pass on a majority vote of
.
In the next stage, the bill must go to the
to repeat the process.
After the bill is resolved in the
, it goes to the president.
Answers
The first step towards a bill becoming a law is for the bill to be introduced in Congress.
Next, the bill goes to a committee to be marked up, dropped, or sent to the floor.
After that, the bill is debated on the floor and can pass with a majority vote of the house that sponsored it.
In the next stage, the bill must go to the other chamber, to repeat the process.
After the bill is resolved in the conference committee, it goes to the president.
What is the Congress?The Congress is sometimes referred to as Senate and it can be defined as a deliberative assembly or council of elected citizens found in the upper chamber or house of a bicameral legislature.
This ultimately implies that, Congress is a federal legislative arm of government of the United States of America, which is saddled with the responsibility of enacting and passing federal laws and bills for the citizens, with the steps enumerated above.
Generally speaking, the first step of making bill to become a law is introducing it to the Congress while the last step is the resolution of a bill if it is voted in favor by at least 44 senators, and then it finally goes to the president for assent through his or her signature.
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Complete Question:
Use the drop down menus to complete the sentences.
The first step in a bill becoming a law is for the bill to be _____.
Next the bill goes to _____ to be marked up, dropped or sent to the floor.
After that, the bill is debated on the floor and can pass on a majority vote of ____.
In the next stage, the bill must go to the ____ to repeat the process.
After the bill is resolved in the ____, it goes to the president.
Thomas the Train chugs along at 2 m/s. Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s. What is Thomas' acceleration?
Answers
The acceleration of Thomas is 0.233 m/s^2.
Acceleration is the rate of change of velocity. Thomas the Train chugs along at a velocity of 2 m/s.
Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s.
We are to find the acceleration of Thomas.
The formula for acceleration is given as :
acceleration = (final velocity - initial velocity) / time
In the given problem, the initial velocity of Thomas, u = 2 m/s.
The final velocity of Thomas, v = 4.33 m/s The time for which Thomas accelerates, t = 10 s.
Therefore, the acceleration of Thomas will be given as:
a = (v - u) / ta = (4.33 - 2) / 10s => 2.33 / 10s => 0.233 m/s^2
Thus, the acceleration of Thomas is 0.233 m/s^2.
To summarize, the acceleration of Thomas is 0.233 m/s^2.
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The mass of an empty cylindrical tin is
proportional to its surface area.
Two empty cylindrical tins, G and H, are
shown below.
The mass of tin G is 72 g, and the surface
area of tin H is 792π cm².
2
a) Work out the total surface area of tin G in
terms of π.
b) Work out the mass of tin H.
Tin G
12 cm
5 cm
Tin H
Not drawn accurately
Answers
a) The total surface area of tin G in terms of π is 170π cm².
b) The mass of tin H is 336 g.
To solve the given problem, we need to determine the total surface area of tin G in terms of π and the mass of tin H. Since the mass of an empty cylindrical tin is proportional to its surface area, we can use the given information to find the solutions.
a) Total surface area of tin G in terms of π:
The surface area of a cylinder consists of two circular bases and the lateral surface area. The formula for the lateral surface area of a cylinder is given by:
Lateral surface area = 2πrh
where r is the radius of the base and h is the height of the cylinder.
In the case of tin G, the given dimensions are a radius of 5 cm and a height of 12 cm. Substituting these values into the formula, we can calculate the lateral surface area:
Lateral surface area = 2π(5 cm)(12 cm)
Lateral surface area = 120π cm²
Since the total surface area of the cylinder includes the two circular bases as well, we need to add their areas. The area of a circle is given by:
Area of a circle = πr²
The radius of the circular base of tin G is 5 cm, so the area of each circular base is:
Area of each circular base = π(5 cm)²
Area of each circular base = 25π cm²
To find the total surface area of tin G, we sum the lateral surface area and the areas of the two circular bases:
Total surface area of tin G = Lateral surface area + 2 × Area of each circular base
Total surface area of tin G = 120π cm² + 2 × 25π cm²
Total surface area of tin G = 120π cm² + 50π cm²
Total surface area of tin G = 170π cm²
Therefore, the total surface area of tin G in terms of π is 170π cm².
b) Mass of tin H:
We are given that the surface area of tin H is 792π cm². We can assume that the same proportionality factor applies as in tin G, so we can set up the following proportion:
(surface area of tin G) / (mass of tin G) = (surface area of tin H) / (mass of tin H)
Using the given values, we have:
(170π cm²) / (72 g) = (792π cm²) / (mass of tin H)
Cross-multiplying and solving for the mass of tin H, we get:
(170π cm²) × (mass of tin H) = (72 g) × (792π cm²)
mass of tin H = (72 g) × (792π cm²) / (170π cm²)
mass of tin H = 336 g
Therefore, the mass of tin H is 336 g.
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Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
Answers
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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An object experiences a force of 15.0 N for 12.0 s. What is its change in momentum?
A. 12.0 N.s
B. 180 N.s
C. 15.0 N.s
D. 1.30 N.s
Answers
Answer:
C. 15.0 N.s
Explanation:
What is its change in momentum?15.0 N.s12.0 N.s180 N.s1.30 N.s
The change in momentum of the object is 180 N.s, which is option B.
What is the momentum of an object?It is an attribute of a moving body that exists due to its mass and motion and is analogous to the product of the body's mass and velocity.
The change in momentum of an object is equal to the product of the force acting on the object and the time interval during which the force is applied.
Using the given values:
Force = 15.0 N
Time = 12.0 s
Change in momentum = Force x Time
Change in momentum = 15.0 N x 12.0 s
Change in momentum = 180 N.s
Therefore, the change in momentum of the object is 180 N.s.
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(Figure 1) shows a velocity-versus-time graph for the bicycle trips of two friends with respect to the parking lot where they started. Xena's position at time zero is 0 and Gabriele's position is 60 m. Write function x(t) for Gabriele with respect to Xena. Express your answer in meters in terms of t , where t is in seconds.
Answers
Based on the velocity-time graph, the function x(t) for Gabriele with respect to Xena is: x(t) = 60 -2t.
What is a velocity-time graph?A velocity-time graph is a the graph of the change in velocity of an object or body with time.
The area under a velocity-time graph gives the displacement of the body within the given time interval.
From the given velocity-time graph:
The position, x, of Xena at time t, = v*t
x = 8t
The position of Gabriele at time t, = v*t
x =60 + 6t
Therefore, the function x(t) for Gabriele with respect to Xena is
x(t) = 60 + 6t - 8t
x(t) = 60 -2t
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Suppose that a woman weighing 130 lb and wearing high heeled shoes momentarily places all her weight on the heel of one foot. If the area of the heel is 0.50 in.2, calculate the pressure exerted on the underlying surface in (a) pounds per square inch, (b) kilopascals, and (c) atmospheres.
Answers
The pressure exerted on a 130 lb woman wearing high heels to momentarily place her entire body weight on the heel with an area of 0.50 in 2 on either foot is:
a. 260 lb/in².
b. 1,794 KPa
c. 17.69 atm
PressurePressure is a strong pushing force. Physics explains that the unit of pressure is symbolized by the letter P.
In addition to N/M², the pressure formula has another unit of measurement, namely Pascal (Pa).
The pressure formula used is:
P = F/A.
Where,
P = pressure (N/m²or Pa)
F = compressive force (N).
A = surface area (m²)
If you have the mass of the object:
P = (m.g)/A
m = object mass (kg)
g = acceleration due to gravity (m/s²)
A = surface area (m²)
We have,
Mass of the woman = 130 lb ⇒ 58.97 kg
The area of the heel = 0.50 in² ⇒ 3.21 m²
So, the pressure exerted on the underlying surface:
a. P = F/A
= 130 lb/0.50 in²
= 260 lb/in²
b. P = (58.97) (9.8) / 3.22
= 179.4 x 10⁴ Pa = 1,794 KPa
c. 1 KPa = 0.0098692329 atm
So, 1,794 KPa = 17.69 atm
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Positive electric charges are always attracted to ________ charges.
Answers
Answer:
Negative electric charges
When converting chemical potential energy to kinetic energy some of the energy is lost as heat.
Answers
Answer:
When converting chemical potential energy to kinetic energy some of the energy is lost as heat.
The two most prominent wavelengths in the light emitted by a hydrogen discharge lamp are 656 nm (red) and 486 nm (blue). Light from a hydrogen lamp illuminates a diffraction grating with 520 lines/mm , and the light is observed on a screen 1.4 m behind the grating.
Required:
What is the distance between the first-order red and blue fringes?
Answers
Answer:
0.143 m
Explanation:
Since
d = 1/N = 1/520 = 1.92 * 10^-3 mm
For red light;
θ = sin^-1 (1 * λred/d) = sin^-1 (1 * 656 * 10^-9/1.92 * 10^-6) = 19.98°
L = 1.4 * (tan 19.98) = 0.509 m
For blue light;
θ = sin^-1 (1 * λblue/d) = sin^-1 (1 * 486 * 10^-9/1.92 * 10^-6) = 14.66°
L = 1.4 * (tan 14.66°) = 0.366 m
Distance between the first-order red and blue fringes= 0.509 m - 0.366 m = 0.143 m
A baseball is tossed straight up in the air. The table shows the height and velocity of the ball at different times as it moves through the air.
Time in Air (seconds) Height of Ball Above Ground (feet) Velocity
(feet per second)
0.00 4 32
0.25 11 24
0.50 16 16
0.75 19 8
1.00 20 0
1.25 19 −8
1.50 16 −16
1.75 11 −24
2.00 4 −32
Which statement is true about the kinetic energy of the baseball at the moment it reaches its maximum height?
The baseball's kinetic energy is less than zero at that instant.
At that moment, all the baseball's kinetic energy has been lost as heat to the atmosphere.
The baseball's kinetic energy is greater than zero at that instant.
✅ At that moment, all the baseball's kinetic energy has been converted to potential energy. (correct answer)
Answers
Answer: At that moment, all the baseball's kinetic energy has been converted to potential energy.
Explanation: I took the test
Two parallel rods are each 0.69 m in length. They are attached at their centers to a spring that is initially neither stretched nor compressed. The spring has a spring constant of 130 N/m. When 1200 A of current is in each rod in the same direction, the spring is observed to be compressed by 3.0 cm. Treat the rods as long, straight wires and find the separation between them when the current is present.
Answers
Answer:
Explanation:
Let the separation required be d .
Force between rod = 10⁻⁷ x 2 I₁ I₂ L / d
where I₁ and I₂ are current in them , d is distance of separation and L is length of wire .
Force between rod = 10⁻⁷ x 2 x 1200 x 1200 x .69 / d
= .1987 /d
Restoring Force by spring = k x where k is force constant and x is compression .
= 130 x .03
= 3.9 N
For balancing
Restoring Force by spring = Force between rod
.1987 /d = 3.9
d = .1987 /3.9
= .0509 m
= 5.09 cm .
Every mass exerts a gravitational force on every other mass.
a. True
b. False
Answers
Answer:
A
Explanation:
newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is directly proportional to the product of their masses
A toy helicopter takes off and moves 6 m up and then 1 m back down. What
is the displacement of the helicopter?
A. 7 m
5 m up
C. 6 m
D. 1 m down
Answers
the answer is 5 m up AKA "B"
A particle starts from rest and is acted on by a net force that does work at a rate that is proportional to the time t. The speed of the particle is proportional to:_____
a. √t
b. t
c. t^2
d.1/√t
e. 1/t
Answers
Answer:
The speed of the particle is proportional to:
c. t²
Explanation:
Given;
initial velocity of the particle, u = 0
let the net force on the object = F
Work done on the particle is given by;
W = F x d
W ∝ t
\(Fd \ \alpha \ t\\\\\frac{mv}{t}d \ \ \alpha \ t\\\\mvd \ \ \alpha \ t^2\\\\v \ \ \alpha \ t^2\)
Therefore, the speed of the particle is proportional to t²
The speed of the particle is proportional to t.
It should be noted that work is a change in kinetic energy. Therefore, power will be calculated as:
Power = Work / Time = force × velocity
Power is proportional to t. Since force is a constant, then the velocity will be proportional to t. Therefore, the speed of the particle is proportional to t.
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A 4 kilogram (kg) toy car accelerates from 3.0 meters per second (m/s) to 8.0 meters per second. What is the change in the cart's momentum?
Answers
Answer:
20 kg*m/s
Explanation:
we're looking for the change in the cars momentum . the formula to identify the cars momentum is Δp=m*vf-m*vi . In this case m= mass , vf= velocity final, and vi= velocity initial . The mass is how much the car weighs , which is 4 kg . Velocity final would be 8 m/s since that's how fast it last was . Velocity initial would be 3 m/s since it had first started at that speed . Now we can jus plug it into the formula .
m= 4 kg
vf= 8 m/s
vi= 3 m/s
Δp= (4)*(8) - (4)*(3)
Δp= 32-12
Δp= 20 kg*m/s
hope this helps .
a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
Answers
When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.
When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.
This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.
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A bubble of air has a diameter of 1 mm whe
n it is 0.5 m under the surface of water (coefficient of surface tension 0.073 N/m). Find the gauge pressure inside the bubble.
Answers
Gauge pressure inside the bubble is: Pgauge = -4846.6 Pa
What is gauge pressure?Pressure measured relative to local atmospheric pressure is known as gauge pressure.
As ΔP = 4γ/r
ΔP -- pressure difference, γ -- coefficient of surface tension, r -- radius of bubble.
r = 0.5 mm = 0.0005 m
ΔP = 4 × 0.073 N/m ÷ 0.0005 m
ΔP = 58.4 N/m²
Patm = ρgh
Patm = 1000 kg/m³ × 9.81 m/s² × 0.5 m
Patm = 4905 Pa
Therefore, gauge pressure inside the bubble is:
Pgauge = ΔP - Patm
= 58.4 N/m² - 4905 Pa
Pgauge = -4846.6 Pa
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Box A has a mass of 35.0kg and Box B has a mass of 20.0kg. What is the tension on Box A if the acceleration of the system is -2.67m/s2 clockwise?
A. 250.N
B. 686N
C. 436N
D. 392N
Answers
Answer:
B. 686N
Explanation:
well do not write this because of I made a big mistake in my calculations
The tension on Box A if the acceleration of the system is provided clockwise is 686N.
What is tension?The tension is the force of pulling in the linear objects.
Given is the system of two masses hung over a pulley with a string. Mass of block A, M(A) =35kg, M(B) = 20kg and the acceleration clockwise a =-2.67 m/s²
The tension in the string of each block = T =m(g-a)
Substitute the values, we get
T = 35 x (9.81-(-2.67)) +20(9.81 +2.67)
T =436.8 N + 249.6
T = 686.4 N
Thus, the tension in the the block A will be approximately 686N.
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A 750 kg race car accelerates to the right. The engine applies a force of
+7000 N to the car. The total friction on the car in the opposite
direction is -200 N.
Find the net force on the car then use 'Fnet = m a' to find the
acceleration.
O a
b
Oc
Od
12.4 m/s2
10.5 m/s2
8.0 m/s2
9.1 m/s2
Answers
Answer: Option D, 9.1 m/s^2
Which label goes through the horizontal axis?
A. Distance
B. Acceleration
C. Force
D. Mass
Answers
Answer:
A: Distance
Explanation:
You can not change gravity with acceleration or force in a weird way. Only mass and distance really affect gravity in normal physics.
Gravity is stronger when two objects are closer. Therefore gravity would decrease as distance increased.
Mass increases gravity.
The image below shows that gravity (depth) increases as the distance from the black hole decreases.
