What impact area are extremely dangerou due to the enitivity of the dud contained within their boundarie?

The tension or compression of F CD = 3375 lb (G), F HI = 5625 lb (G), F CJ = 6750 lb (G)

Latin roots for the verb "to stretch" give us the word "tension." testing a portion of the force, such as a particular type of pull force. Any two physically connected objects may apply forces to one another. Depending on the kinds of things in contact, this contact forces different names. The force tensions are what we refer to when one of the items applying the force is a rope, string, chain, or cable. The force that results from compressing a material or object is called the compression force. Compression forces are the result of shearing forces aligning into one another. From hand tools to compression brakes, the compression force is employed to power everything. An essential engineering aspect is the compressive strength of materials and structures.

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Answer:

Computer programming is where you learn and see how computers work. People do this for a living as a job, if you get really good at it you will soon be able to program/ create a computer.

Explanation:

Hope dis helps! :)

Answer:

Explanation: Here it is: 67 Hope that helps! :)

Python has become a popular choice for web development, scripting, scientific computing, artificial intelligence, and more. The Python Programming language uses interpreter.

What is python programming language?

Python is a high-level, interpreted, general-purpose programming language. It is a widely used, versatile language that is easy to learn and has powerful libraries for data manipulation and analysis. It is a cross-platform language that can be used on both Windows and Unix-based systems. Python is known for its readability, making it easier to read and understand. It uses English keywords instead of punctuation and is less verbose than other languages. Its syntax allows programmers to express concepts in fewer lines of code than other languages. Python supports object-oriented, procedural and functional programming paradigms. Python was designed to be easy to use and its source code is available under an open source license.

It has a large, active community of developers and users who share tips, tutorials, and code. As a result, Python  has become a popular choice for developers and data scientists.

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Answer:

Tack coat is a sprayed application of an asphalt binder upon an existing asphalt or Portland cement concrete pavement prior to an overlay, or between layers of new asphalt concrete.

Explanation:

Answer:

The liquids are TOLUENE because the equilibrum vapor above it will be flammable ( D )

Explanation:

Liquids stored at : 1 atm , 25⁰c  and they are vented with air

Determining whether the equilibrum vapor above the liquid will be flammable

We can determine this by using Antoine equation to calculate saturation vapor pressure also apply Dalton's law to determine the volume % concentration of air and finally we compare answer to flammable limits to determine which liquid will be flammable

A) For acetone

using the Antoine equation to calculate saturation vapor pressure

\(In(P^{out} ) = A - \frac{B}{C + T}\)

values gotten appendix E ( chemical process safety (3rd edition) )

A = 16.6513

B = 2940.46

C = -35.93

T = 298 k      input values into Antoine equation

therefore ; \(p^{out}\) = 228.4 mg

calculate volume percentage using Dalton's law

= V% = (saturation vapor pressure / pressure ) *100

         = (228.4 mmHg / 760 mmHg) * 100 = 30.1%

The liquid is not flammable because its UFL = 12.8%

B) For Benzene

using the Antoine equation to calculate saturation vapor pressure

\(In(P^{out} ) = A - \frac{B}{C + T}\)

values gotten appendix E ( chemical process safety (3rd edition) )

A= 15.9008

B = 2788.52

C = -52.36

T = 298 k   input values into the above equation

\(p^{out}\) = 94.5 mmHg

calculate volume percentage using Dalton's law

V% = (saturation vapor pressure / pressure ) *100

      = (94.5 / 760 ) * 100 = 12.4%

Benzene is not flammable under the given conditions because its UFL =7.1%

C) For cyclohexane

using the Antoine equation to calculate saturation vapor pressure

\(In(P^{out} ) = A - \frac{B}{C + T}\)

values gotten appendix E ( chemical process safety (3rd edition) )

A = 15.7527

B = 2766.63

c = -50.50

T = 298 k

solving the above equation using the given values

\(p^{out}\) = 96.9 mmHg

calculate volume percentage using Dalton's law

V% = (saturation vapor pressure / pressure ) *100

      = ( 96.9 mmHg /760 mmHg) * 100 = 12.7%

cyclohexane not flammable under the given conditions because its UFL= 8%

D) For Toluene

using the Antoine equation to calculate saturation vapor pressure

\(In(P^{out} ) = A - \frac{B}{C + T}\)

values gotten from appendix E ( chemical process safety (3rd edition) )

A = 16.0137

B = 3096.52

C = -53.67

T = 298 k

solving the above equation using the given values

\(p^{out}\) = 28.2 mmHg

calculate volume percentage using Dalton's law

V% = (saturation vapor pressure / pressure ) *100

     = (28.2 mmHg / 760 mmHg) * 100 = 3.7%

Toluene is flammable under the given conditions because its UFL= 7.1%

Answer:

The minimum allowable bolt diameter required to support an applied load of P = 450 kN is 45.7 milimeters.

Explanation:

The complete statement of this question is "Five bolts are used in the connection between the axial member and the support. The ultimate shear strength of the bolts is 320 MPa, and a factor of safety of 4.2 is required with respect to fracture. Determine the minimum allowable bolt diameter required to support an applied load of P = 450 kN"

Each bolt is subjected to shear forces. In this case, safety factor is the ratio of the ultimate shear strength to maximum allowable shear stress. That is to say:

\(n = \frac{S_{uts}}{\tau_{max}}\)

Where:

\(n\) - Safety factor, dimensionless.

\(S_{uts}\) - Ultimate shear strength, measured in pascals.

\(\tau_{max}\) - Maximum allowable shear stress, measured in pascals.

The maximum allowable shear stress is consequently cleared and computed: (\(n = 4.2\), \(S_{uts} = 320\times 10^{6}\,Pa\))

\(\tau_{max} = \frac{S_{uts}}{n}\)

\(\tau_{max} = \frac{320\times 10^{6}\,Pa}{4.2}\)

\(\tau_{max} = 76.190\times 10^{6}\,Pa\)

Since each bolt has a circular cross section area and assuming the shear stress is not distributed uniformly, shear stress is calculated by:

\(\tau_{max} = \frac{4}{3} \cdot \frac{V}{A}\)

Where:

\(\tau_{max}\) - Maximum allowable shear stress, measured in pascals.

\(V\) - Shear force, measured in kilonewtons.

\(A\) - Cross section area, measured in square meters.

As connection consist on five bolts, shear force is equal to a fifth of the applied load. That is:

\(V = \frac{P}{5}\)

\(V = \frac{450\,kN}{5}\)

\(V = 90\,kN\)

The minimum allowable cross section area is cleared in the shearing stress equation:

\(A = \frac{4}{3}\cdot \frac{V}{\tau_{max}}\)

If \(V = 90\,kN\) and \(\tau_{max} = 76.190\times 10^{3}\,kPa\), the minimum allowable cross section area is:

\(A = \frac{4}{3} \cdot \frac{90\,kN}{76.190\times 10^{3}\,kPa}\)

\(A = 1.640\times 10^{-3}\,m^{2}\)

The minimum allowable cross section area can be determined in terms of minimum allowable bolt diameter by means of this expression:

\(A = \frac{\pi}{4}\cdot D^{2}\)

The diameter is now cleared and computed:

\(D = \sqrt{\frac{4}{\pi}\cdot A}\)

\(D =\sqrt{\frac{4}{\pi}\cdot (1.640\times 10^{-3}\,m^{2})\)

\(D = 0.0457\,m\)

\(D = 45.7\,mm\)

The minimum allowable bolt diameter required to support an applied load of P = 450 kN is 45.7 milimeters.

We have that the minimum allowable bolt diameter is mathematically given as

From the question we are told

Generally the equation for the stress   is mathematically given as

\(\mu= 320/4.2 \\\\\mu= 76.190 N/mm^2\)

Therefore

Force = Stress * area

Force = P/2

F= 425,000 N / 2 = 212,500 N

Hence area of each bolt is given as

212,500 = 76.190*( 5* area of each bolt)

area of each bolt = 557.815

Since

area of each bolt=\pi*d^2/4

\pi*d^2/4 = 557.815

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Given information: Length of the hollow fiber, \(L = 20\)cm Radius of the hollow fiber,\(r = 0.005\) cm Filtration flux,\(J = 0.5\) cm/s Feed to the module, \(Q = 500 cm3/s\) Concentration of a solute in the feed, \(C = 6\)g/L Sieving coefficient, So = 0.4

Therefore, the concentration of the solute in the fiber can be found using the formula, \(C b(z) = C*(1-So)*exp(-z^2/(4*L*J))*exp(r^2/R^2-z^2/(4*L*J))C b(z) = C*(1-So)*exp(-z^2/(4*L*J))*exp(1^2/0.01^2-z^2/(4*L*J))Plot of C b(z) for r = 0.01\)cm will be, The MATLAB code for the above can be written as: c lc; clear all; close all;%Given Data\(L = 20; %cm r = 0.005; %cm J = 0.5; %cm/s Q = 500; %cm^3/s C = 6; %g/L So = 0.4;%Flow Rate F = (Q./(pi*r^2)).*exp(-(z.^2)./(4.*L.*J))\)

figure(1)plot(z,F,'LineWidth',2);x label('z (cm)')y label('Flow Rate (cm^3/s)')title('Flow Rate in each fiber')grid on% Concentration of the solute in the fiber (in g/L) as a function of z C b = C.*(1-S_o).*exp(-(z.^2)./(4.*L.*J));figure(2)plot(z,Cb,'LineWidth',2);x label('z (cm)')y label('C b (g/L)')title('Concentration of the solute in the fiber')grid on% C b(z)

For Discussion From the obtained plots, it can be observed that the flow rate in each fiber is maximum at the inlet of the module and it decreases gradually as the fluid passes through the fibers.

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The 30-minute consecutive break could be satisfied by taking 30 consecutive minutes off duty/on duty without driving.

The 30-Minute Break Rule refers that a driver having a window of 8 hours to drive after their last off-duty period of at least 30 minutes. In the old rule, once a driver went on duty in a day, the driver had to take a 30-minute break by the 8th hour before being allowed to drive again.

This rule also implies spending 30 consecutive minutes in the sleeper berth. A combination of both equals 30 consecutive minutes. Drivers must take a 30-minute break when they have driven for a period of 8 cumulative hours without at least a 30-minute interruption.

Therefore, the 30-minute consecutive break could be satisfied by taking 30 consecutive minutes off duty/on duty without driving.

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Your question seems incomplete. The most probable complete question is as follows:

Which of the following would satisfy the 30-minute break required under the interruption of driving provisions:

(a) To find the time when the velocity is again zero, we set the velocity equal to 0 and solve for t:

0 = v0 + at = 9t - 3t^3

Solving for t, we find that t = ±1.

(b) To find the position and velocity when t = 4 s, we first need to find the velocity equation by integrating the acceleration equation:

v = ∫a = ∫(9 - 3t^2)dt = 9t - t^3 + C

Using the initial condition v(0) = 0, we find C = 0 and

v(t) = 9t - t^3

Next, we integrate v(t) to find the position equation:

x = ∫v = ∫(9t - t^3)dt = 3t^2 - t^4 + C

Using the initial condition x(0) = 5, we find C = 5 and

x(t) = 3t^2 - t^4 + 5

Evaluating x(t) and v(t) at t = 4 s, we have:

x(4) = 3(4^2) - 4^4 + 5 = 51

v(4) = 9(4) - 4^3 = -36

(c) To find the total distance travelled by the particle from t = 0 to t = 4 s, we need to find the distance between the initial and final positions:

d = x(4) - x(0) = 51 - 5 = 46 ft

So the total distance travelled by the particle from t = 0 to t = 4 s is 46 ft.

Answer:

nsnsndndnndndndnhhhh

Explanation:

It gives her a sense of purpose.

Complete question is;

Annealing is a process by which steel is reheated and then cooled to make it less brittle. Consider the reheat stage for a 100 mm thick plate (ρ = 7830 kg/m3, Cp = 550 J/kg K, k = 48 W/m K). The plate initially is at 200 °C and is to be heated to a minimum temperature of 550 °C. Heating is effected in a gas-fired furnace where the products of combustion at T∞ = 800 °C maintain a convection heat transfer coefficient of h = 250 W/m.K on both surfaces of the plate. How long should the plate be left in the furnace?

Answer:

860 seconds

Explanation:

We are given;

Initial Temperature; Ti = 200 °C

Minimum Temperature; T_i = 550 °C

T∞ = 800 °C

convection coefficient; h = 250 W/m².K

ρ = 7830 kg/m³

Cp = 550 J/kg K

k = 48 W/m K

Plate thickness = 100mm

Thus,L = 100/2 = 50mm = 0.05 m

Let's find the biot number from the formula;

Bi = hL/K

Bi = (250 × 0.05)/48

Bi = 0.2604

Now, lowest temperature in the slab is given as;

θ_o = (T_o - T∞)/(T_i - T∞)

θ_o = (550 - 800)/(200 - 800)

θ_o = 0.4167

Now, from online tables calculation, we can find the root of the biot number.

Thus, root of the biot number Bi = 0.2604 is;

ζ1 = 0.488 rad

Also, C1 is gotten as 1.0396

Now,formula for thermal diffusivity is;

α = k/ρc

α = 48/(7830 × 550)

α = 1.115 × 10^(-5) m²/s

Also, from online tables, f(ζ1) = 0.401

Thus, we can find the time the plate should the plate be left in the furnace from;

-(ζ1)²(αt/L²) = In 0.401

-(ζ1)²(αt/L²) = -0.9138

t = (-0.9138 × 0.05²)/-(0.488² × 1.115 × 10^(-5))

t ≈ 860 s

In this exercise we want to calculate the time, in seconds, of the time left on the plate in the furnace, like this:

860 seconds

Organizing the information given in the statement we find that:

Using the formula given below, we will have how to calculate the number of biot, like this:

\(B = hL/K\\B = (250 * 0.05)/48\\B = 0.2604\)

calculating the angle that corresponds to the temperature difference as:

\(\theta_o = (T_o - T)/(T_i - T)\\\theta_o = (550 - 800)/(200 - 800)\\\theta_o = 0.4167\)

Using the formula below, we will have:

\(\alpha = k/\rho c\\\alpha = 48/(7830 * 550)\\\alpha = 1.115 * 10^{-5}\)

Combining all the information from the previous calculations, we have that the time will be calculated as:

\(-(\phi)^2(\alpha t/L^2) = In 0.401\\-(\phi )^2(\apha t/^2) = -0.9138\\t = (-0.9138 * 0.05^2)/-(0.488^2 * 1.115 * 10^{-5})\\t = 860 s\)

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Answer:

Well there are a lot of delicious food in the philppines but my most favorite is the Lechon, Adobo, Sisig, Chicken Curry, Crispy pata and Sinigang

Cutting off projections such as bolts, rivets, and previous welded pieces is a process referred to as **trimming**.

Trimming is a common metalworking operation that involves removing excess or unwanted material from a workpiece to achieve the desired shape, size, or finish. When it comes to removing projections like bolts, rivets, or previous welded pieces, trimming is performed to eliminate these unwanted elements and create a clean, smooth surface.

The process of trimming can be accomplished using various tools and techniques depending on the specific application and the material being worked on. Some common methods of trimming include:

1. Grinding: Using grinding wheels or abrasive discs, the unwanted projections can be ground down or cut off to achieve the desired surface finish. Grinding is often used for larger or thicker projections.

2. Cutting: For smaller projections like bolts or rivets, cutting tools such as bolt cutters, hacksaws, or reciprocating saws can be employed to remove them. These tools provide precise cutting and are suitable for removing individual components.

3. Welding: In cases where previous welded pieces need to be removed, techniques like grinding, cutting, or even using specialized welding methods such as plasma arc cutting or oxyfuel cutting can be utilized to sever the welded joint and separate the pieces.

It's important to consider safety precautions while performing trimming operations, as they may involve sharp tools, sparks, or heat. Protective equipment such as safety glasses, gloves, and appropriate clothing should be worn to ensure safety.

Overall, trimming is a vital process in metalworking and fabrication, allowing for the removal of unwanted projections and the preparation of surfaces for subsequent operations or for achieving the desired final product.

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Answer:

Gently push the micropipette into the tip box and tag tightly to load the tip.

Explanation:

The recommended practice when putting a tip on a micropipette is ;  Gently push the micropipette into the tip box and tag tightly to load the tip.

Given that it is not advisable to remove tip from rack so as not to contaminate it, if we want to put a tip on a micropipette we should gently push the micropipette into the tip box.

The stresses in steel and concrete are 1,631.29 MPa and 0.2535 MPa respectively.

The extension of column due to the load is 0.0017mm

To find the stresses in the steel and concrete, we need to use the principle of stress-strain proportionality. The formula for stress is:

Stress (σ) = Load (P) / Area (A)

The area of the steel rods is:

A = (π/4) * (25 mm)^2 = 490.87 mm^2

The area of the concrete is:

A = (π/4) * (600 mm)^2 = 314,159 mm^2

The stress in the steel is:

σ_steel = P / A = 800 kN / 490.87 mm^2 = 1,631.29 MPa

The stress in the concrete is:

σ_concrete = P / A = 800 kN / 314,159 mm^2 = 0.2535 MPa

To find the extension of the column, we need to use the formula for strain:

Strain (ε) = Extension (ΔL) / Original length (L)

We can use the principle of linear elasticity to find the extension of the column due to the load, which states that:

Stress = Young's modulus * Strain

We can use the formula of stress and strain to find the extension of the column:

ΔL = (PL)/(AE)

L = 600mm, P = 800kN and A =314,159 mm^2

ΔL = (80010^310^-360010^-3)/(314,1592510^9) = 0.0017 mm

So the extension of column due to the load is 0.0017mm

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The value of the site is $10,472,000.

The total construction costs are:

$6,000/m2 * 10,000m2 + $400,000 = $64,000,000

The professional fees are:

$64,000,000 * 0.13 = $8,320,000

The total development costs are:

$64,000,000 + $8,320,000 = $72,320,000

The developer's return for risk and profit is:

$72,320,000 * 0.20 = $14,464,000

The total cost of the development is:

$72,320,000 + $14,464,000 = $86,784,000

The expected rent is:

$3,000/m2 * 8,000m2 * 12 months = $28,800,000

The initial yield is:

$28,800,000 * 0.07 = $2,016,000

The value of the site is:

$86,784,000 - $2,016,000 = $10,472,000

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When building a 3-dimensional object with linking cubes, it's important to consider each view and how the object would look from each side's projection.

The Top view would show the object from above, allowing you to see the shape and size of the object as a whole. The Front view would show the object from the front, giving you a clear idea of its height and width.

The Right view would show the object from the side, allowing you to see the depth and width.

The Isometric view is a 3-dimensional projection that shows the object in an angled view, giving you a sense of its depth, height, and width all at once. This is a useful view to see the overall shape and proportion of the object.

Therefore, When sketching each view, it's important to consider the line types used to represent the different parts of the object. For example, using different line types to represent hidden lines and visible lines can help to clearly show the 3-dimensional form of the object. The Sketching Reference resource provides information on different sketching line types that can be used.

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Using the codes in computational language in JAVA it is possible to write a code that create a puppy class with private property weight and both a getter and a setter for that property called getweight and setweight.

class Puppy {

       constructor(n) {

           // private property

           var name = n

           // methods that use private property

           this.getName = () => {return name}

           this.setName = (n) => {name = n}

           // public property

           this.nickname = n

       }

       // methods that use public property

       setNickname(n) { this.nickname = n }

       getNickname() { return this.nickname }

   }

   p = new Puppy("fido")

   console.log("p.name",p.name) // undefined, not accessible

   console.log("p.getName()",p.getName()) // fido

   console.log("p.getNickname()",p.getNickname()) // fido

   console.log("---")

   p.name = "barker" // defines a new property on this instance of Puppy

   console.log("p.name",p.name) // barker

   console.log("p.getName() ",p.getName()) // doesn't change private name fido

   console.log("---")

   p.setName("fuzz") // change private name

   console.log("p.getName()",p.getName()) // fuzz

   console.log("p.getNickname()",p.getNickname()) // fido

   console.log("---")

   p.nickname = "chewy" // set public property directly

   console.log("p.getNickname()",p.getNickname()) // chewy

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Answer:

Software reuse is the principal approach for constructing web-based systems, requirements for those systems cannot be completely specified in advance, User interfaces are constrained by the capabilities of web browsers.

Answer:

I say it if you put 20 points and not 10 points only, I'm sorry!

Explanation:

The code segment that can be used to display the intended output is:

B. Repeat 2 Times

Display "up"

Repeat 3 times

Display "down"

The code segment first repeats the statement "Display 'up'" two times, which displays "up" twice. Then it repeats the statement "Display 'down'" three times, which displays "down" three times in the first line. This pattern is repeated again to display "down" three more times in the second line. Therefore, the output of this code segment is "up down down down up down down down".

Option A only displays "up" and "down" one time each, which does not match the intended output. Option C repeats the statement "Display 'up'" six times, which displays "up" six times and does not match the intended output. Therefore, option B is the correct answer.

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When the variables are expressed in terms of fundamental dimensions, we get:

In physics, derived units are units that are formed by combining fundamental units such as length, mass, time, temperature, and electric charge. For example, velocity is a derived unit that combines length and time, expressed as meters per second (m/s).

The questions 24 to 29 are asking to express the given quantities in terms of fundamental dimensions. The unit of absorbed radiation dose is the joule per kilogram (J/kg).

The unit of electrical field is volts per meter (V/m). The unit of acoustic impedance is pascals per second per meter (Pa s/m). The unit of magnetic permeability is henries per meter (H/m). The unit of ideal gas constant is atmospheres times liters per mole times kelvin (atm L/(mol K)).

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Answer:

When traveling at higher speeds (40 mph or faster), the most fuel-efficient way to keep the car cool is to follow these tips:

1. Use the vehicle's ventilation system: Instead of relying on air conditioning, use the car's ventilation system to circulate fresh air from outside. This helps to cool down the interior without putting extra load on the engine, thus saving fuel.

2. Close windows and sunroofs: To reduce wind resistance and drag, close all windows and sunroofs while driving at higher speeds. Open windows create drag, which can increase fuel consumption.

3. Park in the shade: Whenever possible, park your car in a shaded area to avoid excessive heating when it's not in use. This can help keep the car cooler and reduce the need for extra cooling when you start driving.

4. Use reflective sunshades or window tinting: Use reflective sunshades on your windshield and window tinting on side windows to reduce the amount of heat entering the car. This can help keep the interior cooler, reducing the need for excessive cooling while driving.

5. Maintain your vehicle: Regular maintenance, such as checking and replacing coolant, inspecting the radiator, and ensuring proper functioning of the engine cooling system, can help keep your car running efficiently and prevent overheating.

6. Plan your trips strategically: If possible, try to avoid driving during the hottest part of the day. By planning your trips to avoid peak temperatures, you can reduce the strain on your vehicle's cooling system and minimize the need for excessive cooling.

Remember that these tips are specifically focused on keeping the car cool while maintaining fuel efficiency at higher speeds. In certain circumstances, such as extremely hot weather, using the air conditioning sparingly may be necessary for passenger comfort, but it will increase fuel consumption.

The safety technique that is recommended for this situation of moving a heavy industrial printer is to Bend at the knees when lifting.

This refers to the process of executing a task in a safe and acceptable way that does not put the user or others at risk

Hence, we can see that The safety technique that is recommended for this situation of moving a heavy industrial printer is to Bend at the knees when lifting.

This is to ensure that the person doing the lifting does not injure himself and has the proper form when lifting.

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