What is the strongest type of intermolecular force between solute and solvent in each solution?
(c) CH₃CH₃(g) in CH₃CH₂CH₂NH₂(l)

Answer:Chemical bonds form when the valence electrons of one atom interact with the valence electrons of another atom.J

Explanation:  Byee stay safe: Wear your mask, drink water and stan bts

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Answer:

(a) By the ideal gas law, the temperature of the gas is approximately 423.51129 K

(b) By the Van der Waals equation, the temperature of the gas is approximately 442.00558 K

Explanation:

The given parameters are;

The mass of the methane gas, m = 60 g

The volume of the container in which the gas is placed, V = 1.00-L

The pressure of the gas in the container, P = 130 atm

The molar mass of methane, CH₄ = 16.04 g/mol

The Van der Waals Constant for Methane (CH₄) a = 2.253 atm L²·mole⁻² and b = 0.04278 L·mol⁻¹

The universal gas constant, R = 0.08206 L·atm·mol⁻¹·K⁻¹

The number of moles of methane present, n = 60.0 g/(16.04 g/mol) ≈ 3.7406 48 moles

(a) The ideal gas law is P·V = n·R·T

Where;

P = The pressure of the gas

V = The volume of the gas

R = The universal gas constant

T = The temperature of the gas

n = The number of moles of the gas

Therefore, T = P·V/n·R

By substituting the known values of the variables, we get;

T = 130×1/(3.740648 × 0.08206) ≈ 423.51129 K

The temperature of the gas, T ≈ 423.51129 K

(b) The Van der Waals equation of state;

\(n \cdot R \cdot T = \left (P + a \cdot \dfrac{n^2}{V^2} \right) \cdot (V - n\cdot b)\)

Therefore, we have;

\(T = \dfrac{ \left (P + a \cdot \dfrac{n^2}{V^2} \right) \cdot (V - n\cdot b)}{n \cdot R}\)

Therefore, we have;

\(T = \dfrac{ \left (130 + 2.253 \times \dfrac{3.740648^2}{1^2} \right) \times (1 - 3.740648\cdot 0.04278)}{3.740648 \times 0.08206} = 442.00558 \ K\)

The temperature of the gas, T ≈ 442.00558 K.

Answer:

Ver explicacion

Explanation:

El litio es un metal y el oxígeno no es un metal.

La electronegatividad del litio es 0,98 mientras que la electronegatividad del oxígeno es 3,44.

La diferencia de electronegatividad entre el oxígeno y el litio es 3,44 - 0,98 = 2,46

Basado en esta amplia diferencia en electronegatividad, el enlace entre el oxígeno y el litio es un enlace iónico.

El porcentaje de carácter iónico del enlace se obtiene de;

Porcentaje de carácter iónico = 100 * (1-exp (-0,25 * (Electronegatividad del elemento A-Electronegatividad del elemento B) ^ 2))

Porcentaje de carácter iónico = 100 * (1-exp (-0,25 * (2,46) ^ 2)

Porcentaje de carácter iónico = 77,97%

Answer:

2N2+02>_2N20

Explanation:

u have to use rap formula

Answer:

chemical reaction

Explanation:

i think i have tried

Answer:

The substance's heat changes.

Explanation:

Substances can be made to change phases by fluctuating the temperature, the pressure, or both.

Answer:

A

Explanation:

Ur welcome hope it helps :)

Answer:

A.

Explanation:

All the rest is Chemical Change

Answer:

based on texture/ feel, oder/smell, melting/boiling point

Explanation:

Answer:

Smell it, drink it, throw it at someone.

Explanation:

If none of that hurts or kills anyone, you can mark everything that would off the list.

The EPA stream quality indicator for dissolved oxygen in stream water is:c. 5 mg per liter

Dissolved oxygen (DO) is an important indicator of the health of a water body. The EPA (Environmental Protection Agency) has set guidelines for the minimum dissolved oxygen levels to support a healthy aquatic ecosystem. For streams, the recommended minimum level of dissolved oxygen is 5 mg per liter. This level ensures that the water can support a diverse range of aquatic life, including fish, invertebrates, and other organisms.
To maintain good water quality, it's essential to regularly monitor dissolved oxygen levels using various sampling methods and equipment. If dissolved oxygen levels drop below the recommended threshold, it can indicate problems such as pollution or excessive nutrient loading, which can lead to eutrophication and negatively impact the ecosystem.

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Therefore, the answer is B

The answer can be determined using the given information and the reaction equation. The reaction equation is:

N2O4(g) ⇌ 2NO2(g)

The equilibrium constant for this reaction at 25°C is given as Kc = 4.61 x 10^-3. The initial moles of NO2 and N2O4 in the mixture are given as 0.0205 and 0.750 moles, respectively.

The total volume of the mixture is 5.25 L.

To determine whether the mixture is at equilibrium, we can calculate the reaction quotient (Qc) and compare it to the equilibrium constant (Kc). If Qc is less than Kc,

the reaction will proceed towards forming more products, and if Qc is greater than Kc, the reaction will proceed towards forming more reactants. If Qc is equal to Kc, the reaction is at equilibrium.

The expression for Qc is:

\(Qc = [NO2]^2/[N2O4]\)

Substituting the given values:

Qc = (0.0205/5.25)^2 / (0.750/5.25) = \(1.41 x 10^-4\)

Comparing Qc to Kc, we see that Qc is much smaller than Kc. This means that the mixture is not at equilibrium and the reaction will proceed towards forming more products (i.e., more NO2 and less N2O4) until the system reaches equilibrium.

The mixture is not at equilibrium and will proceed towards forming more products.

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The dependent  variable is the time taken, the independent variable is the type of paper helicopter and the control is the height from which the paper helicopters are dropped.

The term experiment helps us to decode the relationship between two variables. We have to know that in an experiment we are able to establish cause and effect relationships.

The dependent variable is the variable that is changed owing to the fact that another variable (the independent variable) is manipulated in the experiment.

Now, the dependent  variable is the time taken, the independent variable is the type of paper helicopter and the control is the height from which the paper helicopters are dropped.

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According to the nurse preceptor, the new nurse adheres to a number of safe practices while administering red blood cells (RBCs) to a patient.

Based on the given options, the actions that are deemed safe by the nurse preceptor are:

Using large gauge catheters (20-24 gauge). When giving red blood cells (RBCs) to a patient, the novice nurse follows a number of safe procedures, according to the nurse preceptor. To ensure appropriate flushing and lower the chance of an air embolism, the inexperienced nurse correctly primes the intravenous tube with 0.9% sodium chloride in the first step. The second step is for the inexperienced nurse to collect and record a complete set of baseline vital signs. This creates a baseline for monitoring the client's status both before and after the transfusion. Third, in accordance with the advised duration for safe administration, the nurse modifies the infusion rate to administer the RBCs in 4 hours as opposed to 6 hours. Fourth, the inexperienced nurse employs big gauge catheters (20-24 gauge) to promote quick and smooth blood product flow and reduce problems.

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The question is: WHAT DATA OF THE ELECTRONIC CONFIGURATION ALLOWS YOU TO LOCATE THE CHEMICAL ELEMENTS IN THE PERIODIC TABLE?

Explanation:

Elements which have same number of valence electrons tend to show similar chemical properties due to which they are placed in the same group.

Hence, electronic configuration of an element tells us the number of valence electrons present in an element. As a result, it becomes easy to locate the element in its respective group.

Answer:

Does water move in or out of a hypotonic solution?

In a hypertonic solution, the net movement of water will be out of the body and into the solution. ... In hypotonic solutions, there is a net movement of water from the solution into the body. A cell placed into a hypotonic solution will swell and expand until it eventually burst through a process known as cytolysis.

Explanation:

If a cell is placed in a hypertonic solution, water will leave the cell, and the cell will shrink. In an isotonic environment, there is no net water movement, so there is no change in the size of the cell. When a cell is placed in a hypotonic environment, water will enter the cell, and the cell will swell.

Answer:

C. The gas enters the cryosphere as ice sheets

Answer:

D

Explanation:

Explanation:

96.485 columbs=1 faraday will

deposit 64/2g= 32 g cu ion

therfore it will require

96,485 ×2/32 =? coulombs or 1/16 of

Faraday= 1 / 16 mole of electrons .

There are approximately 32.89 grams of sodium in a 120-gram sample of NaHCO3.

The molar mass of NaHCO3 (sodium bicarbonate) can be calculated by adding up the atomic masses of its constituent elements:

NaHCO3 = 1Na + 1H + 1C + 3O

Molar mass of NaHCO3 = 23.0 g/mol + 1.0 g/mol + 12.0 g/mol + (3 × 16.0 g/mol) = 84.0 g/mol

This means that one mole of NaHCO3 has a mass of 84.0 grams.

To determine the number of moles of NaHCO3 in a 120-gram sample, we can use the following equation:

Since the ratio of Na to NaHCO3 is 1:1, there are also 1.43 moles of Na in the sample.

Finally, we can calculate the mass of sodium (Na) in the sample by multiplying the number of moles of Na by its atomic mass:

mass of Na = moles of Na × atomic mass of Na

mass of Na = 1.43 mol × 23.0 g/mol

mass of Na = 32.89 g

Therefore, there are approximately 32.89 grams of sodium in a 120-gram sample of NaHCO3.

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Answer:

where the following choices??

Explanation:

The type of alcohol with two other carbons attached to the carbon with the hydroxyl group is isopropanol or isopropyl alcohol (CH3)2CHOH.

Alcohol is an organic compound with a hydroxyl (OH) group bonded to a saturated carbon atom is called an alcohol. The simplest alcohols are methanol, ethanol, and propanol.The alcohol class is significant because it includes a variety of useful and prevalent compounds. A few examples of alcohols include ethanol, methanol, and isopropyl alcohol, isopropanol.

An alcohol is isopropyl alcohol or isopropanol (CH3)2CHOH, it's a colorless, flammable liquid that has a slightly sweet odor. It is miscible in water and most organic solvents and is used primarily as a solvent and rubbing alcohol. Isopropyl alcohol has been used as an antiseptic since the 1920s. Isopropyl alcohol's antiseptic properties are due to its ability to denature proteins.

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When utilising molecular orbital theory to forecast their stability, the ions or molecule C2 2+ Be2 2+ Li2 exists in a stable form, while Li2 2 does not.

Atomic orbitals are combined in a linear array to create molecular orbitals. Calculating the bond order for each molecule allows one to gauge the stability of molecules or ions based on the electronic arrangement of their molecular orbitals.

After the valence bond theory had been established (1927), Friedrich Hund, Robert Mulliken, John C. Slater, and John Lennard-Jones were principally responsible for the development of molecular orbital theory. The Hund-Mulliken theory was the initial name for the MO theory.

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The acid content in lemon juice can be found via titration with NaOH by using an indicator such as phenolphthalein to detect the endpoint of the reaction.

The procedure to determine the acid content in lemon juice via titration with NaOH is as follows:

1. Accurately measure a 10mL aliquot of lemon juice into a clean flask.

2. Add 50 mL of distilled water and 2 drops of phenolphthalein to the flask. Phenolphthalein changes from colorless to pink at the endpoint.

3. Titrate with 0.1 M NaOH from a burette until the solution turns pink. This indicates that all of the acid in the lemon juice has been neutralized by the NaOH.

4. Record the volume of NaOH required to reach the endpoint.

5. Repeat the titration until consistent results are obtained.

6. The acid content of lemon juice can be calculated by multiplying the volume of NaOH used by its molarity and dividing the result by the volume of lemon juice used.

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Yes, the qs for the formation and decomposition of 1 mol of NO have opposite signs.

The heat of formation, or the heat absorbed when 1 mol of a substance is formed from its elements, represents the symbol qf. The heat of decomposition or the heat is given off when 1 mol of a substance breaks down into its elements, is represented by the symbol qd. The relationship between the two qs is that qf and qd are equal in magnitude but opposite in sign; qf is negative and qd is positive.

The relationship between qf and qd is that they are equal in magnitude but opposite in sign. For example, if qf for the formation of NO is -100 kJ, then qd for the decomposition of NO will be +100 kJ.

In summary, qf and qd is the heat absorbed or released during the formation and decomposition of a substance respectively. They are equal in magnitude but opposite in sign. The heat absorbed during formation is negative and the heat released during decomposition is positive.

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The reaction between H2SO4 in a mixture of KI and MnO2 yields iodine which reacts with hypo solution​ by titration and the iodine is decolorized.

Iodine is decolorized.

The first reaction stated in the question occurs as follows;

2 KI (aq) + 2 H2SO4 (aq) + MnO2 (s) → MnSO4 (aq) + K2SO4 (aq) + I2 (s) + 2 H2O (l)

The reaction here is the formation of iodine from MnO2 and KI in the presence of dropwise H2SO4.

Hypo is the common name of sodium thio-sulphate or sodium hypo-sulfite.

The equation of the titration reaction is;

2Na2S2O3 + I2→ Na2S4O6 + 2NaI

When this reaction takes place, iodine is decolorized due to its reduction to I^-.

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The standard enthalpy change for the given reaction is -828.8 kJ/mol.

Standard enthalpy change refers to the enthalpy change of a reaction when it occurs under standard conditions of temperature and pressure, which are defined as a pressure of 1 atm and a temperature of 25°C.

The standard enthalpy change is also known as the heat of reaction. It is denoted by ΔH°.The standard enthalpy of formation is the energy released or absorbed when one mole of a compound is formed from its constituent elements in their standard state under standard conditions.

The standard enthalpy of formation of a substance is defined as the enthalpy change for the formation of one mole of the substance from its elements in their standard states.

The formation reaction for Fe₂O3 can be written as:

2Fe(s) + 3/2 O₂(g) → Fe₂O3(s)ΔH°f for Fe₂O3 = -824.2 kJ/mol

The combustion reaction for H2 can be written as:

2H₂(g) + O₂(g) → 2H₂O(l)ΔH°f for H₂O(l) = -285.8 kJ/mol

Now, we can calculate the enthalpy change of the given reaction as follows:

ΔH° = ∑ΔH°f(products) - ∑ΔH°f(reactants)

ΔH° = [ΔH°f(Fe₂O3) + 3ΔH°f(H₂)] - [2ΔH°f(Fe) + 3ΔH°f(H₂O)]

ΔH° = [-824.2 kJ/mol + (3 × -285.8 kJ/mol)] - [2 × 0 kJ/mol + 3 × (-285.8 kJ/mol)]

ΔH° = -828.8 kJ/mol

Therefore, the standard enthalpy change for the given reaction is -828.8 kJ/mol.

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Given the data from the question, the starting equation is

C₂H₃Br + O₂ --> CO₂ + H₂O + HBr

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

Considering the equation given from the qustion

2C₂H₃Br + 5O₂ --> 4CO₂ + 2H₂O + 2HBr

We can see that the above equation is already balanced.

Thus, the starting equation will be the skeletal equation which is unbalanced.

Therefore, we can conclude that the starting equation is:

C₂H₃Br + O₂ --> CO₂ + H₂O + HBr

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Answer:

D

Explanation:

took the test

Answer:

It can be improved by:

a) Adding METHANOL

b) Adding BUTANOL

c) Adding ETHANOL.

Explanation:

hope it helps.

Beans are processed through 'nibbing'. During the nibbing process, the roasted cocoa beans are crushed and ground into a paste called cocoa mass or cocoa liquor.

This cocoa mass can then be further processed to separate the cocoa solids from the cocoa butter, which is the fat component of the cocoa bean. The separated cocoa solids and cocoa butter are used in the production of chocolate. Pure cocoa mass (cocoa paste) in solid or semi-solid form is known as chocolate liquor. It includes about equal amounts of cocoa butter and solid cocoa, much like the cocoa beans (nibs) from which it is made. It is made from fermented, dried, roasted, and separated from their skins cocoa beans. To make cocoa mass (cocoa paste), the beans are pulverised.

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Answer:

A. life forms existed during the Cambrian period

Explanation:

Answer:

A

Explanation:

Have a nice day!

Answer:

4,186 joules

Explanation:specific heat, the quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree. The units of specific heat are usually calories or joules per gram per Celsius degree. For example, the specific heat of water is 1 calorie (or 4,186 joules) per gram per Celsius degree.