What is the sum to (-2)(3)

Probability that more than 10 adults in the sample have hypertension is 0.768

Var(X) = 5.25

The probability that more than 10 adults in the sample have hypertension is 0.6086

The National and Nutrition survey reported that 30% of adults in the U. S have hypertension (high blood pressure). Let X be the number of adults in the U. S with hypertension.

A sample of 25 adults is studied:

Calculate the following probabilities using R guro and then fill in the blanks with your answers.

a) The probability that 12 or fewer adults in the sample have hypertension is  . Round your answers to three decimal places.

b) The probability that more than 10 adults in the sample have hypertension is  . Round your answers to three decimal places.

c) Calculate the Var(X)=n ∗p∗(1−p) = . Round the answer to the nearest whole number.

The National and Nutrition survey reported that 30% of adults in the U. S have hypertension

A sample of 25 adults is studied

therefore X = 25

adults in the U. S have hypertension = 30% of 25

                                                              = 7.5

a) the probability that 12 or fewer adults in the sample have hypertension is

Let X: Number of adults that were told they have hypertension.

The scenario here follows the Binomial distribution since trials are independent and the probability of success( i .e having hypertension) is equal from trial to trial.

X~ Binomial(n=12, p =0.30)

Required probability,

P(X≥2)=1−P(X=0)−P(X=1)

=1−( 12                                              ( 12

       0 )0.30^ 0(1−0.30) ^(12−0) −      1)0.30^ 1(1−0.30) ^(12−1)

=1−0.1660−0.0652

=0.768

b) the probability that more than 10 adults in the sample have hypertension is

Let X: Number of adults that were told they have hypertension.

The scenario here follows the Binomial distribution since trials are independent and the probability of success( i .e having hypertension) is equal from trial to trial.

X~ Binomial(n=10, p =0.30)

Required probability,

P(X≥2)=1−P(X=0)−P(X=1)

=1−( 10                                              ( 10

       0 )0.30^ 0(1−0.30) ^(10−0) −      1)0.30^ 1(1−0.30) ^(10−1)

=1−0.2824−0.1089

=0.6086

​c) Calculate the Var(X)=n ∗p∗(1−p)

n= 25

p=0.30

Var(X)=n ∗p∗(1−p)

         = 25*0.30*(1-0.30)

         =5.25

Probability that more than 10 adults in the sample have hypertension is 0.768

Var(X) = 5.25

The probability that more than 10 adults in the sample have hypertension is 0.6086

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Probability that more than 10 adults in the sample have hypertension is 0.768

Var(X) = 5.25

The probability that more than 10 adults in the sample have hypertension is 0.6086

The National and Nutrition survey reported that 30% of adults in the U. S have hypertension (high blood pressure). Let X be the number of adults in the U. S with hypertension.

A sample of 25 adults is studied:

Calculate the following probabilities using R guro and then fill in the blanks with your answers.

a) The probability that 12 or fewer adults in the sample have hypertension is  . Round your answers to three decimal places.

b) The probability that more than 10 adults in the sample have hypertension is  . Round your answers to three decimal places.

c) Calculate the Var(X)=n ∗p∗(1−p) = . Round the answer to the nearest whole number.

The National and Nutrition survey reported that 30% of adults in the U. S have hypertension

A sample of 25 adults is studied

therefore X = 25

adults in the U. S have hypertension = 30% of 25

                                                             = 7.5

a) the probability that 12 or fewer adults in the sample have hypertension is

Let X: Number of adults that were told they have hypertension.

The scenario here follows the Binomial distribution since trials are independent and the probability of success( i .e having hypertension) is equal from trial to trial.

X~ Binomial(n=12, p =0.30)

Required probability,

P(X≥2)=1−P(X=0)−P(X=1)

=1−( 12                                              ( 12

      0 )0.30^ 0(1−0.30) ^(12−0) −      1)0.30^ 1(1−0.30) ^(12−1)

=1−0.1660−0.0652

=0.768

b) the probability that more than 10 adults in the sample have hypertension is

Let X: Number of adults that were told they have hypertension.

The scenario here follows the Binomial distribution since trials are independent and the probability of success( i .e having hypertension) is equal from trial to trial.

X~ Binomial(n=10, p =0.30)

Required probability,

P(X≥2)=1−P(X=0)−P(X=1)

=1−( 10                                              ( 10

      0 )0.30^ 0(1−0.30) ^(10−0) −      1)0.30^ 1(1−0.30) ^(10−1)

=1−0.2824−0.1089

=0.6086

​c) Calculate the Var(X)=n ∗p∗(1−p)

n= 25

p=0.30

Var(X)=n ∗p∗(1−p)

        = 25*0.30*(1-0.30)

        =5.25

Probability that more than 10 adults in the sample have hypertension is 0.768

Var(X) = 5.25

The probability that more than 10 adults in the sample have hypertension is 0.6086

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The error represented in this scenario is an inappropriate task allocation or a mismatch between job responsibilities and the assigned task during the interview process.

The primary role of a customer service representative is to interact with customers, address their concerns, and log calls professionally and efficiently. In contrast, performing a detailed analysis of call-in data falls under the domain of data analysis or business intelligence roles.

By asking the candidate to perform a task unrelated to their potential job responsibilities, the company may not accurately assess the candidate's aptitude for customer service tasks. This error could lead to selecting a candidate who may excel in data analysis but may not possess the necessary communication and problem-solving skills required for a customer service representative position.

To avoid this error, the company should focus on evaluating candidates based on their skills, experience, and performance in tasks directly relevant to the customer service role.

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Answer:

20

50% of 40 is 20 because half of 40 is 20

Answer:

20

Step-by-step explanation:

1) Change 50% into a decimal

50% ⇒ 0.5

2) Multiply 0.5 by 40

0.5 × 40 = 20

Therefore, 50% of 40 is 20.

I hope this helps!

(a) The box can be represented as a population of 200,000 registered voters, with 120,000 of them supporting the ballot proposition and 80,000 opposing it. Each voter can be represented by a ticket, and the box would contain 120,000 tickets labeled "Support" and 80,000 tickets labeled "Oppose."

(b) If we drew 200 times with replacement from this box, there is a 95% chance that the sum of draws (number of voters contacted who support the ballot proposition) would be between 106 and 134. Expressed as a percentage of the 200 people, this is between 53% and 67%.

(a) The box can be represented as a collection of 200,000 balls, where each ball corresponds to a registered voter. Among these, 120,000 balls are labeled as "support" to indicate that the voter supports the ballot proposition, and the remaining 80,000 balls are labeled as "oppose" to indicate that the voter does not support the proposition. When we randomly select 200 voters without replacement and count the number of supporters among them, we are essentially drawing 200 balls from this box without replacement and counting the number of balls labeled as "support".

(b) Since we are drawing with replacement, each draw is independent and has a Bernoulli distribution with a probability of success p = 0.6 (since 60% of the voters support the proposition). The sum of these draws has a binomial distribution with parameters n = 200 (the number of trials) and p = 0.6 (the probability of success). The mean of this distribution is μ = np = 200 x 0.6 = 120, and the standard deviation is σ = sqrt(np(1-p)) = sqrt(200 x 0.6 x 0.4) ≈ 7.75.

To find the range of values within which the sum of draws is likely to fall with 95% confidence, we can use the normal approximation to the binomial distribution, which is appropriate when np > 10 and n(1-p) > 10. In this case, we have np = 120 and n(1-p) = 80, so the normal approximation is valid.

We want to find the values of k such that P(μ - kσ < X < μ + kσ) = 0.95, where X is the sum of draws. Using the standard normal distribution, we have:

P(-k < Z < k) = 0.95,

where Z = (X - μ)/σ is a standard normal variable. From standard normal tables, we find that k ≈ 1.96.

Therefore, the 95% confidence interval for the sum of draws is:

120 - 1.96 x 7.75 ≈ 104.1 to 120 + 1.96 x 7.75 ≈ 135.9.

As a percentage of the 200 people polled, this is between:

104.1/200 x 100 ≈ 52.05% and 135.9/200 x 100 ≈ 67.95%.

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Answer:

\(x+17\)

Step-by-step explanation:

Hi there!

Let \(x\) represent "the number".

The sum of a number and seventeen

⇒ \(x+17\)

I hope this helps!

Answer:

Answer is 3

Step-by-step explanation:

y=

\( \frac{1}{4} \times 12 = 3\)

please mark me brainliest and 5 star

Answer:

see explanation

Step-by-step explanation:

A quadratic function in standard form is

y = ax² + bx + c (a ≠ 0 )

Given

y = - 3x² + 6x + 17 ← compare coefficients with standard form, then

a = - 3, b = 6, c = 17

Given the quadratic in standard form the the equation of the axis of symmetry is

x = - \(\frac{b}{2a}\) = - \(\frac{6}{-6}\) = 1

Equation of axis of symmetry is x = 1

The equation of the axis of symmetry is x = 1.

It is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

A quadratic function in standard form is

y = ax² + bx + c (a ≠ 0 )

Given that, y = - 3x² + 6x + 17 ← compare coefficients with standard form, then.

a = - 3, b = 6, c = 17

The quadratic in standard form the equation of the axis of symmetry is

x = -b / 2a  = -6 / - 6 = 1

The equation of the axis of symmetry is x = 1.

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Answer:

yes it can be

Answer:

Step-by-step explanation:

1.33 and 1.3 are not the same, although they share the digits 1.3.

1.33 is accurate to the hundredths place, whereas 1.3 is accurate only to the tenths place.

So:  1.33 and 1.3 are in the same ball park, but are not the same.

The correct statement about the slope of the line is:

c) The slope from point O to point A is one-third times the slope of the line from point A to point B.

To understand why this statement is true, let's consider the given options:

a) It is fraction negative 1 over 3 throughout the line.

b) It is −3 throughout the line.

d) The slope from point O to point A is three times the slope of the line from point A to point B.

None of these statements can be concluded based on the given information. The slope of a line cannot be determined without specific values or equations. However, statement c can be deduced from the information provided.

Given that line k intersects plane A and contains points Y and Z, we can assume that point A lies on line k. If we denote point O as the point where line k intersects plane B, and point B as another point on line k, then we can define the slope from point O to point A as the change in y-coordinates divided by the change in x-coordinates.

Based on statement c, the slope from point O to point A is one-third times the slope of the line from point A to point B. This implies that the two slopes are related, with the slope from O to A being smaller in magnitude (one-third of the other slope).

Therefore, statement c is the only true statement about the slope of the line based on the given information.

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Answer:

8.7

Step-by-step explanation:

The correct answer is (c) normal distribution.

When comparing two proportions, the difference between them can be calculated, and its sampling distribution can be approximated by a normal distribution when the sample sizes are sufficiently large.

The mean of the sampling distribution is the difference between the true population proportions, and the standard deviation of the sampling distribution is calculated as:

\(sqrt[(p1*(1-p1)/n1) + (p2*(1-p2)/n2)]\)

where p1 and p2 are the population proportions, and n1 and n2 are the sample sizes.

Therefore, the sampling distribution of the difference between two proportions is approximated by a normal distribution with mean (p1-p2) and standard deviation given by the above formula.

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The true statements about the events (d) One independent event does not affect the probability of another independent event.

From the question, we have the following parameters that can be used in our computation:

The events

Where we have:

The true statements about the events are:

Hence, the true statement is (d) One independent event does not affect the probability of another independent event.

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Question

Which statement is TRUE regarding independent and dependent events?

(a) Dependent events do not affect the probability of one another.

(b) The probability of two dependent events both occuring can be calculated through addition.

(c) The probability of two independent events both occuring can be calculated through addition.

(d) One independent event does not affect the probability of another independent event.

If a decision maker wishes to reduce the margin of error associated with a confidence interval estimate for a population mean, she can increase the sample size.

The margin of error refers to the statistic measurement that expresses the level of random sampling error in the outcomes of a survey. If the margin of error of the result is high, the confidence level would be low that a result reflects the census of the entire population. It indicated the difference between the actual and estimated results in a random survey sample. The margin of error is generally used in non-survey contexts to show observational error in reporting measured quantities. In order to minimize the margin of error associated with a confidence interval estimate for a population mean, the researchers can increase the sample size to capture the actual trend of the population more accurately.

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Answer:

2

Step-by-step explanation:

\(\frac{(-5)^{3} + 17}{10(2 - 6) - 2(5 + 2)}\\\\\frac{(-125) + 17}{10(-4)-2(7)}\\\\\frac{-108}{-40-14}\\\\\frac{-108}{-54}\\\\2\)

Answer:

Yes

Step-by-step explanation:

Answer:

25

Step-by-step explanation:

10+7+8=25 this is because her cat weighs 8 pounds and her dog weighs 10 pounds more so that's 18 lb. after words it says Cameron's dog weighs 7 pounds less than bills so you do 18+7 and that equals 25

There are 13,992 integers between 1 and 1,000,000 with a sum of digits equal to 15.

To find the number of integers between 1 and 1,000,000 with a sum of digits equal to 15, we can use a combinatorial approach.

We need to distribute the sum of 15 among the digits of the number. We can think of this as placing 15 indistinguishable balls into 6 distinct boxes (corresponding to the digits).

Using the stars and bars method, the number of ways to distribute the sum of 15 among 6 boxes is given by the combination formula:

C(n + r - 1, r - 1)

where n is the sum (15) and r is the number of boxes (6).

Plugging in the values, we have:

C(15 + 6 - 1, 6 - 1) = C(20, 5)

Calculating this combination, we find:

C(20, 5) = 13,992

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Answer:

Mala had 14 sweets at the start.

Step-by-step explanation:

7 x 2 = 14

To check, 14/2 = 7. (Dividing by 2 is the same as multiplying by 1/2)

Answer:

2x^2 + 2y^2

Step-by-step explanation:

Combine like terms.

(x^2 + 2xy + y^2) + (x^2 - 2xy + y^2) =

= x^2 + 2xy + y^2 + x^2 - 2xy + y^2

= x^2 + x^2 + 2xy - 2xy + y^2 + y^2

= 2x^2 + 2y^2

Answer:

2x^2 + 2y^2

Step-by-step explanation:

The point on the plane 4x - y + 4z = 40 nearest the origin is (-3.048, -0.762, 6.467)

Given data ,

To find the point on the plane 4x - y + 4z = 40 nearest the origin, we need to minimize the distance between the origin and the point on the plane.

The normal vector to the plane 4x - y + 4z = 40 is given by (4,-1,4). To find the perpendicular distance from the origin to the plane, we need to project the vector from the origin to any point on the plane onto the normal vector. Let's choose the point (0,0,10) on the plane:

Vector from origin to (0,0,10) on the plane = <0-0, 0-0, 10-0> = <0,0,10>

Perpendicular distance from the origin to the plane = Projection of <0,0,10> onto (4,-1,4)

= (dot product of <0,0,10> and (4,-1,4)) / (magnitude of (4,-1,4))

= (0 + 0 + 40) / √(4^2 + (-1)^2 + 4^2)

= 40 / √(33)

To find the point on the plane nearest the origin, we need to scale the normal vector by this distance and subtract the result from any point on the plane. Let's use the point (0,0,10) again:

Point on the plane nearest the origin = (0,0,10) - [(40 / √(33)) / √(4^2 + (-1)^2 + 4^2)] * (4,-1,4)

= (0,0,10) - (40 / √(33)) * (4/9,-1/9,4/9)

= (0,0,10) - (160/9√(33), -40/9√(33), 160/9√(33))

= (-160/9√(33), -40/9√(33), 340/9√(33))

Hence , the point on the plane 4x - y + 4z = 40 nearest the origin is approximately (-3.048, -0.762, 6.467)

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Answer:

No

Step-by-step explanation:

If they where scaled versions of each other then the sides would have to be scaled by the same factor. To get from 2 units to 11 units, the scale factor would by 5.5, but 7 multiplied by 5.5 is not 37.

The remainder when f(x) = 2x3 - 12x2 + 11x + 2 is divided by x - 5 is 7.

We can use the remainder theorem to find the remainder when a polynomial is divided by a linear factor.

The remainder theorem states that the remainder when a polynomial f(x) is divided by x - a is f(a). In this case, the polynomial is f(x) = 2x3 - 12x2 + 11x + 2 and the linear factor is x - 5. So, the remainder is f(5).

To find f(5), we can simply substitute x = 5 into the polynomial. This gives us f(5) = 2(5)3 - 12(5)2 + 11(5) + 2 = 7.

Therefore, the remainder when f(x) = 2x3 - 12x2 + 11x + 2 is divided by x - 5 is 7.

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Answer:

\( \frac{x + 19}{ - 2} = 5 \\ x + 19 = 5 \times ( - 2) \\ x + 19 = - 10 \\ x = - 19 - 10 \\ \boxed{x = - 29 }\)

b. Distribution B has a higher variance is an accurate statement regarding these two distributions.

Variance is a measure of the spread of a probability distribution. It tells us how far away from the mean values in the distribution are. The higher the variance, the more spread out the values are.

In this case, Distribution B has a higher variance than Distribution A. To calculate the variance of a distribution, we use the formula:

\($$\sigma^2 = \sum_{i=1}^{n} (x_i - \mu)^2 \cdot P(x_i)$$\)

Where \($x_i$\) is a possible value, \($P(x_i)$\) is the probability of that value, and \($\mu$\) is the mean of the distribution. If we use this formula to calculate the variance of each distribution, we'll find that the variance of Distribution B is larger than the variance of Distribution A.

This means that the values in Distribution B are more spread out and less consistent than the values in Distribution A, making Distribution B have a higher variance.

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the equation of the line in slope-intercept form is:
\(y = \frac{5}{9}x + \frac{5}{3}\)

To write the equation of the line in slope-intercept form (y = mx + b), we need to find the slope (m) and y-intercept (b). We know the line passes through the point (6,5) and has an x-intercept of -3.

The x-intercept occurs when y = 0, so the line also passes through the point (-3, 0). Now, we can find the slope (m) using the formula:

\(m = \frac{(y2 - y1) }{ (x2 - x1)}\)

Using the points (6,5) and (-3,0), we get:

\(m = (0 - 5) / (-3 - 6) = (-5) / (-9) = 5/9\)

Now that we have the slope, we can use the point-slope form to find the equation:

y - y1 = m(x - x1)

Plugging in the point (6,5) and the slope 5/9, we get:

\(y - 5 =\frac{ 5}{9}(x - 6)\)

Now, we can solve for y to put it in slope-intercept form:

\(y = (5/9)x - (5/9)(6) + 5y = (5/9)x - 10/3 + 15/3y = (5/9)x + 5/3\)
So, the equation of the line in slope-intercept form is:

\(y = \frac{5}{9}x + \frac{5}{3}\)

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Answer:

B.) The interquartile range of the data is 2

Step-by-step explanation: