The tension in the string is = 0.118
Given the values in the question,
The volume of the plastic ball = 75 \(cm^{3}\)
Density ( ρ ) = 840 kg / \(m^{3}\)
Let the tension on the ball = T
Since the density is given in centimeters so convert volume also in meters,
⇒ 75 \(cm^{3}\) = 0.000075 \(m^{3}\)
The ball is following the principle of buoyant force, so the ball is stable in the water the force that the ball is exerting into the water is equal to the force the water is exerting on the ball.
The forces could be represented as -
∑ \(F_{y}\) = \(F_{b}\) - T - \(W_{b}\) = 0
T = \(F_{b}\) - \(W_{b}\)
T = ρ x g x \(V_{w}\) - ρ x g x \(V_{b}\)
T = ( 1000 x 9.8 x 0.000075 ) - ( 840 x 9.8 x 0.000075 )
T = 0.735 - 0.617
T = 0.118
Therefore, The tension in the string is = 0.118
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At a temperature of 300 K, the pressure of the gas in a deodorant can is 3 atm.
Calculate the pressure of the gas when it is heated to 900 K.
The pressure of the gas in the deodorant can when it is heated to 900 K is 9 atm.
What is the pressure of the gas when it is heated to 900 Kelvin?Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.
It is expressed as;
P₁/T₁ = P₂/T₂
From the data:
Initial pressure P₁ = 3 atmInitial temperature T₁ = 300 KFinal pressure P₂ = ?Initial temperature T₂ = 900 KWe substitute our values into the expression above and solve for final pressure.
P₁/T₁ = P₂/T₂
P₁T₂ = P₂T₁
P₂ = P₁T₂ / T₁
P₂ = ( 3 atm × 900 K ) / 300 K
P₂ = 9.0 atm
Therefore, the final pressure is 9.0 atm.
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10- A block attached to a spring oscillates in simple harmonic motion along the x axis. The
limits of its motion are x = 10cm and x = 50 cm and it goes from one of these extremes to
the other in 0.25 s. Its amplitude and frequency are:
A 40 cm. 2Hz
B. 20 cm, 4Hz
C. 40cm, 2Hz
D. 25 cm, 4Hz
E. 20 cm, 2Hz
Answer:
Choice E.
Amplitude: \(20\; {\rm cm}\).
Frequency: \(2\; {\rm Hz}\).
Explanation:
The amplitude of a simple harmonic motion (SHM) is the maximum displacement from equilibrium.
In this question, the equilibrium is in the center of the two extremes. With one extreme at \(x = 10\; {\rm cm}\) and the other at \(x = 50\; {\rm cm}\), the center will be at \((1/2)\, (10 + 50)\; {\rm cm} = 30\; {\rm cm}\).
The maximum displacement will be \((50\; {\rm cm} - 30\; {\rm cm}) = 20\; {\rm cm}\) (or equivalently, \((30\; {\rm cm} - 10\; {\rm cm}) = 20\; {\rm cm}\).
Frequency measures the number of cycles completed in unit time (e.g., one second.) In one full cycle of an SHM, the oscillator will travel from one extreme to another and then back to the original extreme. In this question:
Travel from one extreme to the other: \(0.25\; {\rm s}\).Travel from the other extreme back to the original one: \(0.25\; {\rm s}\).In other words, one full cycle of this SHM will take \(0.25\; {\rm s} + 0.25\; {\rm s} = 0.50\; {\rm s}\). The period of this SHM will be \(0.50\; {\rm s}\). Hence, the frequency of this SHM will be:
\(\begin{aligned} (\text{frequency}) &= \frac{1}{(\text{period})} \\ &= \frac{1}{0.50\; {\rm s}} \\ &= 2\; {\rm Hz}\end{aligned}\).
I need help with this question
Explanation:
a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed
The image shows a molecular model of a compound using balls and sticks. Each ball is an atom. If you were to use balls and sticks to model a molecule of an element how must your model differ from what’s shown
Element molecules consist of a single type of atom and are held together by covalent bonds. The model would have uniform-colored balls connected by sticks representing these bonds.
The image represents a molecular model of a compound. Balls represent atoms, while sticks show chemical bonds between atoms. If you are to use balls and sticks to model a molecule of an element, the model would differ from what is shown because the element is made up of one type of atom. In other words, it is a pure substance that can't bond to other atoms of the same kind. Molecules of elements are usually composed of a single element and are not formed by bonding between two or more different atoms.In contrast to compounds, atoms in an element molecule are joined by a chemical bond called a covalent bond. Furthermore, the same atom is represented by a single-colored ball as there is only one type of atom involved in the element molecule. The sticks represent covalent bonds between the atoms of the same kind in a molecule of the element.For more questions on covalent bonds
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Freud believed there was a large________________ part of the mind. This belief led to a study of _____________, ___________________, and _________________________.
Freud believed there was a large psychoanalysis part of the mind. This belief led to a study of preconscious, conscious and unconscious.
According to him, the unconscious mind is the primary source of human behavior.
What is psychoanalysis?Psychoanalysis can simply be defined asa system of psychological theory and therapy which aims to treat mental disorders by investigating the interaction of conscious and unconscious elements in the mind and bringing repressed fears and conflicts into the conscious mind
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Lesson 3
Write a descriptive essay about the basic steps of the scientific method.
Include the following essential content:
Testable hypothesis
Data collection and analysis
Peer review
Also, include where theories fit into the process of the scientific method.
A sample descriptive essay about the basic steps of the scientific method is given below:
When a person is testing a hypothesis, it is important that he collects data and then makes an analysis of it, and puts it through a controlled experiment at the lab.
Next, he would have to peer-review the results of the experiments and when this is confirmed, it becomes a theory,
What is the Scientific Method?This refers to the process of systematic observation that is used to come to a conclusion in a scientific investigation.
Hence, we can see that the descriptive essay about the scientific method is given above,.
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A block m1 rests on a frictionless surface. A second block m2 sits on top of the first block. Here m1 = m2 = m. A horizontal force F is applied to the bottom block to pull it to the right as shown below. Assume that the blocks move together across the surface (block m2 does not slide off of block m1).
A block resting on a frictionless surface experiences a horizontal force that pulls another block atop it to the right, where the two blocks travel in tandem without slamming.
How much static friction is there between the upper and bottom blocks?Response and justification The higher block's acceleration is also equal to 3 m/s2 because there is no relative motion between the upper and lower blocks.
What is the static friction coefficient between block A and a flat floor?Block A and a level floor have a static friction coefficient of 0.45, while Block B has a static friction coefficient of 0.30. Each brick weighs 2.0 kg.
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A 580-g squirrel with a surface area of 850 cm2 falls from a 4.0-m tree to the ground. Estimate its terminal velocity. (Use the drag coefficient for a horizontal skydiver. Assume that the cross-sectional area of the squirrel can be approximated as a rectangle of width 11.0 cm and length 22 cm. Note, the squirrel may not reach terminal velocity by the time it hits the ground. Give the squirrel's terminal velocity, not it's velocity as it hits the ground.)
What will be the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance?
Answer:
its terminal velocity is 19.70 m/s
the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance is 8.85 m/s
Explanation:
Firstly,
given that
m = 580g = 0.58kg
Area A = 0.11 * 0.22 = 0.0242m
g = 9.8
idensity constant p = 1.21 kg/m^3
the terminal velocity of the sphere Vt is ;
Vt = √ ( 2mg / pCA)
we substitute
Vt = √ ( (2*0.58*9.8) / (1.21*1*0.0242)
Vt = √ (11.368 / 0.029282)
Vt = √ ( 388.22)
Vt = 19.70 m/s
its terminal velocity is 19.70 m/s
What will be the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance?
The Velocity of the person is;
V2 = √ 2ax
V2 = √ ( 2 * 9.8 * 4 )
V2 = √ (78.4)
V2 = 8.85 m/s
the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance is 8.85 m/s
What does the difference between gauge pressure and absolute pressure equal?
a.
the pressure within the fluid
c.
the pressure at the bottom of the fluid
b.
the pressure at the surface of the fluid
d.
zero
The actual difference between the guage pressure of a system and an absolute pressure is the same as the pressure at the surface of the fluid.
The correct answer choice is option b.
Why the pressure at fluid surface equals absolute and guage pressure.It follows that the two pressure system mentioned in the given task above has a zero point system as their principle of operation.
When we talk of guage pressure, it uses atmospheric pressure as its own zero point system. However, the sum of both the guage pressure and atmospheric pressure gives what we know as the absolute pressure.
So therefore, we can now deduced that the pressure on a liquid surface is equivalent to the variation between the gauge pressure and absolute pressure.
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Which tells us speed and direction?
1).speed
2).displacement
3).distance
4).velocity
Answer:
velocity
Explanation:
Answer:
Velocity
Velocity tells you the speed and the direction it's going. Speed only tells you the speed, with no direction.
Explanation:
1 If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed?
a The screen would remain dark because no radiation would reach the screen.
b One bright band would appear in the center of the screen.
c A series of light and dark bands would appear on the screen.
d Two bright bands would appear on the screen in line with the slits.
2 Which statement about the interference behavior of electromagnetic radiation seen in the double-slit test experiment is true?
a Waves that make up the radiation collide with each other so that they add together or cancel each other out.
b Particles that make up the radiation collide with each other and scatter randomly.
c Particles that make up the radiation collide with each other so that they add together or cancel each other out.
d Waves that make up the radiation do not interact with each other.
3 Which statement about the observed results of the double-slit experiment is true?
a Waves that are out of phase constructively interfere to create bright bands.
b Waves that are in phase destructively interfere to create bright bands.
c Waves that are out of phase constructively interfere to create bright bands.
d Waves that are in phase constructively interfere to create bright bands.
4 Which statement about the observed results of the double-slit experiment is true?
a Waves that are in phase constructively interfere to form dark bands.
b Waves that are out of phase constructively interfere to form dark bands.
c Waves that are in phase destructively interfere to form dark bands.
d Waves that are out of phase destructively interfere to form dark bands.
5 A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. What will be true about the new interference pattern seen on the screen compared to the original interference pattern?
a The spacing between the dark fringes will increase.
b The spacing between the bright fringes will increase.
c The spacing between the bright fringes will decrease.
d The spacing between the dark fringes will remain the same.
6 Consider the two-slit interference experiment. Electromagnetic radiation passes through the two slits that are a distance of 0.0170 nm apart. A fourth-order bright fringe forms at an angle of 8.0 degrees relative to the incident beam. What is the wavelength of the light?
a 789 nm
b 420 nm
c 581 nm
d 591 nm
Answer:
1. Two bright bands would appear on the screen in line with the slits.
2. Waves that make up the radiation collide with each other so that they add together or cancel each other out.
3. Waves that are in phase constructively interfere to create bright bands.
4. Waves that are out of phase destructively interfere to form dark bands.
5. The spacing between the bright fringes will decrease.
6. 581 nm
Explanation:
If 18 wave cycles pass by in a medium in 6 seconds, what is the period of the wave? Which formula did you use?
Answer:
The period of the wave is 0.33 seconds. The formula used to calculate this is T=T/f, where T is the total time (6 seconds) and f is the frequency (18).
the force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of its speed and inversely as the radius of the curve. It takes 2,600 lbs of force to keep a 1,800 lb car from skidding on a curve with a radius of 425 ft at 45 mph. What force (in lbs) is needed to keep the same car from skidding when it takes a similar curve with a radius of 450 ft at 55 mph? round to the nearest 10 lbs. _____ lb
Answer:
3670 lb.
Explanation:
If we measure the force in pounds, distance in ft and time in hours, then the force need to keep the car from skidding is given by
\(F=k\frac{wv^2}{R}\)where k is a constant, w = weight, R = radius of the path, and v = velocity of the car.
Now we know that when v = 45 mph, w = 1800 lb, R = 425, and F = 2600 lb; therefore,
\(2600=k\frac{1800\cdot(45)^2}{425}\)and we need to solve for k.
simplifying the above gives
\(2600=k(8576.4705.\mathrm{})\)solving for k gives
\(\boxed{k=\frac{221}{729}}\)Now that we have the value of k, we can find the force needed for
There seemes to be a technical issue with the answer tab. So I wont be able to complete the explanation. But you can find the force by F = (221/729)*(1800*(55^2))/450.
How is biochar produced?
Answer:
Biochar is produced by heating biomass in the total or partial absence of oxygen. Pyrolysis is the most common technology employed to produce biochar, and also occurs in the early stages of the combustion and gasification processes. Besides biochar, bio-oil and gas can be collected from modern pyrolysers.
An object is dropped from rest and falls freely 20 meters to Earth. When is the speed of the object 9.8 meters per second?
Answer:
at the end of its first second of fall
Explanation:
Can I have brainliest
1. Determine the kinetic energy of a 625-kg roller coaster car that is moving with a speed of 18.3 m/s,
Answer:
104653.13J
Explanation:
Given parameters:
Mass of roller coaster = 625kg
Speed = 18.3m/s
Unknown:
Kinetic energy = ?
Solution:
The kinetic energy is the energy due to the motion of a body.
Kinetic energy = \(\frac{1}{2}\) x m x v²
m is the mass
v is the speed
Kinetic energy = \(\frac{1}{2}\) x 625 x 18.3² = 104653.13J
Then, complete the riddle below by finding the matching number and writing the letter.
Newton's Second Law
44k el effe &
forces cause an object to accelerate.
3
10
Acceleration depends on I & I and M a ½ ½.
11 12
13
14 15
16
17
18
19
As the force increases, the
accelera
i on
20
21
29
30 31
increases, too.
Why did the artist paint on cement blocks instead of paper?
"
11
He wanted to create
Answer:
I have no clue I'm just trying to get points
Explanation:
:) sorry
3. An object with a mass of 3.2 kg has a force of 6.2 N applied to it. What is the resulting acceleration
of the object?
Answer:
The answer is 1.94 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
where
f is the force
m is the acceleration
From the question we have
\(a = \frac{6.2}{3.2} \\ = 1.9375\)
We have the final answer as
1.94 m/s²Hope this helps you
A cannon shoot a cannon ball. The momentum compared to the cannon ball is
Answer:
After the firing occurs, both the cannon and cannonball have the same momentum (big mass, small velocity vs. small mass, big velocity). But since the momentum for each is moving in the opposite direction, the momentums cancel out, causing the cannon-cannonball system's momentum to equal zero.
Explanation:
Write the word conductor or insulator on each of the lines. Then infer which type of material is inside the holes in the outlet. Explain you answer.
( will mark brainliest if you help.)
The required choice is for both the lines are conductor and conductor.
What is conductor and insulator?A conductor is something that easily allows current to flow through it. As an example, consider metal or any other metal. An insulator is something that does not allow current to travel through it. Polyurethane is an example.
Here,
Inside each socket are two pairs of metal strips that are engineered to bend and flex but return to their original shape when pressure is released. Each pair of strips is linked to one of your power lines (either hot or ground).
When you insert the wall plug, springy brass fingers hold the plug prongs, allowing you to connect to your home's electrical system.
Thus, the required choice is for both the lines to be conductor and conductor.
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Is this equation balanced? 2HCl + CaCO3 → CaCl2 + H2O + CO2
Answer:
Yes it is
Explanation:
the sum moles at the left side equals the sum of moles at the right side
Science Motion Problem pelase elp
Answer:120
Vav = S / t = (120 + 45) m / (4 + 60) sec = 2.6 m/s
In which state of matter do the particles have the most energy? (2 points)
O Solid
O Liquid
O Gas
O Plasma
two particles with equal charge experiences a force of 12 nN where they are 30 cm apart. what is the magnitude of the charge on each particle
Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.
Definition of Coulomb's LawCoulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.
This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:
\(F=k\frac{Qq}{d^{2} }\)
where:
F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).k is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\).The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.
Magnitude of the charge on each particleIn this case, you know that:
F= 12 nN= 1.8×10⁻⁸ N (being 1 nN= 1×10⁻⁹ N)k= 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)Q= qd= 30 cm= 0.3 m (being 100 cm= 1 m)Replacing in the Coulomb's Law:
\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)
Being Q=q:
\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)
Solving:
1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²
2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²
2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²
2×10⁻¹⁸ C²/m² ×0.09 m²= q²
1.8×10⁻¹⁹ C²= q²
√1.8×10⁻¹⁹ C²= q
4.2426 C= q= Q
Finally, each charge has a value of 4.2426 C.
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(a) Calculate the force (in N) the woman in the figure below exerts to do a push-up at constant speed, taking all data to be known to three digits. (You may need to use torque methods from a later chapter.) 401.15
(b)How much work (in J) does she do if her center of mass rises 0.260 m?
(c) What is her useful power output (in W) if she does 30 push-ups in 1 min? (Should work done lowering her body be included? See the discussion of useful work in Work, Energy, and Power in Humans.)
the force the woman exerts to do a push-up at constant speed is 333 N.
the work the woman does is 152 J.
her useful power output is 76 W.
(a) To calculate the force the woman exerts to do a push-up, we need to use torque methods. The woman is doing a push-up at constant speed, which means that the net torque on her body is zero. The only torque acting on her body is due to her weight W, which acts at the center of mass of her body. The distance between her center of mass and her hands is 0.76 m, and the angle between her body and the horizontal is 45 degrees.
The torque due to her weight about her hands is given by:
τ = r x W = (0.76 m) x (cos 45°)(W)
where r is the distance between her hands and her center of mass and cos 45° is the component of the distance perpendicular to the weight vector. Since the woman is at constant speed, the torque she exerts about her hands must be equal and opposite to the torque due to her weight. Therefore:
τ = (0.76 m)(cos 45°)(W) = (1/2)(W)(0.76 m)
Solving for W, we get:
W = 2(τ/0.76 m) = 2[(0.5)(mg)(0.76 m)/(0.76 m cos 45°)] = 333 N
Therefore, the force the woman exerts to do a push-up at constant speed is 333 N.
(b) The work the woman does is equal to the change in her potential energy as her center of mass rises. The woman's mass is not given, so we will assume a value of 60 kg. The gravitational potential energy of the woman is given by:
U = mgh
where m is the mass of the woman, g is the acceleration due to gravity (9.81 m/s^2), and h is the height her center of mass rises (0.26 m). Therefore:
U = (60 kg)(9.81 m/s^2)(0.26 m) = 152 J
Therefore, the work the woman does is 152 J.
(c) The useful power output of the woman is the work she does per unit time, taking into account the work done in lowering her body. Each push-up involves two phases: lifting her body and lowering her body. When she lowers her body, the work done is negative, as the force she exerts is in the opposite direction to the displacement. The work done in lowering her body is equal to the work done in lifting her body, so the total work done in one push-up is zero.
The woman does 30 push-ups in 1 minute, which means she does one push-up every 2 seconds. Therefore, the useful power output of the woman is:
P = (152 J)/(2 s) = 76 W
Therefore, her useful power output is 76 W.
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what exercises most beneficial for your overall health
Answer:
Endurance, or aerobic
Strength, or resistance training
Balance
Flexibility
Explanation:
Answer:
Walking. Walking is simple, yet powerful. It can help you stay trim, improve cholesterol levels, strengthen bones, keep blood pressure in check, lift your mood, and lower your risk for a number of diseases (diabetes and heart disease, for example).
need answer and showed work to question number 1
Answer:
can u show question 1?
Explanation:
Three children are struggling and pulling on a single toy. Two of the children, Abe and Barry, are EACH (individually) pulling with a force of 60 Newtons. The third child, Eric, is pulling with enough force to exactly balance Abe and Barry (no child is winning the tug-o-war for the toy). We can label our forces A, B, and E (from each child's name). These three forces are in equilibrium.
If Abe is pulling toward the North and Barry is pulling toward the East, we want to find the total force R due to Abe and Barry (the Resultant of their forces). Note: in THIS case the two forces and R form a right-triangle (with R as the hypotenuse) - as seen using graphical vector addition. As a convention let's have NORTH upward and EAST rightward on this page.
a. Sketch an ACCURATE free-body diagram (three arrows outward from a point showing LABELED forces A, B, and E - each arrow a reasonable length and correct direction):
b. Sketch a labeled diagram for graphical addition of A and B to get R:
c. Show the calculation of the magnitude of R from the magnitudes of A and B:
d. Give the magnitude of force E (in units of Newtons):
e. Describe the direction of force E in terms of the "cardinal" directions (north, east, south, and/or west):
Solution :
c). \($\vec{F}_A = $\) force applied by Abe
\($\vec{F}_B = $\) force applied by Barry
\($\vec{F}_E = $\) force applied by Eric
\($\vec{F}_R = $\) Resultant force
\($\vec{F}_A $\) in the vector form can be written as :
\($\vec{F}_A = 0 \hat{i} + 60 \hat{j}$\)
\($\vec{F}_B $\) in the vector form can be written as :
\($\vec{F}_B = 60 \hat{i} + 0 \hat{j}$\)
The resultant,
\($\vec{F}_R= \vec{F}_A+\vec{F}_B $\)
\($=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$\)
\($=60 \hat i + 60 \hat j$\)
\($|\vec{F}_R| = \sqrt{60^2+60^2}$\)
= 84.853 N
d). As the three forces are in equilibrium, therefore,
\($|\vec F_E| = |\vec F_R|$\)
\($|\vec F_E| =84.853 \ N$\)
e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.
The direction of the resultant force is :
\($\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$\)
\($ = \tan ^{-1}\left(\frac{60}{60}\right)$\)
= 45° north east
The direction of the force E is 45° west or 45° south west.
How long does it take for a ball thrown vertically upward at 25m/s to rise?
Answer:
2.55 s
Explanation:
To know how long does it take to rise, we will use the following equation:
\(v_f=v_i+at\)Where:
vf is the final velocity, so at the highest point is 0 m/s
vi is the initial velocity, in this case, 25 m/s
a is the acceleration due to gravity, so a = 9.8 m/s²
And t is the time that it takes to rise.
Therefore, we can replace the values and solve for t as:
\(\begin{gathered} 0=25-9.8t \\ 9.8t=25 \\ t=\frac{25}{9.8} \\ t=2.55\text{ s} \end{gathered}\)So, the answer is 2.55 s
A wheel of radius 30.0 cm is rotating at a rate of 3.10 revolutions every 0.0710 s
Through what angle does the wheel rotate in 1.00 s?
To determine the angle through which the wheel rotates in 1.00 second, we can start by finding the angle covered in 0.0710 seconds and then scale it up to 1.00 second.
In 0.0710 seconds, the wheel completes 3.10 revolutions. One revolution corresponds to an angle of 360 degrees or 2π radians. Therefore, in 0.0710 seconds, the wheel rotates through an angle of:
Angle = 3.10 revolutions * 2π radians/revolution = 6.20π radians
To find the angle in 1.00 second, we can use proportional reasoning. Since the time increases by a factor of 1.00/0.0710, the angle covered will also increase by the same factor:
Angle in 1.00 second = 6.20π radians * (1.00/0.0710) = 87.32π radians
Approximately, the angle through which the wheel rotates in 1.00 second is 274.39 radians.
Therefore, the wheel rotates through an angle of approximately 274.39 radians in 1.00 second.
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