What mass of oxygen gas is consumed in a reaction that produces 4.60 mol sulfur dioxide?
1) 3.0 grams of oxygen
2) 4.60 grams of oxygen
3) 32.00 grams of oxygen
4)221 grams of oxygen

Answer:

Answer:Your skeletal system relies on the nutrients it gains from your digestive system to bulid strong healthy bones .A body system is a group of parts that work together to serve a common purpose .

maybe this might be ur answer

To assign each species to a category on the right, we need to understand the properties of each term.

- Strong acids are defined as substances that completely dissociate in water to form H+ ions. Examples of strong acids include HCl, HNO3, and H2SO4.
- Weak acids are defined as substances that only partially dissociate in water to form H+ ions. Examples of weak acids include CH3COOH and H2CO3.
- Strong bases are defined as substances that completely dissociate in water to form OH- ions. Examples of strong bases include NaOH and KOH.
- Weak bases are defined as substances that only partially dissociate in water to form OH- ions. Examples of weak bases include NH3 and C5H11N.

With these definitions in mind, we can now assign each species to a category on the right:

- NaOH: This is a strong base because it completely dissociates in water to form Na+ and OH- ions.
- CH3COOH: This is a weak acid because it only partially dissociates in water to form H+ and CH3COO- ions.
- HI: This is a strong acid because it completely dissociates in water to form H+ and I- ions.
- C5H11N: This is a weak base because it only partially dissociates in water to form OH- ions.
- Clear: This term is not a chemical species and cannot be assigned to any category.

Note: It's important to understand the definitions and properties of each term in order to correctly assign species to their respective categories.

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When 2.60 moles of pentane react with excess oxygen, 13.0 moles of carbon dioxide will form.

The balanced equation for the combustion of pentane (C₅H₁₂) with oxygen (O₂) to form carbon dioxide (CO₂) and water (H₂O) is:

C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O

From the balanced equation, we can see that for every 1 mole of pentane, 5 moles of carbon dioxide are produced. Therefore, if 2.60 moles of pentane react, we can calculate the moles of carbon dioxide formed using the mole ratio:

2.60 moles C₅H₁₂ x (5 moles CO₂ / 1 mole C₅H₁₂) = 13.0 moles CO₂

Therefore, when 2.60 moles of pentane react with excess oxygen, 13.0 moles of carbon dioxide will form.

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Answer:

dimensional analysis is the way of converting different units. when you add two physical quantities or equate them they must be in same units.

uses:

to check the correctness of a physical formula

to convert the value from the one system to another.

to form a relationship between different physical quantities

Answer:

Carbon Monoxide.

Explanation:

I used to lol. Things didn't pop up well in a doctor's appointment and I had it explained to me.

Answer:

I'm pretty sure it is unbalanced

The approximation is valid because  is very small.

Calculation of  concentration:

Since

0.85 M        0    0

(0.85-x)M    x      x

Now the value of x should be

x = 0.0000229

So based on this, the above concentration should be determined.

Now you will solve using the quadratic formula instead of iterations, to show that the same value of x is obtained either way. using the quadratic equation to calculate [h3o+] in 0.00250 m hno2, what are the values of a, b, c and x , where a, b, and c are the coefficients in the quadratic equation ax2+bx+c=0, and x is [h3o+]? recall that ka=4.5×10−4 .

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

[H₃O⁺] = 0.000859M

As HNO₂ is a weak acid, its equilibrium in water is:

HNO₂(aq) + H₂O(l) ⇄ H₃O⁺(aq) + NO₂⁻(aq)

Equilibrium constant, ka, is defined as:

ka = 4.5x10⁻⁴ = [H₃O⁺] [NO₂⁻] / [HNO₂] (1)

Equilibrium concentration of each specie are:

[HNO₂] = 0.00250M - x

[H₃O⁺] = x

[NO₂⁻] = x

Replacing in (1):

4.5x10⁻⁴ = x × x / 0.00250M - x

1.125x10⁻⁶ - 4.5x10⁻⁴x = x²

0 = x² + 4.5x10⁻⁴x - 1.125x10⁻⁶

As the quadratic equation is ax² + bx + c = 0

Coefficients are:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

Now, solving quadratic equation:

x = -0.0013 → False answer, there is no negative concentrations.

x = 0.000859

As [H₃O⁺] = x; [H₃O⁺] = 0.000859M

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The types of intermolecular forces that exist among molecules in CH2Cl2 are dipole-dipole interactions and London dispersion forces. CH2Cl2 is a polar molecule due to the presence of two polar C-Cl bonds and a bent molecular geometry.

The dipole-dipole interactions occur due to the attraction between the partially positive hydrogen atom of one molecule and the partially negative chlorine atom of another molecule. The London dispersion forces occur due to the temporary dipoles that are induced in the nonpolar parts of the molecule. To calculate the pressure in the vial at 298 K, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Since the vial is sealed, the volume remains constant, and we can assume that all of the CH2Cl2 vaporizes, so the number of moles is equal to the initial mass of CH2Cl2 divided by its molar mass. Therefore, P = nRT/V = (m/M)RT/V, where m is the mass of CH2Cl2, M is its molar mass, R is the gas constant, T is the temperature, and V is the volume. Plugging in the numbers, we get P = (1.00 g/50.5 g/mol)(0.0821 L·atm/(mol·K))(298 K/233 K) = 0.189 atm.
(ii) It would be unsafe to remove the vial from the freezer and leave it on a lab bench at 298 K because the sudden increase in temperature would cause the pressure inside the vial to increase dramatically, which could cause the vial to rupture or explode. This is because the boiling point of CH2Cl2 is much higher than the temperature of the lab bench, so the sudden increase in temperature would cause a large amount of CH2Cl2 to vaporize and increase the pressure inside the vial.

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A reagent is a compound that is used for the detection of the absence or presence of another substance.

Your information is incomplete as the available reagents aren't given. Therefore, an overview will be given.

Reagents are the integral part of a chemical reaction as they facilitate a reaction. A reagent is usually used tests.

Some typical examples of reagents include Tollens reagent, Fehling's reagent, Million's reagent, etc.

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The reagents that would be used to convert cyclohexanone to the following compound: hydrogen cyanide, potassium cyanide, and H₃O⁺, heat.

It is an organic compound with a chemical formula \(\rm (CH_2)_5 CO\).

The cyclohexanone is used as Insecticides, paint and varnish remover, synthetic resins, etc.

It is not harmful to humans and animals, inhalation cause irritation.

Thus, the compound: hydrogen cyanide, potassium cyanide, and H₃O⁺, heat.

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Answer:

I believe it's because it's based on gravity

Explanation:

mass is like your true weight while weight is your mass and some equation with gravity. it's been a few years

When acidic or basic solutions are diluted with pure water, the pH of the solution will tend to move towards 7 (neutral). In the case of acidic solutions, dilution will result in an increase in pH towards neutrality. This is because the concentration of H+ ions (which contribute to acidit) decreases as more water is added, resulting in a less acidic solution.

Conversely, for basic solutions, dilution will cause the pH to decrease towards 7. This is because as the concentration of OH- ions (which contribute to basicity) decreases, the solution becomes less basic and more neutral. Overall, dilution tends to have a neutralizing effect on the pH of both acidic and basic solutions. When acidic or basic solutions are diluted with pure water, the pH of the solution generally moves closer to neutral (pH 7). For acidic solutions, the pH will increase, while for basic solutions, the pH will decrease. This occurs because the concentration of ions responsible for acidity or basicity is reduced upon dilution.

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The similarity between law of conservation of mass and law of conservation of energy is that no new substance is created in both rather they are conserved.

Law of conservation of mass states that the mass can neither be created nor destroyed but is transformed from one form to another.

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another.

When a toy car is rolled down a ramp the gravitational potential energy at the given height will be converted into kinetic energy of the toy car.

Thus, the similarity between law of conservation of mass and law of conservation of energy is that no new substance is created in both rather they are conserved.

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The three professional areas that uses metric system are the scientific fields, medical fields, or technical fields.

The metric system is a measurement method that utilizes the meter, liter, as well as gram as base units for length for distance, capacity for volume, and weight for mass.

The primary factors for the United States' failure to embrace the metric system are simply cost and time.

When the country's Industrial Revolution began, expensive manufacturing plants was becoming a major source of American jobs and basic goods.

Thus, the scientific, medical, and technical fields are the three professional fields that use the metric system.

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Yes, 32 fluid ounces (oz) is equivalent to 1 quart (qt) in the US customary unit system.

A fluid ounce is a unit of measurement for liquid volume, while a quart is a unit of measurement for dry or liquid volume. The conversion factor between ounces and quarts is 32, because one quart is equal to 32 fluid ounces. This relationship is defined by the fact that a quart is equal to 32 fluid ounces.

In the US customary unit system, the quart is defined as being equal to one fourth of a gallon, which is equal to 2 pints. The fluid ounce, on the other hand, is defined as 1/128 of a gallon. To convert between fluid ounces and quarts, we can use the conversion factor of 32. For example, if we want to convert 64 fluid ounces to quarts, we can divide 64 by 32, and we get 2 quarts.

In summary, 1 quart is equal to 32 fluid ounces and can be converted by dividing the number of fluid ounces by 32.

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Answer:

Halogens are used in, water and sanitation, plastics, pharmaceutical, pulp and paper, textile, military and oil industries. Bromine, chlorine, fluorine and iodine are chemical intermediates( bleaching agents and disinfectants). Chlorine is used to purify water. Chlorine also is part of salt, sodium chloride, which is one of the most widely used chemical compounds. Fluorine is used in fluorides, which are added to water supplies to prevent tooth decay.

hopes this helps~

Answer:

What are some uses of halogen elements? Chlorine is used to purify water. Chlorine also is part of salt, sodium chloride, which is one of the most widely used chemical compounds. Fluorine is used in fluorides, which are added to water supplies to prevent tooth decay.

Explanation:

Halogen, any of the six nonmetallic elements that constitute Group 17 (Group VIIa) of the periodic table. The halogen elements are fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At), and tennessine (Ts). They were given the name halogen, from the Greek roots hal- (“salt”) and -gen (“to produce”), because they all produce sodium salts of similar properties, of which sodium chloride—table salt, or halite—is best known.

Because of their great reactivity, the free halogen elements are not found in nature. In combined form, fluorine is the most abundant of the halogens in Earth’s crust. The percentages of the halogens in the igneous rocks of Earth’s crust are 0.06 fluorine, 0.031 chlorine, 0.00016 bromine, and 0.00003 iodine. Astatine and tennessine do not occur in nature, because they consist of only short-lived radioactive isotopes.

Answer:

The answer must be B ig I hope its right ❤️

The temperatures describing the value of B is 100 °C, because it is the boiling point of water.Hence, The correct answer is Option (B)

What is Phase change ?

A phase change is when matter changes to from one state (solid, liquid, gas, plasma) to another.

These changes occur when sufficient energy is supplied to the b(or a sufficient amount is lost), and also occur when the pressure on the system is changed.

The given heating curve has two flat lines (Or plateaus) ;

In the given problem, C is the second flat line, so it is boiling point.

Therefore , The temperatures describing the value of B is 100 °C, because it is the boiling point of water.Hence, The correct answer is Option (B)

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The specific heat capacity of Aluminum of mass 3 grams that was heated from 20 °C to 662 °C while absorbing 1728 J of heat is 12.5 J/g°C.

The specific heat capacity of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

According to this question, 3 grams of Aluminum was heated from 20 °C to 66.2 °C while absorbing 1728 J of heat.

1728 = 3 × c × (66.2 - 20)

1728 = 138.6c

c = 1728 ÷ 138.6

c = 12.5 J/g°C

Therefore, the specific heat capacity of Aluminum of mass 3 grams that was heated from 20 °C to 662 °C while absorbing 1728 J of heat is 12.5 J/g°C.

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All they are asking is how much mass of the daughter product is needed and however much of the atomic daughter number. Have a nice day!

A lot of energy is required to overcome these forces and melt or vaporize the alkane

The melting point and boiling point of alkanes (a type of hydrocarbon with only single bonds between the carbon atoms) generally increase as the number of carbon atoms in the molecule increases. This is because the larger the molecule, the more Van der Waals forces (also known as London dispersion forces) that are present. These forces are a type of weak attractive force that can exist between any two molecules and are caused by the fluctuating dipoles (temporary separations of positive and negative charge) that occur within a molecule. The more carbon atoms a molecule has, the more fluctuating dipoles it has, and the stronger the Van der Waals forces are. As a result, more energy is required to overcome these forces and melt or vaporize the substance.

In addition to the size of the molecule, the type of bond present in the molecule can also affect the melting point and boiling point. Single bonds, like those found in alkanes, are weaker than double bonds or triple bonds. As a result, molecules with double or triple bonds have higher melting points and boiling points than molecules with the same number of carbon atoms but only single bonds.

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Actually If you look very close to a plant you see this:

And to answer your question leaves are green due to sun nutrients water and im not sure  what else

Answer:

Grade achieved is the dependent variable in the study.

Explanation:

A variable in any research or study is any property, characteristic, number, or a quantity which shows variability or change in its value i.e. it increases or decreases over time, depending on the treatment conditions.

There are two types of variables: Dependent variable and Independent variable.

An independent variable does not depent on any factor for its value or result, rather, a change units value brings about a change in the dependent variable.

A dependent variable is the variable which depends on some factor which the researcher controls. Any change made on the factor by the researcher would bring about a change on the dependent variable.

For example, in the given example above, studying habit affects academic performance. If a student studies more, his/her academic performance will improve as they will achieve higher grades. On the other hand, if a student fails to study, their academic performance will not show any improvement when compared to the group of students who studied. Thus, grade improvement depends on studying habit.

Therefore, grade obtained is the dependent variable in the study.

Answer:Atomic radius gets bigger

Explanation:

Atomic radius bigger because not only do the atoms have more and more protons and neutrons, and thus more mass in general, there is also stronger shielding affect. Shielding affect is when electrons closer to the nucleus block the positive charge from reaching electrons farther from the nucleus, and thus those far electrons are not drawn towards the nucleus as strongly, and spread out more, increasing atomic radius.

Answer:

Explanation:

This link will take you to a work sheet that I think might help.