when circuit town electronics sets its televisions at three price levels of $699, $899, and $1,099, it is most likely using .

Answer:

Reflection

Explanation:

Very smooth surfaces such as mirrors reflect almost all incident light.

\(\underline\mathtt\colorbox{gold}{Reflection}\)

Explanation:

Bouncing back of light from a surface is called reflection.

Answer:b

Explanation:i just did it

Answer:

nacl with water

they are capable of conducting electricity

Answer:

Hello

The chemical bonds between the atoms of the decomposing compound are broken, and then rearranged between the atoms in new ways to make the products.

Explanation:

The chemical bonds between the atoms of the decomposing compound break, and new substances are formed as new chemical bonds form between the atoms of the elements of the decomposed compound.

Answer: Wavelength

Explanation:

The term wavelength describes the length of one complete wave cycle.

The length of one complete wave cycle is referred to as the wavelength. One wavelength, for example, would be the distance from crest to crest or trough to trough.

Compressions and Rarefactions are areas of maximum displacement in a Longitudinal wave.

The wavelength is the distance between two wave crests, and it is also the distance between two wave troughs.

The frequency is measured in cycles per second (Hz) and is the number of vibrations that pass over a given spot in one second (Hertz). This implies the relationship between wavelength and frequency.

The greater the energy, the shorter the wavelengths and higher the frequency. As a result, the longer the wavelengths and lower the frequency, the lower the energy. E = hv is the energy equation.

Thus, the answer is wavelength.

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The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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Answer:

Medium-sized businesses are usually those with between 100 and 999 employees and more than $50 million but less than $1 billion in annual revenue.

Answer:

40.3044 grams.

Explanation:

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18 moles of oxygen can be produced by decomposing 12 moles of KClO₃.

The balanced chemical equation for the decomposition of KClO₃ is:

2KClO₃ → 2KCl + 3O₂

According to the equation, for every 2 moles of KClO₃ decomposed, 3 moles of O₂ are produced. So, to determine how many moles of O₂ are produced by decomposing 12 moles of KClO₃, we can use the following proportion:

2 moles KClO₃ / 3 moles O₂ = 12 moles KClO₃ / x moles O₂

where x is the number of moles of O₂ produced.

Solving for x, we get:

x = (3 moles O₂)(12 moles KClO₃) / (2 moles KClO₃)

x = 18 moles O₂

Therefore, 12 moles of KClO₃ can produce 18 moles of O₂.

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Conjugate acid-base pair is the combination of two compounds which can accept and donate hydrogen ions.

The compounds are HCI, H₂SO₄, HPO, Acetic acid, Formic Acid, HF, carbonic acid, ammonium ion, water, nitric acid.

a.

Conjugate bases of HCl is Cl⁻.

Conjugate bases of H₂SO₄ is HSO₄⁻.

Conjugate bases of HPO₄²⁻ is PO₄³⁻.

Conjugate bases of CH₃COOH is CH₃COO⁻.

Conjugate bases of formic acid is formate ion.

Conjugate bases of HF is F⁻.

Conjugate bases of carbonic acid is the bicarbonate.

Conjugate bases of ammonium ion ammonia.

Conjugate bases of water is H₃O⁺.

Conjugate bases of HNO₃ is NO₃⁻.

b.

HCl ⇄ H⁺ + Cl⁻

H₂SO₄ ⇄ 2H⁺ + SO₄²⁻

H₃PO₄ ⇄ H⁺ + PO₄³

CH₃COOH ⇄ H⁺ + CH₃COO⁻

HCOOH ⇄ H⁺ + HCOO⁻

HF ⇄ H⁺ + F⁻

H₂CO₃ + H₂O ⇄ HCO₃⁻ + H₃O⁺

Ammonia does not ionizes in water.

H₂O ⇄ H₃O⁺ + OH⁻

HNO₃ ⇄ H⁺ + NO₃⁻

c.

Strong acids: HCl, H₂SO₄, HNO₃,

Weak acids: H₃PO₄, CH₃COOH, HCOOH, HF, H₂CO₃, ammonium ion

Water is both weak and strong acid.

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Answer:

its a gas

Explanation:

Hydrogen  is the chemical element in the periodic table that has the symbol H and atomic number 1. At standard temperature and pressure it is a colorless, odorless, non-metallic, univalent, highly flammable diatomic gas. Hydrogen is the lightest and most abundant element in the universe.

In the given question, the state of matter of Hydrogen is gas in nature.

A state of matter is one of the four distinct forms in which matter can exist as solid, liquid, gas, and plasma.

Hydrogen is a chemical element that occurs naturally as a gas at standard temperature and pressure (STP). It is the lightest and most abundant element in the universe and is found in stars, gas giants, and other celestial bodies.

It is also used in various industrial processes, such as the production of ammonia and methanol, and as a fuel source in fuel cells.

Therefore, hydrogen is in the gaseous state at room temperature and normal atmospheric pressure.

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Because we are looking for the temperature change caused by a volume change at constant pressure, this is for Charles’s law. Taking V1 and T1 as the initial values, we can use the following equation:

We are given:

T1 = 300 K

V1 = 3 L

V2 = 10 L

(3L/300K) = (10L/T2)

T2 = 10L/(3L/300K)

T2 = 1000 K)

Answer:

The correct answer is 0.277 M HCl

Explanation:

NaOH is a strong base and HCl is a strong acid. NaOH reacts with HCl to form a salt (NaCl) and water via a neutralization reaction, as follows:

NaOH + HCl → NaCl + H₂O

At the equivalence point, the moles of NaOH added is equal to the moles of HCl present in the solution to be titrated. Moreover, the moles can be calculated as the product of the concentration of base or acid (Cb or Ca) and the volume (Vb and Va), as follows:

moles NaOH = moles HCl

Cb x Vb         =  Ca x Va

Thus, we calculate the concentration of HCl (Ca), as follows:

Ca = (Cb x Vb)/Va = (0.146 M x 47.5 mL)/(25.0 mL)= 0.277 M

Answer:

nCl= 0,062x3/2=0,093(mol)

Explanation:

Nitrogen G is a colorless, tasteless gas that is the most plentiful element in Earth's atmosphere and is a constituent of all living matter of nitrogen.

Nitrogen is an essential gaseous element with an atomic number of 7 and an atomic weight of 14.0067. Nitrogen gas has two particles of Nitrogen therefore, the molecular formula of this gas is N2. It is a non-metallic element that settled Group 15

nitrogen. [ nī′trə-jən ] N. A nonmetallic element that constructs up about 78 percent of the atmosphere by capacity, Nitrogen is a nonmetal and the lightest member of group 15 of the periodic table

So we can conclude that Nitrogen is the chemical element with the symbol N and atomic number 7.

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Answer:

The molarity of the solution is 1.339 M and the molality is 2.48 m.

Explanation:

To calculate the molarity of the solution, you first need to determine the number of moles of sugar present in the solution. To do this, you can use the formula:

moles = grams / molecular weight

For sugar (sucrose), the molecular weight is 342.3 g/mol. So, the number of moles of sugar present in the solution is:

moles = 46 g / 342.3 g/mol = 0.1339 moles

To calculate the molarity of the solution, you then need to divide the number of moles of solute (sugar) by the volume of the solvent (water) in liters. Since there are 100 ml of water in the solution, the volume of the solvent in liters is 0.100 L. So, the molarity of the solution is:

molarity = moles / liters = 0.1339 moles / 0.100 L = 1.339 M

To calculate the molality of the solution, you need to determine the number of moles of sugar present in the solution and the mass of the solvent (water) in kilograms. Since there are 46 grams of sugar in the solution, the mass of the solvent in kilograms is 100 g - 46 g = 54 g. The mass of the solvent in kilograms is therefore 0.054 kg. The molality of the solution is then calculated using the formula:

molality = moles / kilograms = 0.1339 moles / 0.054 kg = 2.48 m

When the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely become surface run off.

Super saturation occurs with a chemical solution when the concentration of a solute exceeds the concentration specified by the value equilibrium solubility.

Additional water into the soil will cause the soil to be super saturated and eventually runs off due to the steepness of the area.

Thus, when the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely become surface run off.

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The balanced redox reaction equation can be given as;

2BrO2 + 4OH- + N2O4 → 2BrO3- + 2H2O + 2NO2-

Making sure that the number of electrons acquired in the reduction half-reaction equals the number of electrons lost in the oxidation half-reaction is necessary to balance a redox (reduction-oxidation) reaction.

Give each element in the chemical equation an oxidation number. This process aids in identifying how the oxidation states vary throughout the reaction. Find the total redox equation's oxidation half-reaction and reduction half-reaction.

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Answer:

the rate at which reactants form products is the same as the rate at which products form reactants

Explanation:

There is still  a reaction happening just that the second one happens the opposite happens and keeps it at net 0

The empirical formula for a compound composed of 9.93% carbon, 58.6% chlorine, and 31.4% fluorine is CCl₂F₂.

To write the empirical formula, let us assume that total mass of the compound is 100 g, then-

Mass of carbon = 9.93 g

Mass of chlorine = 58.6 g

Mass of fluorine = 31.4 g

We know that,

Molar mass of Carbon = 12.0 g/mol

Molar mass of Chlorine = 35.5 g/mol

Molar mass of Fluorine = 18.9 g/mol

Now, we will calculate the number of moles of each using the formula -

Number of moles = Given mass

                                 Molar mass

Moles of Carbon =   9.93 g     = 0.82 mol

                               12.01 g/mol

Moles of Chlorine =    58.6 g     = 1.65 mol

                                 35.5 g/mol

Moles of fluorine =    31.4 g     = 1.66 mol

                                18.9 g/mol

Now, divide each value with the smallest amount of mole we got,

carbon = 0.82 = 1

               0.82

chlorine = 1.65 =  2

                 0.82

fluorine = 1.66 = 2

                0.82

Therefore, the empirical formula of the compound can be written as - CCl₂F₂

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The oxidation level in the first set from row 1 to row 5 is 4 , 1 ,1,2,1 and in the second set is 3,1,1,1,2. the compounds which  have the same oxidation level as the compound in row 1 in first set is 3 and in second set is none.

Hence, oxidation level of row 1 of first set is 4 with two electronegative O and one electronegative Nalong with an unsaturation. Also row 3 of the first set has oxidation level 4(two unsaturation and two 0) Similarly, oxidation level of row 1 of second set is 3. No other compounds in second set has oxidation level 3, hence first set - 3 and second set - none. The oxidation level of a compound is determined by the number of electronegative elements and unsaturations in the compound. The more number of electronegative elements there are, more is the oxidation level as we know that oxidation is the process of removal of electron or addition of electronegative elements like O and N. Also, the reverse reduction is defined as H being added to the compound. For example, in acetic acid, there are two O atoms and a C=O unsaturation. Hence, the oxidation level is 3. Similarly, in ethene, there is only one unsaturation. Hence, oxidation number is 1.

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the complete question is :

Which of the following compounds have the same oxidation level as the compound in row 1? (Enter your answer in numerical order as the row number(s) separated by commas, i.e. 2, 3, 5. If none of the compounds have the same oxidation level, write 'none'.)

Answer:

1. 2.41 × 1023 formula units

2. 122 L

3. 7.81 L

Explanation:

1. Equation of the reaction: 2 Na(NO3) + Ca(CO3) ---> Na2(CO3) + Ca(NO3)2

Mole ratio of NaNO3 to CaCO3 = 2 : 1

Moles of CaCO3 = mass/molar mass

Mass of CaCO3 = 20 g; molar mass of CaCO3 = 100 g

Moles of CaCO3 = 20 g/100 g/mol = 0.2 moles

Moles of NaNO3 = 2 × 0.2 moles = 0.4 moles

1 Mole of NaNO3 = 6.02 × 10²³ formula units

0.4 moles of NaNO3 = 0.4 × 6.02 × 10²³ = 2.41 × 1023 formula units

2. Equation of reaction : 2 H2O ----> 2 H2 + O2

Mole ratio of oxygen to water = 1 : 2

At STP contains 6.02 × 10²³ molecules = 1 mole of water

6.58 × 10²⁴ molecules = 6.58 × 10²⁴ molecules × 1 mole of water/ 6.02 × 10²³ molecules = 10.93 moles of water

Moles of oxygen gas produced = 10.93÷2 = 5.465 moles of oxygen gas

At STP, 1 mole of oxygen gas = 22.4 L

5.465 moles of oxygen gas = 5.465 moles × 22.4 L/1 mole = 122 L

3.Equation of reaction: 6 K + N2 ----> 2 K3N

Mole ratio of Nitrogen gas and potassium = 6 : 1

Moles potassium = mass/ molar mass

Mass of potassium = 90.0 g, molar mass of potassium = 39.0 g/mol

Moles of potassium = 90.0 g / 39.0 g/mol = 2.3077moles

Moles of Nitrogen gas = 2.3077 moles / 6 = 0.3846 moles

At STP, 1 mole of nitrogen gas = 22.4 L

0.3486 moles of oxygen gas = 0.3486 moles × 22.4 L/1 mole = 7.81 L

1. Volume of oxygen 2.41 × 1023   units

2. Nitrogen gas 122 L

3. 7.81 L

Equation of the reaction:

\(\rm 2Na(No_3)+Ca(Co_3)---- > Na_2(Co_3)+Ca(No_3)_2\)

\(NaNo_3\ and \ CaCo_3=\dfrac{2}{1}\)

\(\rm Moles \ of \ CaCo_3=\dfrac{Mass}{Molar\ Mass}\)

Mass of CaCO3 = 20 g; molar mass of CaCO3 = 100 g

\(\rm \ Moles \ of \ CaCo_3=\dfrac{20}{100} =0.2\)

\(Moles \ of \ NaNo_3=2\times 0.2=0.4\ moles\)

\(1\ mole\ of \ NaNo_3=6.02\times10^{23}\)

0.4 moles of NaNO3 = \(0.4\times 6.02\times 10^{23}=2.41\times 10^{23}\)  

2. Equation of reaction :\(2H_2o---- > 2H_2+o_2\)  

The mole ratio of oxygen to water =  \(\dfrac{2}{1}\)

At STP contains

 \(\dfrac{6.02\times 10^{24}\times 1 \ mole \ of \ water}{6.02\times 10^{23}} =10.93\ moles \ of \ water\)

Moles of oxygen gas produced =

\(\dfrac{10.93}{2} =5.465\ Moles \ of \ oxygen \ gas\)

At STP, 1 mole of oxygen gas = 22.4 L

5.465 moles of oxygen gas =    \(5.465\times 22.4=122\ L\)  

3. Equation of reaction:

\(6k+N_2---- > 2K_3N\)6

The mole ratio of Nitrogen gas and potassium =   \(\dfrac{6}{1}\)

\(Moles\ of \ potassium = \dfrac{Mass}{Molar\ Mass}\)

Mass of potassium = 90.0 g,

molar mass of potassium = 39.0 g/mol

\(Moles\ of \ potassium = \dfrac{90}{39}=2.3077\ moles\)

\(Moles\ of \ Nitrogen = \dfrac{ 2.3077}{6}=0.3846\ moles\)

At STP, 1 mole of nitrogen gas = 22.4 L

0.3486 moles of oxygen gas =

\(0.3486\times 22.4=7.81\ L\)

Thus

1. Volume of oxygen 2.41 × 1023   units

2. Nitrogen gas 122 L

3. 7.81 L

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The sample of air should be heated to 252 Kelvin (K) to increase its volume by 25%.

It is possible to determine the temperature to which the sample of air should be heated by using the concept of the ideal gas law. PV = nRT is the ideal gas law, and it relates the pressure (P), volume (V), number of moles (n), temperature (T), and gas constant (R). we can focus on the relationship between volume and temperature since the number of moles and pressure are assumed to be constant.

By showing the increase in volume as a percentage (25%), we can make the equation (V+0.25V)/T = V/T, where V represents the initial volume of the air.

On making the equation simple, we find  Tfinal / Tinitial = 1.25.

To solve for Tfianal, the final temperature,

Tfinal = Tinitail / 1.25

On substituting the initial temperature value of 315K into the equation, we will be getting;

Tfinal = 315K / 1.25

Tfinal = 252K

Hence, the sample of air should be heated to 252 Kelvin (K) in order to increase its volume by 25%.

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Answer:

D.) NaOH

Explanation:

Sodium always forms the cation, Na⁺.

Hydroxide is always written as OH⁻.

The compound should have an overall charge of 0 (be neutral). As you can see, the charges perfectly balance out (+1 + (-1) = 0). Therefore, there only needs to be one atom of each ion. The ionic compound is thus NaOH.

Answer:

1.904 ppm

Explanation:

Concentration of drug in units of ppm = mass of solute / (mass of solution ) × 1000000

mass of blood = density of blood × volume = 1.05 g / ml × 5000 ml = 5250  g

mass of solution = mass of blood + mass of solute ( statin) = 5250 + 0.01 g  = 5250.01 g

Concentration of drug in units of ppm = (0.01 g / 5250.01 g) × 1000000 = 1.904 ppm

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Answer:

The action is acceleration and the reaction is friction

Answer: Explain how the biogeochemical cycles are essential for life

Biogeochemical cycles are critical to the existence of life, transforming energy and matter into usable forms to support the functioning of ecosystems, as noted previously. ... Carbon is an essential element in the bodies of all living organisms and an essential source of energy for many organisms.

Answer:

Explanation:

From the given information;

Using ideal gas equation:

pV = nRT

when n = 1 mol

\(V = \dfrac{RT}{p}\)

Initial molar volume = \(\dfrac{8.314 \ L.bar .k^{-1}.mol^{-1} \times 300 \ K}{1 \ bar}\)

Initial molar volume = 2494.2 L.mol⁻¹

Final molar volume = \(\dfrac{8.314 \ L.bar .k^{-1}.mol^{-1} \times 300 \ K}{3 \ bar}\)

Final molar volume = 831.4 L.mol⁻¹

Answer:

The correct option for question 1 would be:

a bilayer containing lipids with hydrophilic head groups pointing inward and hydrophobic tail groups facing the solvent (extracellular fluid and cytosol).

The correct option for question number two would be: proteins.

Explanation:

The membranes present phospholipids that act as selective barriers between the intracellular and extracellular space, allowing an internal balance in relation to the external one.

Its conformation is mostly phospholipids, fatty acids, proteins (from transmembrane to intermembrane or external)

Answer:

Millimeter can be used to describe the width of a small piece of metal

Explanation:

The most appropriate unit to describe the width of a small piece of metal would be millimeters (mm). Millimeters are commonly used to measure small lengths or dimensions, such as the width of objects. This unit provides a precise and accurate measurement for small-scale items.

Ounces (oz) are typically used to measure weight or volume and may not be suitable for describing the width of an object.

Moles (mol) are used in chemistry to quantify the amount of a substance, so it is not relevant for measuring dimensions.

Milliliters (ml) are used to measure volume, specifically the capacity of liquids, and are not typically used to describe the width of a solid object.

Therefore, when discussing the width of a small piece of metal, millimeters (mm) would be the appropriate unit as it specifically measures small lengths or dimensions.

AI said C. Millimeter.

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