Which congruence theorem can be used to prove △abc ≅ △dbc? aas sss hl sas

Answer:

f(-2) = -8

Step-by-step explanation:

f(x) = 2x - 4

=> f(-2) = 2(-2) - 4

=> f(-2) = -4 - 4

=> f(-2) = -8

Answer:

2.421

Step-by-step explanation:

Ill put the numbers in order from largest to smallest:

3

2.905

2.81

2.713

2.421

it's the smallest because it has 2 ones, 4 tenths, 2 hundredths, and 1 thousandth

Answer:

2.421

Step-by-step explanation:

All work is provided in the screenshot attached! :)

The solution to the initial value problem y' = 2yx, y(1) = 1/4 is  \(y = (1/(4e)) * e^(^x^2^)\)

To find the solution, follow these steps:

Step 1: Identify the given differential equation and initial condition.
The differential equation is y' = 2yx, and the initial condition is y(1) = 1/4.

Step 2: Separate variables.
Divide both sides of the equation by y to isolate dy/dx:

(dy/dx) / y = 2x

Now, multiply both sides by dx to separate the variables:

(dy/y) = 2x dx

Step 3: Integrate both sides.
Integrate the left side with respect to y, and the right side with respect to x:

\(∫(1/y) dy = ∫(2x) dx\)

ln|y| = x^2 + C₁ (Remember to add the constant of integration, C₁)

Step 4: Solve for y.
To remove the natural logarithm, take the exponent of both sides:

\(y = e^(x^2 + C₁)\)

We can rewrite this as:

\(y = e^(^x^2^) * e^(^C^_1)\)
Since e^(C₁) is also a constant, let C = e^(C₁):

\(y = C * e^(^x^2^)\)

Step 5: Apply the initial condition to find the constant C.
Use the initial condition y(1) = 1/4 and substitute x = 1:

1/4 = C * e^(1^2)

1/4 = C * e

Now, solve for C:

C = 1/(4e)

Step 6: Write the solution.
Substitute the value of C back into the equation for y:

\(y = (1/(4e)) * e^(^x^2^)\)

This is the solution to the initial value problem y' = 2yx, y(1) = 1/4.

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Answer:

(1,-1)

Step-by-step explanation:

The expression a² - 2ab - 36b², can be factorize as: (a - 6b)^2.

The polynomial expression a² - 2ab - 36b² can be factored as shown below:

This is done by finding two numbers that multiply to -36 and add to -2ab. The numbers are -6b and 6b, and the expression can be written as:

(a - 6b)(a - 6b), which can be simplified to (a - 6b)^2.

Therefore, given the polynomial expression, a² - 2ab - 36b², when factorized, we would get (a - 6b)².

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Q6: Approximately 68.3% of the cherry tomatoes sold by Berkeley Bowl fall within the specified diameter limits of 20 mm to 32 mm.

Q7: To achieve half of the Six Sigma Quality, the standard deviation of the process should be approximately 0.22 mm for Berkeley Bowl's cherry tomatoes.

In Q6, we can use the concept of the normal distribution to determine the percentage of tomatoes within the specification limits. Since the average diameter is 26 mm and the standard deviation is 3 mm, we can assume a normal distribution and calculate the percentage of tomatoes within one standard deviation of the mean. This corresponds to approximately 68.3% of the tomatoes falling within the specified limits.

In Q7, achieving Six Sigma Quality means that the process has a very low defect rate. In this case, half of the Six Sigma Quality means reducing the variability in diameter to half the acceptable range.

The acceptable range is 32 mm - 20 mm = 12 mm. To achieve half the range, the standard deviation should be approximately half of 12 mm, which is 6 mm. Since the standard deviation is given as 3 mm, the process would need to be improved to reduce the standard deviation to approximately 0.22 mm for it to meet half of the Six Sigma Quality.

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Answer:

6

Step-by-step explanation:

The average rate of change is the same as the slope. Since the slope is the same no matter what interval you choose, the answer is 6.

Answer:

6

Step-by-step explanation:

The average rate of change is the same as the slope. Since the slope is the same no matter what interval you choose, the answer is 6.

Answer: X= - or + square root of 10

Step-by-step explanation: both negative or positive roots would multiply to be 10

Answer:

134 :)

Step-by-step explanation:

The ordered pairs represent (x,y)

To know what ordered pair is a solution we need to substitute the values of x and y with the ordered pair and if the result is equal we have a solution to the equation

For example

(0,-7)

x=0

y=-7

-7=5(0)-7

-7=0-7

-7=-7

Due the result is equal the ordered pair (0,-7) is a solution of y=5x-7

Answer:

5.8

Step-by-step explanation:

Since B is the image of figure A and was dilated by a scale factor of 5.8, this mean that the area of figure B is 5.8 times the area of figure A
Hope this helps :)

The length, breadth, and height of the rectangular block are 256 cm, 192 cm, and 320 cm respectively.

To calculate the length, breadth, and height of a rectangular block whose ratio is 4:3:5 and its volume is 3840 cm3,

follow the steps below:

The ratio of length, breadth, and height is 4:3:5 respectively.

Therefore, assume the length to be 4x, the breadth to be 3x, and the height to be 5x, where x is the common factor.

Then, the volume of the block is calculated as:

Volume = length × breadth × height= 4x × 3x × 5x= 60x³

Since the volume of the block is 3840 cm³, we can equate the equation above to 3840 and solve for x, then find the

length, breadth, and height.

60x³ = 3840 x³ = 3840/60 x³ = 64

Length = 4x = 4 × 64 = 256 cm

Breadth = 3x = 3 × 64 = 192 cm

Height = 5x = 5 × 64 = 320 cm

Therefore, the length, breadth, and height of the rectangular block are 256 cm, 192 cm, and 320 cm respectively.

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Answer:

Estimate of crowd is 27456.

Step-by-step explanation:

Given that a square of 5 by 5 can have 13 students.

Area of a square = \(side^2\) = 25

Area of 25 can have 13 students.

Now, it is given that 10 feet square are used for crowd.

Area of square of side 10 feet  = 100

So, area of 100 can have 13 \(\times\) 4 = 52 people from crowd

Now, it is given that the parade route is 1 mile long.

1 mile = 5280 feet

1 mile = 528 \(\times\) 10 feet

It means that there are 528 number of such squares on the 1 mile section of the parade route.

Kindly refer to the attached image as well.

So, number of people or the estimate of the size of crowd is:

528 \(\times\) 52 = 27456

Solving (7.80 × 10^7) / (1.0 x 10^4) and giving the answer in scientific notation is 78.7 * 10^-3

Using scientific notation, one can express extremely big or extremely small values.

If a number between 1 and 10 is multiplied by a power of 10, the result is written in scientific notation.

Solving the problem (7.80 × 10^7) / (1.0 x 10^4)

The division

= (7.80 × 10^7) / (1.0 x 10^4)

= 0.0787

= 78.7 * 10^-3

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Step-by-step explanation:

sin^2thita+cosec^2thita. = 1,

it have nothing to do with the given values!

Answer:

7

Step-by-step explanation:

using the identities

• (sinΘ + cosecΘ)² = sin²Θ + 2sinΘcosecΘ + cosec²Θ

• cosecΘ = \(\frac{1}{sin0}\)

then

2sinΘcosecΘ = sinΘ × \(\frac{1}{sin0}\) = 1

Hence

sin²Θ + 2sinΘcosecΘ + cosec²Θ = (sinΘ + cosecΘ)² = 3² = 9

sin²Θ + 2 + cosec²Θ = 9 ( subtract 2 from both sides )

sin²Θ + cosec²Θ = 7

The greatest distance from the origin is 10, which corresponds to vertex L'' (6, 8) of the image triangle.

To determine the vertex of the image triangle that is the greatest distance from the origin, we need to follow the given transformations step by step and find the coordinates of the image vertices.

1. Translation: The given triangle is translated 4 units left and 3 units up.

  - Vertex L' is located at (-2 - 4, 5 + 3) = (-6, 8).

  - Vertex E' is located at (1 - 4, 4 + 3) = (-3, 7).

  - Vertex D' is located at (2 - 4, -2 + 3) = (-2, 1).

2. Reflection: The translated triangle is reflected over the line y = 4.

  - The line y = 4 acts as a mirror. The y-coordinate of each vertex remains the same, but the x-coordinate is reflected.

  - Vertex L'' is located at (-(-6), 8) = (6, 8).

  - Vertex E'' is located at (-(-3), 7) = (3, 7).

  - Vertex D'' is located at (-(-2), 1) = (2, 1).

Now, we have the coordinates of the image triangle vertices: L'' (6, 8), E'' (3, 7), and D'' (2, 1).

To determine which vertex is the greatest distance from the origin (0, 0), we can calculate the distances using the distance formula:

- Distance from the origin to L'': √[(6 - 0)² + (8 - 0)²] = √(36 + 64) = √100 = 10.

- Distance from the origin to E'': √[(3 - 0)² + (7 - 0)²] = √(9 + 49) = √58.

- Distance from the origin to D'': √[(2 - 0)² + (1 - 0)²] = √(4 + 1) = √5.

Therefore, the greatest distance from the origin is 10, which corresponds to vertex L'' (6, 8) of the image triangle.

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Answer:

36 - [18 - {14 - (15 - 4 ÷ 2 × 2)}]= 36-[18-{14-(15-4)}]= 36-[18-{14-9}]=36-[18-5]=36-13=23

Step-by-step explanation:

36 - [18 - {14 - (15 - 4 ÷2 ×2)}]

= 36 - [18 - {14 - (15 - 2 ×2)}]

= 36 - [18 - {14 - (15 - 4)}]

= 36 - [18 - {14 - 11}]

= 36 - [18 - 3]

= 36 - 15

= 21

21

Answer: B. statistic

Step-by-step explanation: A characteristic, usually a numerical value, which describes a sample, is called a statistic.

Answer:

$18 less than the cost of 5 hot dog combos

Step-by-step explanation:

First, we see from the minus sign that this will be subtraction.  PEMDAS (order of operations) says we do the multiplication first, then the subtraction.

Option B does not represent a polynomial identity.

Polynomial identities are equations that are true for all possible values of the variable. The polynomial identities are -

Given are the equations as shown in the image.

The equation that is not a polynomial identity is option B.

Therefore, Option B does not represent a polynomial identity.

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Answer:

Not a right triangle

Step-by-step explanation:

Find AC by doing 22-13=9

Use Pythagorean Theorem to determine if it is a right triangle.

8 squared plus 5 squared=89

Square rt= 9.43

And 9.43 is not equal to 9.

Hyperkalemia is a medical condition that refers to an elevated level of potassium in the blood.

This condition can be caused by several factors, including kidney disease, certain medications, and hormone imbalances. Symptoms of hyperkalemia can range from mild to severe, depending on the level of potassium in the blood.

In a 60-year-old female diagnosed with hyperkalemia, the most likely symptom that would be observed is muscle weakness. This is because high levels of potassium can interfere with the normal functioning of muscles, leading to weakness, fatigue, and even paralysis in severe cases.

Other symptoms that may be observed in hyperkalemia include nausea, vomiting, irregular heartbeat, and numbness or tingling in the extremities. Treatment of hyperkalemia typically involves addressing the underlying cause of the condition, as well as managing symptoms through medication and lifestyle changes.

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Answer:

the answer is 0.77 yes that is the answer

Answer:

C. 0.64

Step-by-step explanation:

the answer is on the picture

The probability that a tire will last longer than 42,000 miles is 0.0432. The probability that a single battery randomly selected from the population will have a life between 60 and 70 hours is 0.242.

The probability that a tire will last longer than 42,000 miles can be calculated using the normal distribution. The normal distribution is a bell-shaped curve that is symmetrical around the mean. The standard deviation of the normal distribution is a measure of how spread out the data is.

In this case, the mean of the normal distribution is 36,000 miles and the standard deviation is 3,500 miles. This means that 68% of the tires will have a life between 32,500 and 39,500 miles. The remaining 32% of the tires will have a life that is either shorter or longer than this range.

The probability that a tire will last longer than 42,000 miles is the area under the normal curve to the right of 42,000 miles. This area can be calculated using a statistical calculator or software, and it is equal to 0.0432.

The probability that a single battery randomly selected from the population will have a life between 60 and 70 hours can also be calculated using the normal distribution. In this case, the mean of the normal distribution is 75 hours and the standard deviation is 10 hours.

This means that 68% of the batteries will have a life between 65 and 85 hours. The remaining 32% of the batteries will have a life that is either shorter or longer than this range.

The probability that a battery will have a life between 60 and 70 hours is the area under the normal curve between 60 and 70 hours. This area can be calculated using a statistical calculator or software, and it is equal to 0.242.

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You will reject the null hypothesis if your sample average is in the area of the null hypothesis sampling distribution called alpha.

In summary, to reject the null hypothesis, the sample average needs to fall in the area of the null hypothesis sampling distribution known as alpha.

To explain the answer, hypothesis testing involves comparing a null hypothesis (the statement being tested) with an alternative hypothesis. In this scenario, the null hypothesis states that the average number of screaming 12-year-olds at Ariana Grande concerts is equal to the known population average of screaming 12-year-olds at Drake concerts.

To make a decision about the null hypothesis, we calculate the sample average from data collected at Ariana Grande concerts. We then compare this sample average to a predetermined significance level called alpha.

If the sample average falls within the critical region, which is determined by alpha, we reject the null hypothesis. The critical region represents extreme values that would be unlikely to occur if the null hypothesis were true.

Therefore, if the sample average is in the area of the null hypothesis sampling distribution called alpha, we reject the null hypothesis, indicating that there is a significant difference between the average number of screaming 12-year-olds at Ariana Grande concerts and the known population average at Drake concerts.

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The complete question is :

Suppose you are testing the null hypothesis that the average number of screaming 12 year-olds at Ariana Grande concerts is equal to the known population average of screaming 12 year-olds at Drake concerts. You will reject the null hypothesis if.....

a)your null (comparison) average is in the area of the alternative hypothesis sampling distribution called D (Beta)

b) your null (comparison) average is in the area of the alternative hypothesis sampling distribution called u (alpha)

c)your sample average is in the area of the null hypothesis sampling distribution called beta

d)your sample average is in the area of the null hypothesis sampling distribution called alpha.

Answer:

10t-2b-2

Step-by-step explanation:

5+2-2123

The value of Absolute maximum are (a) 8, (b) -30.36, (c) -10 and the Absolute minimum are (a) -10, (b) -362.39, (c) -362.39.

We are given a function:f(x) = x³ - 12x² - 27x + 8We need to find the absolute maximum and absolute minimum values of the function f(x) over each of the indicated intervals. The intervals are:

a) Interval = [-2, 0]

b) Interval = [1, 10]

c) Interval = [-2, 10]

Let's begin:

(a) Interval = [-2, 0]

To find the absolute max/min, we need to find the critical points in the interval and then plug them in the function to see which one produces the highest or lowest value.

To find the critical points, we need to differentiate the function:f'(x) = 3x² - 24x - 27

Now, we need to solve the equation:f'(x) = 0Using the quadratic formula, we get: x = (-b ± √(b² - 4ac)) / 2a

Substituting the values of a, b, and c, we get:

x = (-(-24) ± √((-24)² - 4(3)(-27))) / 2(3)x = (24 ± √(888)) / 6x = (24 ± 6√37) / 6x = 4 ± √37

We need to check which critical point lies in the interval [-2, 0].

Checking for x = 4 + √37:f(-2) = -10f(0) = 8

Checking for x = 4 - √37:f(-2) = -10f(0) = 8

Therefore, the absolute max is 8 and the absolute min is -10.(b) Interval = [1, 10]

We will follow the same method as above to find the absolute max/min.

We differentiate the function:f'(x) = 3x² - 24x - 27

Now, we need to solve the equation:f'(x) = 0Using the quadratic formula, we get: x = (-b ± √(b² - 4ac)) / 2a

Substituting the values of a, b, and c, we get:

x = (-(-24) ± √((-24)² - 4(3)(-27))) / 2(3)

x = (24 ± √(888)) / 6

x = (24 ± 6√37) / 6

x = 4 ± √37

We need to check which critical point lies in the interval [1, 10].

Checking for x = 4 + √37:f(1) = -30.36f(10) = -362.39

Checking for x = 4 - √37:f(1) = -30.36f(10) = -362.39

Therefore, the absolute max is -30.36 and the absolute min is -362.39.

(c) Interval = [-2, 10]

We will follow the same method as above to find the absolute max/min. We differentiate the function:

f'(x) = 3x² - 24x - 27

Now, we need to solve the equation:

f'(x) = 0

Using the quadratic formula, we get: x = (-b ± √(b² - 4ac)) / 2a

Substituting the values of a, b, and c, we get:

x = (-(-24) ± √((-24)² - 4(3)(-27))) / 2(3)x = (24 ± √(888)) / 6x = (24 ± 6√37) / 6x = 4 ± √37

We need to check which critical point lies in the interval [-2, 10].

Checking for x = 4 + √37:f(-2) = -10f(10) = -362.39

Checking for x = 4 - √37:f(-2) = -10f(10) = -362.39

Therefore, the absolute max is -10 and the absolute min is -362.39.

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Answer:  g(4n+5) = 16n^2 + 40n + 30

Step-by-step explanation:

g(n)=n^2-4

h(n)=4n+5

find g°h

g°h is g(4n+5) = (4n+5)^2 + 5

g(4n+5) = (16n^2 + 40n + 25) + 5

g(4n+5) = 16n^2 + 40n + 30

Answer:

ds hj bfsj gjhbyuabfdbsybfy

Step-by-step explanation:

sdbhabjbgfybsbfsad gfhysabfubdfr