Which of the following elements has the heaviest atom?


a. nickel

b. lead

c. iron

d. gold

Answer:Favorable

Explanation:um I know That it is Favorable sorry!

Answer:

sabatomic particle also called elementary particle of any various self contained units of matter or energy that are fundamental constitution of all methods

Atomic radius increases with atomic number and mass only on moving down the group while it decreases on moving along a period.

On moving down the group, atomic radius increases as a new shell is successively added along each group and mass only increases because with each element there is an increase in number of protons which leads to the increase in mass.

While, moving across a period, atomic radius decreases as electrons are added  to the same shell and due to the inter-electronic repulsions  the atom tends to shrink.

Factors which lead to an increase in atomic radius are:

1)Number of protons

2)Number of shells

3)Shielding effect

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The partial pressure (in mmHg) of water vapor, given that partial pressure of oxygen is 320.0 mmHg and that of hydrogen is 55 mmHg, is 409 mmHg

We know that the total pressure of a given system is related to the partial pressure of the gases present in the system according to the following formula:

Total pressure = Partial pressure of gas A + Partial pressure of gas B

With the above formula, we can easily obtain the partial pressure of water vapor. Details below:

Total pressure = Partial pressure of oxygen + Partial pressure of hydrogen + Partial pressure of water vapor

784 = 320 + 55 + Partial pressure of water vapor

784 = 375 + Partial pressure of water vapor

Collect like terms

Partial pressure of water vapor = 784 - 375

Partial pressure of water vapor = 409 mmHg

Thus, the partial pressure of the water vapor is 409 mmHg

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Answer:

Explanation:

The quick and short answer to this question is that the moment it is made into Na (the atom) the moment that happens, Na will react with water to become NaOH. Sodium is very responsive to water.

Equation

2Na  + 2HOH ====> 2NaOH + H2

Answer:

0.3+Na

Explanation:

The relative molecular mass of Br2 is 160.

The relative molecular mass refers to the mass of one mole of a substance. We can obtain the relative molecular mass by looking at the mass spectrum of a compound.

The fact that the he third peak occurs at 160 and is twice  as big as the other two peaks shows that that is the peak that contains the most abundant isotope.

Hence, the relative molecular mass of Br2 = 158 + 162 + 160/3 = 160.

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The element that has the same number of valence electrons as phosphorus and the same number of electron shells as iodine is Antimony,  Sb.

Valence electrons are the electrons that are found in the outermost shell of an atom of an element.

The number of valence electrons in an atom determines the group to which the elements belong.

Electron shells are the shells in an atom to which an electron is fed into the atom. An electron shell determines the period an element belongs to.

Phosphorus has 5 valence electrons, hence belongs to group 5A or 15.

Iodine has 5 electron shells, hence belongs to period 5.

The element that belongs to group 5A period 5 is antimony.

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Answer:

Na

2

SO

4

.10H

2

O

=(2×23)+32+(4×16)+(10×18)

=46+32+64+180

=322

Answer:0.226 gram

Explanation:you can get the answer in two steps calculate 3.40 . 10^22 atoms =

Answer:

4.2 × 10²² ÷ 6.022× 10²³

4.2 × 10²² equals 0.069 moles (approx)

weight of 1 mole of iron = 56g

therefore, 0.069 moles = 56 × 0.069 = 3.9 g

Sorry for lazy work.. :P

Here is a step-by-step guide for guiding students on how to write balanced chemical equations and ionic equations:

Steps:

1. Determine the reactants and products: Start by identifying the reactants and products in the chemical reaction. This involves reading the problem and identifying the substances that are being reacted.

2. Write the unbalanced equation: Once the reactants and products have been identified, write the unbalanced chemical equation using the chemical formulas for each reactant and product.

3. Balance the equation: To balance the equation, adjust the coefficients of the reactants and products so that the number of atoms of each element is equal on both sides of the equation. Begin by balancing the atoms of elements that appear only once on each side of the equation, and then move on to elements that appear more than once.

4. Check the balanced equation: After balancing the equation, double-check to make sure that the number of atoms of each element is the same on both sides of the equation.

5. Write the ionic equation: To write the ionic equation, break apart any soluble ionic compounds into their individual ions. Then, cancel out any spectator ions that appear on both sides of the equation.

6. Check the ionic equation: Double-check the ionic equation to make sure that the same number and type of ions appear on both sides of the equation.

7. (Optional) Include states of matter: It is common practice to include the states of matter (solid, liquid, gas, aqueous) of the reactants and products in the chemical equation. This can be done by using abbreviations in parentheses after each chemical formula.

By following these steps, students can learn how to write balanced chemical equations and ionic equations accurately and efficiently.

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Answer:

D

Explanation:

i learned this in elementary

There are 8.73 × 10²⁴ formula units in 14.5 moles of sulfuric acid.

Formula units is an empirical formula of an ionic compound (that does not possess individual molecules) for use in stoichiometric calculations.

The formula unit can be calculated by multiplying the number of moles in a substance by Avogadro's number (6.02 × 10²³).

According to this question, there are 14.5 moles in sulfuric acid. The formula unit can be calculated as follows:

Formula units of sulfuric acid = 14.5 × 6.02 × 10²³

Formula units = 8.73 × 10²⁴ formula units

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In forming the Al³⁺ ion, the Al atom loses the electrons in its outermost energy level, causing a decrease in the atomic radius, hence option A is correct.

The number of protons in the nucleus of AlandAl3+ AlandAl3+ is the same, however there are differing numbers of electrons in the final shell. Al³⁺ is smaller than Al because it has fewer electrons.

The Al atom will become an Al³⁺ ion when it loses its third electron and develops a tri-positive charge on it. In forming the Al³⁺ ion, the Al atom loses the electrons in its outermost energy level, causing a decrease in the atomic radius.

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Convex lenses refract light inward toward a focal point. Light rays progress through the edges of a convex lens and are bent most.

convex lenses are across in the middle. Rays of light that pass through the lens are conducted closer together (they converge). A convex lens is a meet lens. When parallel rays of light pass through a convex lens the refracted rays cross at one point called the principal focus.

. A convex lens is a connecting lens. When parallel rays of light pass through a convex lens the refracted rays merge at one point called the principal focus.

So we can conclude that Convex Lens. Concave Lens; It is known as a converging lens as light rays, when passed through this lens, tends to bend towards each other. It is known as a Convex Lens

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Answer:

The answer would be B

Explanation:

It has a different definition than the other options

Answer:

16.1923 kj

Explanation:

Given data:

Mass of ice = 30.1 g

Initial temperature = -250 °C

Final temperature = 15.0 °C

Energy required = ?

Solution:

Specific heat capacity of ice is 2.03 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = 15.0°C - (-250 °C)

ΔT  = 265°C

Q = 30.1 g × 2.03 J/g.°C × 265°C

Q = 16192.3 J

J to kJ:

16192.3 J × 1 KJ /1000 j

16.1923 kj

The correct statement from the given option is as follows : Check and see if anyone else can use the chemical. If not, discard in the proper waste container.

A student removes the chemical sample from the reagent bottle to used in an experiment. He should do with any excess chemical that is remaining from that sample after the experiment is complete is he should Check and see if anyone else can use the chemical. If not, discard in the proper waste container.

The remaining chemical can not return to the bottle because , if the student return the this leftover sample, than it can contaminate the entire sample store in the container.

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There are numerous ways to determine whether lead is present in an ore. Atomic absorption spectroscopy is a popular approach. With this method, an ore sample is dissolved in acid and then atomized in a flame or plasma.

The sample's atoms will absorb light at particular wavelengths that are peculiar to the element under investigation. The amount of light absorbed can be used to calculate how much lead is present in the sample. Inductively coupled plasma mass spectrometry and X-ray fluorescence spectroscopy are further techniques. It is crucial to remember that these procedures call for specialized tools and training, thus they ought to only be carried out in a lab by qualified experts.

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Answer:

.

Explanation:

A light-year is how astronomers measure distance in space. It's defined by how far a beam of light travels in one year – a distance of six trillion miles. Think of it as the bigger, badder cousin of the inch, the mile, the kilometer, and the furlong.

Answer:

b) Li2S(aq)+Pb(NO3)2(aq)

e) K2S(aq)+Sn(NO3)4(aq)

Explanation:

they are the only two of the options that contain a sulfide ion (S) therefore they are the only ones that could be considered in the question.

b) Li2S(aq)+Pb(NO3)2(aq)

e) K2S(aq)+Sn(NO3)4(aq)

This element is in group 1.

According to the octet rule, this element would be expected to form an ion with a charge of +1.

If X is in period 5, the ion formed has the same electron configuration as the noble gas Krypton

The symbol for the ion is Rb⁺

Electronic configuration refers to the arrangement of electrons in the orbitals of an atom or molecule, indicating the energy level of the electrons, the number of electrons in each energy level, and the number of electrons in each orbital.

Considering the given element:

It has one valence electron, hence it is in group 1. Group 1 elements form ions with a charge of +1.

Losing one electron will give the ion the same electron configuration as Kyrton since it is the noble gas in Period 4.

The element is rubidium and the ion is Rb⁺.

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The equation that is correct for coffee-cup calorimeter is q reaction = -q calorimeter. Details about coffee-cup calorimeter.

A calorimeter is an apparatus for measuring the heat generated or absorbed by either a chemical reaction, change of phase or some other physical change.

A coffee-cup calorimeter is a specific type of calorimeter that involves the absorption of heat of a reaction by water when a reaction occurs.

The enthalpy change of the reaction is equal in magnitude but opposite in sign to the heat flow for the water:

qreaction = -(qwater)

Therefore, the equation that is correct for coffee-cup calorimeter is q reaction = -q calorimeter.

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Answer:

one from each parent

Explanation:

20.0 moles of oxygen react with Antimony to form 13.3 moles of Antimony (III) Oxide. We want to calculate how many moles of Antimony (III) Oxide will be formed from 20.0 moles of oxygen. This is a stoichiometry problem.

The link between the proportional amounts of components participating in a reaction or generating a compound is known as stoichiometry, and it is often expressed as a ratio of whole integers.

Assuming a balanced chemical equation, the stoichiometric ratio between Antimony (III) Oxide  and oxygen can be used to determine the number of moles of Antimony (III) Oxide  formed.

For example, the balanced equation for the reaction of Antimony with O2 to form Antimony (III) Oxide  is:

4 Antimony + 3 O2 → 2 Antimony (III) Oxide

From this equation, it can be seen that 3 moles of oxygen react with 2 moles of Antimony (III) Oxide . Therefore, if there are 20.0 moles of O2, then the number of moles of Antimony (III) Oxide  formed would be:

20.0 moles oxygen × (2 moles Antimony (III) Oxide  / 3 moles oxygen) = 13.3 moles Antimony (III) Oxide.

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The Mole fraction of solute is 8.1 and the mole fraction of solvent is 0.9 when a non-volatile solute depresses the freezing point of cyclohexane by 4.0°C.

To calculate the mole fraction of the solute and the solvent, we need to first calculate the molality of the solution, which is the number of moles of solute per kilogram of solvent.

Given The density of the cyclohexane solution is = 0.760 g/mL=760 kg/L.

Using the freezing point depression equation, we can calculate the molality of the solution:

Molality = (ΔT * Kf)/(i * m) Where ΔT is the change in freezing point (4.0°C), Kf is the cryoscopic constant of cyclohexane (20.2 kg/mol•K), i is the van't Hoff factor (1 for non-ionic solutes), and m is the molal mass of the solute (the mass of the solute in grams divided  by the molar mass).

Molality = \((4.0C * 20.2 kg/mol*K) / (1 * m)\)

Molality = 80.8 kg/mol•K /m

m = (Density of solution * 1000) / Molality

m =\((760 kg/L * 1000) / 80.8 kg/mol*K\)

m = 94.4 g/mol

Mole fraction of solute = (Moles of solute) / (Moles of solute + Moles of solvent)

Moles of solute = (Density of solution * Volume of solution) / Molar mass of solute

Moles of solvent = (Density of solution * Volume of solution) / Molar mass of solvent

Mole fraction of solute = (Density of solution * Volume of solution) / (Molar mass of solute + Molar mass of solvent)

Mole fraction of solute =\((760 kg/L * 1 L) / (94.4 g/mol + 86.2 g/mol)\)

Mole fraction of solute = 8.1

Mole fraction of solvent = 1 - 8.1 = 0.9

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Answer:

A) 2-pentene

Explanation:

We count from side where we encounter double bond closest so that's going to be from left to the 2nd carbon. Total carbons are 5.

Thus pent- for prefix of 5 carbons and -ene as suffix for double bond.

2- for locant of double bond.

Thus, 2-pentene

(a) The empirical formula of the compound is \(C_{29}H_ {36}O\)

(b) The molecular formula of the compound is approximately \(C_{8}H_{118}O_{3}\)

To determine the empirical formula of the organic compound, we need to find the simplest whole-number ratio of the elements present.

(a) The given percentages of carbon, hydrogen, and oxygen can be converted into moles by dividing them by their respective atomic masses:

Carbon: 0.624 g / 12.01 g/mol = 0.052 mol

Hydrogen: 0.065 g / 1.008 g/mol = 0.064 mol

Oxygen: 0.028 g / 16.00 g/mol = 0.0018 mol

Next, we divide each of the mole values by the smallest mole value (0.0018 mol in this case) to obtain the mole ratio:

Carbon: 0.052 mol / 0.0018 mol ≈ 29

Hydrogen: 0.064 mol / 0.0018 mol ≈ 36

Oxygen: 0.0018 mol / 0.0018 mol = 1

Therefore, the empirical formula of the compound is \(C_{29}H_ {36}O\)

(b) To find the molecular formula, we need the relative molecular mass of the compound, which is given as 1940 g/mol. The empirical formula mass can be calculated by summing the atomic masses in the empirical formula:

Empirical formula mass: (29 × 12.01 g/mol) + (36 × 1.008 g/mol) + (1 × 16.00 g/mol) = 588.94 g/mol

To find the multiplier, we divide the relative molecular mass by the empirical formula mass:

Multiplier: 1940 g/mol / 588.94 g/mol ≈ 3.29

Rounding to the nearest whole number, the molecular formula of the compound is approximately 3 times the empirical formula, resulting in \(C_{8}H_{118}O_{3}\).

In summary, the empirical formula of the compound is\(C_{29}H_ {36}O\), and the molecular formula is approximately \(C_{8}H_{118}O_{3}\).

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