Which of the following is true about an object's weight but NOT about its mass? (S8P3.b)
A. It may vary depending on the object's location.
B. It is a measure of the amount of matter in the object.
C. It is measured in kilograms or grams.
D. It would be the same on the moon as it is on Earth.

A free-falling object has a consrant force acting on it . . .  the force of gravity, or what technical experts refer to as its "weight".

Since the object has a constant force acting on it, it must constantly accelerate according to Newton's 2nd law of motion. The way this acceleration reveals itself, the object's speed is constantly increasing.

Since the object is speeding up as it falls, there are a few weird things that happen:

 --  It will fall 2 meters in less than double the time for 1 meter.

 --  It will fall 3 meters in less than triple the time for 1 meter.

 --  It will fall 4 meters in less than quadruple the time for 1 meter, and less than double the time for 2 meters.

 --  It will fall 1 meter near the bottom in less time than 1 meter near the top.

None of the choices exactly answers the question.

Choices ' a ' and ' d ' are false statements.

Choice-b is a true statement, but it isn't a "Yes".

Choice-c  is kind of confused, but is probably the one you should select.

Answer:

Her displacement is 0 miles and her distance is 5 miles.

Explanation:

Given information:

Sophie runs in an oval track. The length of track is 5 m.

Distance is the total length of path covered during motion while displacement is the shortest distance between initial and final position.

In this case, Sophie completes one cycle in the oval track and the track length is 5 m. So, the distance covered by her will be 5 m.

Now, after completing the track, the initial and final position of Sophie will be same and hence, the displacement she covered will be 0 miles.

Therefore, option "Her displacement is 0 mile and her distance is 5 miles" is correct.

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The displacement of Sophie is 0 and her distance is 5 m

The displacement of Sophie is the change in her position.

If she runs in an oval track, she will return to her initial starting position. The initial position and the final position will be equal, the change in her displacement will be zero.

\(\Delta x = x_f- x_i\\\\\Delta x = 5 - 5 = 0\)

The distance traveled by Sophie is the sum of the total distance covered.

distance = 5 m

Thus, the displacement of Sophie is 0 and her distance is 5 m

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Answer:

A measure of central tendency is a single value that attempts to describe a set of data by identifying the central position within that set of data. As such, measures of central tendency are sometimes called measures of central location. They are also classed as summary statistics. The mean (often called the average) is most likely the measure of central tendency that you are most familiar with, but there are others, such as the median and the mode.

The mean, median and mode are all valid measures of central tendency, but under different conditions, some measures of central tendency become more appropriate to use than others. In the following sections, we will look at the mean, mode and median, and learn how to calculate them and under what conditions they are most appropriate to be used.

Mean (Arithmetic)

The mean (or average) is the most popular and well known measure of central tendency. It can be used with both discrete and continuous data, although its use is most often with continuous data (see our Types of Variable guide for data types). The mean is equal to the sum of all the values in the data set divided by the number of values in the data set. So, if we have  values in a data set and they have values  …, the sample mean, usually denoted by

This formula is usually written in a slightly different manner using the Greek capitol letter, , pronounced "sigma", which means "sum of...":

The mean is essentially a model of your data set. It is the value that is most common. You will notice, however, that the mean is not often one of the actual values that you have observed in your data set. However, one of its important properties is that it minimizes error in the prediction of any one value in your data set. That is, it is the value that produces the lowest amount of error from all other values in the data set.

When not to use the mean

The mean has one main disadvantage: it is particularly susceptible to the influence of outliers. These are values that are unusual compared to the rest of the data set by being especially small or large in numerical value. For example, consider the wages of staff at a factory below:

Another time when we usually prefer the median over the mean (or mode) is when our data is skewed (i.e., the frequency distribution for our data is skewed). If we consider the normal distribution - as this is the most frequently assessed in statistics - when the data is perfectly normal, the mean, median and mode are identical. Moreover, they all represent the most typical value in the data set.

The median is the middle score for a set of data that has been arranged in order of magnitude. The median is less affected by outliers and skewed data.

Our median mark is the middle mark - in this case, 56 (highlighted in bold). It is the middle mark because there are 5 scores before it and 5 scores after it. This works fine when you have an odd number of scores, but what happens when you have an even number of scores? What if you had only 10 scores?

Mode

The mode is the most frequent score in our data set. On a histogram it represents the highest bar in a bar chart or histogram. You can, therefore, sometimes consider the mode as being the most popular option.

We are now stuck as to which mode best describes the central tendency of the data. This is particularly problematic when we have continuous data because we are more likely not to have any one value that is more frequent than the other. For example, consider measuring 30 peoples' weight (to the nearest 0.1 kg). How likely is it that we will find two or more people with exactly the same weight (e.g., 67.4 kg)? The answer, is probably very unlikely - many people might be close, but with such a small sample (30 people) and a large range of possible weights, you are unlikely to find two people with exactly the same weight; that is, to the nearest 0.1 kg. This is why the mode is very rarely used with continuous data.

In the above diagram the mode has a value of 2. We can clearly see, however, that the mode is not representative of the data, which is mostly concentrated around the 20 to 30 value range. To use the mode to describe the central tendency of this data set would be misleading.

Skewed Distributions and the Mean and Median

Summary of when to use the mean, median and mode

Please use the following summary table to know what the best measure of central tendency is with respect to the different types of variable.

Type of Variable                  Best measure of central tendency

Nominal                                                     Mode

Ordinal                                                    Median

Interval/Ratio (not skewed)                    Mean

Interval/Ratio (skewed)                          Median

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With the charges of the square as +2.0-nC point charge and -3.0-nC point charge, The magnitude of the electric field  is mathematically given as

Et= 14.42 N/c

Question Parameters:

A +2.0-nC point charge is placed at one corner of a square (1.5 m on a side), and a -3.0-nC charge

Generally, the equation for the electric field is mathematically given as

E = k*q1/a^2

Therefore

E1= 9*10^9*2*10^-9/1.5^2

E1= 8 N/c

For E2

E2= 9*10^9*3*10^-9/1.5^2

E2= 12 N/c

In conclusion, The magnitude of the electric field at either of the two unoccupied corners

\(Et = \sqrt{E1^2 + E2^2}\)

Et= 14.42 N/c

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Answer:

22

Explanation:

Answer:

Difference is given below.

Explanation:

The main difference between beneficial and harmful friction is that beneficial friction is necessary for performing different activities while on the other hand, harmful effect of friction is destroy different parts of products and machines. examples of beneficial friction are walking, holding things, rubbing hands to produce heat, running etc whereas examples of harmful friction are destruction of sole, slipping, tearing of machine's part, Wet roads and Mudslides etc.

Based on the given information, we can conclude that the net force on Julie is zero N. This is because the upward force (labeled as F_N) is equal in magnitude to the downward force due to gravity (labeled as F_g), and they act in opposite directions. Mathematically, we can express this as:

Net force = F_N - F_g = 265 N - (-265 N) = 530 N

Since the net force is equal to 530 N in the upward direction and there are no other forces acting on Julie in the horizontal direction, she will remain in a state of rest or uniform motion (i.e., swinging back and forth at a constant speed).

This is an example of balanced forces, where the forces acting on an object are equal in magnitude and opposite in direction, resulting in a net force of zero N and no acceleration of the object.

Answer:

0

Explanation:

Answer:

acceleration: 5.48 m/s²

time taken: 9.3 seconds

Given:

\(\boxed{\sf acceleration = \dfrac{Force}{mass}}\)    \(\boxed{\sf time \ taken = \dfrac{final \ velocity - initial \ velocity}{acceleration} }\)

using the formula's:

answer 1:

\(\sf acceleration = \dfrac{F}{m}\)

\(\sf acceleration = \dfrac{6572 }{1200 }\)

\(\sf acceleration = 5.4766... \ m/s^2\)

\(\sf acceleration = 5.48 \ m/s^2\)             // rounded to nearest hundredth //

answer 2:

\(\sf time \ taken = \dfrac{\Delta v}{a}\)

\(\sf time \ taken = \dfrac{66 - 15}{5.48}\)

\(\sf time \ taken = 9.3122 \ seconds\)

\(\sf time \ taken = 9.3 \ seconds\)           // rounded it to nearest tenth //

Answer:

\(\large\boxed{\sf Time =9.30\ s }\)

\(\large\boxed{\sf Accl^n =5.47\ m/s^2 }\)

Explanation:

Here it is given that a car of mass 1200kg has an initial velocity of 15m/s achieves a velocity of 66m/s . A force of 6572N was applied in order to increase the velocity and we need to find the time taken in doing so .

From Newton's Second Law of Motion ,

\(\sf\qquad\longrightarrow Force = \triangle p\\\\ \)

As momentum (p) = mass × velocity ,

\(\\\sf\qquad\longrightarrow Force = \dfrac{m(v-u)}{t} \\\\ \)

Here ,

• On substituting the respective values ,

\(\sf\qquad\longrightarrow 6572N = \dfrac{1200kg ( 66- 15 )m/s }{t}\\\\ \)

\(\sf\qquad\longrightarrow 6572N = 1200kg \times \dfrac{51}{t} \\\\ \)

\(\sf\qquad\longrightarrow t = \dfrac{1200×51}{6572N } \\\\ \)

\(\sf\qquad\longrightarrow t =\dfrac{61200}{6572}s \\\\ \)

\(\sf\qquad\longrightarrow \pink{\frak{ Time = 9.30\ s }} \)

• For finding acceleration ,

\(\sf\qquad\longrightarrow Force = mass * acceleration \\\\ \)

\(\sf\qquad\longrightarrow accl^n =\dfrac{Force}{mass} \\\\ \)

\(\sf\qquad\longrightarrow accl^n =\dfrac{6572N }{1200kg} \\\\ \)

\(\sf\qquad\longrightarrow \pink{\frak{ acceleration= 5.47\ m/s^2}} \\\\ \)

\(\rule{200}4\)

By using the blackbody radiation formula, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.

We need to know about black body radiation to solve this problem. The energy radiated by a black body object is proportional to the area and the fourth power of temperature. It can be determined as

P = A . e . σ . T⁴

where P is power, A is surface area, e is emissivity, σ is Stefan Boltzmann's constant ( 5.67 x 10¯⁸ W/m²K⁴) and T is temperature.

From the question above, we know that

P1 = 10 watt

P2 = 100 watt

T1 = T1

By using the black body radiation formula, the ratio of temperature is

T1⁴ / T2⁴ = P1 / P2

Hence,

T1⁴ / T2⁴ = P1 / P2

T1⁴ / T2⁴ = 10 / 100

T1⁴ / T2⁴ = 1 / 10

T2⁴ = 10T1⁴

T2 = ⁴√(10T1⁴)

T2 = T1 x 10⁰'²⁵

Thus, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.

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Answer: Carbohydrates , proteins and lipids are large molecules that are needed by the body for growth, repair and metabolism . They are found in our food. These molecules are too large to pass from the intestine into the blood, so digestive enzymes break them down into smaller molecules.

Explanation:

Answer:

Digestion is the mechanical and chemical break down of food into small organic fragments. It is important to break down macromolecules into smaller fragments that are of suitable size for absorption across the digestive epithelium. Large, complex molecules of proteins, polysaccharides, and lipids must be reduced to simpler particles such as simple sugar before they can be absorbed by the digestive epithelial cells. Different organs play specific roles in the digestive process. The animal diet needs carbohydrates, protein, and fat, as well as vitamins and inorganic components for nutritional balance. How each of these components is digested is discussed in the following sections

The net force on the car is zero, since the car is moving at a constant velocity which means the forces acting on it are balanced.

If a vehicle is moving at a constant velocity, then there is no net force acting on it. This is because the net force is the sum of all the forces acting on an object, and if the vehicle is moving at a constant velocity, then the forces acting on it must be balanced.

If a vehicle is accelerating, then there is a net force acting on it. This is because acceleration is a change in velocity over time, and to change velocity, a net force must be applied to the object.

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Answer:Mach, April, May (Sunmer), June, July, August,(Autumn), September, Ov

Explanation:

To calculate the efficiency of a cyclical heat engine, we can use the formula: Efficiency = (Work Output / Heat Input) * 100%

Given that the efficiency of the cyclical heat engine is 21.5% and the heat input is 5.2 × 10^9 J, we can calculate the work output.

Efficiency = (Work Output / Heat Input) * 100%

0.215 = (Work Output / (5.2 × 10^9 J)) * 100%

Rearranging the equation to solve for the work output:

Work Output = Efficiency * Heat Input / 100%

Work Output = (21.5% * (5.2 × 10^9 J)) / 100%

Calculating the work output:

Work Output = (0.215 * 5.2 × 10^9 J) / 100%

Work Output ≈ 1.118 × 10^9 J

Therefore, the work output of the cyclical heat engine is approximately 1.118 × 10^9 J.

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On gas-loaded accumulators, safety devices like relief valves, burst discs, and temperature fuse plugs are all used as  precautionary measures to maintain the efficiency​.

Accumulators are pressurized containers that can hold fluid. When a system needs a boost in power, this stored energy can be used, recharged, and then used again. The right precautions should be taken to keep pressure and temperatures under control because this stored energy can be hazardous.

On accumulators, a number of modest but crucial accessories can be placed to stop the release of this stored energy and guarantee that temperatures stay within their safe operating range.

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To calculate the magnitude of the force that would exactly counterbalance these three forces, we need to use the principle of vector addition. This involves combining the three forces vectorially to find the net force acting on the object.

First, we need to find the resultant of the two forces that are at an angle of 90 degrees to each other. This can be done using the Pythagorean theorem:

Resultant = √(25² + 12²) = √(625 + 144) = √769 = 27.74 N

Next, we need to find the net force acting on the object by adding the third force (4 N) to the resultant of the first two forces (27.74 N).

Net force = 4 N + 27.74 N = 31.74 N

Therefore, the magnitude of the force that would exactly counterbalance these three forces is 31.74 N.

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Given speed and the distance that must be covered, the time it will take the ultraviolet light to reach the earth is 3.7 × 10⁴ hours.

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

We substitute our given values into the expression above.

Speed = Distance ÷ time

1.08 × 10⁹km/h = 4.0 × 10¹³km ÷ t

t = 4.0 × 10¹³km ÷ 1.08 × 10⁹km/h

t = 3.7 × 10⁴ hrs

Therefore, given speed and the distance that must be covered, the time it will take the ultraviolet light to reach the earth is 3.7 × 10⁴ hours.

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Answer:

what a fat bear I love physics

The open-circuit test was performed on the low voltage side of the transformer, while the short-circuit test was performed on the high voltage side.

To find the approximate equivalent circuit referred to the high side, we need to calculate the following parameters:
1. Referred Resistance (R'):
\(R' = (Short-circuit power) / (Short-circuit current)^2\)
\(R' = 320 watts / (8 A)^2\)
\(R' = 320 watts / 64 A^2R' = 5 ohms\)
2. Referred Reactance (X'):
X' = sqrt[(Open-circuit power)^2 - (Referred Resistance)^2]
\(X' = sqrt[(100 watts)^2 - (5 ohms)^2]\)
\(X' = sqrt[10000 - 25]\)
\(X' = sqrt[9975]\)
\(X' ≈ 99.87 ohms\)
The approximate equivalent circuit referred to the high side is represented as follows:
Series combination of Referred Resistance (R') and Referred Reactance (X') in parallel with the ideal transformer.

To find the approximate equivalent circuit referred to the low side, we can use the following formulas:
1. Referred Resistance (R''):
\(R'' = (Referred Resistance) * (Turns ratio)^2\)
\(R'' = 5 ohms * (2500 V / 250 V)^2\)
\(R'' = 5 ohms * (10)^2\)
\(R'' = 5 ohms * 100\)
\(R'' = 500 ohms\)
2. Referred Reactance (X''):
\(X'' = (Referred Reactance) * (Turns ratio)^2\)
\(X'' = 99.87 ohms * (2500 V / 250 V)^2\)
\(X'' = 99.87 ohms * (10)^2\)
\(X'' = 99.87 ohms * 100\)
\(X'' = 9987 ohms\)The approximate equivalent circuit referred to the low side is represented as follows:
Series combination of Referred Resistance (R'') and Referred Reactance (X'') in parallel with the ideal transformer.

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Answer:

it has 3 electrons. brainliest please

Consider a force of magnitude F pulling an object over a surface. The object is moving horizontally, with an angle of between the force and motion direction.

The length of the line AB makes up the force's component in the direction of motion.

What effects does angle have on force?

The component of force perpendicular to the incline reduces as the angle increases, while the component of force parallel to the incline grows. The weight vector's parallel component is what drives the acceleration. As a result, accelerations increase with increasing incline angles.

If we measure the acceleration and the driving force, we can use the formula F = ma to compute the mass of an item moving uniformly in a circle.

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The answers are physically and mathematically reasonable, since both have the same order of magnitude of the external forces shown in the figure.

Let be a system at equilibrium, which mathematically is represented by the following formulas:

\(\Sigma F = 0\) (1)

\(\Sigma M = 0\) (2)

We construct equations around points A and B by Newton's Laws and D'Alembert Principle:

\(\Sigma M = F_{B}\cdot (1\,m)-(3000\,kgf)\cdot (2\,m)-(10000\,kgf)\cdot (6\,m) = 0\) (3)

\(\Sigma M = -F_{A,x}\cdot (1\,m) - (3000\,kgf)\cdot (2\,m)-(10000\,kgf)\cdot (6\,m) = 0\) (4)

\(\Sigma F_{x} = F_{A,x} + F_{B} = 0\) (5)

\(\Sigma F_{y} = F_{A,y} -3000\,kgf-10000\,kgf = 0\) (6)

The solution of the entire system is: \(F_{A,x} = -66000\,kgf\), \(F_{B} = 66000\,kgf\) and \(F_{A,y} = 13000\,kgf\).

The magnitude of the force acting on the crane at point A is determined by the Pythagorean theorem:

\(F_{A} = \sqrt{(-66000\,kgf)^{2}+(13000\,kgf)^{2}}\)

\(F_{A} \approx 67268.120\,kgf\)

The force acting on the crane at point A has a magnitude of approximately 67268.128 kilograms-force. \(\blacksquare\)

The force acting on the crane at point B has a magnitude of approximately 66000 kilograms-force. \(\blacksquare\)

The answers of parts (a) and (b) have an order of magnitude of \(10^{3}\), the same order of magnitude of the external forces shown in the figure. Hence, those answers are physically and mathematically reasonable.

Figure is missing. The statement is incomplete. Complete statement is presented below:

A 3000 kilograms-force is supporting a 10000 kilograms-force crate. The crane pivots about point A and is at rest pressed against a support at B.

(a) FInd the force acting on the crane at point A.

(b) Find the force acting on the crane at point B.

(c) Use order of magnitude sense-making to determine the reasonableness of your answers to parts (a) and (b). Hint: consider how the lever arm to the crate  is much different than that to other points.

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The acceleration due to gravity on the surface of the planet is 98.1 m/s² or 10 times that of the Earth.

The mass of a planet is 10 times that of the Earth and has a radius that is 100 times that of the Earth. The acceleration of gravity on the planet's surface, expressed in units of the Earth's acceleration of gravity, g, is 1000 g.

As we know, the acceleration of gravity is determined by the following formula: Where g is the acceleration due to gravity, M is the mass of the planet, and R is the radius of the planet.

So, let's begin with the calculation.  Here's how:

Given:

M = 10 × mass of Earth

R = 100 × radius of Earth

g/1000 = 1000 g

We know that the acceleration due to gravity on Earth, g, is 9.81 m/s².Substituting the values of M, R, and g in the formula, we get:

Therefore, the acceleration due to gravity on the surface of the planet is 98.1 m/s² or 10 times that of the Earth.

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When the resistor in the circuit has a larger resistance value, it will lower the total current that flows in the circuit.

In an electric circuit, resistance is the opposition that an electrical circuit exhibits to the flow of electric current. In general, resistance is measured in ohms (Ω).

When large resistance used:

When large resistor added:

As a result, adding a larger resistor to a circuit would lower the total current that flows in the circuit.

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Answer:

Chris lives farther from the school than Alex lives, and Chris walked to school at a faster rate than Alex walked.

Explanation:

The Force per meter on a straight wire carrying current in a magnetic field is  0.045 N/m.

Calculation:-

       F/ℓ = B I sin θ

  Where B – Magnetic field = 0.02 T I – Current = 5 A          

Substituting the values

F/ℓ = (0.02) (5) (sin 27 deg)

F/ℓ = 0.045 N/m

A force is an influence that can alternate the motion of an item. A force can cause an item with mass to trade its pace, i.e., to boost up. force can also be described intuitively as a push or a pull. A pressure has both value and course, making it a vector quantity.

The push or pull on an item with mass causes it to change its velocity. force is an external agent capable of converting a frame's nation of relaxation or motion. It has significance and a path. A force is a push or pulls among gadgets. it is called an interplay because if one object acts on some other, its movement is matched with the aid of a reaction from the alternative object.

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Answer:

Think of it like this potential energy is exactly what it sounds like it has potential. while kinetic energy which is what the body possesses by virtue of being in motion.

Explanation:

Answer: Yes

Explanation: The block moves a distance d under the influence of the force, so work is done by the force. Note that since the object is not accelerating, there is another force present, most likely friction.

b.

Answer:

v = 2000m/60s; v = 33.33 m/s (plus, in velocity direction is needed in answer, if given)

Explanation:

velocity = distance/time

The figure skater spinning with her arms held straight out will have greater rotational speed at her fingertips compared to her shoulders.

When the skater extends her arms straight out, the moment of inertia increases as the mass is distributed farther from the axis of rotation (her body).

According to the conservation of angular momentum, the product of moment of inertia and angular velocity remains constant unless an external torque acts on the system.

Since the moment of inertia increases when her arms are extended, the angular velocity must decrease to maintain the constant angular momentum.

As a result, the rotational speed is higher at her fingertips because they have a larger distance from the axis of rotation compared to her shoulders.

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