Which other element is most likely to be a nonreactive gas?

A. Li, number 3
B. C, number 6
C. Ni, number 28
D. Kr, number 36​

The command that allows moving a file from one location to another is the "mv command".

The mv command renames or transfers files and folders from one directory to another. A file or directory keeps its base file name when moved to a new directory. All links to other files are preserved when you transfer a file, with the exception of when you move it to a different file system. A directory and its contents are added beneath the existing directory when you transfer a directory into it.

The TargetDirectory option of the mv command allows you to provide a new file name or a new directory path name when renaming a file or directory.

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ANSWER

the volume of the solution is 2.05 liters

EXPLANATION

Given that;

The concentration of Ca(OH)2 is 0.420M

The grams of Ca(OH)2 is 64.0 grams

Follow the steps below to find the volume of the solution

Step 1; Calculate the number of moles of Ca(OH)2 using the below formula

Recall, that the molar mass of Ca(OH)2 is 74.093 g/mol

Step 2; Find the volume of the solution in liters using the below formula

Therefore, the volume of the solution is 2.05 liters

The plasma pencil is a device that generates non-thermal plasma, and its operation typically involves a high-frequency voltage source.

The period of a voltage source refers to the time it takes for one complete cycle of its output waveform.The exact period of the voltage source for a plasma pencil can vary depending on its design and application. To determine the period, you would need to know the frequency of the voltage source (f). You can calculate the period (T) using the formula:

T = 1/f

Where T is the period, and f is the frequency of the voltage source in Hertz (Hz).

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The period of a voltage source for a plasma pencil depends on its operating frequency, the period being the inverse of the frequency. The time taken for one complete cycle signifies the period.

The period of a voltage source that operates the plasma pencil would depend on the frequency at which the voltage source is operating. The period (T) is the reciprocal of the frequency (f), given by the formula T = 1 / f. Therefore, if we know the frequency at which the voltage source is operating, we can find the period. For instance, if our voltage source operates at a frequency of 100 Hz, our period would be 1/100 or 0.01 seconds, which means our voltage source completes one full cycle every 0.01 seconds.

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When the pressure (P) and temperature (T) are constant, the volume (V) constituting an ideal gas (n) directly varies with the amount of moles constituting the gas (n).

A measurement of three-dimensional space is volume. It is frequently expressed quantitatively using SI-derived units, like the cubic metre or litre, or different imperial or US-standard units, including the gallon, quart and cubic inch. Volume and length (cubed) have a symbiotic relationship.

The volume of an item is typically thought of as its capacity, not as the amount of space it takes up. In other words, the volume is the quantity of fluid (liquid or gas) that the container may hold. When the pressure (P) and temperature (T) are constant, the volume (V) constituting an ideal gas (n) directly varies with the amount of moles constituting the gas (n).

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The atomic number (Z) of Iminium (Im) is 125, and since alpha decay results in the loss of 2 protons, Z will decrease by 2, giving a value of 123 for the newly formed element.

After a decay event by alpha decay, the Iminium (Im) atom with atomic number 125 (Z) and atomic mass number 282 (A) will change. Alpha decay involves the loss of 2 protons and 2 neutrons from the nucleus. Therefore, the new values for A and Z will be:

- New atomic number (Z) = 125 - 2 = 123
- New atomic mass number (A) = 282 - 4 = 278

So, the atom that was formerly 282Im will now have an atomic number (Z) of 123 and an atomic mass number (A) of 278.

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When the original solution of KNO3 is cooled to 15°C, a certain amount of KNO3 will settle to the bottom of the beaker. To determine the total mass of KNO3 that settles, several factors need to be considered, such as the solubility of KNO3 at different temperatures, the initial concentration of KNO3 in the solution, and the volume of the solution. By taking these factors into account, the total mass of KNO3 that settles can be calculated using appropriate equations.

The solubility of KNO3, which is the maximum amount of KNO3 that can dissolve in a given amount of solvent, is temperature-dependent. As the temperature decreases, the solubility of KNO3 decreases. Therefore, when the solution is cooled to 15°C, some of the KNO3 will no longer remain in the dissolved state and will start to precipitate or settle at the bottom of the beaker.

To determine the total mass of KNO3 that settles, several factors need to be considered. Firstly, the initial concentration of KNO3 in the solution is important. It determines the amount of KNO3 present in the solution before cooling. Secondly, the volume of the solution also plays a role, as it affects the total amount of KNO3 that can be dissolved. Finally, the solubility of KNO3 at 15°C needs to be known.

To calculate the mass of KNO3 that settles, the amount of KNO3 remaining in the solution at 15°C needs to be determined. This can be done by subtracting the solubility of KNO3 at 15°C from the initial concentration of KNO3 in the solution. The difference represents the amount of KNO3 that has precipitated and settled. Multiplying this difference by the volume of the solution gives the total mass of KNO3 that settles to the bottom of the beaker when the solution is cooled to 15°C.

It's important to note that this calculation assumes ideal conditions and that other factors, such as impurities or the presence of other substances, may affect the solubility and precipitation of KNO3. Additionally, accurate solubility data at the specific temperature of 15°C should be consulted for precise calculations.

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Answer: Possibility of a single replacement reaction

Explanation:

The activity of the series of element is determined by the single replacement reactions. The activity series of element can be used to predict the possibility of a single replacement reaction.

A single replacement reaction is one in which one substance is replacing the other. The replacement of a metallic ion in solution by a metal atom higher in the activity series than the metal in solution falls into this category of reactions.

The reaction is depending on the reactivity of the elements. If the reactivity of the elements is very low, then the reaction very slow, some time reaction can not take place. To get reaction there is some driving force is needed.

The relative position of the two elements in the activity series provides the driving force for this kind of reaction. More active elements undergo readily reaction then less reactive like noble gas elements. It very necessary to elements very active to get react.

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That is incorrect. The olfactory nerves pass through foramina in the cribriform plate of the ethmoid bone, not the crista galli of the sphenoid bone.

The cribriform plate is a part of the ethmoid bone located in the anterior cranial fossa, and it contains numerous small openings called olfactory foramina through which the olfactory nerves pass.

The ethmoid bone is a delicate, sponge-like bone located between the nasal cavity and the brain. It consists of two lateral masses and a central vertical plate called the perpendicular plate. The cribriform plate is a thin, horizontal part of the ethmoid bone that forms the roof of the nasal cavity.

Within the cribriform plate, there are multiple tiny foramina known as olfactory foramina. These foramina allow the passage of the olfactory nerve fibers, which are responsible for transmitting the sense of smell from the olfactory epithelium in the nasal cavity to the olfactory bulb in the brain.

So, to clarify, the olfactory nerves pass through foramina in the cribriform plate of the ethmoid bone, not the crista galli of the sphenoid bone. It's important to have accurate anatomical knowledge, especially when studying or discussing the cranial nerves and their pathways.

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Answer:

B. Design homes that can be built on stilts where flooding is likely to occur.

C. Replace power lines that have been damaged by severe weather.

Explanation:

\(Hope\) \(this\) \(helps!\) \(:)\)

Answer:B

Explanation:Because when the object heats up the particles move faster and it will turn into a liquid or gas but if it is being cooled then the particles will slow down and either make a liquid or solid.

Pure toluene (c7h8) has a normal boiling point of 110.60oc. A solution of 7.80 g of anthracene (c14h10), in 100.0 g. toluene has a boiling point of 112.06oc. The molality of the solution is 0.438 mol/kg. and the molal boiling point elevation constant for Toluene is 3.33 °C/m.

Given that,

Molecular weight of Toluene, C7H8 = 92 g/mol

Molecular weight of Anthracene, C14H10 = 178 g/mol

Boiling point of pure Toluene, Tb° = 110.6°C

Boiling point of Toluene solution containing Anthracene, Tb = 112.06°C

We need to find the molality of the solution and the molal boiling point elevation constant for Toluene.

Molality of the solution:

Molality is defined as the number of moles of solute per kilogram of solvent.

(Here, the solvent is Toluene and the solute is Anthracene.) Number of moles of Anthracene,

n2 = Weight of Anthracene / Molecular weight of Anthracene = 7.80 g / 178 g/mol = 0.0438 moles

Number of kilograms of solvent,

w1 = Weight of Toluene / 1000 = 100.0 g / 1000 = 0.1 kg

Molality of solution, m = n2 / w1 = 0.0438 / 0.1 = 0.438 mol/kg

Therefore, the molality of the solution is 0.438 mol/kg.

Molal boiling point elevation constant for Toluene:

The elevation in the boiling point of the solvent is given by the formula:

ΔTb = Kb . m . i

where Kb is the molal boiling point elevation constant. m is the molality of the solution. i is the van't Hoff factor (which is equal to 1 for non-electrolytes like Anthracene)

ΔTb = Tb - Tb°= 112.06°C - 110.6°C = 1.46°C

We know that m = 0.438 mol/kg

Hence,1.46 = Kb . 0.438 . 1Kb = 3.33 °C/m

Therefore, the molal boiling point elevation constant for Toluene is 3.33 °C/m.

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Given :

• Molar mass of FeBr3 = 295.56 g/mol

• Mass of FeBr3 = 449 g

The balanced reaction is given as :

by stoichiometry , we can see that :

• 2 moles of FeBr3 produces 1 moles of Fe2S3

Therefore ;

• 1.52 mol of febr3 produces X Fe2S3

• X moles of FE2S3, = (1.52moles FeBr3 * 1 mol Fe2S3) /2 moles

FeBr3.

=0.755 moles

≈0.76 moles

• This means that 0.76 moles of Fe2S3 would be produced from the complete reaction of 449 g iron(III)bromide,

Answer:

2Mg + O2 → 2MgO

Explanation:

Answer:

Hello calcium maintains healthy bones and muscles. Zinc is for immune function. Iron carrier oxygen to blood. Sodium maintains fluid balance in the body.

Answer: Zinc : plays a role in immune system function

Iron: carries oxygen to all body tissues

Calcium: Maintains healthy bones and muscles

Sodium: maintains fluid balance in the body

Explanation: Got it right on PLATO/edmentum

The given statement "The molar enthalpy of sublimation of a given substance can be determined if its enthalpies of fusion and vaporization are known" is true.

The molar enthalpy of sublimation of a substance can be determined if its enthalpies of fusion (melting) and vaporization (boiling) are known. The enthalpy of sublimation refers to the energy required to change a substance from the solid phase directly to the gaseous phase, bypassing the liquid phase.

The enthalpy change during sublimation can be calculated by considering the enthalpies of fusion and vaporization. When a substance undergoes sublimation, it first requires energy to melt from the solid phase to the liquid phase (enthalpy of fusion) and then additional energy to vaporize from the liquid phase to the gaseous phase (enthalpy of vaporization). The sum of these two enthalpies represents the overall energy change during sublimation.

Therefore, by adding the enthalpy of fusion and the enthalpy of vaporization, one can determine the molar enthalpy of sublimation for a given substance.

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Answer:

Carbon is released back into the atmosphere when organisms die, volcanoes erupt, fires blaze, fossil fuels are burned, and through a variety of other mechanisms.Humans play a major role in the carbon cycle through activities such as the burning of fossil fuels or land development.

Answer: The answer should be (D.)Decomposition of dead organisms

Explanation: Because Carbon is released back into the atmosphere when organisms die

There are six liquids found on the periodic table.

1. Bromine

2. Mercury

3. Caesium

4. Gallium

5. Rubidium

6. Francium

Answer:

beryllium has a higher ionization energy because its radius is smaller. boron has a higher ionization energy because its radius is smaller.

Utilizing several well pads can drastically minimize the quantity of well pads, access roads, pipeline routes, and production facilities, decreasing habitat disruption, negative effects on the general population, and the environmental footprint overall.

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Approximately 12.45 grams of solid silver chromate will precipitate when 150 mL of 0.500 M silver nitrate solution is added to excess potassium chromate.

To determine the number of moles of AgNO3 present in 150 mL of a 0.500 M AgNO3 solution, we can use the formula:

moles = concentration × volume

Given:

Concentration of AgNO3 solution = 0.500 M

Volume of AgNO3 solution = 150 mL

First, we need to convert the volume from milliliters (mL) to liters (L) since the concentration is given in moles per liter (M).

1 L = 1000 mL

Therefore, the volume of the AgNO3 solution in liters is:

150 mL × (1 L / 1000 mL) = 0.150 L

Now we can calculate the moles of AgNO3 using the formula:

moles = concentration × volume

moles = 0.500 M × 0.150 L

moles = 0.075 mol

So, there are 0.075 moles of AgNO3 present in 150 mL of the 0.500 M AgNO3 solution.

Now, let's proceed to determine how many grams of solid silver chromate (Ag2CrO4) will precipitate when the AgNO3 solution reacts with excess potassium chromate (K2CrO4).

From the balanced chemical equation:

2AgNO3(aq) + K2CrO4(aq) → Ag2CrO4(s) + 2KNO3(aq)

We can see that the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Therefore, for every 2 moles of AgNO3, we will form 1 mole of Ag2CrO4.

Since we have 0.075 moles of AgNO3, we can calculate the moles of Ag2CrO4 formed:

moles of Ag2CrO4 = 0.075 mol / 2 = 0.0375 mol

To determine the mass of Ag2CrO4, we need to multiply the moles by its molar mass. The molar mass of Ag2CrO4 is calculated by summing the atomic masses of each element in the compound:

Ag2CrO4 = 2(Ag) + 1(Cr) + 4(O) = 2(107.87 g/mol) + 1(52.00 g/mol) + 4(16.00 g/mol) = 331.87 g/mol

mass of Ag2CrO4 = moles of Ag2CrO4 × molar mass of Ag2CrO4

mass of Ag2CrO4 = 0.0375 mol × 331.87 g/mol = 12.45 g

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Answer:

Single replacement

Explanation:

Answer:

color

Explanation:

The effective temperature is directly related to the color of the star: the higher the temperature, the bluer the light emitted by the star.

Given that 1.55 moles of methane reacts.The equation for the reaction is:CH4 + 2O2 → CO2 + 2H2OWe can balance the equation by ensuring that the number of moles of each element in the reactant is equal to the number of moles in the product.

Moles of Carbon (C) = Moles of Carbon (C)Moles of Hydrogen (H) = Moles of Hydrogen (H)Moles of Oxygen (O) = Moles of Oxygen (O)
Therefore,1 mole of methane (CH4) will react with 2 moles of oxygen (O2) to give 1 mole of carbon dioxide (CO2) and 2 moles of water (H2O).In the question, the number of moles of methane given is 1.55 moles.
Thus, to find the number of moles of oxygen required, we need to use the balanced chemical equation.
So, 1 mole of methane requires 2 moles of oxygen.
Thus, for 1.55 moles of methane, the moles of oxygen required would be:2 × 1.55 = 3.1 moles of O2Therefore, the main answer is 3.1 moles of O2.

When 1.55 moles of methane reacts, 3.1 moles of oxygen reacts.

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Answer:

Matter is NOT being created

Explanation:

There's a fundamental law of conservation of mass and energy which states we CANNOT create new mass or energy, we can just rearrange stuff.

I went to your PHET lab and one thing you could do to prove it is show that you react two h2 and two O2 in process of making water. You will see on the box on the right that you get two water molecules and a leftover H2. Now count up the number of atoms of each element on both sides.

In left side with reactants, you have 2 H2 (so a total of 4 hydrogen atoms), and 2 O2 (so a total of 4 oxygen)

In right side with product and leftover, you have two water molecule (each water molecules has two hydrogen and one oxygen so total you have 4 hydrogen and two oxygen since you ahve two water molecule). But you also have one O2 left over (that's two oxygen atoms)

Now see the magic, we started with 4 hydrogen atoms and 4 oxygen atoms

We ended with 4 hydrogen atoms and 4 oxygen atoms!!

NO MATTER was created, the atoms were just rearranged. Does that make sense?

The prefix system for the following binary molecular compound is :A. Carbon dioxide (CO₂)

B. Carbon tetrachloride (CCl₄)

C. Phosphorus penta chloride (PCl₅)

D. Selenium hexafluoride (SeF₆)

E. Diarsenic pentoxide (As₂O₅)

In the prefix system, the names of binary molecular compounds are determined by using numerical prefixes to indicate the number of atoms for each element in the compound.

A. Carbon dioxide consists of one carbon atom (mono-) and two oxygen atoms (-dioxide), so the name is "Carbon dioxide."

B. Carbon tetrachloride contains one carbon atom (tetra-) and four chlorine atoms (-tetrachloride), resulting in the name "Carbon tetrachloride."

C. Phosphorus penta chloride has one phosphorus atom (penta-) and five chlorine atoms (-penta chloride), leading to the name "Phosphorus penta chloride."

D. Selenium hexafluoride includes oe selenium atom (hexa-) and six fluorine atoms (-hexafluoride), giving the name "Selenium hexafluoride."

E. Diarsenic pentoxide consists of two arsenic atoms (di-) and five oxygen atoms (-pentoxide), resulting in the name "Diarsenic pentoxide."

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Answer:

Refer to the picture.

The empirical formula of the product in question 5.79 can be determined by finding the ratio of the elements present.

Given that a 29.3 g sample of Ti reacts with O2 to form 48.9 g of product, we need to calculate the moles of Ti and O in the reaction. The molar mass of Ti is 47.87 g/mol, so the moles of Ti in the sample is:

moles of Ti = mass of Ti / molar mass of Ti

moles of Ti = 29.3 g / 47.87 g/mol = 0.612 mol

To find the moles of O, we can use the difference in mass between the sample and the product:

mass of O = mass of product - mass of Ti

mass of O = 48.9 g - 29.3 g = 19.6 g

The molar mass of O is 16.00 g/mol, so the moles of O in the product is:

moles of O = mass of O / molar mass of O

moles of O = 19.6 g / 16.00 g/mol = 1.225 mol

Now we can find the empirical formula by dividing the number of moles of each element by the smallest number of moles:

Empirical formula = Ti(0.612 mol) O(1.225 mol) = TiO2

Therefore, the empirical formula of the product is TiO2.

The given information provides the masses of titanium (Ti) and oxygen (O) in the reaction. By converting these masses to moles and comparing their ratios, we determine the empirical formula of the product to be TiO2. This means that the product contains one titanium atom and two oxygen atoms per formula unit.

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The substance that Channel X transmits would be the smallest substance dissolved in the extracellular fluid, which is likely to be potassium ions .

Channel X only transmits the smallest substances dissolved in the extracellular fluid through the axon membrane. . It would not be proteins as they are generally too large to be dissolved in the extracellular fluid, and sodium ions are not necessarily the smallest substance dissolved in the extracellular fluid. These channels are found in the axon membrane of neurons, and act as a gate that can open and close to allow the passage of potassium ions through the membrane. This allows the neuron to regulate the electrical potential across the membrane, and thus control the flow of electrical signals.

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