Which statement is true?
Question 13 options:

A)
–|3| = 3 and |4| = 4

B)
|–3| = 3 and –|–4| = –4

C)
|–3| = 3 and –|4| = 4

D)
|–3| = 3 and |–4| = –4

The answers that describe the quadrilateral DEFG area rectangle and parallelogram.

The correct answer choice is option A and B.

A quadrilateral is a parallelogram, which has opposite sides that are congruent and parallel.

Quadrilateral DEFG

if line DE || FG,

line EF // GD,

DF = EG and

diagonals DF and EG are perpendicular,

then, the quadrilateral is a parallelogram

Hence, the quadrilateral DEFG is a rectangle and parallelogram.

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Answer:

A. Solution=(x-8)(x+2),Zeros are 8,-2

The integer coefficient of x² is >1 and so the graph which is a parabola,curves downward and opens upward

B. The vertex or turning point is the minimum point =-b/2a=-(-6)/2(1)=3

f(3)=(3)²-6(3)-16=-25

the vertex occurs at y=-25

C. Equation of the axis of symmetry =-b/2a

which is x=3

Answer:

Step-by-step explanation:

\( \sf{6(4 - y) = 5 + 3}\)

Distribute 6 through the parentheses

\( \sf{24 - 6y = 5 + 3}\)

Add the numbers

\( \sf{24 - 6y = 8}\)

Move constant to right hand side and change it's sign

\( \sf{ - 6y = 8 - 24}\)

Calculate

\( \sf{ - 6y = - 16}\)

Divide both sides of the equation by -6

\( \sf{ \frac{ - 6y}{ - 6} = \frac{ - 16}{ - 6} }\)

Calculate

\( \sf{y = 2.6}\)

Hope I helped!

Best regards!!

Answer: Hi!

First, we need to distribute 6 to the terms inside of the parentheses, 4 and -y.

6 * 4 = 24

6 * (-y) = -6y

Our equation now looks like this:

24 - 6y = 5 + 3

We can now combine like terms.

24 - 6y = 5 + 3

5 + 3 = 8

Our equation now looks like this:

24 - 6y = 8

We can now use inverse operations to get rid of 24. Remember, our goal is to isolate the x. The inverse operation for addition (24 is positive) is subtraction, so we subtract 24 on both sides:

 24 - 6y = 8

- 24       - 24

Our equation now looks like this:

-6y = -16

Last step! We now use inverse operations to get rid of -6. The inverse operation for multiplication is division (-6 is being multiplied by y); so we divide -6 on both sides.

-6y/-6 = y

-16/-6 = 8/3 = 2 2/3

Our equation now looks like this:

y = 2 2/3

Therefore, your solution is 2 2/3.

Hope this helps!

Answer:

Step-by-step explanation:

(x - 6)/2= -2

x - 6 = -4

x = 2

(y + 3)/2 = 2

y + 3 = 4

y = 1

(2, 1) coordinates of B

The correct statement is: c. Gross pay - job expenses = total employment compensation

In the context of calculating total employment compensation, the statement in option c is always true. Gross pay refers to the total amount earned by an employee before any deductions or taxes.

The Job expenses are expenses related to performing the job such as travel expenses or necessary tools/equipment. By subtracting the job expenses from the gross pay, we arrive at the total employment compensation which represents the net amount the employee receives after accounting for the expenses associated with their job.

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Answer:

I think it is D I'm not sure

Step-by-step explanation:

If two angle and one ️ are congruent to two angles of a second ️ and also if the included sides are congruent, then the ️ are congruent. If in ️ PRQ and TUV, angle P=angle T, angle R=angle and PR=TU, then triangles PRQ is congruent to triangle TUV

Answer:

1577

Step-by-step explanation:

Answer:

− 386

Step-by-step explanation:

Um i dont really know what you were going for but if you can retype the question i can give yo a better answer

ANSWER:

STEP-BY-STEP EXPLANATION:

We have the following system of equations

In the case x = 7, it is parallel to the y axis, through the point 7 in x, and in the case y = 0, it is the same x axis, therefore the intercept is the point (7 , 0)

The solution is:

To calculate the cash balance at the end of the period, we need to consider the cash inflows and outflows.

Starting cash balance: $4,520

Cash inflows: $1,654 (receivables collected)

Cash outflows: $1,961 (payments to suppliers) + $500 (cash expenses)

Total cash inflows: $1,654

Total cash outflows: $1,961 + $500 = $2,461

To calculate the cash balance at the end of the period, we subtract the total cash outflows from the starting cash balance and add the total cash inflows:

Cash balance at the end of the period = Starting cash balance + Total cash inflows - Total cash outflows

Cash balance at the end of the period = $4,520 + $1,654 - $2,461

Cash balance at the end of the period = $4,520 - $807

Cash balance at the end of the period = $3,713

Therefore, the cash balance at the end of the period is $3,713.

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Answer: 9(x−4)

Step-by-step explanation: Hope this help :D

Answer:

600

Step-by-step explanation:

It is 600 because 602 rounded to the nearest whole number is 600. And, the decimal part makes no difference on the rounding itself in this number. Therefore, the answer is 600.

Answer:

Step-by-step explanation:

From the given information:

The ratio of the limiting floor area to lot area is 0.60 to 1

i.e.

= 0.60 : 1

For instance, let's take that the remodel size as p sq.ft on 1140 sq.ft

Then, the ratio = \(\dfrac{p}{11400}\)

The proportion of these equations is as follows:

\(\dfrac{p}{11400} = \dfrac{0.60}{1}\)

\(p \times 1 = 11400 \times 0.60\)

\(p = 11400 \times \dfrac{60}{100}\)

\(p =\dfrac{ 11400 \times 60}{100}\)

\(p =\dfrac{ 114 \times 100 \times 60}{100}\)

\(p = 114 \times 60\)

p = 6840 sq ft

Thus, the maximum allowable size of a remodeled house is 6840 sq.ft

b.

Recall that, the size of the home remodeled by limiting floor to lot area is

0.60:1

Then the proportion equation form is as follows:

\(\dfrac{0.60}{1}= \dfrac{5040}{x}\)

By cross multiplying

\(0.60 \times x = 5040 \times 1\)

\(x = \dfrac{5040 \times 1}{0.60 }\)

\(x = \dfrac{5040 \times 100}{60 }\)

\(x = \dfrac{84 \times 60 \times 100}{60 }\)

\(x =84 \times 100\)

x = 8400 sq.ft

Hence, the size of lot area is 8,400 sq.ft

The statement ''Quasi-experiments examine relationships between the manipulated variable (iv) and the dv while experiments examine causation between these variables.'' is false because -

Quasi-experiments and experiments differ in terms of the level of control over the independent variable (IV) and the ability to establish causal relationships between the IV and the dependent variable (DV).

In quasi-experiments, the researcher does not have full control over the assignment of participants to different groups or conditions.

Quasi-experiments typically involve naturally occurring groups or conditions, such as pre-existing groups, different locations, or different time periods.

Quasi-experiments examine relationships between the manipulated variable (IV) and the DV but do not have the same level of control as experiments.

While they can identify associations or correlations between variables, they cannot establish causal relationships with certainty due to the potential influence of confounding variables.

Experiments, on the other hand, involve the random assignment of participants to different groups or conditions, allowing for greater control over the manipulation of the IV.

Experiments are designed specifically to establish causal relationships between the IV and the DV by ensuring that any observed effects are due to the manipulation of the IV and not other factors.

Therefore, it is false to say that quasi-experiments examine relationships between the manipulated variable (IV) and the DV, while experiments examine causation between these variables.

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Answer:

7.25 mph(miles per hour)

Step-by-step explanation:

The solution to the differential equation \(\(\frac{{dy}}{{dt}} = 4(y-16)\)\), with the initial condition \(\(y(0) = 15\)\), is given by \(\(y(t) = 16 + e^{4t}(y_0 - 16)\)\), where \(\(y_0\)\) is the initial value of y.

To solve the given first-order linear ordinary differential equation, we can use the method of separation of variables. Rearranging the equation, we have \(\(\frac{{dy}}{{y-16}} = 4dt\)\). Integrating both sides, we get \(\(\int \frac{{dy}}{{y-16}} = \int 4dt\)\).

The left-hand side can be integrated using the substitution \(\(u = y-16\)\), which gives \(\(\ln|y-16| = 4t + C_1\)\), where \(\(C_1\)\) is the constant of integration. Exponentiating both sides, we obtain \(\(|y-16| = e^{4t+C_1}\)\).

Considering the initial condition \(\(y(0) = 15\)\), we substitute t = 0 and y = 15 into the equation above. Since the absolute value can be positive or negative, we split it into two cases: \(\(y-16 = e^{C_1}\)\) for \(\(y > 16\)\) and \(\(y-16 = -e^{C_1}\)\) for \(\(y < 16\)\).

Simplifying each case, we have \(\(y = 16 + e^{C_1}\)\) for \(\(y > 16\)\) and \(\(y = 16 - e^{C_1}\)\) for \(\(y < 16\)\). Since \(\(C_1\)\) is an arbitrary constant, we can rewrite it as \(\(C_1 = \ln|y_0-16|\)\), where \(\(y_0\)\) is the initial value of y. Thus, the solution to the differential equation is \(\(y(t) = 16 + e^{4t}(y_0 - 16)\)\), where \(\(y_0\)\) is the initial value of y.

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Answer: Well, it’s obviously not the first one. But if you could scroll down, so I could see the other graphs, that would be amazing. It would also help me answer the question!

Step-by-step explanation:

Answer:

10×10.70=$107 spent on cups

107-293=$186 spent on the jacket

so for the jackets 186= how many they got and much each cost.

u=186÷x

or 186=u the cost of each × x how many they got.

Answer:

AAS

Step-by-step explanation:

Answer:

41 degrees

Step-by-step explanation:

you get the inner angle by 180-125 which is 55 then you can find the angle by subtracting away all the other angles in the triangle so 180-55-68-16=41

Answer: 41

Step-by-step explanation:

180 - 125= 55

55 + 68 + (x + 16)= 180

123 + x + 16= 180

x= 41

Answer:

7/16

Step-by-step explanation:

To find the answer, simply just add the numbers together:

For the numerators:

4 + 3 = 7

For the denominators:

9 + 7 = 16

So, we have 7/16 because this cannot be simplified down anymore.

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Answer:

Exact Form:

55/63

Decimal Form:

¯¯¯¯¯¯¯¯¯¯¯¯

0.873015

Step-by-step explanation:

Step-by-step explanation:

Given f(x) = 5x - 7 and g(x) = x² - 3, find f(f(2))

Answer:

We have 6 cards.

9 of hearts

5 of spades

6 of hearts

2 of spades

4 of hearts

7 of hearts.

A is the event where Anwar selects an even numbered card.

B is the event where she choses a heart.

we have 3 even cards (and two of them are hearts)

we have 4 hearts (2 of them are even)

The probability of event A is Pa = 3/6 = 1/2

the probability of event B is = Pb = 4/6 = 2/3

The probability of event A and Event B is the number of heart cards with even numbers, that are 2 divided the total number of cards:

Paandb = 2/6 =  1/3

the probabilty of A if we know that B is true:

P(AIB) = 2/4 = 1/2 (this is because we have 4 hearts, and we know that 2 of those 4 cards are even)

the probability of B if we know that A is true:

P(BIA) = 2/3 (this is because we have 3 even cards, and 2 of them are hearts)

Answer:

A,B,C,E

Step-by-step explanation:

Khan.

TRUST ME!!!!!!!!!!!! THIS IS RIGHT!!!!!!!

Answer:

0.4987

Step-by-step explanation:

What we must do is calculate the z value for each value and thus find what percentage each represents and the subtraction would be the percentage between those two values.

We have that z is equal to:

z = (x - m) / (sd)

x is the value to evaluate, m the mean, sd the standard deviation

So for 80 we have:

z = (80 - 80) / (3)

z = 0

and this value represents 0.5

for 89 we have:

z = (89 - 80) / (3)

z = 3

and this value represents 0.9987

we subtract:

0.9987 - 0.5 = 0.4987

Which means that it represents 49.87%

ANSWER :

The height of the prism is h = 7 ft

The are of the base is B = 12 ft^2

The perimeter of the base is P = 18 ft

Fill in the formula. S = 2x12 + 18x7

The surface area of the triangular prism is 150 ft^2

EXPLANATION :

The given formula for the surface area is :

where B = Base area

P = perimeter of the bases

h = height of the prism

The height of the prism is h = 7 ft

The base is a triangle with dimensions of b = 8 ft and a height h = 3 ft

The area of a triangle is :

The are of the base is B = 12 ft^2

The perimeter of the base is 5 + 5 + 8 = 18 ft, so P = 18 ft

Substitute the results in the formula :

The solution of the given initial value problem, x'' + 33.64x = 4cos(6t), with x(0) = x'(0) = 0, can be expressed as a sum of the homogeneous solution and the particular solution.

To find the solution, we start by solving the homogeneous equation, x'' + 33.64x = 0. The characteristic equation associated with this homogeneous equation is \(r^2 + 33.64 = 0\), which yields the roots

r = ±i√33.64. Thus, the homogeneous solution can be expressed as

x_h(t) = A*cos(√33.64*t) + B*sin(√33.64*t),

where A and B are constants determined by the initial conditions.

Next, we need to find the particular solution for the forced oscillation. Since the right-hand side of the equation is of the form Acos(ωt), where ω = 6, we assume a particular solution of the form x_p(t) = C*cos(ω*t + φ), where C and φ are constants to be determined. Taking the derivatives, we have x_p''(t) = -ω^2*C*cos(ω*t + φ) and x_p'(t) = -ω*C*sin(ω*t + φ). Substituting these into the original equation, we obtain -ω^2*C*cos(ω*t + φ) + 33.64*C*cos(ω*t + φ) = 4*cos(ω*t).

To satisfy this equation, the coefficient of the cosine term must be 4, while the coefficient of the sine term must be zero. This gives us two equations: -ω^2*C + 33.64*C = 4 and -ω*C = 0. Solving these equations, we find C = 4/(33.64 - ω^2) and φ = 0. Therefore, the particular solution is x_p(t) = (4/(33.64 - ω^2))*cos(ω*t).

Finally, we combine the homogeneous solution and the particular solution to obtain the complete solution:

x(t) = x_h(t) + x_p(t) = A*cos(√33.64*t) + B*sin(√33.64*t) + (4/(33.64 - ω^2))*cos(ω*t).

By substituting the initial conditions x(0) = x'(0) = 0 into this equation, we can determine the values of A and B. With the obtained values, the final solution for the initial value problem can be expressed in terms of the given constants and the trigonometric functions involved.

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Answer:

5 6/7 or C option

Step-by-step explanation:

5 6/7 is equal to 5.857 and rounded it is 6

While all the others round to 5

Hopes this helps please mark brainliest

Answer:

the average speed of the car is 40 km in 1 hour

Step-by-step explanation:

Answer:

QUESTION:

answer 2x + 5 = 4x - 5

ANSWER:

Isolate the variable by dividing each side by factors that don't contain the variable.

x = 5

Step-by-step explanation:

Hope that this helps! :)

Have a great rest of your day/night!

Answer:

x = 5

Step-by-step explanation:

First you will need to add 5 to each side.

Then you need to subtract 2x to each side.

Lastly, you will need to divide each side by 2.

Answer:

Option B

Domain: all real numbers

Range \(f(x) \le -8\)

Step-by-step explanation:

Given function is:
\(f\left(x\right)=-\dfrac{5}{6}\:\left(x\:+\:2\right)^2\:-\:8\)

The domain is the set of all x values that result in a real and defined value for f(x).

The function has no undefined points and x is free to range from -∞ to +∞

So the domain is -∞ < x <∞ which is
All real numbers

The range is the set of all possible values for f(x) given a specific domain. In order to determine the range without too much hard work, let's first examine the function f(x)

The above function is the equation for a parabola.

Some things to note about a parabola equation:

Let us compare the general vertex form equation of the parabola with the specific f(x) equation given

General Equation:    \(a (x - h)^2 + k\)

This example:           \(-\dfrac{5}{6}\:\left(x\:+\:2\right)^2\:-\:8\)

Comparing the similarity between the two equations we easily see that

\(\boxed{a = -\dfrac{5}{6}}\)
This means the parabola opens downward and (h, k) represents a max point in the parabola

\(x - h = x + 2\\\\-h = 2\\\\h = -2\\\)

\(k = -8\)

So the vertex is at (-2, -8)

Since -8 is the maximum value for f(x), and the parabola extends to infinity on both sides, the range is :

\(\boxed{f(x) \le -8}\)

The attached graph may help you understand better