During the 3.00 s interval when the elevator's speed decreases at a rate of 0.550 m/s², the scale reading will be less than the true weight of an object inside the elevator.
The scale reading in an elevator measures the normal force exerted by the floor of the elevator on an object. When the elevator is in motion, there are additional forces acting on the object, such as the force of gravity and the acceleration or deceleration force.
In this case, the elevator is moving upward, but its speed is decreasing at a rate of 0.550 m/s² for 3.00 s. This means that the elevator is experiencing a deceleration.
During deceleration, the normal force exerted by the elevator floor on the object will be less than the object's true weight. This is because the deceleration force reduces the net force acting on the object and therefore reduces the normal force. The scale reading will reflect this reduced normal force.
To calculate the scale reading, we need to consider the forces acting on the object. The two main forces are the force of gravity (mg) and the normal force (N).
Since the elevator is decelerating, we can write the equation of motion for the object as:
mg - N = ma
In this case, the acceleration (a) is -0.550 m/s² (negative because it's in the opposite direction of motion), and the mass (m) is the mass of the object.
To find the scale reading (N), we rearrange the equation as:
N = mg - ma
Substituting the given values and solving for N will give us the scale reading during the 3.00 s interval when the elevator's speed is decreasing at a rate of 0.550 m/s².
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A Saturn V Moon rocket has a mass at lift-
off of 3.0 x 106 kg. The thrust at lift-off is
3.3 × 107 N. Find:
a) the weight of the rocket on Earth
b) the resultant (unbalanced) force at lift-off
c) the acceleration at lift-off
d) the apparent weight of the rocket in orbit.
Explanation:
a) weight = m * g = 3 x 10^6 kg * 10 m/s^2 = 3.0 x 10^7 N
b) Thrust - weight = 3.3 x 10^7 N - 3.0 x 10^7 N = 3 x 10^6 N
c) F = ma 3. x 10^6 = 3 X 10^6 * a solve for 'a' = 1 m/s^2
d) weightless (but not massless)
Consider a turbojet engine mounted on a stationary test stand at sea level. The inlet and exit areas are t 1.0 atm, and 800 K respectively Calculate the static thrust of the engine
a.) Thrust-31880N
b.) Thrust 32680N
c.) Thrust -31600N
d.) Thrust- 3868 N
The static thrust of the turbojet engine mounted on a stationary test stand at sea level, with inlet and exit areas at 1.0 atm and 800 K respectively, is b.) Thrust 32680N.
To calculate the static thrust of the engine, we can use the ideal rocket equation:
Thrust = mass flow rate * exhaust velocity
The mass flow rate can be calculated using the equation:
mass flow rate = air density * inlet area * inlet velocity
The exhaust velocity can be approximated as the exit area times the exit velocity.
Given that the engine is mounted on a stationary test stand at sea level, we can assume the inlet velocity is zero. Additionally, we know the inlet and exit areas, as well as the atmospheric pressure at sea level.
By calculating the mass flow rate and the exhaust velocity using the provided information and plugging them into the ideal rocket equation, we arrive at the static thrust of approximately 32680N.
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volume is a geometrical quantity that depends on the dimensions of the object. the unit of volume (based on si unit of length) is
"The SI unit of volume is based on the SI unit of length, which is known to be cubic metres."
Volume is a term used to describe the amount of space occupied by a three-dimensional form or item. A cube's volume is equal to the cube of its third side's length. For instance, a cube whose edge length is 5 cm will have the following volume:
V = 5 × 5 × 5 cm equals 125 cubic cm
A solid's volume, which includes its length, area, and volume, is often expressed in cubic units. The volume of any object will be given in cubic metres, for instance, if the dimensions are given in metres. The International System of Units uses cubic metres as the default unit of volume. The same goes for different volume units, such as cubic centimetres, cubic inches, cubic feet, etc.
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A spring-mass oscillator with negligible friction has a 10 kg mass and a spring
constant of 20 N/m. When set in motion, what is the period of vibration when the
system is vertical and horizontal, respectively?
Answer: The period of vibration for both vertical and horizontal motion is 0.9867 s.
Explanation:
The period of a spring-mass oscillator can be calculated using the equation:
T = 2π * √(m/k)
where T is the period of vibration, m is the mass of the object attached to the spring, and k is the spring constant.
a) Vertical Motion:
When the system is vertical, the weight of the mass acts downward and is balanced by the upward force of the spring. The effective force acting on the mass is the force due to gravity, which is equal to the weight of the mass (mg), minus the force exerted by the spring (kx).
At the equilibrium position, the net force is zero, so we have:
mg - kx = 0
Solving for x, we get:
x = mg/k = 10 kg * 9.81 m/s^2 / 20 N/m = 4.905 m
The period of vibration is:
T = 2π * √(m/k) = 2π * √(10 kg / 20 N/m) = 0.9867 s
b) Horizontal Motion:
When the system is horizontal, the weight of the mass acts downward, but the spring force acts horizontally in the opposite direction.
At the equilibrium position, the net force is zero, so we have:
mg = kx
Solving for x, we get:
x = mg/k = 10 kg * 9.81 m/s^2 / 20 N/m = 4.905 m
The period of vibration is:
T = 2π * √(m/k) = 2π * √(10 kg / 20 N/m) = 0.9867 s
Therefore, the period of vibration for both vertical and horizontal motion is 0.9867 s.
the angular speed of an automobile engine is increased at a constant rate from 1200 rev/min to 3000 rev/min in 12 s. (a) what is
a) The angular acceleration of the automobile engine is 150 rev/min².
b) The engine makes 18360 revolutions during the 12 s interval.
(a) To find the angular acceleration of the automobile engine, we can use the formula:
α = (ω - ωᵢ) / t
where α is the angular acceleration, ω is the final angular speed, ωᵢ is the initial angular speed, and t is the time interval.
Substituting the given values, we get:
α = (3000 rev/min - 1200 rev/min) / (12 s) = 150 rev/min²
(b) To find the number of revolutions made by the engine during the 12 s interval, we can use the formula:
θ = ωᵢ t + (1/2) α t²
where θ is the angle traversed, ωᵢ is the initial angular speed, t is the time interval, and α is the angular acceleration.
Substituting the given values, we get:
θ = (1200 rev/min) (12 s) + (1/2) (150 rev/min²) (12 s)² = 18360 rev
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Complete question is:
The angular speed of an automobile engine is increased at a constant rate from 1200 rev/min to 3000 rev/min in 12 s.
(a) What is its angular acceleration in revolutions per minute-squared?
(b) How many revolutions does the engine make during this 12 s interval?
While operating at 120 volts, an electric toaster has a resistance of 15 ohms. The power used by the toaster is
Answer:
960 Watt
Explanation:
From the question,
Electric power = Voltage squared/Resistance
P = V²/R ..................... Equation 1
Where P = power, V = Voltage, R = Resistance
Given: V = 120 volts, R = 15 ohms.
Substitute these values into equation 1
P = 120²/15
P = 14400/15
P = 960 Watt
Question 5 of 25
Two point charges are separated by a distance d. The first has a charge of
+2e, and the second has a charge of +3e. How does the electric potential
energy of the +2e charge change if it is moved to a new position, so that it is
separated from the second charge by a distance of 4d?
(PE=
k= 9.00 x 10° Nm²/C²)
k9192
Y
O A. The new electric potential energy is
electric potential energy.
as strong as the original
B. The new electric potential energy is 4 times as strong as the
original electric potential energy.
C. The new electric potential energy is as strong as the iginal
electric potential energy.
16
D. The new electric potential energy is 16 times as strong as the
original electric potential energy.
Two point charges are separated by a distance d. The first has a charge of +2e, and the second has a charge of +3e. The new electric potential energy is the same as the original electric potential energy. (option C)
To determine how the electric potential energy of the +2e charge changes when it is moved to a new position, we need to consider the formula for electric potential energy and analyze the situation.
Electric potential energy formula:
The electric potential energy (PE) between two point charges is given by the formula PE = k * (q1 * q2) / r, where k is the electrostatic constant (k = 9.00 x 10^9 Nm²/C²), q1 and q2 are the charges of the two point charges, and r is the distance between them.
Original electric potential energy:
In the original position, the distance between the charges is d. Therefore, the original electric potential energy (PE_original) is given by PE_original = k * (2e * 3e) / d.
New position and distance:
In the new position, the distance between the charges is 4d. Therefore, the new electric potential energy (PE_new) is given by PE_new = k * (2e * 3e) / (4d).
Comparing the original and new electric potential energies:
To compare the two electric potential energies, we can simplify the expressions. By canceling out the common factors, we find that PE_new = PE_original.
Therefore, the new electric potential energy is the same as the original electric potential energy. Thus, the correct answer is C. The new electric potential energy is the same as the original electric potential energy.
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Which of these actions is an example of chemical weathering? A. Freezing water widens the cracks in rocks B. plant roots force their way into cracks and rocks and brake them C. oxygen an area eggs with our content in rocks causing them to change color D. strong winds peel soft rock away leaving hard rock behind
Answer:
A. freezing water widens the cracks in rocks
Explanation:
chemical weathering (from what i can tell anyways) is when water comes in contact with rocks and over time wears it down.
Acceleration of a particle on the x-axis is a=−v2 The initial position and velocity are x(0)=1,x(0)=2 Find the position, velocity, and acceleration as functions of time x(t),v(t),a(t)
Given, acceleration of a particle on the x-axis is a = -v². The initial position and velocity are x(0) = 1, x'(0) = 2. We have to find the position, velocity, and acceleration as functions of time x(t), v(t), a(t). We can use the formulas below to solve the given problem. Position as a function of time, x(t)To find the position as a function of time x(t), we need to integrate the given acceleration function with respect to time.taking negative sign common we get,a = -v²dv/dx = -v dv = -v dx dv/v² = -dx x = ∫ dx/x² + cputting limits and solving the integral.
we get,x = 1/(v + c₁)Taking derivative both side w.r.t t,x'(t) = (-1/(v+c₁)²) . dv/dtTo find the value of constant c₁, we use the initial velocity,x'(0) = 2 = (-1/(v(0)+c₁)²) . dv/dt(2/1) = dv/dt ..... (1)Integrating both sides of the above equation with respect to t, we getv(t) = -2t + Cwhere C is the constant of integration. Substituting the value of v(t) in the equation x = 1/(v + c₁), we getx(t) = 1/(-2t + C + c₁)Velocity as a function of time, v(t).
The velocity as a function of time, v(t) is given byv(t) = -2t + C, where C is the constant of integration.Initial velocity is v(0) = -2(0) + C = C = 2Substituting this value in the above equation, we getv(t) = -2t + 2Acceleration as a function of time, a(t)Acceleration as a function of time is given bya(t) = -v²(t) = -(-2t+2)²= -(4t² - 8t + 4)= -4(t² - 2t + 1) = -4(t-
1)²Therefore, Position as a function of time, x(t) is x(t) = 1/(-2t + C + c₁).Velocity as a function of time, v(t) is v(t) = -2t + 2.Acceleration as a function of time, a(t) is a(t) = -4(t-1)².
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if load is 10 kn, cross sectionl area is 2 square mm, contact area = 5 square mm. what will be bearing stress?
The bearing stress in this scenario is 2 kN/mm². To calculate the bearing stress, we need to use the formula:
Bearing Stress = Load / Contact Area
Substituting the given values:
Bearing Stress = 10 kn / 5 square mm
Bearing Stress = 2 N/mm^2
It is important to note that bearing stress is a measure of the force per unit area exerted on the contact surface between two components. In this case, the load is distributed over an area of 5 square mm, resulting in a bearing stress of 2 N/mm^2. It is important to ensure that the bearing stress is within the allowable limits to prevent failure or damage to the components.
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How is data recorded in science?
Answer:
Yes
Explanation:
You need data to be able to compare experiments and come up with predictions.
Write a paragraph to describe seafloor spreading and subduction? Use all of the words
-Mountains + Boundary
-Oceanic crust
-Divergent boundary
-Continental boundary
-Convergent boundary
-creates new crust
-destroys old crust
-mid-ocean rigde
Tectonic plates, which are huge slabs of the Earth's lithosphere, split apart from one another during the geologic process known as seafloor spreading.
When two continental plates collide and slip under one another, this process is known as subduction.
At divergent plate borders, seafloor spreading happens. Heat from the convection currents in the mantle causes the crust to become less thick and more flexible when tectonic plates slowly drift apart from one another. Less dense material rises, frequently creating a mountain or elevated portion of the seafloor.
Large mountain ranges that rise from the ocean floor, known as mid-ocean ridges, are where seafloor spreading occurs. Seafloor spreading causes the Mid-Atlantic Ridge to form in the Atlantic Ocean.
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4) An astronaut drops a hammer from 2.0 meters above the surface of the
moon. If the acceleration due to gravity on the moon is 1.62 m/s2, how long
will it take for the hammer to fall to the Moon's surface? (Show your work)
Answer: The time, t, is approximately 1.57 seconds
Explanation:
The data we have from the question;
Displacement = 2.0 meters
Acceleration due to gravity on the moon = 1.62
Initial velocity = 0 m/s
We can use the second equation of motion for this one;
S = ut + 1/2at²
Where:
- S is the displacement.
- u is the initial velocity.
- a is the acceleration.
- t is the time measured in seconds.
We are now ready to substitute;
2 = 0(t) + 1/2(1.62)t²
==> 2 = 0 + 0.81t²
==> 2/0.81 = 0.81t²/0.81
==> \(\sqrt{2.47}\) = \(\sqrt{t ^{2}\)
==> The time, t, is approximately 1.57 seconds
Hope this helped! Have a good day :D
What do you think causes such change in wave velocity?
Answer:
The velocity of a wave is equal to the product of its wavelength and frequency (number of vibrations per second) and is independent of its intensity. ... Longitudinal waves, such as sound, are transmitted through media with velocities depending on the density and elasticity of the substance
a boat takes 3.40 hours h o u r s to travel 30.0 km k m down a river, then 5.30 hours h o u r s to return. part a how fast is the river flowing? express your answer with the appropriate units.
The speed of the stream when the distance and time taken to travel are given is calculated to be 1.41 km/h.
A boat takes 3.4 hrs to travel 30 km.
It takes 5 hrs to return through same distance.
The speed of the boat during the downstream is, v + u = D/t
where,
v is the speed of the boat
u is the speed of the stream
D is the total distance
t is the time
v + u = 30/3.4 = 8.82 km/h
v = (8.82 - u) km/h
The speed of the boat upstream is given as, v - u = D/t
Substituting the values into the above equation,
v - u = D/t
(8.82 - u) - u = 30/5
8.82 - 2 u = 6
2 u = 8.82 - 6
2 u = 2.82
u = 1.41 km/h
Thus, the speed of the stream is calculated to be 1.41 km/h.
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horizontal angulation is a. determined by the stabe bite-block. b. correct when the central ray is parallel to the curvature of the arch. c. the side-to-side angulation. d. different when using the paralleling and bisecting techniques.
The location of the tubehead and the central ray's direction in a horizontal, or side-to-side, plane are referred to as horizontal angulation. Whether you use the paralleling or bisecting technique, the horizontal angulation stays the same.
How does vertical angulation work?The recorded image's length is determined by vertical angulation. When employing the paralleling technique and receptor holders, the holding device determines the vertical angulation, which causes the x-ray beam to be directed perpendicular to both the receptor and teeth.
What distinguishes vertical from horizontal angulation?Angles in the vertical: The long axis of the tooth and the film should both be perpendicular to the central ray of the x-ray beam. Horizontal angulation: Pass the x-ray beam's central ray via the contact points where the teeth are located.
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When energy is transformed, some is used, but most is released as unusable heat energy, according to the law of thermodynamics.
Rainwater contains dissolved substances that allow it to conduct electricity. Why would you not be
electrocuted if you walked under an electric transmission line during a rainstorm?
As the raindrops do not provide a continuous path to flow the electrons because the air between the rain droplets acts as an insulator, therefore, the person walking under an electric transmission line would not be electrocuted.
What is a electrical conductor?In physics, a conductor can be described as a type of material that allows the flow of charge in one or more directions. Electric current is produced by the flow of negatively charged electrons or ions in some cases.
Raindroplets have dissolved impurities which make them somewhat conductive of electricity, but conductors should be continuous to create a conducting path at normal voltages.
The electric current can only flow when there is a continuous path of conductive material providing a conductor for electrons to travel through. The continuous flow of electrons needs to be an unbroken path to allow it to flow.
Since the air can be considered an insulating material and an air gap separates prevents a continuous path has been broken therefore electrons cannot flow.
Therefore, due to the absence of the closed circuit, you would not be electrocuted during a rainstorm if you walked under an electric transmission line.
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find the direction of the dune of these two vectors
Given:
Vector A = 63.5 m at 90 degrees
Vector B = 101 m at 57.0 degrees
Let's find the direction of the sum of these two vectors.
To find the direction, let's first find the x- and y-components of the vectors.
• Vector A:
\(\begin{gathered} A_x=65.3cos90=0\text{ m} \\ A_y=63.5sin90=63.5\text{ m} \end{gathered}\)• Vector B:
\(\begin{gathered} B_x=101cos57.0=55\text{ m} \\ B_y=101sin57=84.7\text{ m} \end{gathered}\)For the sum of components, we have:
x = Ax + Bx = 0 + 55 = 55 m
y = Ay + By = 63.5 + 84.7 = 148.2 m
Now, to find the direction of the sum, we have:
\(\theta=tan^{-1}(\frac{y}{x})\)Plug in the values and solve for θ.
We have:
\(\begin{gathered} \theta=tan^{-1}(\frac{148.2}{55}) \\ \\ \theta=69.6^o \end{gathered}\)Therefore, the direction of the sum of the vectors is 69.6 degrees.
ANSWER:
69.6 degrees.
A man pulls a sled at a constant velocity across a horizontal snow surface. If a force of 85 N is being applied to the sled rope at an angle of 56° to the ground, what is the force of friction between sled and snow?A. 85 NB. 70 NC. 48 ND. 5 NE. 43 N
The force of friction between sled and snow 43 N.The correct answer is E. 43 N.
To solve this problem, we need to use trigonometry to find the horizontal and vertical components of the force being applied to the sled. The horizontal component of the force is given by:
Fhorizontal = Fapplied x cos(θ)
where Fapplied is the force being applied (85 N) and θ is the angle between the force and the ground (56°).
Plugging in the values, we get:
Fhorizontal = 85 N x cos(56°)
Fhorizontal ≈ 48 N
Since the sled is moving at a constant velocity, the force of friction must be equal and opposite to the horizontal component of the applied force.
Therefore, the force of friction is 48 N. Choice E. 43 N
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how freezing could be used to remove sugar from a mixture of sugar and water.
If 100.0 g of carbon-14 decays until only 25.0 g of carbon is left after 11 460 y, what is
the half-life of carbon-14?
Answer:
5730 yr
Explanation:
25 = 100 (1/2)^11460/x where x = half life
.25 = (1/2)^11460/x
log .25 / log.5 = 11460/x
x = 5730 yr
imagine holding two identical bricks in place under water. brick 1 is just beneath the surface of water, while brick 2 is held about 2 feet down. the force needed to hold brick 2 in place is
Holding Brick 2 in place requires more force than holding Brick 1 just beneath the water's surface due to the higher pressure and buoyant force acting on it at a greater depth.
The force needed to hold Brick 2 in place underwater is greater than the force needed to hold Brick 1 just beneath the surface. This difference in force is primarily due to the increased pressure acting on Brick 2 as a result of its deeper position in the water.
In this scenario, there are two main forces acting on the bricks: the gravitational force, also known as weight (W), and the buoyant force (Fb). The weight of the bricks remains constant regardless of their position, as it depends only on their mass and the acceleration due to gravity. The buoyant force, on the other hand, depends on the volume of fluid displaced by the bricks and the density of the fluid, which in this case is water.
The pressure in a fluid increases with depth, which means that the buoyant force acting on Brick 2 is greater than that acting on Brick 1. Consequently, to keep Brick 2 submerged at a depth of 2 feet, you would need to exert a greater force to counteract the increased buoyant force.
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9.4 million km in light year.
Hey there!
Answer:
9.4 million kilometers (km) converted to light years would be 9.93580784e-7 I believe.
Hope this helps!
The measurement of an object's mass is a
For most everyday objects, scientists use a balance to obtain an object's mass. A balance compares an object with a known mass to the object in question. One example of a balance is the triple beam balance.
thuli wants to buy tv for R8500.a bank offers to loan her the money at an interest rate of 5%.she decides to pay the tv off in 3 years calculate the simple interest she will have to pay .also calculate the total she will pay
Answer:
The total she has to pay is R8500 plus the 5% interest.
PLEASE ADD BRAINEEST
what is the correct answer?
The effective resistance of the Parallel circuit is 3 ohms.
option B.
What is the effective resistance of the circuit?
In a parallel circuit, the sum of the currents through each path is equal to the total current that flows from the source.
The total resistance or effective resistance in a Parallel circuit with the following formula:
1/Rt = 1/R1 + 1/R2
where;
Rt is the effective resistanceR1 is the resistance of the first resistorR2 is the resistance of the second resistor1/Rt = 1/4 + 1/12
1/Rt = (3 + 1 ) / 12
Rt = ( 12 ) / ( 4 )
Rt = 3 ohms
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A 0.150-kg rubber stopper is attached to the end of a 1.00-m string and is swung in a circle. If the rubber stopper is swung 2.3 m above the ground and released, how far will the stopper travel horizontally before hitting the ground?
The stopper travels approximately 4.5 meters horizontally before hitting the ground.
We can use conservation of energy to solve this problem. At the highest point of the stopper's motion, all of its energy is in the form of potential energy, and at the lowest point (when it hits the ground), all of its energy is in the form of kinetic energy.
The potential energy of the stopper at the highest point is:
Ep = mgh
where m is the mass of the stopper, g is the acceleration due to gravity, and h is the height above the ground. Plugging in the values given in the problem, we get:
Ep = (0.150 kg) * (9.81 m/s²) * (2.3 m) ≈ 3.2 J
At the lowest point, all of the potential energy has been converted to kinetic energy:
Ek = (1/2) * mv²
where v is the speed of the stopper just before it hits the ground. Since the stopper is released from rest, we can use conservation of energy to equate the potential energy at the highest point to the kinetic energy just before hitting the ground:
Ep = Ek
mgh = (1/2) * mv²
Solving for v, we get:
v = √(2gh)
where h is the height from which the stopper was released. Plugging in the values given in the problem, we get:
v = √(2 * 9.81 m/s² * 2.3 m) ≈ 6.6 m/s
Now we can use the time it takes for the stopper to fall to the ground to calculate the horizontal distance it travels. The time is given by:
t = √(2h/g)
Plugging in the values given in the problem, we get:
t = √(2 * 2.3 m / 9.81 m/s²) ≈ 0.68 s
During this time, the stopper travels a horizontal distance given by:
d = vt
Plugging in the values we just calculated, we get:
d = (6.6 m/s) * (0.68 s) ≈ 4.5 m
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In an inverse relationship which one variable increases the other?
Answer:
as A increases, B decreases, and as B increases, A increases. Hope this helps!
Explanation:
Compare and contrast the electric forces with the gravitational force.
please help, i need this asap
Answer:
They both act between two bodies without any means of contact. However gravitational force acts on mass while the electric force acts on charge. Gravitational force are only attractive while electric field can be attractive/repulsive. Electric field is much stronger than gravitational field.
Explanation: