would you expect manganese(ii) oxide, mnomno , to react more readily with hf(aq)hf(aq) or naoh(aq)naoh(aq) ? would you expect manganese(ii) oxide, , to react more readily with or ? hf(aq)hf(aq) naoh(aq)naoh(aq) they react equally cannot be determined

Answer:

Balanced forces do not cause a change in motion.

The result is no motion. Balanced forces can cancel each other out. Any time there is a balanced force, the object does not move.

Explanation:

Answer:

The result is no motion. Balanced forces can cancel each other out. Any time there is a balanced force, the object does not move.

Explanation: MARK MOST BRAINLIEST PLEASE

According to the graph, only the reactant A was present at the beginning of the reaction.

The graph shows the concentration for the reactant A and the product that is A2. In this graph, the concentration is displayed on the vertical axis, while the horizontal axis shows the time.

In general terms, it can be observed that at the beginning only the reactant A is present, but as the reaction occurs the concentration of this reactant decreases, while the concentration of the product A2 increases.

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Answer: It is B.) 1s^22s^12p^1

Explanation: mind giving me brainliest? :)

Answer:

ñanamaisañia ñanamaisañia

Explanation:

n

Answer:

it have been already balanced

2H2 + O2 = 2H2O.

Answer:

thank u for the points

Explanation:

The first one needs 5 sample values and the second one needs 15 sample values to exactly describe the bandlimited periodic signals.

(a) x(t)= 8+3cos(8πt )+ 9sin(4πt )

The period of this signal should be the least common multiple of 1/4 (the period of cos(8πt)) and 1/2 (the period of sin(4πt)), which yields T0=1/2 s. By frequency analysis,we can find fm= 4Hz , so fNyq=2fm=8 Hz . In order to exactly describe the signal,sampling frequency fs should larger than Nyquist rate fNyq . Within a period of 1/2s, sample values should larger than T0fNyq=(1/2)*8=4 and must be a integer, which yields to 5. So we need 5 samples within one period of T0=1s and s=5/T0= 10Hz.

(b) x(t)= 8+3cos(7πt )+ 9sin(4πt )

Similar to the part(a),The period of this signal T0  should be the least common multiple of 2/7 (the period of cos(7πt)) and 1/2(the period of sin(4πt)), which yields T0=2s. By frequency analysis,we can find fm= 3.5Hz , so fNyq=2fm=7Hz. In order to exactly describe the signal,sampling frequency fs should larger than Nyquist rate fNyq . Within a period of 2s, sample values should larger than T0fNyq=2*7=14 and must be a integer, which yields to 15. So we need 15 samples within one period of T0=2s and 15/T0= 7.5Hz.

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Opinion and  and factless ideas  are not science and engineering practice as these are based on observations.

Observations are defined as a set of statements or facts which are recorded while conducting an experiment.Observations are made through sensing changes in the variables of the experiment.

It is specifically defined as an act of knowing or recording the changes in the variables of the experiment.Recording observations holds importance as recording observations avoid the experiment to be repeated over and over again.

It is important to note down observations so that the testing of hypothesis is made easier.There are four types of observations .Observations need to be descriptive and must be written in complete sentences and should include all the numerical data of the experiment.

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Answer:

Salt is any neutral chemical compound made of cations (positive ions) attached to anions (negative ions). The main kind of salt is sodium chloride with the chemical formula NaCl. It is formed when hydrochloric acid is added in sodium hydroxide.

The rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

To determine the rate of change of the concentration of sodium oxalate (Na₂C₂O4), we can use the rate equation:

Rate = (Δ[Na₂C₂O4]) / (Δt)

where Δ[Na₂C₂O4] represents the change in concentration of Na₂C₂O4 and Δt represents the change in time.

In this case, the initial concentration of Na₂C₂O4 is 1.34 M, and after 19.3 seconds, the concentration is 0.276 M.

Substituting the values into the rate equation, we have:

Rate = (0.276 M - 1.34 M) / (19.3 s - 0 s)

Rate = (-1.064 M) / (19.3 s)

Rate = -0.0551 M/s

Therefore, the rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

The negative sign indicates that the concentration of Na₂C₂O4 is decreasing over time, as the reactant is being consumed in the reaction.

It's important to note that the rate of a reaction is influenced by various factors, such as the reaction mechanism, temperature, and presence of catalysts. The rate can be determined experimentally by measuring the change in concentration of a reactant or product over a specific time interval.

The given information allows us to calculate the rate of change for the specific reaction involving Na₂C₂O4. However, without additional information about the reaction, it is not possible to determine the exact nature or stoichiometry of the reaction, as well as any other reactants or products involved.

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2.5 mmol/mL of HCl stock is needed so that 2.5 ml of this stock diluted to 0.025 l will yield 25 mm.

Given the volume of HCl (V1) = 2.5mL

Let the concentration of HCl = M1

The volume of solvent (V2) = 0.025L = 25mL

The concentration of solvent (M2) = 25mm = 0.025M

Molarity of the HCl stock = (25 mmol/0.025 L) x (2.5 mL/1000 mL) = 2.5 mmol/mL.

Molarity is a unit of concentration which measures the amount of a substance present in a given volume of solution. It is expressed as moles of solute per liter of solution (M/L).

Therefore,  2.5 mmol/mL HCl stock solution is needed to yield 25mM.

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The mass of \(Al_{2} S_{3}\) produced is 15.616 grams.

The reaction taking place is as follows:

\(2Al+ 3S\) →\(Al_{2} S_{3} (s)\)

Moles of Al = mass/molar mass = 10.0g/27.0g/mol

= 0.370 mol

Moles of S = mass/molar mass = 15.0g/(32.065g/mol)

= 0.468 mol

Al and S reacts in the molar ratio of 2:3.

2 moles of Al reacts with 3 moles of S

0.370 moles of Al will react with S = (3/2)*0.370mol

= 0.555 mol

Similarly, 0.468 moles of S will react with Al = 2/3 *0.468mol

= 0.312 mol

Thus, Al is in excess and S is the limiting reactant (some of Al will be left over ,S will completely react)

So, moles of \(Al_{2} S_{3}\) produced=1/3*0.312 mol of S

= 0.104 mol

Mass of \(Al_{2} S_{3}\) produced = moles*molar mass of \(Al_{2} S_{3}\)

= 0.104mol*150.158g/mol

= 15.616 grams

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Answer:

b

Explanation:

Answer:

D) C5H12

Explanation:

In order to answer this question, we must have to take our minds back to the idea of intermolecular forces. These are forces of attraction that exist between molecules of a substance.

C7H15OH, C7H15NH2 and C6H13COOH are polar molecules that are held together by hydrogen bonds in addition to dispersion forces hence they all have a slower rate of evaporation than the other two compounds that remain from the list.

We are now left with two compounds in the list; C7H16 and C5H12. The both compounds are only held together by weak dispersion forces(the are both alkanes). The magnitude of dispersion forces increases as the molar mass of the compound increases.

Hence, C5H12 evaporates the most quickly than the other substances because it has the least degree of intermolecular interaction between its molecules.

The pressure in the container is 20.6 atm.

In a chemical reaction, the pressure is the force exerted by the molecules on the walls of the container in which the reaction is taking place. The pressure of a gas is directly proportional to the number of gas molecules present in the container.

According to the kinetic molecular theory of gases, the pressure of a gas is determined by the number of collisions that occur between gas molecules and the walls of the container.

When a chemical reaction occurs, the number of gas molecules in the container may change, leading to a change in pressure. For example, if a gas is produced during a chemical reaction, the pressure in the container will increase as the number of gas molecules increases.

Conversely, if a gas is consumed during a chemical reaction, the pressure in the container will decrease as the number of gas molecules decreases.

The balanced chemical equation for the reaction is:

\(\begin{equation}\mathrm{CaCO_3 (s) \rightarrow CaO (s) + CO_2 (g)}\end{equation}\)

According to the equation, one mole of CaCO3 produces one mole of CO2 at the same temperature and pressure. The molar mass of CaCO3 is 100.1 g/mol. Thus, the number of moles of CaCO3 is:

\(\begin{equation}n_{\mathrm{CaCO_3}} = \frac{50.0\, \mathrm{g}}{100.1\, \mathrm{g/mol}} = 0.499\, \mathrm{mol}\end{equation}\)

Since all the CaCO3 reacts, the number of moles of CO2 produced is also 0.499 mol. The ideal gas law can be used to find the pressure of CO2:

\(\begin{equation}PV = nRT\end{equation}\)

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. Rearranging the equation to solve for P, we get:

\(\begin{equation}P = \frac{nRT}{V}\end{equation}\)

Substituting the values gives:

\(\begin{equation}P = \frac{(0.499\, \mathrm{mol})(0.0821\, \mathrm{\frac{L\, atm}{mol\, K}})(500\, \mathrm{K})}{5.0\, \mathrm{L}} = 20.6\, \mathrm{atm}\end{equation}\)

Therefore, the pressure in the container is 20.6 atm.

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1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d³ or [Ar] 4s²3d³

Given

Vanadium, atomic number 23

Required

The electron configuration

Solution

In an atom, there are levels of energy in the shell and subshell  

This energy level is expressed in the form of electron configurations.  

Charging electrons in the subshell uses the following sequence:  

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.  

The electron configuration is based on the atomic number which indicates the number of electrons of the atom

Vanadium has the atomic number 23, so the number of electrons = 23

Electron configuration:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d³

or we can write it using the noble gas notation

[Ar] 4s²3d³

Answer:

A)

Explanation:

Entre todos esas materias el hidrógeno es el más fuerte

Reaction B releases more energy than reaction A releases.The correct option is B)

The energy released by these reactions can be evaluated using the concept of nuclear binding energy. Nuclear binding energy is defined as the amount of energy required to break up a nucleus into its individual nucleons (protons and neutrons). This energy is a measure of the strong nuclear force that holds a nucleus together.

Reaction A involves the formation of a sodium chloride molecule by the transfer of one electron from a sodium atom to a chlorine atom. The energy released in this reaction is due to the formation of ionic bonds between the positively charged sodium ion and negatively charged chloride ion.

The energy released in this reaction is relatively low compared to nuclear reactions.In contrast, reaction B involves the decay of an oxygen isotope to form a nitrogen isotope, releasing a large amount of energy. The decay of an isotope involves the spontaneous breakdown of its nucleus due to a variety of factors.

This process releases a large amount of energy in the form of radiation and kinetic energy of the decay products.The energy released by nuclear reactions is much larger than that released by chemical reactions, such as reaction A. Therefore, option B, Reaction B releases more energy than reaction A releases, is the best description of the energy released per gram by these reactions.

Option B
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Answer:

i think it is D

Explanation:

i dont know what you are learning but ecological succession is the change of enviroment pretty much.

Answer:

concentrated B ...............

The oxidation of benzaldehyde to the corresponding carboxylic acid leads to the formation of benzoic acid.

The oxidation of benzaldehyde to benzoic acid is the conversion of the aldehyde group (–CHO) to a carboxyl group (–COOH). This oxidation is commonly carried out using an oxidizing agent such as potassium permanganate or chromic acid.

When benzaldehyde is oxidized, the aldehyde group undergoes oxidation, resulting in the addition of an oxygen atom to form a carboxyl group. The product, benzoic acid, retains the benzene ring from benzaldehyde.

In this reaction, [O] depicts the oxidizing agent, which provides the necessary oxygen atom for the oxidation process.

The resulting product, benzoic acid, has a carboxyl group (–COOH) attached to the benzene ring. It is a white crystalline solid at room temperature and is commonly used as a food preservative, as well as in the production of various chemicals and pharmaceuticals.

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Answer:

The correct answer is B. 1-propanamine.

Explanation:

Amines can form hydrogen bonds with water molecules, which makes them soluble in water. The more hydrogen bonding sites an amine has, the more soluble it will be in water.

Out of the given options, 1-propanamine has only one carbon chain, which allows it to form more hydrogen bonds with water molecules compared to amine molecules with longer carbon chains. Also, it does not have any other functional groups that could interfere with hydrogen bonding. Therefore, 1-propanamine would be the most soluble in water.

Hope it helps!

We should only carry out terrace farming on the sloppy land.​ This is the type of farming done on slope land

Terrace farming is a method of farming where steps (terraces) are built into the slopes of a hill or mountain to create flat surfaces for cultivation. This technique is commonly used in areas with steep slopes or hills where traditional flat farming is not feasible.

The terraces help to prevent soil erosion, improve water retention, and make it easier to cultivate crops. Terrace farming has been used for centuries by various civilizations around the world, including the Incas in South America and the rice farmers of Southeast Asia.

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Answer:

0.8833 mole of C3H8

Explanation:

Given:

Mass of C₃H₈ (Propane) = 38.95 gram

Computation:

Molar mass of C = 12.01

Molar mass of H = 1.008

Molar mass of C₃H₈ (Propane) = 3(12.01) + 8(1.008)

Molar mass of C₃H₈ (Propane) = 36.03 + 8.064

Molar mass of C₃H₈ (Propane) = 44.094

Number of mol in 38.95 gram Propane = Mass / Molar mass

Number of mol in 38.95 gram Propane = 38.95 / 44.094

Number of mol in 38.95 gram Propane = 0.88334

Answer:

Use the Periodic Table to find molar masses.

Propane (C3H8), a common fuel, reacts with oxygen to form carbon dioxide and water according to the equation below:

C3H8 + 5O2 → 3CO2 + 4H2O

If a propane heater burns 38.95 g C3H8, it consumes

38.95 mol C3H8.

0.8830 mol C3H8.

1 mol C3H8.

44.10 mol C3H8.

Part 2

How many moles of oxygen are required to produce 37.15 g CO2?

37.15 g CO2 = 1.407 mol O2

Part 3

What mass of propane is necessary to react with the amount of oxygen calculated in the previous question?

12.41   g C3H8    

The baking of a pizza is categorized as an endothermic process because the dough absorbs heat. Therefore, option D is correct.

An endothermic process is a process that absorbs heat from the surroundings. In an endothermic process, the system gains energy from the surroundings, usually in the form of heat. This energy is used to break bonds within the system or to convert a solid or liquid into a gas.

Examples of endothermic processes include:

Thus, option D is correct.

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Measuring tool would you use to measure the area of a football field is used a tender wheel

If you need to measure much longer lengths for example the length of a football pitch then you could use a trundle wheel then you use it by pushing the wheel along the ground and it clicks every time it measures one meter and to measure the football field area then

Area = length×breadth

Area = 90m×45m

Area = 4.05m²

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So, at STP, there are around 891 grammes of nitrogen gas in every 759 litres.

The two stable isotopes of naturally occurring nitrogen (7N) are nitrogen-14 and nitrogen-15, with nitrogen-14 constituting 99.6% of all naturally existing nitrogen. Along with one nuclear isomer, 11mN, fourteen radioisotopes with atomic masses ranging from 10 to 25 are also known.

Assuming "ST" refers to standard temperature and pressure (0°C and 1 atm), we can use the ideal gas law to calculate the mass of nitrogen gas:

PV = nRT

where n is the number of moles, P is the pressure, V is the volume, and T is the temperature, and R is the gas constant.

The temperature and pressure are 273.15 K and 1 atm, respectively, at STP.

To solve for n, the number of moles, we can rearrange the ideal gas law equation as follows:

n = PV / RT = (1 atm) * (759 L) / (0.0821 L·atm/(mol·K) * 273.15 K) = 31.8 mol

Now we can calculate the mass of nitrogen gas:

mass = n * molar mass = 31.8 mol * 28.01 g/mol ≈ 891 g.

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The correct choice is A) −5Δ[Br−]/Δt. The rate expressed as Δ[Br2]/Δt is proportional to -5 times the rate of change of Br−.

In the given reaction 5Br−(aq) + BrO3−(aq) + 6H+(aq) → 3Br2(aq) + 3H2O(aq), the stoichiometric coefficients provide information about the relationship between the reactants and products. To determine the rate expressed as Δ[Br2]/Δt, we need to compare it with the rate of change of the other species.

Based on the balanced equation, for every 5 moles of Br− consumed, 3 moles of Br2 are produced. Therefore, the rate of change of Br−, Δ[Br−]/Δt, is related to the rate of change of Br2, Δ[Br2]/Δt, by a factor of -5/3.

The other choices, B) −0.6Δ[Br−]/Δt, C) 3Δ[BrO3−]/Δt, and D) −Δ[H2O]/Δt, do not correspond to the correct relationship based on the stoichiometric coefficients of the reaction. Therefore, the correct answer is A) −5Δ[Br−]/Δt.

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Answer:

A

Explanation:

A solid that dissolves in water produce alkaline solutions

ex. sodium reacts with water to form sodium hydroxide – caustic soda

Answer:

the answer is O²- hopefully