Write the word as an equation
2 1/2 is the same as the sum of the number w and 1/2
An equation that represents this sentence is...

The equations will be solved by putting the values of the variables in the bracket.

1. (b + a) = 4; use a = 1 and b = 3

( 1 + 3) = 4

2) c(b + b); use b = 1 and c = 5

5(1 + 1)

= 5 × 2 = 10

3) 4+ pm; use m = 4 and p =3

= 4 + (4 × 3)

= 4 + 12

= 16

4) 5+ pm; use m = 4 and p = 2

= 5 + (2 × 4)

= 5 + 8

= 13

5) m(p + 2); use m = 5 and p = 2

= 5(2 + 2)

= 5 × 4

= 20

6) h+j²; use h = 1 and j = 4

= 1 + 4²

= 17

7) y-(x - 5); use x = 5 and y = 6

= 6 - (5 - 5)

= 6 - 0

= 6

8) 4xy; use x = 5 and y = 2

= 4 × 5 × 2

= 40

9) n(p + 3); use n = 2 and p = 2

= 2(2 + 3)

= 10

10) y +x+x; use x = 3 and y=5

= 5 + 3 + 3

= 11

11) 6+ a-b; use a = 4 and b = 4

= 6 + 4 - 4

= 6

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The statement is true about the home appliances sales is "Home appliances sales increased profits by 8 percentage points".

Given that ,

The right answer is that 90% of all random samples of 50 students from this high school would produce a 90% confidence interval that contains the actual mean amount of money students spend on lunch.

an appliance store manager noted that the sales of home appliances contributed

74 % of the store profits in the year 2010, and 82 % in the year 2011.

Thus, the profit in the year 2010 is 74 %.

The profit in the year 2011 is 82 %.

The increased profit from year 2010 to 2011 is ( 82-74 ) % = 8%

Hence, the statement true about the home appliances sales is "Home appliances sales increased profits by 8 percentage points".

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Answer:

There are a total of 25 marbles in the bag.

The probability of choosing a red marble first is 8/25 since there are 8 red marbles out of 25 marbles in the bag.

Since a marble is not replaced after the first selection, there are now 24 marbles in the bag. There are still 3 blue marbles in the bag.

The probability of choosing a blue marble second, after a red marble has already been selected, is 3/24 or 1/8 since there are 3 blue marbles left out of 24 marbles in the bag.

To find the probability of both events occurring together, we multiply their individual probabilities:

8/25 x 1/8 = 1/25

Therefore, the probability that a red marble is chosen first, followed by a blue marble, is 1/25.

Answer:

1 1/2

Step-by-step explanation:

Answer:

The answer is 5 ft squared

Step-by-step explanation:

so you have the find the area of the circle first and you do that by starting with the formula which is

pi r2

the diameter is 2.45 so you divide that by to to get the radius and get 1.25

the you would multiply 1.25 times 1.25 times 3.14, and get 4.91 which rounds to by the nearest whole umber as 5 ft 2.

Answer:

78

Step-by-step explanation:

250 - 172 = 78

Answer:

All of them are composite

Step-by-step explanation:

In math, composite numbers can be defined as the whole numbers that have more than two factors. Whole numbers that are not prime are composite numbers, because they are divisible by more than two numbers.

The item most likely to weigh 2 kilograms is a roast chicken.

The size, breed, and any other ingredients or stuffing used can all affect the weight of a roast chicken. Weights of roast chickens can range from petite ones weighing less than 1 kilogram to larger ones weighing more than 2 kilograms.

The other things that we have there would either weigh less than 2 Kg such as a tea bag or much more than 2 Kg such as a horse. The egg and the tea a very light and would be less than 2 Kg in weight while the bag and the horse would be above 2 Kg in weight.

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Answer:

idont konw but ask google

Step-by-step explanation:

57898765432345678909876543jgfhjfghjfhgjfgj

The total materials handling cost allocated to the modular homes is $246,372.84.

The total materials handling cost allocated to the Prefab Barns is closest to $108,000.

To allocate materials handling cost based on material moves, we must determine proportion of material moves for each product and then apply that proportion to the total materials handling cost.

Proportion of material moves for Modular Homes:

= (Total expected material moves for Modular Homes) / (Total expected material moves for both products)

= 590 / (590 + 190)

= 0.756

Total materials handling cost allocated to Modular Homes:

= Proportion of material moves for Modular Homes * Total materials handling cost

= 0.756 * $325,890

= 246 372.84

= $246,372.84.

To allocate the materials handling cost based on direct labor-hours, we need to determine proportion of direct labor-hours for each product.

For Modular Homes:

Total direct labor-hours for Modular Homes:

= 6,000 units * 800 hours/unit

= 4,800,000 hours

For Prefab Barns:

Total direct labor-hours for Prefab Barns:

= 9,000 units * 300 hours/unit

= 2,700,000 hours

Total direct labor-hours for both products:

= 4,800,000 hours + 2,700,000 hours

= 7,500,000 hours

Proportion of direct labor-hours for Prefab Barns:

= 2,700,000 hours / 7,500,000 hours

= 0.36

Allocated materials handling cost for Prefab Barns:

= Proportion of direct labor-hours for Prefab Barns * Total materials handling cost

= 0.36 * $300,000

= $108,000.

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The graph of f(x) relate to its parent function by B. The parent function has been translated up.

Given that

f(x) = 3x +2 +4

When evaluated, we have

f(x) = 3x + 6

The parent function of the above is

f(x) = 3x

When f(x) = 3x is compared to f(x) = 3x + 6, we have

Difference = 6

This means that the parant function is translated up by 6 units

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Answer:

Step-by-step explanation:

3y + 10 = -2y + 15

5y + 10 = 15

5y = 5

y = 1

x = 3(1) + 10

x = 3 + 10

x = 13

(13, 1)

Answer:

30k^2+55k+25

Step-by-step explanation:

30k^2+30k+25k+25

=30k^2+55k+25

\(30k { }^{2} + 30k + 25k + 25\)

\(30k ^{2} + 55k + 25\)

It takes time of near about 35 year.

Given that,

Storage capability of computers has been doubling every 5 years

The date of 1st computer made = 1980

computer could store 5 megabytes,

Now,

We can use the following calculation to determine how long it took computers to store 100 megabytes:

Therefore,

Log₂ (final amount / beginning amount)

=  Log₂ (100 / 0.5)

= log₂ (200)

= 7.64 is the number of doublings.

If each doubling takes five years, then it would take computers just over seven doublings or almost 35 years to store 100 megabytes.

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Answer:

it is 74389

Step-by-step explanation:

you do 74 + 094904

By the Mean Value Theorem, there exists a number c in (1, 7) such that ƒ'(c) = 2/c and 2/c = ln7 / 6, and c ≈ 0.909.

The Mean Value Theorem (MVT) states that if a function ƒ(x) is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists a number c in (a, b) such that:

ƒ'(c) = [ ƒ(b) - ƒ(a) ] / (b - a)

ƒ(x) = 2lnx - 8 is continuous on the closed interval [1, 7], since it is the sum and composition of continuous functions.

ƒ(x) = 2lnx - 8 is differentiable on the open interval (1, 7), since its derivative ƒ'(x) = 2/x is defined and continuous on (1, 7).

Therefore, the Mean Value Theorem can be applied to ƒ(x) on [1, 7]. To find the value of c, we need to solve the equation:

ƒ'(c) = [ ƒ(b) - ƒ(a) ] / (b - a)

Substituting the given values, we get:

2/c = [ 2ln7 - 2ln1 ] / (7 - 1)

2/c = ln7

c = 2 / ln7

c ≈ 0.909

Therefore, by the Mean Value Theorem, there exists a number c in (1, 7) such that ƒ'(c) = 2/c and 2/c = ln7 / 6, and c ≈ 0.909.

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Answer:

A could be a possible answer actually

The possible outfits that Casey can make is 30 and  this is shown in the image that is attached.

The tree diagram is known to be one that shows the hierarchical organization of tasks and subtasks that must be done to achieve a goal. The branching diagram start with a single element that divides into two or more, each of which further divides into two or more, and so forth.

Based on the question, Casey has:

5 shirts

3 skirts

2 blazers

Therefore, to make a tree diagram of any possible outfits that Casey can make.​, there are a total of:

5 x 3 x 2

= 30

So, the possible outfits that Casey can make is 30.

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Answer:

1/4+1/3+1/8

=17/24

Step-by-step explanation:

1-17/24

=7/24

7/24×240

=70

The turning points of the function y = x³ - 3x² - 9x + 4 are (3, -23) and (-1, 9).

To determine the turning points of the given function y = x³ - 3x² - 9x + 4, we need to find the critical points where the derivative of the function is equal to zero.

1. Find the derivative of the function:

  y' = 3x² - 6x - 9

2. Set the derivative equal to zero and solve for x:

  3x² - 6x - 9 = 0

3. Factorize the quadratic equation:

  3(x² - 2x - 3) = 0

4. Solve the quadratic equation by factoring or using the quadratic formula:

  (x - 3)(x + 1) = 0

  This gives us two possible values for x: x = 3 and x = -1.

5. Substitute these critical points back into the original function to find the corresponding y-values:

  For x = 3:

  y = (3)³ - 3(3)² - 9(3) + 4

    = 27 - 27 - 27 + 4

    = -23

  For x = -1:

  y = (-1)³ - 3(-1)² - 9(-1) + 4

    = -1 - 3 + 9 + 4

    = 9

6. Therefore, the turning points are (3, -23) and (-1, 9).

Note: It appears that there was a typo in the original equation, where the term "-9x" should have been "-3x²". The above solution assumes the corrected equation.

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The mean, mean deviation mode, median standard deviation, and coefficients of variation, CV, are as follows;

1. The mean deviation about the mean, median mode are;

2.653, 3.709, and 3.709, respectively

The coefficients of variation are;

0.364, 0.337, 0.337, respectively

The variance is about 9.462

The standard deviation is about 3.076

2. Section A has a higher relative dispersion than section B

3. City 2

4. a. Mean ≈ 43.85

b. Mode 40 - 54 inches

c. Median ≈ 45.16

The variance ≈ 125.8056

Standard deviation ≈ 11.216

Coefficient of variation ≈ 0.268

The coefficient of variation of a data quantifies or is a measure of the variability of the values in the set of data.

The mean for the data can be calculated as follows;

Mean  = (3×10 + 6×15 + 11×25 + 2×6 + 4×4 + 10×3 + 5×2 + 7×8 + 8×9 + 9×4)/(10+15+25+6+4+3+2+8+9+4) ≈ 7.29

The median is the 86/2 value = 43rd value

10 + 15 + 25 = 50

Therefore, the median is in the class with a frequency of 25, which is 11

The mode of the data, which is the value with the highest frequency in the data set is 11

The mean deviation from the mean is therefore;

(|3 - 7.29|×10 + |6 - 7.29|×15 + |11 - 7.29| ×25 + |2 - 7.29| ×6 + |4 - 7.29| ×4 + |10 - 7.29| ×3 + |5 - 7.29| ×2 + |7 - 7.29|×8 + |8 - 7.29| ×9 + |9 - 7.29| ×4)/(10+15+25+6+4+3+2+8+9+4) ≈ 2.653

The coefficient for the mean deviation about the mean is therefore; 2.653/7.29 ≈ 0.364

The mean deviation about the median is therefore;

(|3 - 11|×10 + |6 - 11|×15 + |11 - 11| ×25 + |2 - 11| ×6 + |4 - 11| ×4 + |10 - 11| ×3 + |5 - 11| ×2 + |7 - 11|×8 + |8 - 11| ×9 + |9 - 11| ×4)/(10+15+25+6+4+3+2+8+9+4)

The mean deviation about the median = 319/86 ≈ 3.709

The coefficient ≈ 3.709/11 ≈ 0.337

The median = The mean deviation about the mode ≈ 3.709

The coefficient is about 0.337

The variance = (10×(3 - 7.29)² + 15×(6 - 7.29)² + 25×(11 - 7.29)² + 6×(2 - 7.29)² + 4×(4 - 7.29)² + 3×(10 - 7.29)² + 2×(5 - 7.29)² + 8×(7 - 7.29)² + 9×(8 - 7.29)² + 4×(9 - 7.29)²)/(10+15+25+6+4+3+2+8+9+4) ≈ 9.462

The standard deviation, s ≈ √(9.462) ≈ 3.076

2. The coefficient of variation, CV, can be used to compare the variability of the datasets comprising of different scales as follows;

CV = Standard deviation/( The mean of the data)

Therefore; CV for section A = 23/79 ≈ 0.2911

CV for section B = 11/64 ≈ 0.172

The higher CV value for section A indicates that the scores of section A have a higher relative dispersion than the scores for the section B

3. The consistency values can be obtained by finding the standard deviation for the values in the data for each city, using a web based tool as follows;

City 1; Mean = 23

Variance = 50/4

Standard deviation, City 1 = (√(50))/2 = 5·√2/2

City 2; Mean = 21.8

Sample variance = 2.2

Standard deviation, City 2 = √(2.2) ≈ 1.483

City 3; Mean = 29.2

Sample variance = 18.7

Standard deviation, City 3 = √(18.7) ≈ 4.324

The standard deviation of city 2, which is the smallest compared tom the other cities, indicates that the City 2, has the most consistent temperature

4. The mean of the data obtained from the data using the midpoint of the data, is; Mean = ∑fx/∑f

Therefore; The mean obtained using an online tool is; 43.85

The mode is the data that occurs most frequently, which is the data with the value; 40 - 54 inches

The median is the value at the middle of the data set, which is the value with a frequency of 53, and in the interval 40 - 54 inches

The median is; 39.5 + (54.5 - 39.5) × (50 - 30)/53 ≈ 45.16

The standard deviation found for the grouped data, using an online tool is as follows;

Variance, σ² ≈125.8056

The standard deviation, σ ≈ √(125.8056) ≈ 11.216

The coefficient of variation is; 11.216/41.83 ≈ 0.268

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Answer:

11/10 or 1 1/10

Step-by-step explanation:

110%=110/100

Now let's simplify 110/100:

11/10

Hope this helped! :)

Answer:

1 1/10

Step-by-step explanation:

Hope this helps and have a great day!!!!

Answer:

y = Ae^2xcos√3 x + Be^2xsin√3 x

Step-by-step explanation:

Given the differential equation

y''-4y' +7y =0

Let my = y' and m²y =y''

The auxiliary equation is expressed as;

m²y - 4my +7y = 0

(m²-4m+7)y =0

Divide through by y;

m²-4m+7= 0

Factorize the auxiliary equation

m = 4±√16-4(7)/2

m = 4±√-12/2

m = 4±2√3 i/2

m = 2+√3i

From the complex number a = 2(real part)

b = √3 (imaginary part)

Substitute into the general solution

y = Ae^axcosbx + Be^axsinbx

y = Ae^2xcos√3 x + Be^2xsin√3 x

Answer:

Step-by-step explanation:

266 divided by 7 is 38 laps a day

Using thie model ,The answer is D. 27.

To calculate 9÷1/3 using the model below, we can imagine dividing the green rectangle into thirds vertically. Each third would contain 3 cells.

Then, we can see that there are a total of 9 cells in the rectangle. Since we are dividing by 1/3, we need to find out how many sets of 1/3 are in 9.

We can see that there are 3 sets of 1/3 in each row (since each row contains 3 cells, which are thirds). So, in total, there are 3 rows of 3 sets of 1/3, which gives us:

9÷1/3 = 3 rows x 3 sets of 1/3 = 9 sets of 1/3 = 27

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Answer:

a.0.375

b.0.125

c.0.375

1.0.375

2.0.125

3.0.375

Step-by-step explanation:

a.

The total events in a sample space are n(S)=8

The events that contains exactly two boys

Boy Boy Girl,Boy Girl Boy,Girl Boy Boy.

Let A be the event that there are exactly two boys. Thus, n(A)=3.

So, probability of exactly 2 boys is P(A)=n(A)/n(S)=3/8=0.375.

b.

The event that contains exactly 0 girls.

Boy Boy Boy

Let B be the event that contains exactly 0 girls. Thus, n(B)=1.

So, probability of exactly 0 girls is

P(B)=n(B)/n(S)=1/8=0.125.

c.

The events that contains exactly 1 girl.

Boy Boy Girl,Boy Girl Boy,Girl Boy Boy

Let C be the event that contains exactly 1 girl. Thus, n(C)=3.

So, probability of exactly 1 girl is

P(C)=n(C)/n(S)=3/8=0.375.

Q1 is same as part a.

Q2 is same as part b.

Q3. is same as part c

Answer:

4 inches

Step-by-step explanation:

Answer:

4 inches

Step-by-step explanation:

If 1ft= 12 inches

then 1/3ft= ?

cross multiply

12*1/3= 4

=4 inches