You're in a boat with a big rock, in a swimming pool. You toss the rock overboard. Level of water will increase as of the mass of big rock to the level of the water in the pool.
The buoyancy of any floating object partially or totally submerged in a fluid can be computed thanks to Archimedes' principle. The weight of the thing alone exerts a downward mass on it. The upward or buoyant force acting on the object is what is meant by the aforementioned Archimedes' principle. The difference between the buoyant force and the object's weight is therefore the net force acting on it. In the event that this net force is positive, the item will rise; in the event that it is negative, the object will sink; and in the event that it is zero, the object will be neutrally buoyant, remaining stationary. Simply said, when a body is partially or entirely submerged in a fluid, the Archimedes' principle applies. Consider a cuboid submerged in a fluid, with its top and bottom facing in the direction of gravity, which is considered to be constant throughout the length of the cube. Each face of the fluid will experience a normal force, but only the normal forces on the top and bottom will result in buoyancy. The height directly affects the pressure difference between the top and bottom faces (difference in depth of submersion). A net force on the cuboid is created by multiplying the pressure difference by the area of a face.
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which two forms of energy do burning substances produce
Answer:thermal (heat) energy and radiant (light) energy.
Explanation:
Answer:
Answer: We use the chemical energy in fuels by burning them and transforming them into other types of energy: thermal energy, as when we burn fuel for heat; and kinetic energy, as when we burn gasoline to power our car's motion
Explanation:
hope it will help you
A car is driving down a road in the early morning when a deer walks into the road. if the deer was 25 meters away when the driver noticed it and the car was traveling at 20 m/s, did the car strike the deer? assume instant reaction time and that the car has a braking acceleration of -8.33 m/s2.
For the auto now no longer to strike the deer, the minimal deceleration ought to be eight m / (s ^ 2) with a blended immediately drivers response took at the distance of 15 metres.
The given parameters are;
The distance farfar from the deer the auto turned into while the motive force notices the deer = 25 m
The velocity of the auto = 20m / s
Therefore, for the auto now no longer to strike the deer, the minimal deceleration of the auto ought to be from 20 ^ 2 / (2 * 25) = eight m/s² for a direct motive force response time
For a motive force response time of 0.five seconds, we have
Distance moved with the aid of using car = 0.five * 20 = 10 metersDistance moved with the aid of using car = 0.five * 20 = 10 meters
Minimum deceleration of the auto required = 20 ^ 2 / (2 * 15) =13. overline three m/s^ 2
Distance of the auto from the deer on the begin of deceleration = 25 - 10 = 15 meters.
Therefore, climate the deer is struck with the aid of using the auto relies upon at the drivers response time and deceleration of the auto.
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An object has a mass of 785g and a volume of 15cm cubed what is its density
Answer:
we have ,
mass(m)=785g
volume (v)= 15 cm^3
now , density(d)= m/ v
=785/15
=52.33g/cm^3... is anwer
a car rounds a curve at a steady 50 km/h. if it rounds the same curve at a steady 70 km/h, will its acceleration be any different? explain.
Answer:
Acceleration would be \(1.96\) times the initial value.
Explanation:
The vehicle is in a centripetal motion as it rounds the circular curve. Acceleration of the vehicle during the motion would be:
\(\displaystyle a = \frac{v^{2}}{r}\),
Where:
\(v\) is the speed of the vehicle, and\(r\) is the radius of the curve.In this question, \(r\) stays the same since the vehicle is rounding the same curve. Acceleration of the vehicle would be proportional to the square of velocity.
The new velocity of the vehicle is \((70 / 50)\) times the original one. Hence, the new acceleration would be \((70 / 50)^{2} = 1.96\) times the original value.
a. 8.25749 x 1017 protons and 5.26 x 1014 electrons; the charge on this object is ____ coulombs.
8.25749 x 10¹⁷ protons and 5.26 x 10¹⁴ electrons; the charge on this object is 0.4791 coulombs
To determine the charge on an object given the number of protons and electrons, we need to consider the elementary charge of a single proton and electron and their respective quantities.
The elementary charge, denoted as "e," is the fundamental unit of electric charge and is approximately equal to 1.602 x 10⁻¹⁹ coulombs.
Given that the number of protons is 8.25749 x 10¹⁷ and the number of electrons is 5.26 x 10¹⁴, we can calculate the total charge on the object.
Charge on protons = (Number of protons) * (Charge of a proton)
= (8.25749 x 10¹⁷) * (1.602 x 10⁻¹⁹ C)
Charge on electrons = (Number of electrons) * (Charge of an electron)
= (5.26 x 10¹⁴) * (-1.602 x 10⁻¹⁹ C) (Note: electrons have a negative charge)
Total charge = Charge on protons + Charge on electrons
Performing the calculations, we have:
Charge on protons = (8.25749 x 10¹⁷) * (1.602 x 10⁻¹⁹ C) ≈ 1.3227 C
Charge on electrons = (5.26 x 10¹⁴) * (-1.602 x 10⁻¹⁹ C) ≈ -0.8436 C
Total charge = 1.3227 C + (-0.8436 C) ≈ 0.4791 C
Therefore, the charge on this object is approximately 0.4791 coulombs.
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A 2 kg ball is thrown down off a roof 10 meters high. At the bottom when it hits the ground
it is traveling 15 m/s. What is it's kinetic energy as it hits the ground?
The kinetic energy as it hits the ground with mass of 2kg and velocity 15m/s is found to be 225J
Explain what is kinetic energy?The energy a body has as a consequence of motion is known as kinetic energy. A force has to be applied to an object in order to propel it. We must put in effort in order to apply a force. After the work has been finished, energy is transferred to the item, which then travels at a new, constant speed.
At the bottom when ball hit ground with velocity = 15m/s
KE = 1/2 m v^2 => 1/2 x 2 x 15^2 => 225J
What distinguishes kinetic energy from potential energy?Potential energy is the energy that is kept in reserve in a system or object as a result of its orientation or configuration. An object's kinetic energy is measured in relation to stationary and moving items in its immediate surroundings. Potential energy is irrespective of an object's surroundings.
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7. You are using a Bunsen burner to heat a chemical. You need your notebook, which is on the other side of the flame.
Accident:
Prevention:
Accident: Get burned
Prevention: turn off the burner.
The size of a cam will be bigger if ____
a. the rise is bigger b. the pressure angle is bigger c. the base circle is smaller d. the pitch circle is smaller
The size of a cam will be bigger if the base circle is smaller.
A cam is a rotating or sliding part of a machine that is responsible for transmitting motion to other parts of the machine. A cam follower is in contact with the cam's surface, and its motion is translated to a reciprocating motion of the follower.
A cam's shape determines how the follower's motion is translated, and the size of the cam has a direct impact on the size and complexity of the machine it is used in. The base circle is the circle that forms the basis of the cam's geometry. It is the circle that the cam would have if it were not modified. If the base circle is smaller, then the size of the cam will be bigger.
This is because a smaller base circle requires a cam with more complex geometry to achieve the desired motion transmission. A larger cam will require more material and will be more complex to manufacture than a smaller cam.The size of a cam is directly proportional to the size of its base circle.
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A student is recording how far an ant can crawl over time. He gets so interested in the project that he forgets to enter a few data
points. Based on the data in the table the values for the missing data points are MOST LIKELY
A)
9 minutes and 8 inches
B)
9 minutes and 9 inches
10 minutes and 9 inches
D)
10 minutes and 10 inch
Eliminate
Answer: 10 minutes and 9 inches
Explanation:
I got it right and they are counting by 2 and 3
Venn diagrams show the similarities and differences between two items being compared. Similarities are listed where the circles overlap, and differences are listed where the circles are not overlapping. This Venn diagram is looking at different kinds of technologies.
Which titles best describe this diagram?
Title 1 should be Microtechnology, and Title 2 should be Nanotechnology.
Title 1 should be Nanotechnology, and Title 2 should be Microtechnology.
Title 1 should be Quantum Mechanics, and Title 2 should be Traditional Physics.
Title 1 should be Traditional Physics, and Title 2 should be Quantum Mechanics.
Venn diagram should be titled traditional physics
Based on the Venn Diagram, Title 1 should be Quantum Mechanics, and Title 2 should be Traditional Physics.
What is a Venn Diagram?A Venn Diagram is a diagram which shows the similarities as well as differences between two or more items.
Overlapping points show similarities while non-overlapping points show differences.
The Venn Diagram above illustrates Traditional physics and quantum mechanics.
Title 1 is quantum mechanics and Title 2 is Traditional physics.
Therefore, the Venn Diagram illustrates the difference and similarities between quantum physics and traditional physics.
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during which lunar phase does every solar eclipse occur?
Answer:
It has to be the "New Moon" because that is when the moon is between the sun and the earth.
A lunar eclipse can occur when the earth is between the sun and the moon.
If you measure the average brightness and pulsation period of a cepheid variable star, you can also determine its?
If you measure the average brightness and pulsation period of a cepheid variable star, you can also determine its distance.
Cepheid variable stars belong to a class of stars that have a distinct relationship between variation period and luminosity.
Their period of cycle and luminosity are closely related to each other and they differ in temperature and diameter.
As their brightness increases and decreases, therefore, it helps out in the measurement of intergalactic and interstellar distances.
The changes in amplitude of their motion and cycle period have a definite impact on their brightness which enables us to determine their distance.
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how large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius 105 m m at a speed of 102 km/h k m / h ?
The car must have a static friction coefficient of 0.568 in order to safely round the bend.
What is a suitable friction coefficient?"The Occupational Safety and Health Administration advises that walking surfaces have a static coefficient of friction of 0.5," reads the appendix statement (at A4. 5). The allocation of a 0.5 COF to OSHA is most likely explained by the regulatory proposal from OSHA and the mention in ADAAG taken together.
To get the static friction coefficient required for a vehicle to travel at 102 km/h around a flat curve with a radius of 105 m,
F = mv²/r
F = μs * N
μs × N = mv²/r
N = mg
μs × mg = mv²/r
μs = v²/(gr)
μs = (102 km/h)² / (9.8 m/s² × 105 m)
μs = 0.568
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a sign posted gives a maximum recommended speed of 65 km/h for a certain curve on a level road. the curve is a circular arc with a radius of 95 m. what is the magnitude of the centripetal acceleration of a car that takes this curve at the maximum recommended speed?
The magnitude of the centripetal acceleration of a car taking a curve with a radius of 95 m at the maximum recommended speed of 65 km/h is approximately 2.86 m/s².
To find the magnitude of the centripetal acceleration, we need to use the formula a = v²/r, where a is the centripetal acceleration, v is the velocity of the car, and r is the radius of the curve. First, we need to convert the maximum recommended speed of 65 km/h to meters per second, which is 18.06 m/s. Next, we plug in the values for v and r into the formula to get:
a = (18.06 m/s)² / 95 m = 3.44 m/s²
Therefore, the magnitude of the centripetal acceleration is approximately 3.44 m/s². However, this is the maximum centripetal acceleration that can be achieved at the recommended speed. To stay within a safe range, we should reduce the speed slightly to ensure that the car can comfortably take the curve without skidding off the road. A speed of 60 km/h would result in a centripetal acceleration of 2.57 m/s², which is still well within a safe range.
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A person is lifted 24 meters by the elevator in a building. If the
person has a mass of 74 kg, what is the gravitational potential
energy gained by the person? Estimate g to 9.81 and keep 5
significant figures.
Answer: 17,423 J
Explanation:
Potential Energy = mass x gravity x height
PE = 74kg x 9.81m/s^2 x 24 m
PE = 17,423 J
The required value of gravitational potential energy gained by the person is 17422.56 J.
Given data:
The lifting height is, h = 24 m.
The mass of person is, m = 74 kg.
The energy possessed by the person by virtue of its position is known as gravitational potential energy of the person. The expression for the gravitational potential energy of person is given as,
U = mgh
Here,
g is the gravitational acceleration.
Solving as,
\(U = 74 \times 9.81 \times 24\\\\U =17422.56\;\rm J\)
Thus, we can conclude that the required value of gravitational potential energy of person is 17422.56 J.
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The stage in which the sales of a service start to lessen is called the
Explanation:
The stage in which the sales of a service start to lessen is called the Decline stage.
Will give brainliest!! Pls answer! HELP ME!!!!!!
Answer:
See the explanation.
Explanation:
Q9. Irregular reflection happens when a set of parallel beams are reflected from non-smooth surface which results in non-parallel reflected beams.
Q10.
i) Periscope
ii) There are different types of periscopes but the main characteristic of this instrument is observation over the obstacles or in general objects that are not in the line-of-sight. Basic Periscope uses parallel angled mirrors to project objects that are above the surface in submarines.
How do wings help a plane to fly?
ANSWER
EXPLANATION
We want to find out how wings help a plane to fly.
The wings of an airplane are there to help lift the plane. They are shaped to make air move faster over the wings.
They are used for lifting, landing, turning and controlling the airplane. The curve on the wings make the air move faster than the air at the bottom of the wings which appropriates Bernoulli's principle to push the plane into the air.
Which particles contribute to the net charge and how does each change the net charge?
The two subatomic particles that contribute to the net charge of an ion are electrons and protons.
What is an atom?Atom is the smallest possible amount of matter which still retains its identity as a chemical element, now known to consist of a nucleus surrounded by electrons.
The atom is made up of three components called subatomic particles as follows;
ProtonsElectronsNeutronsThe proton is the positively charged subatomic particle forming part of the nucleus of an atomwhile the electron is the subatomic particle having a negative charge and orbiting the nucleus.
This suggests that the two subatomic particles that contribute to the net charge of an ion are electrons and protons. That is;
Net charge = protons - electrons
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What is TRUE about a capitalist society?
The idea behind capitalism is that the free market of products and ideas is owned and driven by private citizens. A capitalist society is a social order in which private property rights and the free market serve as the basis of trade, distribution of goods, and development.
Answer:
In ideal terms: In a capitalist economic system, the owner of production is the individual, and the benefactors of production are first the individual and second the society. In a socialist or communist economic system, the owner of production is the state or the society, and the benefactor is the society.
When a person sits up, increasing the vertical position of their brain by 36.0 cm, the heart must continue to pump blood to the brain at the same rate. (a) What is the gain in gravitational potential energy for 100 mL of blood raised 36.0 cm? (b) What is the drop in pressure, neglecting any losses due to friction?
(c) Discuss how the gain in gravitational potential energy and the decrease in pressure are related.
A) The gain in gravitational potential energy 0.374 Joules B) The drop in the pressure is 3.743 kN/m².
Volume of the blood, V = 100 ml = 1 × 10⁻⁴ m³
Acceleration due to gravity, g = 9.81 m/s²
Density of blood, ρ = 1060 kg/m³
Increase in the vertical position, Δh = 36 cm = 0.36 m
Gain in gravitational potential energy, ΔP.E = mgΔh
ΔP.E = (ρ×V)gΔh
ΔP.E = 1060 × 1 × 10⁻⁴ × 9.81 × 0.36
ΔP.E = 0.374 J
B) Drop in pressure, Δp = ρgΔh
Δp = 1060 × 9.81 × 0.36
Δp = 3743.5 N or 3.743 kN/m²
C) Gravitational potential energy increases with the increase in elevation of the object, where as pressure decreases with the increase in the elevation of the object. We know gain in potential energy,
ΔP.E = mgΔh = ρVgΔh
Drop in pressure, Δp = ρgΔh
ΔP.E = ΔpV
Here V is the volume of the blood.
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if we want to see what galaxies looked like at a time close to the beginning of the universe, where should we look?
Answer: 4 billion years ago
Explanation:
I need help to build a mouse trap race car for my science class and this is my final and these are the materials I have.
So, your science teacher has given your class the classic "mousetrap car" assignment: to make, design, and build a small vehicle powered by the snapping action of a mousetrap to make your car travel as far as possible. If you want to come out ahead of all the other students in your class, you'll need to make your car as efficient as possible so you can squeeze every last inch out of your "car". With the right approach, it's possible to streamline your car's design for maximum distance using only common home materials. You could also buy a mousetrap car kit from any craft store and skip wondering if it will work.
Use large rear wheels. Large wheels have greater rotational inertia than small wheels. In practice, this means that once they start rolling, they're harder to stop rolling. This makes large wheels perfect for distance-based contests — theoretically, they'll accelerate less quickly than smaller wheels, but they'll roll much longer and they'll travel a greater distance overall. So, for maximum distance, make the wheels on the drive axle (the one the mousetrap is tied to, which is usually the rear one) very large. The front wheel is a little less important — it can be large or small. For a classic drag racer look, you'll want big wheels in the back and smaller ones in front.
Use thin, light wheels. Thinner wheels have less friction and may go farther if the distance is what you want or need with your mousetrap racer. It's also important to take the weight of the wheels themselves into account — any unneeded weight will ultimately slow your car down or lead to added friction. In addition, it's worth noting that wide wheels can even have a small negative effect on the car's drag due to air resistance. For these reasons, you'll want to use the thinnest, lightest wheels available for your car.
Old CDs or DVDs work fairly well for this purpose — they're large, thin, and extremely light. In this case, a plumbing washer may be used to reduce the hole size in the middle of the CD (to fit the axle better).
If you have access to old vinyl, these also work extremely well, though they may be too heavy for the smallest mousetraps.
Use a narrow rear axle. Assuming your car is a rear-wheel-drive car, each time your rear axle turns, the rear wheels turn. If your rear axle is extremely skinny, your mousetrap car will be able to turn it more times for the same length of string than it would if it were wider. This translates to turning your rear wheels more times, meaning greater distance! For this reason, it's a wise idea to make your axle out of the skinniest material available that can still support the weight of the frame and wheels.
Narrow wooden dowel rods are a great, easily-accessible choice here. If you have access to thin metal rods, these are even better — when lubricated, they usually have less friction.
Create traction by giving the edges of the friction of the wheels. If the wheels slip against the ground when the trap is sprung, energy is wasted — the mousetrap works to make the wheels turn, but you don't get any extra distance. If this happens with your car, adding a friction-inducing material to the rear wheels may reduce their slippage. To keep your weight requirements down, use only as much as is necessary to give the tips of the wheels some grip and no extra. Some suitable materials are:[1]
Electrical tape
Rubber bands
Additionally, placing a piece of sandpaper under the rear wheels at the start line can reduce slippage as the car begins to move (when it is most likely)
lamp power with what is the current through the lamp when it is connected to a battery ?
Answer:
lamp power with what is the current through the lamp when it is connected to a battery ?
Explanation:
If the light bulbs are connected in parallel, the current flowing through the light bulbs combine to form the current flowing in the battery, while the voltage drop is 6.0 V across each bulb and they all glow. One bulb burning out in a series circuit breaks the circuit.
A kid pushes a stationary
merry-go-round, creating an
acceleration of 0.135 rad/s^2.
How much time does it take the
merry-go-round to complete
2.00 rotations?
(Unit = s)
Remember: CCW is +, CW is. 1 rev= 2*pi rad
The merry-go-round takes approximately 29.41 seconds to complete 2.00 rotations.
Given data:
Acceleration (α) = 0.135 rad/\(s^2\)
Number of rotations (θ) = 2.00
To find the time taken (t) for 2.00 rotations, we need to use the formula:
θ = 0.5 * α * \(t^2\)
Rearranging the formula, we get:
\(t^2\) = (2 * θ) / α
Plugging in the given values, we have:
\(t^2\) = (2 * 2.00) / 0.135
\(t^2\) = 29.63
Taking the square root of both sides, we find:
t ≈ √29.63
t ≈ 5.439
Therefore, the time taken for the merry-go-round to complete 2.00 rotations is approximately 5.439 seconds.
Note: It's important to round the final answer to an appropriate number of significant figures, considering the given data. In this case, we have used four significant figures in the final answer.
However, if we want to adhere to the given significant figures in the acceleration (0.135 rad/\(s^2\)), the answer should be rounded to three significant figures. In that case, the final answer would be approximately 5.44 seconds.
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A race car can be slowed with a constant acceleration of -11 m/s2. a. If the car is going 55 m/s, how many meters will it travel before it stops? b. How many meters will it take to stop a car going twice as fast?
Answer:
137.5 meters
Explanation:
v = Vo + a t
so
v = 55 - 11 t
when is v = 0 ?
0 = 55 - 11 t
so t = 5 seconds to stop
d = Vo t + (1/2) a t^2
d = 55 (5) - (1/2) 11 (25)
= 275 - 137.5
=137.5 meters
What is a common disease caused by a fungus?
A.
common cold
B.
HIV/AIDs
C.
athlete's foot
D.
pneumonia
I need help with the 1st and the 3rd one plzzzzzzzzzzzzz
Answer for the first one is 2. The answer for the 3rd one is 8
Assume that it is now January 1, 2022. Wayne-Martin Electric Inc. (WME) has developed a solar panel capable of generating 200% more electricity than any other solar panel currently on the market. As a result, WME is expected to experience a 14% annual growth rate for the next 5 years. Other firms will have developed comparable technology by the end of 5 years, and WME's growth rate will slow to 5% per year indefinitely. Stockholders require a return of 12% on WME's stock. The most recent annual dividend (Do), which was paid yesterday, was $1.75 per share. a. Calculate WME's expected dividends for 2022, 2023, 2024, 2025, and 2026. Do not round intermediate calculations. Round your answers to the nearest cent. D2022 = $ X D2023 = $ D2024 = $ X D2025 = $ D2026 = $ b. Calculate the value of the stock today, Po. Proceed by finding the present value of the dividends expected at the end of 2022, 2023, 2024, 2025, and 2026 plus the present value of the stock price that should exist at the end of 2026. The year end 2026 stock price can be found by using the constant growth equation. Notice that to find the December 31, 2026, price, you must use the dividend expected in 2027, which is 5% greater than the 2026 dividend. Do not round intermediate calculations. Round your answer to the nearest cent. X S C. Calculate the expected dividend yield (D2/Po), capital gains yield, and total return (dividend yield plus capital gains yield) expected for 2022. (Assume that Do = P, and recognize that the capital gains yield is equal to the total return minus the dividend yield.) Do not round intermediate calculations. Round your answers to two decimal places. D1/Po = X % Capital gains yield = % Expected total return = % Then calculate these same three yields for 2027. Do not round intermediate calculations. Round your answers to two decimal places. D/Ps = % Capital gains yield = % Expected total return = %
a) D2022 = $1.9975, D2023 = $2.27715, D2024 = $2.60554, D2025 = $2.98868, D2026 = $3.43243
b) Po = $13.63
c) Dividend yield = 13.85%, Capital gains yield = 74.52%, Expected total return = 88.37%. Dividend yield = 17.89%, Capital gains yield = -23.29%, Expected total return = -5.40%.
a) Dividend is the distribution of earnings to shareholders. Expected dividend for each year can be calculated as follows:
D2022 = D0 (1 + g) = $1.75 (1 + 0.14) = $1.9975
D2023 = D2022 (1 + g) = $1.9975 (1 + 0.14) = $2.27715
D2024 = D2023 (1 + g) = $2.27715 (1 + 0.14) = $2.6055415
D2025 = D2024 (1 + g) = $2.6055415 (1 + 0.14) = $2.98868161
D2026 = D2025 (1 + g) = $2.98868161 (1 + 0.14) = $3.432429195
b) The present value of dividends expected in 2022, 2023, 2024, 2025 and 2026 can be calculated using the following formula:
PVD = D / (1 + r)t
where
PVD = present value of dividends expected
D = dividend expected in a future year
t = number of years from now
r = required rate of return
PVD2022 = $1.9975 / (1 + 0.12)¹ = $1.77700934579
PVD2023 = $2.27715 / (1 + 0.12)² = $1.88843867485
PVD2024 = $2.6055415 / (1 + 0.12)³ = $1.99719364693
PVD2025 = $2.98868161 / (1 + 0.12)⁴ = $2.10928913223
PVD2026 = ($3.432429195 + ($3.432429195 * 1.05)) / (1 + 0.12)⁵ = $2.25661605368
The present value of the stock price that should exist at the end of 2026 can be calculated using the constant growth equation:
Po = D1 / (r - g)
where
Po = price of stock today
D1 = dividend expected at the end of 2026r = required rate of return
g = expected growth rate
Po = $3.60484320761
Total present value of all dividends expected plus the present value of the stock price at the end of 2026 can be calculated using the formula:
Total PV = PVD2022 + PVD2023 + PVD2024 + PVD2025 + PVD2026 + PoTotal PV = $1.77700934579 + $1.88843867485 + $1.99719364693 + $2.10928913223 + $2.25661605368 + $3.60484320761 = $13.6333900619
The value of the stock today, Po, is $13.63.
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If you traveled 20 meters in 4 seconds, what was your average velocity?
Answer:
Explanation:
the average speed of the object is 6.67 m/s