A student measures out 5.0 g of magnesium and burns it. After the reaction, the student
measures 7.9 g of magnesium oxide. How much oxygen must have been used in the
reaction? (include the correct unit)
1

Answer:

option C

since F=ma

the acceleration of an object depends on the object's mass and the net applied force

Answer:

The expected time is 2.28 hours.

Explanation:

The speed of storm = 35 km/hr

The distance between the house and the storm = 80 km.

Now, we have to find the time taken by storm to arrive at the house. Here, we can determine the time by dividing the distance with speed.

The time, taken by storm =  Distance/speed

The time, taken by storm = 80 / 35

The time, taken by storm = 2.28 hours.

Answer: Refraction is an effect that occurs when a light wave, incident at an angle away from the normal, passes a boundary from one medium into another in which there is a change in velocity of the light The wavelength decreases as the light enters the medium and the light wave changes direction.

Let me know if you need anything else

Have a great day.

Answer:

below

Explanation:

1.1115 im not sure tho

Answer:

A

Explanation:

Please see the attached picture for the full solution.

Since we are only concerned about the decrease in gravitational potential energy of the car, we look at the decrease in height of the car as it moves from point X to point Y, instead of the distance travelled by the car.

The amount of energy involved in melting a substance without changing its temperature is called the heat of fusion (D).

Heat of fusion refers to the amount of heat energy required to melt or freeze a unit mass or a quantity of a substance. Heat of fusion is expressed in joules per gram (J/g) or in calories per gram (cal/g). The amount of energy needed to melt a solid substance into a liquid state at a constant temperature is the heat of fusion. The temperature of a substance remains constant during the melting process because the energy being added is used to break the intermolecular bonds between the molecules of the substance.

Hence, the correct answer is Option D.

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Answer:

Here are some uses...

Explanation:

Uses of convex mirror:

It is used in supermarkets and stores for surveillance.

It it is used as rear view mirror in automobiles.this is due to the reason that a convex mirror provides a wider field of view than a plane or concave mirror.

Uses of concave mirror:

It is used in torches.

They are used in headlights of vehicles to send parallel rays to infinity , in shaving mirror to get an enlarged image of the face and also by dentists to see a bigger image of the tooth / teeth .

Mark as brainliest if helped thanks!

The particles that are in the interior of the atom are the nucleons while the particles at those on the shells are the electrons.

Atoms are composed of three types of subatomic particles: protons, neutrons, and electrons.

Protons: Positively charged particles that are found in the nucleus of an atom. The number of protons in an atom's nucleus is called its atomic number, which determines the identity of the element.

Neutrons: Neutral particles that are also found in the nucleus. The number of neutrons in an atom can vary, and they help to determine the mass of an atom.

Electrons: Negatively charged particles that occupy the electron cloud or shells surrounding the nucleus. Electrons are much lighter than protons and neutrons and are involved in chemical reactions. The arrangement of electrons in an atom determines its chemical properties and reactivity.

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The frequency of a mass-spring oscillator depends on the mass of the object and the stiffness of the spring.

In a mass-spring oscillator, the frequency is determined by the mass (m) of the object attached to the spring and the spring constant (k), which represents the stiffness of the spring. The relationship between these factors can be expressed using the formula:

f = (1 / 2π) √(k / m)

In this formula, f represents the frequency of the oscillator. As the mass of the object increases, the frequency decreases, since the system takes more time to complete one oscillation. Conversely, as the spring constant increases, indicating a stiffer spring, the frequency also increases, as the system oscillates more quickly.

This relationship demonstrates that both the mass and the spring constant play a crucial role in determining the frequency of a mass-spring oscillator. By understanding and manipulating these factors, it is possible to control the behavior of such oscillating systems, which have numerous applications in fields such as engineering, physics, and mechanics.

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Answer:

Hello There!!

Explanation:

The answer is=>A.blue, base.

hope this helps,have a great day!!

~Pinky~

\(\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}\)

A.blue, base.

Answer:

\(\huge\boxed{\sf V_i=60 \ m/s}\)

Explanation:

Final speed = \(V_f\) = 40 m/s

Time = t = 5 s

Acceleration = a = -4 m/s²

Initial velocity = \(V_i\) = ?

\(\displaystyle a = \frac{V_f-V_i}{t}\)

Put the givens in the above formula

\(\displaystyle -4=\frac{40 - V_i}{5} \\\\Multiply \ -5 \ to \ both \ sides\\\\-4 \times 5 = 40 - V_i\\\\-20 =40-V_i\\\\Subtract \ 40 \ to \ both \ sides\\\\-20-40=-V_i\\\\-60\ m/s=-V_i\\\\60 \ m/s = V_i\\\\V_i=60 \ m/s\\\\\rule[225]{225}{2}\)

One of the most important relationships between electric and magnetic fields is that a changing electric field produces a magnetic field, and a changing magnetic field produces an electric field.

Electric and magnetic fields are two fundamental components of the electromagnetic force, which is one of the four fundamental forces of nature. The electric field is created by electric charges, while the magnetic field is created by moving electric charges or current.

One of the most important relationships between electric and magnetic fields is that a changing electric field produces a magnetic field, and a changing magnetic field produces an electric field. This is known as electromagnetic induction and is the basis for many technologies, including electric generators and transformers.

Additionally, electric and magnetic fields are intimately related through Maxwell's equations, which describe how electric and magnetic fields interact with each other and with electric charges. These equations show that a changing electric field produces a magnetic field, while a changing magnetic field produces an electric field.

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Answer:

B

Explanation:

thanks me later

thanks for 5 points love you

hehehehe

Answer:

For metric-system conversions, follow this method: Sound travels at about 340 m/s, so multiply the number of seconds you counted by 340, and you'll know how many meters away lightning struck. A three-second count, then, would place the lightning strike about 1,020 m away, or roughly 1 km.

Explanation:

hope it hep and if it doesnt sorry

The distance struck by the lighting flashes is 680 m.

The given parameters;

The distance struck by the lighting is calculated by applying the principle of echo as follows;

\(v = \frac{2d}{t} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{340 \times 4}{2} \\\\d = 680 \ m\)

Thus, the distance struck by the lighting flashes is 680 m.

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 The charge Q is uniformly distributed throughout the sphere. The correct answer is (B)

When a solid conducting sphere is given a positive charge Q, the charge will distribute itself evenly throughout the surface of the sphere due to the repulsion of like charges. This is known as the "Faraday's ice pail experiment".

According to the principle of electrostatics, the charge on a conductor always resides on its surface and distributes itself in a way that the electric field inside the conductor is zero. Since the charge on a conductor always resides on its surface, it follows that the charge Q in this case must be uniformly distributed throughout the surface of the sphere.

Option (A) is not true because the charge is not concentrated at the center of the sphere. If the charge was concentrated at the center of the sphere, the electric field would not be zero inside the conductor, which contradicts the principle of electrostatics.

Option (C) and (D) are not true because the density of the charge does not change radially outward from the center. If the density decreased or increased radially outward, the electric field inside the conductor would not be zero, which again contradicts the principle of electrostatics.

Option (E) is not true because the charge is distributed throughout the entire volume of the sphere, not just on its surface. A solid conductor has free charges that can move throughout its entire volume, so the charge will distribute itself throughout the entire volume of the sphere until the electric field inside the conductor is zero.

Therefore, the correct answer is (B) it is uniformly distributed throughout the sphere.

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When the box is exactly halfway between the center and the right support, the ratio of the magnitude of the force of the right support on the board to the magnitude of the force of the left support on the board is 3:1. If the board has significant weight and the box is sitting above the left support, the force vectors will be adjusted accordingly, and the ratio of the weight of the board to the weight of the box would be 1:1.

The force exerted by each support depends on the location of the box on the board. When the box is moved, the force distribution changes to maintain equilibrium. In the given scenario, the box is halfway between the center and the right support. Using the principle of moments, we can calculate the ratio of the forces exerted by the left and right supports, which turns out to be 3:1.

In a situation with significant board weight, the force vectors will be adjusted to maintain equilibrium. When the box is above the left support, both the box's weight and the board's weight will be acting on the left support, resulting in a 1:1 ratio for the weights of the board and the box.

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Answer:

3N

Explanation:

Answer:k

Explanation:k

k

The rate at which the energy will now dissipate by the unknown resistor is 0.344 W.

To find the rate at which energy is now dissipated in the unknown resistor connected to a 10.5 V battery, follow these steps:

1. First, find the resistance of the unknown resistor using the power dissipation formula P = V^2/R, where P is the power, V is the voltage, and R is the resistance. Given the 12.0 V battery and a power dissipation of 0.450 W:
0.450 W = (12.0 V)^2 / R

2. Solve for R:
R = (12.0 V)^2 / 0.450 W ≈ 320 ohms

3. Now that we know the resistance, we can calculate the new power dissipation when the unknown resistor is connected to the 10.5 V battery. Use the same power dissipation formula, but this time with the 10.5 V battery:
P_new = (10.5 V)^2 / 320 ohms

4. Solve for P_new:
P_new ≈ (10.5 V)^2 / 320 ohms ≈ 0.344 W

So, when the unknown resistor is connected to the 10.5 V battery, energy is dissipated at a rate of approximately 0.344 W.

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The horizontal distance travelled by the football is 3.1 m.

The angle of projection of the football is calculated as follows;

tan ( θ ) = Vy / Vx

where;

tan ( θ ) = 5 / 3

tan ( θ ) = 1.667

θ = arc tan (1.667)

θ = 59⁰

The resultant velocity of the ball is calculated as follows;

v = √ (Vx² + Vy²)

v = √ (3² + 5²)

v = 5.83 m/s

The horizontal distance travelled by the football is calculated as follows;

x = v² sin(2θ) /g

where;

x = [ (5.83)² sin(2 x 59) /9.8 ]

x = 3.1 m

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A promising evidence of a habitat that might support life on the planet Mars is water.

There is evidence supporting the existence of liquid water on Mars from numerous sources. The finding of repeated black streaks on Martian slopes and the presence of hydrated minerals suggest the potential of seasonal or location-specific briny water flows. A necessary component of life as known is liquid water.

Additionally, Mars possesses underground ecosystems that could provide defence against radiation and severe surface conditions. Researchers have found evidence of ancient underground hydrothermal systems as well as beneath ice. These settings might offer consistent conditions for the development of microbial life.  Methane gas has been found in the Martian atmosphere, along with variations over time, and this has led to questions regarding its origin. Both geological and biological processes can result in the production of methane.

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Perceptual errors, cognitive biases, and emotions can indeed have negative effects on negotiations. Here are three examples illustrating each:

1. Perceptual error: One common perceptual error is the halo effect, where an overall impression of a person or situation influences the perception of specific attributes or qualities. In a negotiation, I may have made the mistake of perceiving my counterpart as more competent and trustworthy due to their confident demeanor and well-dressed appearance. This perceptual bias may have led me to underestimate their true intentions or overlook potential risks.

2. Cognitive bias: Confirmation bias is a cognitive bias where we seek and interpret information in a way that confirms our pre-existing beliefs or expectations. During a negotiation, I might have had a confirmation bias that my proposed solution was the best option. As a result, I might have selectively paid attention to information that supported my viewpoint and dismissed or ignored evidence that challenged it. This bias could have hindered open-mindedness and prevented me from considering alternative solutions.

3. Emotion: Emotions play a significant role in negotiations and can impact decision-making. For example, I might have experienced strong frustration during a negotiation due to the slow progress and lack of cooperation from the other party. This emotional response could have impaired my ability to think rationally and objectively, leading to impulsive or aggressive behavior. It might have also hindered effective communication and collaboration, potentially damaging the negotiation process.

In negotiations, it's important to be aware of these potential pitfalls and actively work to mitigate their effects. Developing self-awareness, practicing empathy, seeking diverse perspectives, and employing logical analysis can help counteract the negative impact of perceptual errors, cognitive biases, and emotional responses.

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Answer:False static friction helps us from not sliding it hold us.

Explanation:

Explanation:

a) i) Calculation of the friction force:

The friction force can be determined using the equation:

friction force = coefficient of friction * normal force

The normal force is equal to the weight of the object, which can be calculated as:

normal force = mass * gravitational acceleration

where the gravitational acceleration is approximately 9.8 m/s².

normal force = 75 kg * 9.8 m/s² = 735 N

friction force = 0.4 * 735 N = 294 N

ii) Calculation of the acceleration of the body:

Now, we can calculate the acceleration using Newton's second law:

net force = mass * acceleration

Since the applied force and the friction force act in opposite directions, the net force can be calculated as:

net force = applied force - friction force

net force = 300 N - 294 N = 6 N

mass = 75 kg

6 N = 75 kg * acceleration

acceleration = 6 N / 75 kg = 0.08 m/s²

b) Explanation:

In part (a), we calculated the friction force to be 294 N and the acceleration of the body to be 0.08 m/s². The positive acceleration indicates that the body is moving in the direction of the applied force.

The friction force opposes the motion of the body and acts in the opposite direction to the applied force. In this case, the applied force of 300 N is greater than the friction force of 294 N. As a result, the net force acting on the body is 6 N in the direction of the applied force.

The small net force of 6 N, compared to the body's mass of 75 kg, results in a relatively low acceleration of 0.08 m/s². This indicates that the body will accelerate slowly in the direction of the applied force due to the presence of friction.

Overall, the friction force and the resulting acceleration of the body are determined by the coefficient of friction (μ) and the mass of the object. In this case, the body experiences a relatively high friction force, leading to a small acceleration.

Given that,

The mass of marble A, m₁=0.08 kg

The mass of marble B, m₂=0.05 kg

The initial velocity of marble A, u₁=0.5 m/s

As the marble B was at rest, the initial velocity of marble B is u₂=0 m/s

The final velocity of marble A, v₁=-0.1 m/s

Let the final velocity of marble B be v₂.

According to the law of conservation of momentum, the total momentum before the collision is equal to the total after the collision.

Therefore

On rearranging the above equation,

On substituting the known values in the above equation,

Therefore the

Answer:

See below

Explanation:

Use conservation of momentum (rather than Kinetic Energy ) for collision problems:

Momentum A  = mv = .08 * .5 = .04  km m/s

Momentum B = mv  = 0

    Total Momentum = .04 + 0 = .04  kg m/s

After collision the sum must be the same

A = mv = .08 ( -.1 ) = - .008 kg m/s

B = m vb   = .05 vb

    .04   =  - .008   +  .05 vb

      vb =  + .96 m/s      in the same direction as original A direction

Answer:

plagiarism

Explanation:

thats the answer because plagiarism means: the practice of taking someone else's work or ideas and passing them off as one's own.

Thats the definition!!!

lmk if this helped

Answer:phishing

Explanation:the definition of phishing is: the fraudulent practice of sending emails purporting to be from reputable companies in order to induce individuals to reveal personal information, such as passwords and credit card numbers.

Answer:

E(efficiency) = E(out) / E(in)

.4 = 400 J / E (in)

E (in) = 1000 J

Heat input : 1000J

The efficiency of a heat engine  is defined as the ratio of work done by the heat engine absorbed per cycle.

Given : work output = 400 J

          Efficiency = 40 % = 0.4

          heat input = ?

Efficiency = work output / heat input

                0.4 = 400/heat input  

heat input : 1000J

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The rotation rate of the object will increase if the mass of the rotating object becomes more concentrated.

The law of conservation of angular momentum states that the angular momentum of a rotating objects remains constant if no external torque is applied to it.

I₁ω₁ = I₂ω₂

Where, I₁ is the moment of inertia = Mr₁²

I₂ = Mr₂²

Initial angular momentum = ω₁

Final angular momentum = ω₂

If the mass becomes more concentrated, it means the radius of the rotation becomes less then,

ω₂ = Mr₁²ω₁/Mr₂²

ω₂ = (r₁/r₂)²×ω₁

Since r₁ > r₂, so ω₂ > ω₁

Hence we can say that the rotation rate will increase if the mass becomes more concentrated.

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Assuming that the standard deviation is known to be 1.1, for a mean of 1080 samples, it can be said that the data supports the claim that the current ozone level is insufficient at the 0.02 level.

Step 1 of 5: Enter the hypotheses:

Null hypothesis (H0): The current ozone level is sufficient (μ = 7.0 ppm)

Alternative hypothesis (H1): The current ozone level is insufficient (μ < 7.0 ppm)

Step 2 of 5: Enter the value of the z-test statistic:

To find the z-test statistic, we'll use the formula:

z = (X' - μ) / (σ / √n)

where:

X' = sample mean = 6.9 ppm

μ = population mean = 7.0 ppm

σ = standard deviation = 1.1 ppm

n = sample size = 1080

Substituting the values into the formula:

z = (6.9 - 7.0) / (1.1 / √1080)

z = -0.1 / (1.1 / 32.863)

z ≈ -0.1 / 0.033157

z ≈ -3.018

Step 4 of 5: Enter the decision rule:

Since the alternative hypothesis is one-tailed (μ < 7.0 ppm), we need to compare the z-test statistic with the critical value for the given significance level.

At a significance level of 0.02, the critical value can be found using a z-table or a calculator. For a one-tailed test, the critical value is approximately -2.055.

Step 5 of 5: Enter the conclusion:

The z-test statistic (-3.018) is smaller than the critical value (-2.055). Therefore, we reject the null hypothesis.

Conclusion: The data supports the claim that the current ozone level is insufficient at the 0.02 level.

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A. The resistance of the wire if a potential difference of 12 V is found to produce a current of 0.40 A in a 3.2-m length of wire with a uniform radius of 0.40cm is 30 ohm.

B. The resistivity of the wire is 4.71 × 10⁻⁶ ohm-meters.

To find the resistance of the wire, we can use Ohm's Law:

V = IR

Where V is the potential difference (12 V), I is the current (0.40 A), and R is the resistance.

Rearranging the formula to solve for R, we get:

R = V/I

Substituting the values, we have:

R = 12 V / 0.40 A

R = 30 Ω

So, the resistance of the wire is 30 ohms.

To find the resistivity of the wire, we can use the formula:

R = ρ(L/A)

Where R is the resistance (30 Ω), ρ is the resistivity, L is the length of the wire (3.2 m), and A is the cross-sectional area of the wire.

First, let's find the cross-sectional area (A) using the formula for the area of a circle:

A = πr²

where r is the radius of the wire (0.40 cm = 0.004 m).

A = π(0.004 m)²

A ≈ 5.027 × 10^-5 m²

Now we can rearrange the resistivity formula to solve for ρ:

ρ = R(A/L)

Substituting the values, we get:

ρ = 30 Ω (5.027 × 10⁻⁵ m²) / 3.2 m

ρ ≈ 4.71 × 10⁻⁶ Ω·m

So, the resistivity of the wire is approximately 4.71 × 10⁻⁶ ohm-meters.

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