Look at the image and answer please

Answer:

3x - 5 = 2x + 6  

Step one- Subtract 2x to isolate the variable  

X – 5 = 6  

Step two- Add 5 to continue to isolate the variable  

X = 11  

Your answer is      x = 11  

Hopefully this helps! Feel free to mark brainliest!

Answer: x=11

Step-by-step explanation:

3x-5=2x+6

+5. +5

3x=2x+11

-2x -2x

x=11

Answer:

x = 6

Step-by-step explanation:

Given that Δ JKL  is equilateral then the 3 sides are congruent.

Equate any 2 sides and solve for x, that is

13x + 5 = 8x + 35 ( subtract 8x from both sides )

5x + 5 = 35 ( subtract 5 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

An equilateral triangle is a triangle where all three sides are equal.

The value of x is 6.

It is a two-dimensional figure which has three sides and the sum of the three angles is equal to 180 degrees.

We have,

An equilateral triangle is a triangle where all three sides are equal.

∆JKL is an equilateral triangle.

JK = 13x + 5

KL = 17x – 19

JL = 8x + 35

Now,

JK = 13x + 5

KL = 17x – 19

JK = KL

13x + 5 = 17x - 19

5 + 19 = 17x - 13x

24 = 4x

x = 6

Thus,

The value of x is 6.

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The mathematical expression for the function that gives the center of mass is m=\(\(\int\limits \int\limits\)\(D_{p}\)(x, y)dA\)

The center of mass is a point specified relative to an object or set of things. It is the weighted average position of all the system's pieces. For simple stiff objects with homogenous density, the centroid is the location of the center of mass.

A lamina that occupies the region inside the circle x²+y²=14y

Outside the circle is x²+y²=49.m

x²+y²=\(\(\int\limits\)P(x, y)dA\)

Where

r²=14rsinθ

x²+y²=49r=7

Therefore, the center of mass is-x=\((i/m) \(\int\limits\)xp(x, y)dA\)

-x=\((1/m)\(\int\limits \int\limits\)(r cosθ)p(r, θ)r drdθ\)

-y=\((1/m)\(\int\limits \int\limits\)Dyp(x, y)dA\)

-y= \((1/m)\(\int\limits \int\limits\)D(rsinθ)p(r, θ)r drdθ\)

Therefore, the center of mass is

m=\(\(\int\limits \int\limits\)\(D_{p}\)(x, y)dA\)

The mathematical expression for the function that gives the center of mass is

m=\(\(\int\limits \int\limits\)\(D_{p}\)(x, y)dA\)

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Solution for the question 2 :

It is given that ,

The population after n years is given by exponential function ,

Population after 9 years is calculated as,

Thus the population after 9 years is 956 .

Answer:

y=50 and z=60 (vertically opposite)

x+60+y=180

or x+60+50=180

or x+110=180

or x=70

Answer:

Step-by-step explanation:

a.x = 95 degree

reason = being vertically opposite angles

x + 145 degree = 180 degree

x = 180 -145

x=35 degree

reason = being linear pair

b.40 + x =90 degree

x = 90 - 40

x = 50 degree

reason = being perpendicular

y = x + 40

y = 50 + 40

y = 90 degree

reason = being vertically opposite angles

c.50 + 60 + x=180 degree

110 + x =180

x = 180-110

x = 70 degree

reason = being linear pair

z = 60 degree

reason = being vertically opposite angles

y = 50 degree

reason = being vertically opposite angles

d. x = 80 +10

x =90 degree

reason = being vertically opposite angles

y + x =180 degree

y + 90 =180

y = 180 - 90

y = 90 degree

reason = being linear pair

Answer:

\(Perimeter = 12 + 6y\)

Step-by-step explanation:

Represent the length with x and width with y

By analysis, we have:

Length = 6 + 2 times the width.

Mathematically, the expression is:

\(x = 6 + 2 * y\)

\(x = 6 + 2 y\)

Required: Determine the perimeter

Perimeter of a rectangle is calculated as:

\(Perimeter = 2 * (Length + Width)\)

Substitute x for length and y for width

\(Perimeter = 2 * (x + y)\)

Substitute 6 + 2y for x

\(Perimeter = 2 * (6 + 2y + y)\)

\(Perimeter = 2 * (6 + 3y)\)

Open bracket

\(Perimeter = 2 * 6 + 2 * 3y\)

\(Perimeter = 12 + 6y\)

Answer:

3p-p

Step-by-step explanation:

I always think of the negative sign out ruling the positive sign so let's do that for the -p part.

3p-p is what it becomes

Your question says simplify but just in case you want the answer here it is:

-p is also the same as -1p

So therefore we have

3p-1p

And we subtract the coefficients and keep the variable

2p would be your answer but once again I don't know if you wanted that so just to be sure I put 3p-p as my "answer".

Answer: 33.33 megabytes per day

Step-by-step explanation:

From the question, we are informed that in June, Clarissa used 1 gigabytes of data on her cell phone. Since June has 30 days, the amount of data she uses on average per day? will be:

= 1000megabyte/30

= 33.33mb

Note that:

1000 megabytes = 1 gigabyte

Answer:

f(x) approaches positive infinity.

g(x) approaches negative infinity.

the y-intercept of f(x) is less than the y-intercept of g(x).

Step-by-step explanation:

the highest power of x in f(x) is 3, and it has a positive sign. so, the bigger x the more the x³ part will dominate.

therefore, with x going to positive infinity, also f(x) goes to positive infinity.

the graph of g(x) clearly dives down never to come back up or flatten out. so, with x going to positive infinity, g(x) goes to negative infinity.

the y-intercept of f(x) = f(0).

that means the functional value when x=0.

so, for x=0 this means

y = 2×0³ - 3×0² + 5×0 + 7 = 7

the graph of g(x) shows that g(0) is 8.

so f(0) is less than g(0).

As x approaches positive infinity, f(x) approaches positive infinity and g(x) approaches negative infinity. The y-intercept of the function f is 7 and the y-intercept of function g is 8. #SPJ5

Polynomials are algebraic expressions whose form is described below:

\(y = \sum \limits_{i = 0}^{n} c_{i}\cdot x^{i}\)     (1)

Where \(c_{i}\) is the i-th coefficient of the polynomial.

In this question we have two polynomials in two distinct presentations, an analytical and a graphical one, whose behaviors must be analyzed to fill the blanks of the paragraph given. The complete paragraph is shown below:

As x approaches positive infinity, f(x) approaches positive infinity and g(x) approaches negative infinity. The y-intercept of the function f is 7 and the y-intercept of function g is 8. #SPJ5

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The potential energy of the ball will be 7200 Joules.

Given is a 6-kg bowling ball sits on top of a building that is 120 meters tall.

We can write the potential energy of the ball as -

E = mgh

E = 6 x 10 x 120

E = 60 x 120

E = 7200 Joules

Therefore, the potential energy of the ball will be 7200 Joules.

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Answer:

C. (-5,1)

Explanation:

One point in the pre-image has the coordinates (-3, 7)

The translation rule is given below:

Therefore, the coordinates of its image will be:

The correct choice is C.

Hence, the required value of the line integral is\($\boxed{-84550}$\).

The given line integral is \($\int_{C}xyz ds$\), where the given curve C is \($x=8\sin t$, $y=t$, $z=-8\cos t$, $0\leq t\leq \pi$\).

Formula to evaluate line integral:\($$\int_{C}f(x,y,z)ds = \int_{a}^{b}f(x(t),y(t),z(t))\sqrt{\left(\frac{dx}{dt}\right)^2+\left(\frac{dy}{dt}\right)^2+\left(\frac{dz}{dt}\right)^2} dt$$Here, $f(x,y,z) = xyz$, $x(t)=8\sin t$, $y(t)=t$, $z(t)=-8\cos t$, $a=0$, $b=\pi$.\)

Hence, we have\($$\begin{aligned}\int_{C}xyz ds &= \int_{0}^{\pi} (8\sin t)(t)(-8\cos t)\sqrt{\left(\frac{dx}{dt}\right)^2+\left(\frac{dy}{dt}\right)^2+\left(\frac{dz}{dt}\right)^2} dt \\ &= \int_{0}^{\pi} (-64\sin t\cos t)(t)\sqrt{(8\cos t)^2+1^2+(-8\sin t)^2} dt \\ &= -64\int_{0}^{\pi} t\sin t\cos t\sqrt{64\cos^2t+64\sin^2t+1} dt\end{aligned}$$Let $u=64\cos^2t+64\sin^2t+1=65$, $du = 0$. When $t=0$, $u=65$, and when $t=\pi$, $u=65$\)

Hence, we have\($$\begin{aligned}& \int_{C}xyz ds = -64\int_{0}^{65} \left(\frac{t}{2}\right)\sqrt{u}\left(\frac{du}{32}\right) \\ &= -2\int_{0}^{65} t\sqrt{u}\ du \\ &= -2\left[\frac{2}{5}u^{\frac{5}{2}}\right]_{0}^{65} \\ &= -\frac{2}{5}(65)^{\frac{5}{2}} \\ &= -\frac{2}{5}(65)(65)^2 \\ &= \boxed{-84550}\end{aligned}$$\)

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Step-by-step explanation:

5x-16 = 3 (10+x)

=> x= 23

Answer:

30

Step-by-step explanation:

idek

The second Taylor polynomial of a function is a polynomial approximation to that function which is accurate near a particular point x0.

Construct the second Taylor's polynomial P2(x) for f(x)= sin(2x) about x0 = 0

We are to find the second Taylor polynomial for the function f(x) = sin (2x) about the point x0 = 0.

The second derivative of sin(2x) is -4 sin(2x),

so the second Taylor polynomial is given by:

P2(x) = f(x0) + f '(x0)(x - x0) + (1/2!)f ''(x0)(x - x0)²

P2(x) = sin(0) + cos(0)(x - 0) - 2sin(0)(x - 0)²

P2(x) = x - 2x²

Use P2(π/3) to approximate f(π/6)

We haveP2(x) = x - 2x²

Putting x = π/3, we get

P2(π/3) = (π/3) - 2(π/3)²

P2(π/3) = (π/3) - 2(π²/9)

P2(π/3) = (π/3) - (2π²/9)

To approximate f(π/6), we substitute π/6 for x in the original function. We get:

f(π/6) = sin(2(π/6))

= sin(π/3)

Now we use P2(π/3) to approximate sin(π/3):

sin(π/3) ≈ P2(π/3)

= (π/3) - (2π²/9)

≈ (1.05) - (2/3)(3.14)²

≈ 0.6724

We found that the second Taylor polynomial for the function f(x) = sin (2x) about the point x0 = 0 is:

P2(x) = f(x0) + f '(x0)(x - x0) + (1/2!)f ''(x0)(x - x0)²

P2(x) = sin(0) + cos(0)(x - 0) - 2sin(0)(x - 0)²

P2(x) = x - 2x²

We used P2(π/3) to approximate f(π/6) and found that sin(π/3) ≈ P2(π/3) = (π/3) - (2π²/9) ≈ 0.6724

The second Taylor polynomial of a function is a polynomial approximation to that function which is accurate near a particular point x0. The Taylor polynomial can be used to approximate function values near x0.

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Answer:

i think b) option b

Step-by-step explanation:

lmk if this is incorrect

After subtraction (3x+4) - (x+7), the resultant answer is 2x-3.

One of the four operations used in mathematics, along with addition, multiplication, and division, is subtraction.

Removal of items from a collection is represented by the operation of subtraction.

For instance, in the following image, there are 5 2 peaches, which means that 5 peaches have had 2 removed, leaving a total of 3 peaches.

So, we have:

(x+7) and (3x+4)

We have to subtract as:

(3x+4) - (x+7)

Now, subtract as follows:

(3x+4) - (x+7)

3x+4 - x-7

2x-3

Therefore, after subtraction (3x+4) - (x+7), the resultant answer is 2x-3.

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The estimated median price of a single-family home in Charleston/No. Charleston in the 1st Quarter of 2008 is $201,048. If the median price continues to decrease at the same rate for the next two years, the estimated median price of a single-family home in the 1st Quarter of 2011 would be $144,458.

(a) To estimate the median price of a single-family home in the 1st Quarter of 2008, we need to calculate the original price before the 8.15% decrease. Let's assume the original price was P. The price after the decrease can be calculated as P - 8.15% of P, which translates to P - (0.0815 * P) = P(1 - 0.0815). Given that the end of 1st Quarter of 2009 median price was $184,990, we can set up the equation as $184,990 = P(1 - 0.0815) and solve for P. This gives us P ≈ $201,048 as the estimated median price of a single-family home in the 1st Quarter of 2008.

(b) If the median price of a single-family home falls at the same rate for the next two years, we can calculate the price for the 1st Quarter of 2011 using the estimated median price from the 1st Quarter of 2009. Starting with the median price of $184,990, we need to apply an 8.15% decrease for two consecutive years. After the first year, the price would be $184,990 - (0.0815 * $184,990) = $169,805.95. Applying the same percentage decrease for the second year, the price would be $169,805.95 - (0.0815 * $169,805.95) = $156,012.32. Therefore, the estimated median price of a single-family home in the 1st Quarter of 2011 would be approximately $144,458.

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Jorge mowed 18 lawns.

Let the number of lawns mowed by Jorge =x

So according to the question

Number of lawns mowed by sandra = x/3

Number of lawns mowed by Danny =x/2

Number of lawns mowed by Valeria =16

sum of total lawns mowed = lawns mowed by Jorge + lawns mowed by sandra + lawns mowed by Danny + lawns mowed by Valeria.

\(x+\frac{x}{3} +\frac{x}{2} +16=49\)

taking LCM as 6 and solving further we get

\(\frac{6x+2x+3x+96}{6} =49\)

By cross Multiplying we get

11x+96=294

11x=198

Solving further for x,

x=198/11

x=18

Therefore,  the number of lawns mowed by Jorge is 18 .

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Yes, Andre is correct. That is any real number can go in either of the boxes will be a real number.

Polynomial expression:

Any expression which consists of variables, constants, and exponents, and is combined using mathematical operators like addition, subtraction, multiplication, and division in a polynomial expression.

The given polynomial expression is

(5 \(x^{4}\) + _x³ )( 4\(x^{ -}\) - 6) = A

Here in the blank space we can write any real number which will give a polynomial expression.

So, Andre is correct.

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Answer:

Step-by-step explanation:

The loop will run an infinite number of times

Answer:

Step-by-step explanation:

A)1) I found the LCM, by multiplying the common term with highest power and multiplying all the uncommon terms

2) I factored the trinomials into binomials that satisfies (i) the sum of two numbers is (-7) (ii)  Product of the two numbers is 6

9514 1404 393

Answer:

  -3

Step-by-step explanation:

The "b" is the y-intercept in the slope-intercept form ...

  y = mx + b

Filling in the given values, we can find b.

  -1 = (2/3)(3) +b

  -1 = 2 + b . . . . simplify

  -3 = b . . . . . . . subtract 2

The value for b is -3.

Answer:

to find the perimeter of a rectangle , just add up all the values of the sides.

hope it helps :)

The Taylor series for a function about x=0 is given by 2^k/3kx^k. We are supposed to find f5(0).The given Taylor series can be written as follows'(x) = ∑_k=0^∞▒(2^k)/(3k)x^k``f5(x) = (2^5)/(3×5)x^5``f5(0) = (2^5)/(3×5)×0^5 = 0`Therefore, f5(0) = 0. The work leading to this answer has been shown above.
To find f^(5)(0), we need to identify the term in the Taylor series that corresponds to the 5th derivative of the function evaluated at x=0. The general term in the Taylor series is given by:

(2^k / 3k) * x^k

We need to find the term where k = 5:

(2^5 / 3*5) * x^5 = (32 / 15) * x^5

Now, to find f^ (5)(0), we evaluate this term at x = 0:

(32 / 15) * 0^5 = 0

So, f^ (5)(0) = 0.

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The work done by the force can be found to be 206. 45 foot-pounds.

To find the work done by the force, the formula is:

Work = Force × Distance × cos (θ)

The angle was 55° , the distance was 20 feet and the force was 18 pounds. This is included in the question and so can be used to find the work done to be :

= 18 × 20 × cos ( 55 °)

= 18 × 20 × 0. 573576

= 206. 44568

= 206. 45 foot - pounds

In conclusion, the work done by the force was approximately 206. 45 foot - pounds.

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The work that is done by the force is 280.2 J.

When a force acts on an object and causes it to move a specific distance, the amount of energy that is transmitted is known as the work done. It is described as the result of the amount of force that is exerted on an item and the distance that the object moves in the force's direction.

We have;

W = FdCosθ

W = work done

F = force

d = distance

θ = Angle turned

F = 18 Ib = 80.1 N

d = 20 feet = 6.1 m

θ = 55°

W = 80.1 N * 6.1 m * Cos 55

= 280.2 J

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The number of novels purchased was 9 novels.

Let the number of novels purchased be x and the number of magazines purchased be y.

Hence, \(x + y = 11.\)

Let the selling price of novels be a and that of magazines be b.

Therefore, \(ax + by = 20.\)

Similarly, given the price of magazines and novels as shown below:

\(a=  2\\b = 1\)

We can use the given equations above to find the number of novels purchased.

To find the value of x, we substitute the value of a and b into the equations,

\(ax + by = $20$2x + $1y \\= $20\)

We can also use the equation we found from \(x + y = 11,\) and solve for \(y:y = 11 - x\)

We can now substitute this value of y into the equation\(2x + 1y = 202x + 1(11 - x) \\= 201x \\=9x \\= 9 novels\)

Therefore, the number of novels purchased was 9 novels.

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