The pendulum has the greatest kinetic energy and no potential energy when it is _____.


swinging upward

at the top of the swing

at the bottom of the swing

swinging downward

Answer:

Answers 1. An amide linkage between the carboxyl group of one amino acid and the amine group of the other amino acid. 2. An ester is a compound formed from the reaction of a carboxylic acid and an alcohol. ( I apologise, I cant figure out number 3.. )

Answer:

reaction of phosphorus with the helegones

When 100 mL of carbon disulfide is burned completely, we get 37.02 L of CO2 and 74.14 L of SO2 at STP.

What is STP?

STP stands for Standard Temperature and Pressure. It is defined as a temperature of 0 degrees Celsius (273.15 K) and a pressure of 1 atmosphere (or 101.325 kPa). STP is used as a reference point for many thermodynamic calculations and is often used to compare gas volumes under standardized conditions.

The balanced equation for the combustion of carbon disulfide (CS2) is:

CS2 + 3O2 → CO2 + 2SO2

From the equation, we can see that for every mole of CS2 burned, we get one mole of CO2 and two moles of SO2.

To find the moles of CS2 in 100. mL, we need to convert the volume to mass using the density of CS2:

mL x (1.26 g/mL) = 126 g

The molar mass of CS2 is 76.14 g/mol, so the number of moles of CS2 is:

126 g / 76.14 g/mol = 1.655 mol

Therefore, we will get:

1.655 mol CO2 and 2 x 1.655 = 3.31 mol SO2

To convert these values to volume at standard temperature and pressure (STP), we can use the conversion factor:

1 mol of any gas at STP occupies 22.4 L

So:

1.655 mol CO2 x 22.4 L/mol = 37.02 L CO2

3.31 mol SO2 x 22.4 L/mol = 74.14 L SO2

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Sodium (Na) and chlorine (Cl) are the largest dissolved components in ocean water due to the abundance of sodium and chloride ions in the Earth's crust and the continuous input of these elements into the oceans through various processes. Sodium is one of the most common elements in the Earth's crust, and chlorine is widely distributed in rocks, minerals, and salts.

Over millions of years, weathering of rocks, volcanic activity, and erosion release these elements into rivers and ultimately into the oceans. The combination of sodium and chlorine ions results in the formation of sodium chloride, which is commonly known as table salt and contributes to the salinity of seawater.

The most abundant dissolved gas in ocean water is carbon dioxide (CO2). Carbon dioxide dissolves in the surface waters of the ocean through gas exchange with the atmosphere. It plays a crucial role in regulating the pH of seawater and is an essential component of the carbon cycle. Carbon dioxide is involved in various biological and chemical processes in the ocean, including photosynthesis by marine plants and the formation of calcium carbonate shells by marine organisms. Additionally, the increase in atmospheric carbon dioxide due to human activities has led to ocean acidification, which is a significant concern for marine ecosystems.

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Due to the fact that they combine to form the ionic compound sodium chloride (NaCl), also known as salt, sodium (Na) and chlorine (Cl) are the two most abundant dissolved elements in ocean water.

Thus, Salts are among the many dissolved compounds that water from rivers and streams transports into the ocean.

In particular, sodium and chloride ions have accumulated in the ocean throughout time, leading to the high concentration of these elements in seawater. Magnesium, calcium, potassium, and sulphate ions are among the other dissolved substances in ocean water.

Oxygen  is the dissolved gas that is most prevalent in ocean water.

Thus, Due to the fact that they combine to form the ionic compound sodium chloride (NaCl), also known as salt, sodium (Na) and chlorine (Cl) are the two most abundant dissolved elements in ocean water.

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Answer:

Mathematical

Explanation:

It shows how to find the hypotenuse

Answer:

Kinetic energy

Explanation:

This is the energy possessed by a moving object.

Answer:

Only 3 atoms

Explanation:

The 3 came from the coefficient.

Explanation:

O, S, Se

because they belong to same group (Group 16).

According to the solving the concentration of the aqueous solution is 3.0 mol/L (or 3.0 M).

Water with one or more dissolved substances is known as an aqueous solution. An aqueous solution can contain dissolved gases, particles, or other liquids. A mixture needs to be stable to qualify as a real solution.

To calculate the concentration of an aqueous solution that contains 1.5 moles of NaCl in 500 milliliters of solution, we can use the following formula:

C = n/V

where n is the amount of solute in moles, and V is the volume of solution in liters.

First, we need to convert the volume of solution from milliliters to liters:

500 milliliters = 0.5 liters

Now we can plug in the values we have:

C = 1.5 moles / 0.5 liters = 3.0 mol/L

Therefore, the concentration of the aqueous solution is 3.0 mol/L (or 3.0 M).

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Answer:(0.500/0.750) x 98.8 = 65.9 kPa.

Explanation:

I think that's the answer

Answer:

i'm attaching the report i made

Explanation:

(It does include the chart information)

hope this helps! have a wonderful day :)

The solubility of a solid solute increases with temperature.

The solubility of a solute is the amount of solute that dissolves in a given volume of solvent at a particular temperature.

The solubility of a solute increases with increase in temperature.

Based on the lab results, it was seen that with increase in temperature, the mass of sugar that dissolves in water increases.

50 mL of water at 2 °C dissolved only 80 g of sugar whereas at 102 °C, 250 g of sugar dissolved.

Therefore, it can be concluded that solubility of a solute increases with temperature.

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Answer:

Explanation: Elements in group 14 have 4 valence electrons. Meaning that to achieve a stable octet they need to either gain or lose 4 electrons in total. That would take significantly more energy than other elements, e.g., group 1 (alkaline metals) or group 17 (halogens.)

Explanation:

In the periodic table, the elements in column 4 have four valence electrons and are less reactive compared to s- block elements but more reactive than the p-block elements.

Periodic table is a tabular arrangement of elements in the form of a table. In the periodic table, elements are arranged according to the modern periodic law which states that the properties of elements are a periodic function of their atomic numbers.

It is called as periodic because properties repeat after regular intervals of atomic numbers . It is a tabular arrangement consisting of seven horizontal rows called periods and eighteen vertical columns called groups.

Elements present in the same group have same number of valence electrons and hence have similar properties while elements present in the same period show gradual variation in properties due to addition of one electron for each successive element in a period.

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Answer:helium or the noble gases

Explanation: The ionization energy decreases from top to bottom in groups, and increases from left to right across a period. Thus, helium has the largest ionizing energy

Answer:

Did u get the answers

Explanation:

Answer: False

Explanation: The moon travels at 1.42 mph around the Earth.

Answer:

false

Explanation:

4-ethylheptanoic acid will react with ethanol to produce the desired product, which is 5-ethyl-2-octanone.

4-ethylheptanoyl chloride → 4-ethylheptanoic acid

(NₐOH) → 5-ethyl-2-octanone (H₂SO₄)

To convert 4-ethylheptanoyl chloride to 5-ethyl-2-octanone, you can follow a two-step process:

Step 1: Conversion of 4-ethylheptanoyl chloride to 4-ethylheptanoic acid

Reagent: Aqueous sodium hydroxide (NₐOH)

Procedure: Treat 4-ethylheptanoyl chloride with aqueous sodium hydroxide (NₐOH) to undergo hydrolysis and convert it into the corresponding carboxylic acid, which is 4-ethylheptanoic acid.

The reaction is an acid-base reaction, where the chloride group is replaced by the hydroxyl group.

Step 2: Conversion of 4-ethylheptanoic acid to 5-ethyl-2-octanone

Reagent: Acidic conditions, such as sulfuric acid (H₂SO₄)

Procedure: Treat 4-ethylheptanoic acid with acidic conditions, such as sulfuric acid (H₂SO₄), to undergo an esterification reaction.

In this reaction, the carboxylic acid reacts with an alcohol to form an ester.

Here, 4-ethylheptanoic acid will react with ethanol to produce the desired product, which is 5-ethyl-2-octanone.

Overall, the conversion can be summarized as follows:

4-ethylheptanoyl chloride → 4-ethylheptanoic acid

(NₐOH) → 5-ethyl-2-octanone (H₂SO₄)

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The multi-step process to convert 4-ethylheptanoyl chloride to 5-ethyl-2-octanone requires the reagents: water, ethanol, sulfuric acid, sodium hypochlorite, and PCC. Each step involves specific conditions and reactions to achieve the desired product.

To convert 4-ethylheptanoyl chloride to 5-ethyl-2-octanone, you will need to follow a multi-step process. Here are the reagents required for each step:
Step 1: Hydrolysis of 4-ethylheptanoyl chloride to 4-ethylheptanoic acid
- Reagent: Water (H2O)
- Condition: Room temperature or slightly heated
Step 2: Esterification of 4-ethylheptanoic acid to 4-ethylheptanoate
- Reagent: Ethanol (C2H5OH)
- Acid catalyst: Sulfuric acid (H2SO4)
- Condition: Room temperature or slightly heated
Step 3: Oxidation of 4-ethylheptanoate to 4-ethylheptanoic acid
- Reagent: Sodium hypochlorite (NaOCl)
- Condition: Room temperature or slightly heated
Step 4: Oxidation of 4-ethylheptanoic acid to 5-ethyl-2-octanone
- Reagent: PCC (pyridinium chlorochromate)
- Condition: Room temperature
It's important to note that these are general steps, and the specific conditions and reagents may vary depending on the reaction conditions and desired yields. Additionally, it's crucial to conduct each step carefully, ensuring the reactions occur under the appropriate conditions and monitoring the progress through suitable analytical techniques.
In summary, the reagents necessary to carry out the conversion from 4-ethylheptanoyl chloride to 5-ethyl-2-octanone include water, ethanol, sulfuric acid, sodium hypochlorite, and PCC.

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It is inappropriate that Ingestion of a toxic substance is the only way a poisoning can occur.

A poison can be any substance that is harmful to the body. It can be swallowed, inhaled, injected or absorbed through the skin. Poisoning is the harmful effect that occurs when too much of that substance has been taken. Poisoning is not to be confused with envenomation.

Acute poisoning is exposure to a poison on one occasion or during a short period of time. Symptoms develop in close relation to the degree of exposure. Absorption of a poison is necessary for systemic poisoning (that is, in the blood throughout the body)

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Answer:

no

Explanation:

light is a form of energy so it doent have matter therefore it doent take up sapce

The compound that exhibits both ionic and covalent bonding is NO4 (Option D).

This is because NO4 is a polyatomic ion that is made up of both covalent and ionic bonds. The nitrogen and oxygen atoms within the NO4 ion form covalent bonds with each other, sharing electrons to create a stable molecule. However, the NO4 ion as a whole has a net charge of -1, which means that it has gained an electron from another atom. This indicates that there is also an ionic bond between the NO4 ion and the atom that has donated the electron.
On the other hand, KCI is a compound that exhibits only ionic bonding. This is because it is made up of a metal (potassium) and a non-metal (chlorine), which have a large difference in electronegativity. As a result, potassium donates its electron to chlorine, forming an ionic bond between the two ions.
Similarly, Cl2O2 is a compound that exhibits only covalent bonding. This is because it is made up of two non-metals (chlorine and oxygen) that share electrons to form a stable molecule.
In summary, NO4 is the only compound listed that exhibits both covalent and ionic bonding, due to the covalent bonding between the nitrogen and oxygen atoms and the ionic bonding between the NO4 ion and another atom.

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Answer:

boiling point is an intensive property because it stays the same no matter the amount of an element or molecule

Explanation:

Answer:

The correct answer is - 2.26*10^5 J

Explanation:

Given:

The amount of water need to vaporized = 100 g

We know:

The heat of vaporization of water = 2260 j/g

The required heat (q)

= mass of the liquid (m) * the heat of vaporization of liquid (ΔH)

q = m*ΔH .......1

So, from the equation 1,

the 100 gram sample of water being completely vaporized needs

= 2260*100

=2.26*10^5 J.

Thus, the correct answer is = 2.26*10^5 J.

Answer:   Graphite is nonpolar carbon which associates with the nonpolar hexanes. The cellulose in the exposed paper contains polar regions that are attracted to the polar water.

Explanation:

Answer:

= - 303.975 Joules

Explanation:

Given that:

The volume of the cylinder = 0.003 m^3

Now, to liters:

The volume = 0.003 *1000 L

= 3 L

For an open cylinder, we mean the atmospheric pressure is at standard condition.

Thus, the workdone = -PΔV

= - 1 atm (3 L)

= - 3 L atm

1 L atm to Joules

= 101.325 Joules

Therefore;

=- 3* 101.325 Joules

= - 303.975 Joules

The limiting reagent is 129.8 g of methane which will react completely with 259 g of oxygen, and 159 g of methane is in excess.

To determine the mass of water required to react completely with 1.70 mol of acetylene, we need to first write and balance the chemical equation:

CHCH + 2H2O ⟶ HOCH2CH2OH

From the equation, we can see that 1 mole of acetylene reacts with 2 moles of water. Therefore, 1.70 mol of acetylene would require:

2 mol H2O/mol CHCH × 1.70 mol CHCH = 3.40 mol H2O

To convert mol of water to grams, we need to use the molar mass of water, which is approximately 18.015 g/mol:

3.40 mol H2O × 18.015 g/mol = 61.27 g of water

Therefore, 61.27 g of water would be required to react completely with 1.70 mol of acetylene.

To determine the limiting reagent, we need to first write and balance the chemical equation for the combustion of methane:

CH4 + 2O2 ⟶ CO2 + 2H2O

From the equation, we can see that 1 mole of methane reacts with 2 moles of oxygen. Therefore, we can calculate the moles of methane and oxygen present:

Moles of CH4 = 159 g / (12.01 g/mol + 4(1.01 g/mol)) = 159 g / 16.05 g/mol = 9.91 mol

Moles of O2 = 259 g / 32.00 g/mol = 8.09 mol

To determine the limiting reagent, we need to compare the moles of each reactant present to the stoichiometric ratio in the balanced equation. The reactant that is present in excess will not be completely consumed and therefore, the other reactant will be the limiting reagent.

For methane, the stoichiometric ratio with oxygen is 1:2, which means that 1 mole of methane requires 2 moles of oxygen. Therefore, the maximum number of moles of oxygen that can be consumed is:

2 mol O2/mol CH4 × 9.91 mol CH4 = 19.82 mol O2

Since we only have 8.09 mol of oxygen available, oxygen is the limiting reagent. Therefore, methane is present in excess and some of it will remain unreacted. The amount of methane that will react with the available oxygen can be calculated as:

1 mol CH4/1 mol O2 × 8.09 mol O2 = 8.09 mol CH4

To convert the moles of methane to grams, we can use the molar mass of methane, which is approximately 16.04 g/mol:

8.09 mol CH4 × 16.04 g/mol = 129.8 g CH4

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The number of mole present in 87 grams of potassium bromide, KBr is 0.731 mole

We'll begin our calculation by obtaining the molar mass of potassium bromide, KBr. Details below:

Molar mass of potassium bromide, KBr = K + Br

Molar mass of potassium bromide, KBr = 39 + 80

Molar mass of potassium bromide, KBr = 119 g/ mol

Finally, we shall determine the number of mole present. Details below:

Mole = mass / molar mass

Mole of potassium bromide, KBr = 87/ 119

Mole of potassium bromide, KBr = 0.731 mole

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Complete question:

How many moles are in 87g of potassium bromide?

Answer:

Concept of chemi-fluorescence

Explanation:

A glow stick usually consists of two chemicals in a larger plastic tube: , a base catalyst (mostly sodium salicylate), and a suitable dye (sensitizer, or fluorophor). This creates an exergonic reaction when mixed together.

When a glow stick is bent, the flurophor which is a chemical that easily re-emits light upon excitation in smaller capsules is released into the other substance, there by causing it to emit radiation/light in the uv-visible region. The brightness and longevity of the glow stick is determined by varying the concentration of these chemicals.

I hope this explanation clarifies things.